Converting scientific notation string to number?

This is raising an error:
> ToNumber (u201C2.75E-05u201D)
How do you convert scientific notation strings to numbers?
This is coming from XML. I can probably have the XML written so that it's not scientific notation.
Tim

Here's a not-so-pretty way:
Local StringVar Array x;
Local StringVar mantissa;
Local StringVar exponent := "0";
// Split into mantissa and exponent parts.
x:= Split("24.2233E+2", "e", 2, 1);
mantissa := x[1];
If (UBound(x) = 2)
Then
    exponent := x[2];
// CDbl cannot interpret leading positive sign, so removie
If Left(mantissa, 1) = "+"
Then
    mantissa := Right(mantissa, Length(mantissa) - 1);
If Left(exponent, 1) = "+"
Then
    exponent := Right(exponent, Length(exponent) - 1);
// Compute number
CDbl(mantissa) * 10 ^ CDbl(exponent);
Sincerely,
Ted Ueda

Similar Messages

  • Convert Scientific Notation to Float

    Hello
    How can we convert Scientific notation to float.
    e.g.
    1.23E-3(string) as  0.00123(float)
    Thanks
    Solved!
    Go to Solution.

    Use Fract/EngStringToNumber. Or ScanFromString with format %f…
    Best regards,
    GerdW
    CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
    Kudos are welcome

  • Convert scientific notation value into normal number

    hi,
    I am importing excel(.csv) file into Oracle database, a value in excel file 8.70773E+11 is displaying in scientific notation format, i want to store it like 870772521002.

    i have already run this query, it gave me 871000000000.0000000000 this result.
    Table Structure,
    SQL> desc cdr;
    Name Null? Type
    INVOICENO VARCHAR2(50)
    OCEANREGION NUMBER
    CALLDATE DATE
    CALLTIME VARCHAR2(10)
    ORIGINATORNO                             VARCHAR2(50)
    SUBSCRIBER VARCHAR2(75)
    DESTNO VARCHAR2(50)
    VOLUME FLOAT(50)
    UNIT VARCHAR2(5)
    this above Originatorno field had Number data type, but it wasnt working.

  • Convert Scientific Notation to Numeric (ABAP)

    I am currently consuming a WebService from XIgnite, that is returning a 7.5863900E-01 and I need to update the TCURR (Exchange Rate table) with .758639. 
    I need an ABAP example to use to place within the program that is importing the data for exchange rates.
    Thanks.

    try this:
    DATA: W_EXPO TYPE QPMK-SOLLWERT,
          W_PCKDECI(16)  TYPE P DECIMALS 3.
    MOVE : '7.5863900E-01' TO W_EXPO,
           W_EXPO TO W_PCKDECI.

  • Scientific Notation to Integer?

    I have a string like 1.780657E7 that I need to convert to an integer. I think that might be too big for Integer, so maybe BigInt would be better.
    Anyway, I can't figure out how to do this! I guess I could write my own method, but I'm sure it's already out there somewhere. I'm pretty new to Java.
    Thanks a lot,
    - Andrew.

    A small exegesis of prometheuzz's perfectly accurate, if slightly terse solution.
    Scientific notation is assumed to be floating-point. You must therefore parse a scientific-notation string using Float.parseFloat() or Double.parseDouble() and "integerise" the result if an integer is what you want.
    The last line is to show that your sample number is easy to fit in an int variable.

  • How let labview to verify string is in Scientific Notation.

    Hey all,
    I want labview to convert a spreadsheet string to an array. This is easy using the 'spreadsheet string to array' tool. The only problem I've got is that I get the string from a RS232 device and it is time critical.
    Example:
    If I read the data from the buffer it gives me:
    +1.50337800E+00,+1.70316300E+00 for two channels, this is converted and accepted
    if there is a small delay I get:
    +1.50337800E+00,+1.70316
    This will also be accepted because +1.70316 is also recognized as a number.
    How can program labview to check that every number it reads is according to the Scientific Notation?
    Thanks
    Solved!
    Go to Solution.

