Count of words in a string

i have a string "hai oracle tech team"
i want to calculate the number of words in it
i.e. it should return 4
how to do it

Haven't you answers in your duplicate thread from the last week ?
Re: how to calculate the number of words in a column
Nicolas.

Similar Messages

How i can count the number of words in a string?

hi, i want to know how to count the number of words in a string
e.g. java is a very powerful computer language.
i will get 7 words.
thanks in advance..

Jverd, this has actually been answered, but due to an
attack of goldie-itis, all the answers were hosed.
The OP did get an answer, though.Yeah, I know. I just didn't know if he saw the answer before it went away.

Counting a particular word in a string

Hi All,
Have a query to find the occurence of a particular word in a string using a query.
ex: str := 'a,b,a,c,d'
search_str := 'a'
=> need to get the number of times 'a' is getting repeated in the string str.
output: 2
Hoping for the best support as always.
Edited by: Aparna16 on Jul 17, 2012 5:55 AM
Edited by: Aparna16 on Jul 17, 2012 5:56 AM

SQL> ed
Wrote file afiedt.buf
1 with sample_data as
2 (
3 select 'aaa,abcdd,abc,abc,asdasd' cola, 'abc' matchCol from dual union all
4 select 'a,b,a,c,d', 'a' from dual union all
5 select 'a,b,a,c,d', 'e' from dual union all
6 select 'aaa,abcdd,abc,abc,asdasd,abc', 'ab' from dual union all
7 select 'aaa,abcdd,abc,abc,asdasd,abc', 'abc' from dual
8 )
9 select cola, matchcol, length(cola||',') - length(replace(cola||',',matchcol||',',substr(matchcol,2)||',')) cnt
10* from sample_data
SQL> /
COLA                         MAT        CNT
aaa,abcdd,abc,abc,asdasd     abc          2
a,b,a,c,d                    a            2
a,b,a,c,d                    e            0
aaa,abcdd,abc,abc,asdasd,abc ab           0
aaa,abcdd,abc,abc,asdasd,abc abc          3

Find word in text file and count specific words

now I'll try to explain what I need to do. I have file.txt file, It looks like:
John //first line - name
One
Three
Four
Peter //first line - name
Two
Three
Elisa //first line - name
One
Three
Albert //first line - name
One
Three
Four
Nicole //first line - name
Two
FourSo I have program's code:
public class Testing {
        public static void main(String args[]) throws Exception {
            Scanner input = new Scanner(System.in);
            System.out.println("Select word from list:");
            System.out.println();
            try {
                FileReader fr = new FileReader("src/lt/kvk/i3_2/test/List.txt"); // this is list of words, everything all right here
                BufferedReader br = new BufferedReader(fr);
                String s;
                while((s = br.readLine()) != null) {
                    System.out.println(s);
                fr.close();
                String stilius = input.nextLine();   // eneter word which I want to count in File.txt
                BufferedReader bf = new BufferedReader(new FileReader("src/lt/kvk/i3_2/test/File.txt")); // from this file I need to count word which I entered before
                int counter = 0;
                String line;
                System.out.println("Looking for information");
                while (( line = bf.readLine()) != null){
                    int indexfound = line.indexOf(stilius);
                    if (indexfound > -1) {
                         counter++;
                if (counter > 0) {
                    System.out.println("Word are repeated "+ counter + "times");}
                    else {
                    System.out.println("Error...");
                bf.close();
            catch (IOException e) {
                System.out.println("Error:" + e.toString());
        }This program counting specific word (entered by keyboard) in file.txt.
I need to make this program: for ex.: if I enter word: One It must show:
Word One repeated 3 times by John, Elisa, AlbertAll what I need to elect by who this word repeated. But I don't know really how to make It, maybe LinkedList or I dont know, someone could help me?
Thank you very much.

