Converting int type into two bytes!

Hi everyone,
i need help in converting types.
I have and int ranging from 0-4095 that i would like
to write in a file as couple of bytes.
For example suppose the int has four bytes
[A][C][D]
i would like to write in a file only the two bytes [C][D].
How can i do?
What does the byte casting do?
int number = 1000;
(byte)number = ??
Thank you in advance
-- Andy

someting like this:
int data;
byte byte0=(byte)((data&0x000000ff)>>0);
byte byte1=(byte)((data&0x0000ff00)>>8);
byte byte2=(byte)((data&0x00ff0000)>>16);
byte byte3=(byte)((data&0xff000000)>>24);

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Hi,
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Hi,
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Hi!
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Hi,
I have a question which I would really appreciate any help on.
I am trying to send a byte array, that contains multiple types using a UDP app. and then receive it on the other end.
So far I have been able to do this using the following code. Please note that I create a new String, Float or Double object to be able to correctly send and receive. Here is the code:
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socket.send(packet);
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So I tried creating another class, and then creating an obj of this class and stuffing it with the 4 types:
public class O_struct{
//the indiv. objects to be sent...
public String mymessage; public int nbr; public Double nbr2;
public Float nbr3;
//construct...
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in main():
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However on the receiving side, I am not sure how to be able to correctly retrieve the 4 types. Before I was explicitely creating those objects for sending, then I was casting them again on the receiving side to retrieve then and it does work.
But if I create a O_struct object and cast it as I did before with the indiv objects on the receiving end, I can't get the correct retrievals.
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I might be making this more complicated than needed, but this was the only way I could figure out how to do this and any help will be greatly appreciated.
If there an easier way to do I certainly will appreciate that advise as well.
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public class O_struct implements Serializable {
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I will be sending 1000s of these byte arrays, and I'm sure having to create a new Double or Float on both ends will hinder this.
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That's the wrong way to approach this. You're talking about adding complexity to your code and fuglifying it because you think it might improve performance. But you don't know if it will, or by how much, or even if it needs to be improved.
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If you think object creation is going to be a problem, then before you go and cock up your real code to work around it, create some tests that measure how fast it is one way vs. the other. Then only use the cock-up if the normal, easier to write and maintain way is too slow AND the cock-up is significantly faster.

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Hi all,
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Message was edited by:
Djaunl

I've been working with 8-bit
data (this is 12-bits, NOT packed), Obviously that is contradictory.
I currently have this method to convert a byte[] of
8-bit data into a short (I do this because Java does
not support signed types and I need that 8th bit):
Yes it does. The fact that it displays a byte as and integer and the conversion in that process produces a negative display value has nothing at all to do with the bits.
Is there a way to modify this to place two bytes into
one short? short s = (short)(((b1 << 8) & 0x0ff) | (b2 & 0x0ff))
Of course you still have to deal with getting the order correct.
(You can probably get rid of that first mask but you would need to test that.)

CAST Not working for me - Arithmetic overflow error converting int to data type numeric - error

GPM is DECIMAL(5,2)
PRICE is DECIMAL(11,4)
COST is DECIMAL(7,2)
Trying to update the Gross Profit Margin % field and I keep getting the "Arithmetic overflow error converting int to data type numeric" error.
UPDATE SMEMODETAIL SET SMD_GPM = (SMD_PRICE-SMD_COST) / SMD_PRICE * 100
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Hi GBerthume,
The error is caused by some value such as 1000.01 of the expression (SMD_PRICE-SMD_COST) / SMD_PRICE * 100 exceeds the
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SMD_COST DECIMAL(7,2),
SMD_GPM DECIMAL(5,2)
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SELECT * FROM SMEMODETAIL
DROP TABLE SMEMODETAIL
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Eric Zhang
TechNet Community Support

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Thanks. I might use it soon...
Does it automatically make folders named after the volume labels? And does it handle the conversion of spaces and non-alphanumeric characters to octal codes?
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How to convert a integer into bytes!!!