    Don_Phillips wrote:
    This regex seems to work for me for all the cases I tried:
    [+/-]\d+\.\d+[Ee][+/-]\d+
    Note that it is very restrictive and only follows the form of ±n.nnnE±mm
    If it was up to me, I'd fix the problem and not the symptom - but many times, it is NOT up to me.  MANY times there are artificial constraints (like the time allocated to fix the problem) so you just have to make a band-aid like this.  I get grumpy when I'm forced to program a workaround instead of a fix. 
    Bill
    (Mid-Level minion.)
    My support system ensures that I don't look totally incompetent.
    Proud to say that I've progressed beyond knowing just enough to be dangerous. I now know enough to know that I have no clue about anything at all.

  • Convert from scientific notation

    Can someone help me with this? I cannot get this working even using some of the tips I found on this site and elsewhere:
    Round this and format this with 2 decimals: '-2.58069E-11'.
    Now I realize this would end up -2.58, but it is giving me an error instead.
    Error converting data type varchar to numeric.
    SELECT CAST('2.58069E-11' AS NUMERIC(24,2))
    SELECT CAST('2.58069E-11' AS NUMERIC(24,12))
    I tried 12 just to make sure that there was enough room for the decimals
    If I use ISNUMERIC, it returns 1, so SQL Server considers it a number (at least with that function)
    The next example works, but it is not what I want.
    SELECT CAST('2.58069E-11' AS REAL) just returns the same thing with the 'E', (as REAL, of course)
    In these example I haven't done the rounding yet.
    I get all kinds of negative and positive numbers with different decimal lengths, but the scientific notation is particularly tricky.

    Before I put this to bed, I have found out both the above solutions are wrong when using a regular decimal:
    Try this:
    SELECT CAST(CAST('-1131658.27' AS REAL) AS NUMERIC(24,2))
    And this:
    SELECT CAST(CONVERT(REAL, -1131658.27) as DECIMAL(24,12))
    They both yield -1131658.25, and -1131658.250000000000, respectively.
    This is probably some floating point error, but how do I take care of it?

  • Double.parseDouble(String) - problems when string is in scientific notation

    Hello guys,
    I'm doing some numerical calculations and I wonder whether it is possible for Double.parseDouble(String) to parse string in the scientific notation i.e. 1.0824234234E-10. Is it the notation itself causing the exception : NumberFormatException or the number is just too big/small and double can't hold it ?
    If it's just the notation how can I fix it ?
    Regards

    i'm not quite sure whether double odoes not allow it.
    perhaps consider the api Double.valueOf() and the testing code provided; reproduced below:To avoid calling this method on a invalid string and having a NumberFormatException be thrown, the regular expression below can be used to screen the input string:
            final String Digits     = "(\\p{Digit}+)";
      final String HexDigits  = "(\\p{XDigit}+)";
            // an exponent is 'e' or 'E' followed by an optionally
            // signed decimal integer.
            final String Exp        = "[eE][+-]?"+Digits;
            final String fpRegex    =
                ("[\\x00-\\x20]*"+  // Optional leading "whitespace"
                 "[+-]?(" + // Optional sign character
                 "NaN|" +           // "NaN" string
                 "Infinity|" +      // "Infinity" string
                 // A decimal floating-point string representing a finite positive
                 // number without a leading sign has at most five basic pieces:
                 // Digits . Digits ExponentPart FloatTypeSuffix
                 // Since this method allows integer-only strings as input
                 // in addition to strings of floating-point literals, the
                 // two sub-patterns below are simplifications of the grammar
                 // productions from the Java Language Specification, 2nd
                 // edition, section 3.10.2.
                 // Digits ._opt Digits_opt ExponentPart_opt FloatTypeSuffix_opt
                 "((("+Digits+"(\\.)?("+Digits+"?)("+Exp+")?)|"+
                 // . Digits ExponentPart_opt FloatTypeSuffix_opt
                 "(\\.("+Digits+")("+Exp+")?)|"+
           // Hexadecimal strings
           "((" +
            // 0[xX] HexDigits ._opt BinaryExponent FloatTypeSuffix_opt
            "(0[xX]" + HexDigits + "(\\.)?)|" +
            // 0[xX] HexDigits_opt . HexDigits BinaryExponent FloatTypeSuffix_opt
            "(0[xX]" + HexDigits + "?(\\.)" + HexDigits + ")" +
            ")[pP][+-]?" + Digits + "))" +
                 "[fFdD]?))" +
                 "[\\x00-\\x20]*");// Optional trailing "whitespace"
      if (Pattern.matches(fpRegex, myString))
                Double.valueOf(myString); // Will not throw NumberFormatException
            else {
                // Perform suitable alternative action
    http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Double.html

