Converting a string to integer error

I have this code
temp = token.nextToken().toString();
numero = Integer.parseInt(temp);
Is is giving me a numberFormatExeption error Knowing that temp is a string
can anyone help

Add the following print statement and tell us exactly what it prints out. (You will probably know what the error is once you see what it prints.=
temp = token.nextToken().toString();
System.out.println("temp = \"" + temp + "\"");
numero = Integer.parseInt(temp);

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Converting time string to integer (****) in Labview 5.1

So i'm very new to labview, learning as i go, but as the title says, i
need to convert a time string to an ineger so that it can be placed in
an integer array which will be compiled then writen to file at a
specified end ( by user ) I just want 4 digits **** to indicate
military time. And unfortuanly i'm stuck with labview 5.1. Any help would be greatly appreciated.

I believe the diagram I have attached may have been possible in LV 5.1.
Try to wire this up and see if it works.
The icons may have changed a little between LV 5.1 and 6.1.
Ben
Message Edited by Ben on 10-15-2005 02:49 PM
Ben Rayner
I am currently active on.. MainStream Preppers
Rayner's Ridge is under construction
Attachments:
Mitary Time.JPG ‏19 KB

Converting a string to an integer - NumberFormatException

Hello,
I have 2 string arrays, one that olds names and one that holds id numbers. They are both stored in a file as Strings. I then read this file into my program and put split the strings up into an array.
I then try to convert the id to integer inside my program like so:
public void make_array(String[] car_info) {
                // put in arraylist and change variable type to correct ones
                final int ID_INDEX = 0;
                final int TYPE = 1;
                int cust_id = 22;
                String type;
                //convert to correct variable types
                try {
                        //convert to string
                        cust_id = Integer.parseInt(car_info[ID_INDEX]);
                } catch (NumberFormatException e) { System.out.println(e); }
                type = car_info[TYPE];
}I then get the errors when i try this:
java.lang.NumberFormatException: For input string: "1"
So the id was stored as "1", but i want to convert it to an integer value. Any ideas on why this happends? Also before i try to convert i output the id from the array and it is correct, after the conversion it is 0, obviously it is not working. But i'm not sure what is wrong.
Any ideas?

only works when the string is a single number suchas
"1" or "4". If you try to use it with the input
string as a longer one like "123" or "12" itcreates
a NumberFormatExceptionYou must be mistaken. The value must not be what you
think it is. Do some debugging:
String strVal = car_info[ID_INDEX].trim();
System.out.println("This is the number to be
parsed -->" + strVal + "<--");
customer_id = Integer.parseInt(strVal);That is a good idea, but it seems as though the string is fine: I did:
gary@linuxbox# cat cars
this output:
1,5,Renault Clio,Small Car,25,4,false
As you can see the number 25 is a two figure number, and it looks good. I also output the number in the java program like this:
System.out.println("the number is ------>" + twodigitnumber + "<------");This output the number: ------->25<---------- So there doesn't seem to be any wierd spacing or characters there.

Convert text box string into integer

i have an html file in which i m using a text box , for entering amount i m using that text box entry at next jsp. i want to convert amount string into integer for further processing. At next jsp i m using:-
String amount= request.getParameter("bal");
int ammount1= Integer.parseInt(ammount);
and in sql query i m using amount1 as:-
ResultSet rs1 = st.executeQuery("update saving set balance = balance - amount1 where saving.account_no = '" + acc +"'");
my problem is i m getting following error:-
server encountered an internal error and
exception:- numberformat exception
please help me as soon as possible

int ammount1= Integer.parseInt(ammount).toString();
good to put try block too..
try
int ammount1 = Integer.parseInt(ammount).toString();
catch(NumberFormatException e)
...}

Convert string to integer

package onjava;
import java.io.*;
import java.net.*;
import java.util.*;
import org.apache.soap.*;
import org.apache.soap.rpc.*;
import java.lang.*;
import java.sql.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class CalcClient extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\"");
out.println("\"http://www.w3.org/TR/html4/loose.dtd\">");
out.println("<html>");
out.println("<head>");
out.println("<meta http-equiv=\"Content-Type\" content=\"text/html; charset=iso-8859-1\">");
out.println("<title>Substraction using SOAP</title>");
out.println("</head>");
    URL url = new URL ("http://localhost/soap/servlet/rpcrouter");
Integer p1=request.getParameter("param1");
Integer p2=request.getParameter("param2");
In the above statement i have to convert the string to integer because that has to be passed in my program as an argument to a function so please let me know how to do that
    // Build the call.
    Call call = new Call();
    call.setTargetObjectURI("urn:onjavaserver");
    call.setMethodName("subtract");
    call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC);
    Vector params = new Vector();
    params.addElement(new Parameter("p1", Integer.class, p1, null));
    params.addElement(new Parameter("p2", Integer.class, p2, null));
    call.setParams (params);
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    // XML-SOAP rpc router does not need this. This may change in the
    // future.
    Response resp = call.invoke(url, "" );
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    if ( resp.generatedFault() ) {
      Fault fault = resp.getFault ();
     out.println("The call failed: ");
     out.println("Fault Code   = " + fault.getFaultCode());
     out.println("Fault String = " + fault.getFaultString());
    else {
      Parameter result = resp.getReturnValue();
      out.println(result.getValue());
out.println("</body>");
out.println("</html>");

