Count specific while iteration

Greetings ladies and gentleman;
So, i have the following issue.
I want to know the exact amount of iterations a while loop is executed. The main problem is that, this while loop, is not always running, and sometimes it jumps to the next step of the program and the comes back to the same while-loop.
In the attached VI you can see a variable named Y, colored RED that is, in fact, counting this particular while loop. The thing is that, when it meets the condition and moves forward in the program, then it has a possibility to return to this particular loop, but when it returns i lose my account iterations and starts all over again.
The program is simple, it just takes some random numbers and if it meets the conditions of > or < then it chooses the next path. The Leds are there to know in wich while-loop it is runing. I have changed the wait in the while-loop i would like to measure so it can repeat itseld a lot if times.
Thanks, if i dont explain it too well, plis let me know.
Kind Regards,
stgo.
Solved!
Go to Solution.
Attachments:
MC Try to count all.vi ‏39 KB

stgo,
I would guess that you have programmed in some text-based language and are now learning LabVIEW, right? The structure of your code looks like a conversion from a text-based language and not one which takes advantages of LabVIEW's dataflow paradigm.
Try to do this without duplicated code (all of the case structures and several while loops) and without sequence structures. For the duplicated code create subVIs. The sequence structures can ususllay be eliminated by dataflow. Your stacked sequence structures might be replaced by for loops.
You may also want to consider a better way to stop the program. As it presently is constructed the Stopp button is read almost immediately when an iteration of the outer while loop begins. The code inside the sequence structure takes several seconds or longer to execute. Assuming the Stopp button was pressed shortly after (say 100 ms) the iteration started, the loop will not stop until that iteration completes AND the next iteration (when the True Stopp value is read) completes. This makes the user interface seem very unresponsive to the user. probably something like a state machine architecture could reduce the code to one loop which would respond to the user in ~100 ms.
To do the count you want Y needs to be on a shift register on the outer loop. After the inner loop where Y now is located completes, add the value of i for that loop to the value in the shift register.
Lynn

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