  • Expression Builder: convert string to number

    Hi all,
    I'm having trouble building a field validation rule for bank account numbers.
    The numbers have 12 positions, so I cannot use a string or text number.
    The validation rule to be implemented is that the last two digits are calculated based on the first 10 (modulo 97).
    However, when I use the Mid function to pick the first characters, I am unable to do any calculations on it. Apparently, the string to number conversion doesn't work (it should work when I read the manual, as it says that when using an operator between two data types, the second type is converted to the first (cf. example of 1234+abcd (should result in 1234 as to the manual))). So I tried '1*Mid(...)' or '0+Mid(...)'. Syntactically the expression builder accepts it and I can save it. BUT when I change the particular value on the screen, it gives me an SSO error (not the Field Validation error message I entered).
    Why isn't there simply a function ToNumber (like ToChar)????? How could I workaround this?
    Any input very welcome!
    Frederik

    Apparently, I was a bit confused when typing the first sentence, it should be:
    The numbers have 12 positions, so I cannot use an integer or number data type, but have to use String.

  • How can I convert an ASCII string of variable length to a HEX number?

    Hello,
    I read data from the serial port 5 times in a second (while loop) and the number of bytes read varies every time.
    The data comes in as ASCII string, and I can see the HEX representation if I connect a HEX string indicator, but I need to permanently convert data to a HEX number. 
    How can that be done?

    Like This.
    Ton
    Free Code Capture Tool! Version 2.1.3 with comments, web-upload, back-save and snippets!
    Nederlandse LabVIEW user groep www.lvug.nl
    My LabVIEW Ideas
    LabVIEW, programming like it should be!

  • Converting a binary string to a number...

    Hi guys,
    I'm trying to convert a binary string into a decimal integer. I'm not sure if LabVIEW has a VI that does that. I haven't found one yet. Basically, say I have the string '0101'. I want to convert that to the value '5'. Or say I'm using hex, I want '10101111' to be converted to 'AF'. So that's my dilemma. I'm hoping I'm not going to have to make my own VI. Thanks a lot!
    -Mike

    LabVIEW has exactly what you want even if it can be hard to find it.
    To convert a binary text string like "0101" to a decimal value can easily be done using the Scan Value function found under the String/Number conversion section. If you provide the format %b to it (not mentioned in the manual) you will get the decimal value of your binary string.
    Also, on your front panel you can change the format of your numerical indicators by right clicking on it and selecting Format & Precision. If you have a numerical indicator you can set it do display the numbers in e.g. hexadecimal form.
    However, if you want to convert a number to a hexadecimal text string you can use the Number to Hexadecimal String function also found under the String/Number conversion section.
    I
    attached a simple example, Conversions.vi, that shows how it works. I hope this helps. /Mikael
    Attachments:
    conversions.vi ‏14 KB

  • Long number in CSV file appearing in scientific notation by default

    Hi,
    How can I stop a long number in a CSV file that is opened in excel from appearing in scientific notation by default?
    eg.
    "hello","778002405501 ", "yes"
    becomes:
    hello | 7.78002E+11 | yes
    I have tried wrapping the data in quotes in the csv but to no avail.
    Thanks in advance,
    Alistair

    You can change the extension from ".csv" to ".xls" and use table to form the data and use
    style=”mso-number-format:\@;”
    Please read the sample code below in Classic ASP:
    You can also read in my blog http://sarbashish.wordpress.com/2012/11/30/export-to-excel-how-to-prevent-long-numbers-from-scientific-notation/
    <%
    Response.Clear
    Response.CacheControl = “no-cache”
    Response.AddHeader “Pragma”, “no-cache”
    Response.Expires = -1
    Response.ContentType = “application/vnd.ms-excel”
    Dim FileName
    FileName = “TestDB Lookup-” & month(now)&”-”&day(now)&”-”&year(now)&”.xls”
    Response.AddHeader “Content-Disposition”, “inline;filename=” & FileName
    %>
    <html xmlns:o=”urn:schemas-microsoft-com:office:office” xmlns:x=”urn:schemas-microsoft-com:office:excel” xmlns=”http://www.w3.org/TR/REC-html40″;>
    <head>
    <meta http-equiv=Content-Type content=”text/html; charset=UTF-8″>
    <!–[if gte mso 9]>
    <xml>
    <x:ExcelWorkbook>
    <x:ExcelWorksheet>
    <x:WorksheetOptions>
    <x:DisplayGridlines/>
    </x:WorksheetOptions>
    </x:ExcelWorksheet>
    </x:ExcelWorksheets>
    </x:ExcelWorkbook>
    </xml>
    <![endif]–>
    </head>
    <body>
    <table border=”0″>
    <tr>
    <td>ID</td>
    <td>Name</td>
    </tr>
    <tr>
    <td style=”mso-number-format:\@;”>01234567890123456567678788989909000030</td>
    <td>Sarbashish B</td>
    </tr>
    </table>
    </body>
    </html>
    Sarbashish Bhattacharjee http://sarbashish.wordpress.com