I am trying to pack the length of the data transamitted over a stream into 2 bytes (Each byte is a unsigned char in terms of 'C' language). When i am using the bytes in java any value greater than 127 is a negative number (I understand the very definition of 'byte' in java), my question is how to pack the length of the data the 'C' way still following Java rules??
Example :: Length of the data is 168 say!
the 2 bytes would be 0x00, 0x80 (the respective ascii values would be NULL, P) but with Java i get some thing different as we know??
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For what it's worth:package ca.adaptor.util;
* $Id: ByteUtil.java,v 1.6 2003/03/28 18:24:47 mike Exp $
* Copyright (c) 2002 by Michael Coury
* This library is free software; you can redistribute it and/or
* modify it under the terms of the GNU Lesser General Public
* License as published by the Free Software Foundation; either
* version 2.1 of the License, or (at your option) any later version.
* This library is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
* You should have received a copy of the GNU Lesser General Public
* License along with this library; if not, write to the Free Software
* Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
* @author Michael Coury (mdc)
* @created Sep 20, 2002
* @version $Revision: 1.6 $, $Date: 2003/03/28 18:24:47 $
public final class ByteUtil {
private static final int __NUM_BYTES_IN_LONG_   = 8;
private static final int __NUM_BYTES_IN_INT_    = 4;
private static final int __NUM_BYTES_IN_SHORT_ = 2;
private static final int __NUM_BITS_IN_BYTE_    = 8;
private static final long __BYTE_MASK_           = 0xFF;
/** PRIVATE CONSTRUCTOR */
private ByteUtil() {}
            ///// ENCODE /////
   * Converts a number to its binary equivalent and returns that as a byte array
public static final byte[] toBytes(final long aNum) {
    final byte[] ret = new byte[__NUM_BYTES_IN_LONG_];
    for(int i = 0; i < __NUM_BYTES_IN_LONG_; i++)
      ret[i] = (byte) (aNum >>> ((__NUM_BYTES_IN_LONG_ - 1 - i) * __NUM_BITS_IN_BYTE_));
    return ret;
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public static final byte[] toBytes(final int aNum) {
    final byte[] ret = new byte[__NUM_BYTES_IN_INT_];
    for(int i = 0; i < __NUM_BYTES_IN_INT_; i++)
      ret[i] = (byte) (aNum >>> ((__NUM_BYTES_IN_INT_ - 1 - i) * __NUM_BITS_IN_BYTE_));
    return ret;
   * Converts a number to its binary equivalent and returns that as a byte array
public static final byte[] toBytes(final short aNum) {
    final byte[] ret = new byte[__NUM_BYTES_IN_SHORT_];
    for(int i = 0; i < __NUM_BYTES_IN_SHORT_; i++)
      ret[i] = (byte) (aNum >>> ((__NUM_BYTES_IN_SHORT_ - 1 - i) * __NUM_BITS_IN_BYTE_));
    return ret;
   * Converts a number to its binary equivalent and returns that as a byte array
public static final byte[] toBytes(final double aNum) {
    return toBytes(Double.doubleToRawLongBits(aNum));
   * Converts a number to its binary equivalent and returns that as a byte array
public static final byte[] toBytes(final float aNum) {
    return toBytes(Float.floatToRawIntBits(aNum));
            ///// DECODE /////
   * Converts a byte array representing a long back to a long
public static final long toLong(final byte[] aNum) {
    try {
      long ret = 0L;
      for(int i = 0; i < __NUM_BYTES_IN_LONG_; i++) {
        ret += ((long) aNum[i] & __BYTE_MASK_) << ((__NUM_BYTES_IN_LONG_ - 1 - i) * __NUM_BITS_IN_BYTE_);
      return ret;
    catch(Exception e) {
      throw new NumberFormatException("Invalid number of bytes for long. Found: " + aNum.length
                                      + " Required: " + __NUM_BYTES_IN_LONG_);
   * Converts a byte array representing an int back to an int
public static final int toInt(final byte[] aNum) {
    try {
      int ret = 0;
      for(int i = 0; i < __NUM_BYTES_IN_INT_; i++)
        ret += (aNum[i] & __BYTE_MASK_) << ((__NUM_BYTES_IN_INT_ - 1 - i) * __NUM_BITS_IN_BYTE_);
      return ret;
    catch(Exception e) {
      throw new NumberFormatException("Invalid number of bytes for int. Found: " + aNum.length
                                      + " Required: " + __NUM_BYTES_IN_INT_);
   * Converts a byte array representing a short back to a short
public static final short toShort(final byte[] aNum) {
    try {
      short ret = 0;
      for(int i = 0; i < __NUM_BYTES_IN_SHORT_; i++)
        ret += (aNum[i] & __BYTE_MASK_) << ((__NUM_BYTES_IN_SHORT_ - 1 - i) * __NUM_BITS_IN_BYTE_);
      return ret;
    catch(Exception e) {
      throw new NumberFormatException("Invalid number of bytes for short. Found: " + aNum.length
                                      + " Required: " + __NUM_BYTES_IN_SHORT_);
   * Converts a byte array representing a double back to a double
public static final double toDouble(final byte[] aNum) {
    return Double.longBitsToDouble(toLong(aNum));
   * Converts a byte array representing a float back to a float
public static final float toFloat(final byte[] aNum) {
    return Float.intBitsToFloat(toInt(aNum));
            ///// SHIFTING /////
public static final byte shiftRightUnsigned(final byte b, final int shift) {
    return (shift > __NUM_BITS_IN_BYTE_) ? 0x00 : (byte) ((b & 0xFF) >>> shift);
public static final byte shiftRight(final byte b, final int shift) {
    return (byte) (b >> shift);
public static final byte shiftLeft(final byte b, final int shift) {
    return (shift > __NUM_BITS_IN_BYTE_) ? 0x00 : (byte) (b << shift);
}