966676 wrote:
All what I need to elect by who this word repeated. But I don't know really how to make It, maybe LinkedListYou should choose the simplest type fullfilling your needs. In this case I'd go for <tt>HashSet</tt> or <tt>ArrayList</tt>.
or I dont know, someone could help me?You need to introduce a variable to store the actual name which must be resetted if an empty line is found and then gets assigned the verry next word in the file.
bye
TPD

How to count a occurence of a string in file

import java.util.*;
import java.io.*;
class Count
public static void main(String args[ ] )throws Exception
     FileReader fr=new FileReader("d:\\compfetch\\clean\\first.txt");
     BufferedReader br=new BufferedReader(fr);
     StringBuffer sb=new StringBuffer();
     while((s=br.readLine())!=null)
          sb.append(s);
     s=sb.toString();
Vector v= new Vector();
     v.addElement("job");
     v.addElement("jobs");
     v.addElement("career");
     v.addElement("careers");
     v.addElement("vacancy");
     v.addElement("vacancies");
     v.addElement("opportunity");
     v.addElement("openings");
     v.addElement("posting");
     v.addElement("postings");
     v.addElement("opportunities");
     v.addElement("placement");
     v.addElement("placements");
     v.addElement("job");
     v.addElement("job");
     Enumeration vEnum=v.elements();
     while(vEnum.hasMoreElements())
          System.out.println(vEnum.nextElement());
I need to count the occurence of each string given in the vector from the text file.I have the file and the vector.How do i compare the vector and textfile ,so that i can count the occurence of eachString in the vector with the text file.The text file may contain any of the words given in the vector.If found ,a count shld be made for each string .
regards,
koel

Try this code:
import java.util.*;
import java.io.*;
class Count
public static void main(String args[ ] )throws Exception
     FileReader     fr = new FileReader("c.c");
     BufferedReader br = new BufferedReader(fr);
     StringBuffer   sb = new StringBuffer();
     String         s;
     while((s=br.readLine())!=null)
          sb.append(s);
     s=sb.toString();
     Vector v= new Vector();
     v.addElement("job");
     v.addElement("jobs");
     v.addElement("career");
     v.addElement("careers");
     v.addElement("vacancy");
     v.addElement("vacancies");
     v.addElement("opportunity");
     v.addElement("openings");
     v.addElement("posting");
     v.addElement("postings");
     v.addElement("opportunities");
     v.addElement("placement");
     v.addElement("placements");
     Enumeration vEnum=v.elements();
     while(vEnum.hasMoreElements())
          String l = (String)vEnum.nextElement();
          int    a = 0;
          int    p = s.indexOf(l,a);
          int    c = 0;
          while (p != -1)
               c = c + 1;
               a = a + l.length() + p;
               p = s.indexOf(l,a);
          System.out.println(l+" "+c);
}

Hou can I count the words on a text

I am using Iterator which I think it only counts unique word so who can I count the all the words on the text

See i have Thispublic int getCount(String word) {
          // returns count for word
          Iterator<StringCounter> iter = ourWords.iterator();
          StringCounter sc;
          int count=0;
          while (iter.hasNext()) {
               sc = iter.next();
               if (sc.getString().equals(word)) {
                    sc.increment();
               count++;
          return count;
     }this only gets the words that are unique

How can i count the word in a cell.

Dear Experts,
i want to count the word in cell how can i do this ?
Isthere any function ?
plz give logic or command.

You can ty :
SQL> var text varchar2(50)
SQL> exec :text := 'How do I count the number of words in my cell?'
PL/SQL procedure successfully completed.
SQL> select text,
2         sum(case when substr(text,rownum,1)=' '
3                       and substr(text,rownum-1,1)!=' '
4                  then 1
5                  else 0 end) nb_word
6 from (select rownum,:text||' ' text,length(:text) ln from dual)
7 connect by level <= ln+1
8 group by text
9 /
TEXT
   NB_WORD
How do I count the number of words in my cell?
        11
SQL> exec :text := 'How     do I count the number of words in my   cell?    '
BEGIN :text := 'How     do I count the number of words in my   cell?    '; END;
ERROR at line 1:
ORA-06502: PL/SQL: numeric or value error: character string buffer too small
ORA-06512: at line 1
SQL> var text varchar2(1000)
SQL> exec :text := 'How     do I count the number of words in my   cell?    '
PL/SQL procedure successfully completed.
SQL> select text,
2         sum(case when substr(text,rownum,1)=' '
3                       and substr(text,rownum-1,1)!=' '
4                  then 1
5                  else 0 end) nb_word
6 from (select rownum,:text||' ' text,length(:text) ln from dual)
7 connect by level <= ln+1
8 group by text
9 /
TEXT
   NB_WORD
How     do I count the number of words in my   cell?
        11
SQL> select * from v$version where rownum=1;
BANNER
Oracle9i Enterprise Edition Release 9.2.0.7.0 - Production
SQL> Nicolas.
Well, we can discuss about what limit a word : here space, but there is point, double-point, and so on... And about what is a word : do the punctuation is a word ?
For example :
"It's a word !"=>how many words are in this sentence ?
http://en.wikipedia.org/wiki/Word
Message was edited by:
N. Gasparotto