  • Create an NSString for number in scientific notation from double?

    Hi
    Given a double, I want to create a string in scientific notation.
    e.g for a double with a value of 123.456, I want the NSString to be "1.23456e+2" for entering in to a UITextField.
    I've looked through the docs but can't find a formatter. (There is mention of "%a" being scientific format, but it produces hex output.)
    Thanks for any clues.
    Steve

    Here, you should find what you are looking for:
    http://developer.apple.com/mac/library/documentation/Cocoa/Conceptual/Strings/Ar ticles/FormatStrings.html#//apple_ref/doc/uid/20000943
    http://developer.apple.com/mac/library/documentation/Cocoa/Conceptual/Strings/Ar ticles/FormatStrings.html#//apple_ref/doc/uid/20000943
    http://developer.apple.com/mac/library/documentation/Cocoa/Reference/Foundation/ Classes/NSStringClass/Reference/NSString.html#//appleref/occ/clm/NSString/stringWithFormat:

  • Why Number displayed in  scientific notation

    I have tried to add two numbers and got a result displayed in scientific notation.
    Then I have used the 'decimalformat()' function and result is wrong.
    How can display the correct result. Please help
    Please see the code I have used
    <cfset N1=1>
    <cfset N2=9999999999999899999999>
    <cfset RESULT = N1+ N2>
    <cfoutput>
    #RESULT#
    <br />
    #decimalformat(RESULT)#
    </cfoutput>
    result :
    1E+022
    92,233,720,368,547,760.00
    Thanks in advance

    I think in floating point math adding 1 to 9999999999999899999999 is going to be a meaningless operation as by the time one converts 1 to a floating point of the scale & precision needed to represent 9999999999999899999999, it's going to lose any significance (ie: it's going to basically be represented as zero).
    You'll need to do a search on how to deal with numbers of very high precision & scale.  I don't have any code to hand.  Have you done any of your own investigation on how to deal with this?
    Adam

  • How to input a number of scientific notation in equations

    On new version of Numbers, I try to input a equation, such as "=A1 x 6.02E+23" , but I cannot input the equation, because "E" regarded as "columnE".
    Please tell me how to imput a a number of scientific notation in equations.

    You can override the parser using escape. This might be new to version 3.2, I don't remember it in 3.0 or 3.1. It used to override it until you hit Enter, then it would revert back into a cell reference. Now it is working correctly.
    = A1*6.02E (then hit ESC) 23
    The result will be
    =A1×6.02E+23

Maybe you are looking for

  • Applet Method Signed?

    Hello, I'm relativly new to the applet world so sorry if my question looks stupid. I'm currently working on a Java applet that performs a screencapture and save it to the client file system. To be able to capture the screen and write it , i had to si

  • Airport dropped after awoken from sleep mode

    i just started using it in sleep mode instaed of full shut down, when ever i come back i get an error saying the airport network cant be found orsomething, and it takes like 5 minutes to get it to find it even w/ the airport 2 feet away...

  • Authorization object P_APPL

    Hi experts, How should I use authorization object P_APPL in order to give access to all infotypes except for one concrete? Is there any way I can only specify which the user should not have access instead of specify to which it should? Thanks, mforma

  • Upgrade pre-built Oracle Virtual Machine using  Siebel VM template

    Hello I'm planning to deploy a Siebel environment for testing purposes using Oracle Virtual Machines templates (http://www.oracle.com/technetwork/server-storage/vm/siebel-092480.html). this template has been made to deploy Siebel CRM SIA 8.1.1.ENU an

  • I want to download a free trail for ps cs6

    i want to download a free trail for ps cs6 any body have a link??