How to convert an int number to a byte array, and how to convert back?

Hello, everybody,
Just as the topic, if I have an int number(which should have 32-bit, or 4-byte), how can I convert it into a byte array. And also, how to convert it back.
Thank you in advance!

Alternatively you can use ByteBuffers to do this work for you
// to a Byte Array
int originalInt =...;
ByteBuffer myBuffer = ByteBuffer.allocate(4);
myBuffer.putInt( originalInt );
byte myArray[] = myBuffer.array();
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ByteBuffer myOtherBuffer = ByteBuffer.wrap(myArray);
int finalInt = myOtherBuffer.getInt();

How to convert String array into int.

void getSoldSms(Vector vecSoldSms)
     String str[]=new String[vecSoldSms.size()];
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how do i convert words which is a string array into int type. i kno string can be converted into int using interger.parseint. but wat abt string arrays??? plz help me out with the above code.

i did tht its still giving the same errorFor Heaven's sake, what about taking a second to try to understand the code you're copying first? If you really can't fix the error yourself, you have a more serious problem than just convertingStrings to ints.
And if you want { "1", "2", "3" } to be 123:
StringBuffer b = new StringBuffer();
for (int i = 0; i < array.length; i++) {
b.append(array);
int result = Integer.parseIn(b.toString());

Trying to drag pdf files i have and combine them into one pdf file in the account i just purchased with Adobe. when i drag a pdf file over Adobe doesn't accept it. says it can not convert this type of file. but it is an Adobe file. Do I need to change it?

Trying to drag pdf files i have and combine them into one pdf file in the account i just purchased with Adobe. when i drag a pdf file over Adobe doesn't accept it. says it can not convert this type of file. but it is an Adobe file. Do I need to change it in some other form befor dragging it?

Hello djensen1x,
Could you please let me know what version of Acrobat are you using.
Also, tell me your workflow of combining those PDF files?
Please share the screenshot of the error message that you get.
Hope to get your response.
Regards,
Anubha

Converting int type into two bytes!

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