Two possibilities: Try either java.lang.Integer.valueOf() or java.text.NumberFormat and its parse method.
Either one will do what you want. I think Integer will be the simpler of the two.
The code you have is obviously not correct, because getParameter returns a String:
Integer p1=request.getParameter("param1");Do it like this:
Integer p1=Integer.valueOf(request.getParameter("param1"));%

Convert from String to Int

Hi,
I have a question.
How do I convert from String to Integer?
Here is my code:
try{
String s="000111010101001101101010";
int q=Integer.parseInt(s);
answerStr = String.valueOf(q);
catch (NumberFormatException e)
answerStr="Error";
but, everytime when i run the code, i always get the ERROR.
is the value that i got, cannot be converted to int?
i've done the same thing in c, and its working fine.
thanks..

6kyAngel wrote:
actually it convert the string value into decimal value.In fact what it does is convert the (binary) string into an integer value. It's the String representation of integer quantities that have a base (two, ten, hex etc): the quantities themselves don't have a base.
To take an integer quantity (in the form of an int) and convert it to a binary String, use the handy toString() method in the Integer class - like your other conversion, use the one that takes a radix argument.

Converting String to integer?

I looked on the sun forums and only found a lot of things that convert integers to Strings. Nothing to do the opposite.
Does anyone know how I can convert a String to an int?

coopkev2 wrote:
an "A" from a "B"?? I don't understand what you are saying... I want to convert "100" to 100.
Edit-- I'll be back soon.Read "A" as "Integer" and "B" as "String".
In this case: read the [java.lang.Integer API|http://java.sun.com/javase/6/docs/api/java/lang/Integer.html] if there is a method which takes a String and returns an Integer or int.

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Error on select when using value converted from varchar to integer (with isnumeric in where)

Hi,
Why is it, that when I convert a varchar into integer and filter it to numeric only that I get the Error 'Conversion failed when converting the nvarchar value '...' to data type int.'
Here is a short SQL witch shows the Error:
create table tTest(ID int, sText nvarchar(15))
insert into tTest
select 1, null
insert into tTest
select 2, 'q'
go
select distinct ID, sText, convert(int,sText) AS ID2 from tTest where isnumeric(sText) = 1
go
SELECT DISTINCT TOP 100 PERCENT
ID
FROM
(select distinct ID, sText, cast(sText as int) AS ID2 from tTest where isnumeric(sText) = 1) v1
WHERE
id2 = 1
go
drop table tTest
As a workaround I replaced the case with 'cast(case when isnumeric(sText) = 1 then sText else null end as int)', but this rater unexpected.
It works fine in a short query, but if I create a view with the SQL from V1 then the error is unexpected, since I only know that if I view the source of the view

>'cast(case when isnumeric(sText) = 1 then sText else null
ISNUMERIC is not 100% accurate.
BOL: "ISNUMERIC returns 1 for some characters that are not numbers, such as plus (+), minus (-), and valid currency symbols such as the dollar sign ($). For a complete list of currency symbols, see money and smallmoney (Transact-SQL)."
LINK: http://technet.microsoft.com/en-us/library/ms186272.aspx
ISNUMERIC examples:
http://sqlusa.com/bestpractices/isnumeric/
Kalman Toth Database & OLAP Architect
Free T-SQL Scripts
New Book / Kindle: Exam 70-461 Bootcamp: Querying Microsoft SQL Server 2012

Trouble converting "double like" string to integer

Hi everyone,
I have a trouble here. Let's say I have a string which its value is "314.12345667". the value is "like a double". How do i convert it into an integer where the integer only takes the value of da string before the decimal point (as in the value of string = 314 only)? Thanks for helping.

hi xamule,
tey this..
String s="314.123876"
double d=Double.parseDouble(s);
int x=d.intValue();
hope it may help u..
bye bye,
Pramod

Converting a string to an integer array

This is kind of a newbie question, but:
If I have a string which looks like this: "12,54,253,64"
what is the most effective/elegant/best/etc. way to convert it into an integer array (of course not including the ","s :-)
Any suggestions are greatly appreciated.

Thanks, I'll do that. I was looking at StringTokenizer and other things, but it seems they are not implemented in j2me?

Logic of converting strings to integer

Hi all,
I know that , I can convert a string into a number using API , Ineger.parseInt() . But i want to know the reall algoritham behind that
.Can anybody explane that ?
Basically I am interested in
String s = "123";
int i = Integer.parseInt(s);
But i want to know what is the logic running behind this ?. Can anybody please help me. ...?
Thanks in advance....