Here's how to find the right word in a string

I needed to find the rightmost word in a string. I didn't find a simple formula in these forums, but I now have one, so I wanted to share it. Hope you find it useful.
Assuming that the string is in cell A1, the following will return the rightmost word in the string:
RIGHT(A1,LEN(A1)-FIND("*",SUBSTITUTE(A1," ","*",LEN(A1)-LEN(SUBSTITUTE(A1," ","")))))

I found the problem. Whatever character was being used in the substitution was parsed out by the forum parser. I replaced it with "œ" (option q on my keyboard).
=RIGHT(A1,LEN(A1)-FIND("œ",SUBSTITUTE(A1," ","œ",LEN(A1)-LEN(SUBSTITUTE(A1," ","")))))
Still needs an error check for a single-word "sentence" and to remove the trailing period but it does seem to work. Pretty slick.
Message was edited by: Badunit
I see below that the problem was fixed by the OP.
Message was edited by: Badunit

How to read each and every word from a string.

Hi all,
I have a string which is having many label numbers. if the string is lv_str, its value is like, 11111111111111##22222222222222##3333333333333.
I need to move the values alone into internal table. each value should be updated as a single row into one internal table. How to read each and every word of the string and move to an internal table.
the internal table should be like this.
11111111111111
22222222222222
3333333333333
Can any one give me a suggestion in this regard.
POINTS PROMISED.
Regards,
Buvana

Hi,
If you know the format and length of the data
Use split at '#' so that you will get the individual values.
Thean append it to internal table.
Reward iof helpful.

How to search for a particular word in a string?

How to search for a particular word in a string?
thanks for your help....

This works fine.
public class Foo {
    public static void main(String[] args) {
    String s = "Now is the time for all good...";
    String s2 = "the time";
    System.out.println(s.contains(s2));
    System.out.println(s.contains("for al"));
    System.out.println(s.contains("not here"));
}output:true
true
falseYou must have something else wrong in your code.
JJ

How to get the second and third.... words in a string

Hi all,
is there any way to get the words in a string seperate columns in a row.
"xxx yyyy zzzz aaaa bbbb"
required answer is
a b c d e
xxx yyyy zzzz aaaa bbbb
a b c d e are the column names
Thanks

WITH t as (
SELECT 'xxx yyyy zzzz aaaa bbbb' as t FROM dual
-- end of sample data.
SELECT t,
       regexp_substr(t, '[^ ]+', 1, 1) as a,
       regexp_substr(t, '[^ ]+', 1, 2) as b,
       regexp_substr(t, '[^ ]+', 1, 3) as c,
       regexp_substr(t, '[^ ]+', 1, 4) as d,
       regexp_substr(t, '[^ ]+', 1, 5) as e
FROM t;
T                       A                       B                       C                       D                       E
xxx yyyy zzzz aaaa bbbb xxx                     yyyy                    zzzz                    aaaa                    bbbb

Replacing first Character of every word in a string with an Uppercase

Hi,
Is it possible to replace all first character of every word in a string with UpperCase?
$="autocad lite"
Should look "Autocad Lite" .
Thanks,
François

Hi FRacine,
Please refer to the script below:
$givenname="autocad lite"
$givenname
$givenname = $givenname.substring(0,1).toupper()+$givenname.substring(1)
$givenname
Edit: to change first character in every word, please refer to this script, this may not be the best way, but it can work:
$givenname="autocad lite"
$givenname
$words=$givenname.split(" ")
$givenname=""
foreach ($word in $words){
$givenname+=$word.substring(0,1).toupper()+$word.substring(1)+" "}
$givenname=$givenname.trim()
$givenname
If there is anything else regarding this issue, please feel free to post back.
Best Regards,
Anna Wang

To get Length of each word in a String.

