Count how many time we have each element

Question

I can't count how many the same element is on my array, I have an array [21, 12, 4, 21, 21, 4]
I expect to have something like this:
number exist number
21 3
12 1
4 1
below is the code
System.out.printf("%10s,%10s \n", "number exist", "number");
          for(i = 0; i < list.size(); i++){
               for(int j = 0; j < list.size(); j++){
                    if (list.get(i) == list.get(j))
                         v++;
          System.out.printf("%10s,%10s \n",v,list.get(i));     
Edited by: ronisto on 11-Mar-2008 1:34 PM
Edited by: ronisto on 11-Mar-2008 1:39 PM

Answer 1

good actually I 'm using a List, I could'nt find where is wrong, I can print for the first one, but if I try to use the for it' s not working...look the code below with a list like this [5 , 1, 7, 1, 1, 5]
          System.out.printf("%10s,%10s \n", "Column1", "Column2");
               for(j = 0; j < list.size(); j++){
                         if (list.get(j) == list.get(0))
                              v++;
               System.out.printf("%10s,%10s \n",v,list.get(0));
result give me:
Column1 Column1
3 1
til here is good but when I try to print samething for all elements of my list it doesn't work
System.out.printf("%10s,%10s \n", "number exist", "number");
               for (i = 0; i < list.size(); i++){
                    for(j = 0; j < list.size(); j++){
                         if (list.get(j) == list.get(i))
                              v++;
               System.out.printf("%10s,%10s \n",v,list.get(i));
Edited by: ronisto on 11-Mar-2008 6:04 PM