The decompiled version parseInt() from Integer class
     * Parses the string argument as a signed decimal integer. The
     * characters in the string must all be decimal digits, except that
     * the first character may be an ASCII minus sign <code>'-'</code>
     * (<code>'\u002D'</code>) to indicate a negative value. The resulting
     * integer value is returned, exactly as if the argument and the radix
     * 10 were given as arguments to the
     * {@link #parseInt(java.lang.String, int)} method.
     * @param s        a <code>String</code> containing the <code>int</code>
     *             representation to be parsed
     * @return     the integer value represented by the argument in decimal.
     * @exception NumberFormatException if the string does not contain a
     *               parsable integer.
    public static int parseInt(String s) throws NumberFormatException {
     return parseInt(s,10);
     * Parses the string argument as a signed integer in the radix
     * specified by the second argument. The characters in the string
     * must all be digits of the specified radix (as determined by
     * whether {@link java.lang.Character#digit(char, int)} returns a
     * nonnegative value), except that the first character may be an
     * ASCII minus sign <code>'-'</code> (<code>'\u002D'</code>) to
     * indicate a negative value. The resulting integer value is returned.
     * <p>
     * An exception of type <code>NumberFormatException</code> is
     * thrown if any of the following situations occurs:
     * <ul>
     * <li>The first argument is <code>null</code> or is a string of
     * length zero.
     * <li>The radix is either smaller than
     * {@link java.lang.Character#MIN_RADIX} or
     * larger than {@link java.lang.Character#MAX_RADIX}.
     * <li>Any character of the string is not a digit of the specified
     * radix, except that the first character may be a minus sign
     * <code>'-'</code> (<code>'\u002D'</code>) provided that the
     * string is longer than length 1.
     * <li>The value represented by the string is not a value of type
     * <code>int</code>.
     * </ul><p>
     * Examples:
     * <blockquote><pre>
     * parseInt("0", 10) returns 0
     * parseInt("473", 10) returns 473
     * parseInt("-0", 10) returns 0
     * parseInt("-FF", 16) returns -255
     * parseInt("1100110", 2) returns 102
     * parseInt("2147483647", 10) returns 2147483647
     * parseInt("-2147483648", 10) returns -2147483648
     * parseInt("2147483648", 10) throws a NumberFormatException
     * parseInt("99", 8) throws a NumberFormatException
     * parseInt("Kona", 10) throws a NumberFormatException
     * parseInt("Kona", 27) returns 411787
     * </pre></blockquote>
     * @param      s   the <code>String</code> containing the integer
     *                representation to be parsed
     * @param      radix   the radix to be used while parsing <code>s</code>.
     * @return     the integer represented by the string argument in the
     *             specified radix.
     * @exception NumberFormatException if the <code>String</code>
     *              does not contain a parsable <code>int</code>.
    public static int parseInt(String s, int radix)
          throws NumberFormatException
        if (s == null) {
            throw new NumberFormatException("null");
     if (radix < Character.MIN_RADIX) {
         throw new NumberFormatException("radix " + radix +
                             " less than Character.MIN_RADIX");
     if (radix > Character.MAX_RADIX) {
         throw new NumberFormatException("radix " + radix +
                             " greater than Character.MAX_RADIX");
     int result = 0;
     boolean negative = false;
     int i = 0, max = s.length();
     int limit;
     int multmin;
     int digit;
     if (max > 0) {
         if (s.charAt(0) == '-') {
          negative = true;
          limit = Integer.MIN_VALUE;
          i++;
         } else {
          limit = -Integer.MAX_VALUE;
         multmin = limit / radix;
         if (i < max) {
          digit = Character.digit(s.charAt(i++),radix);
          if (digit < 0) {
              throw NumberFormatException.forInputString(s);
          } else {
              result = -digit;
         while (i < max) {
          // Accumulating negatively avoids surprises near MAX_VALUE
          digit = Character.digit(s.charAt(i++),radix);
          if (digit < 0) {
              throw NumberFormatException.forInputString(s);
          if (result < multmin) {
              throw NumberFormatException.forInputString(s);
          result *= radix;
          if (result < limit + digit) {
              throw NumberFormatException.forInputString(s);
          result -= digit;
     } else {
         throw NumberFormatException.forInputString(s);
     if (negative) {
         if (i > 1) {
          return result;
         } else {     /* Only got "-" */
          throw NumberFormatException.forInputString(s);
     } else {
         return -result;
    }

Converting a String to an integer?

i need to convert a string to an integer..i searched through the site but i didn't find anything...
Is this conversion possible?

You didn't look very hard - it's right in the javadocs:
String s = "44";
int x = Integer.parseInt(s);I'll leave the exception handling for you.

Converting a string to an integer value

How can I convert a string to an integer?

sorry, not "of new Integer.." but "or new Integer(.."
Message was edited by:
s-e-r-g-e

Beginner ?: Converting String to Integer

Hello! I'm having some trouble converting a string to an integer. Here is my code:
var str:String = e.currentTarget.name as String; // Getting values like "song1", "song2"
str = str.replace("song", ""); // Changes it from "song1" or "song2" to "1" or "2"
var num:int = str as int; // SHOULD be converting the "1" to 1 and "2" to 2
trace("num:" + num + ", str:" + str);
The trace is always outputting:
num:0, str:1
num:0, str:2
etc..
The str value is there, but when it gets put into num then it zeros out. What am I doing wrong?
Thanks in advance!

Try using: var num:int = int(str);

Converting a string to integer error

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