Hi,
I wanted to know, how to calculate the length of each word in a string.Suppose for example if the input is like this:
i/p:'Tech on the Net'
o/p:4 2 3 3
ie Tech-4 on-2 the-3 Net-3
another Ex:i am a good boy
o/p:1 2 1 4 3
Kindly let me know any PL/SQL function or SQL query which would help to achieve this.
Thanks&Regards
Zaheer

sql>select substr('tech on the net',decode(n,0,1,instr('tech on the net',' ',1,n)+1),
              decode(instr('tech on the net',' ',1,n+1),0,length('tech on the net')-instr('tech on the net',' ',1,n),
                    instr('tech on the net',' ',1,n+1)- decode(n,0,0,instr('tech on the net',' ',1,n))-1)) wrd,
      length(substr('tech on the net',decode(n,0,1,instr('tech on the net',' ',1,n)+1),
              decode(instr('tech on the net',' ',1,n+1),0,length('tech on the net')-instr('tech on the net',' ',1,n),
                    instr('tech on the net',' ',1,n+1)- decode(n,0,0,instr('tech on the net',' ',1,n))-1))) cnt
from(select rownum-1 n
     from dual
     connect by level <= length('tech on the net') - length(replace('tech on the net',' ',''))+1)
WRD CNT
tech 4
on 2
the 3
net 3

Delete the first word in a string?

Hi, i have a code in which i can extract the first three words in a string. after it's found the three first words, i would like it to remove the first one, what could i add?
this is what the code looks like:
import java.util.regex.*;
class Test187D {
     public static void main(String[] args) {
          String word1;
          String word2;
          String word3;
          String partDesc = "Hi my name is SandraPandra";
          Pattern pattern = Pattern.compile("^(\\w+)\\s+(\\w+)\\s+(\\w+)");
          Matcher matcher = pattern.matcher(partDesc);
          //Find the first word of the part desc
          if (matcher.find()) {
               word1 = matcher.group(1);
               word2 = matcher.group(2);
               word3 = matcher.group(3);
               System.out.println (word1 + " " + word2 + " " + word3);
} Thank you in advance

Take the length of the first word, plus one for the length of the space, that's how many characters to remove. Take the substring of the original string from the end of the removed part to the end of the whole string. Look up the String methods length(), and substring().

[svn:fx-trunk] 13501: Bug: BLZ447 - AMF3 Deserialization: Wrongly counted reference ID of duplicated String when in the same message there are Strings with only wildcards

Revision: 13501
Revision: 13501
Author:   [email protected]
Date:     2010-01-14 06:01:23 -0800 (Thu, 14 Jan 2010)
Log Message:
Bug: BLZ447 - AMF3 Deserialization: Wrongly counted reference ID of duplicated String when in the same message there are Strings with only wildcards
QA: Yes - please keep an eye on AMFX (HTTPChannel) tests.
Doc: No
Checkintests: Pass - except the usual 4-5 tests that time out on my machine.
Modified Paths:
    flex/sdk/trunk/frameworks/projects/rpc/src/mx/messaging/channels/amfx/AMFXDecoder.as

Dear Pallavi,
Very useful post!
I am looking for similar accelerators for
Software Inventory Accelerator
Hardware Inventory Accelerator
Interfaces Inventory
Customization Assessment Accelerator
Sizing Tool
Which helps us to come up with the relevant Bill of Matetials for every area mentioned above, and the ones which I dont know...
Request help on such accelerators... Any clues?
Any reply, help is highly appreciated.
Regards
Manish Madhav

Count of words in a string

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