Copy array and sort the numbers in the new array

Question

Hi!
I have an array containing some digits where some of the digits are zeros. I want to copy the digits to another array but the zeros (well, I actually want to copy the zeros as well but I want to have them in the end of the new array).
I suppose I need an if-statement that checks if the old array contains any zeros and in that if-statement copy the content to the new array and put the zeros in the end.
This is my code so far and I don�t know how to go on from here:
int[] new_array = new int[array.length];
          for (int i = 0; i < array.length; i++)
               if (array[i] > 0)
                    new_array[i] = array;
                    new_array = array;
               System.out.print(new_array[i] + " ");

Answer 1

Roxxor wrote:
I think I know how to do it but only if I can catch the digits bigger than zero.
My code below just checks if there are positive digits and if there are, the whole old array is copied to the new one.Yes. Don't do that, you can see it's wrong.
So my problem is that I don�t know how to catch the digits bigger than zero and copy them. Is there any built in java keyword that catches signs, number etc?
if (array>=0)
     new_array[i] = array[i];
     new_array = array;
Yes, there is such a keyword. And you are already using it correctly in your code. You are already testing if the array entry is bigger than zero. Your only problem is, you don't know what to do when it is. But now you've been given two hints about what to do.