Count the continous digit

I have a value as mention below, my requirement is I just want to select those rows where the length of continuous numbers is between 12 to 19 in a string
than means numbers should not be interrupted by any character or special character etc. If only numbers are in continuous then only they should
come as output. I did tried the below mentioned query but here it count the all the numbers present in the string irrespective of whatever position
they are present which I do not want. And also in output it print the length of the continuous digit and the actual values of the continuous digit
I am using oracle 10 g
WITH T AS (
select 'CVIUSD00.00/1234567891097193T/1115/N194940*34739292' str from dual
UNION ALL SELECT 'CCDC123456789109719/0213/A001781' FROM DUAL
UNION ALL SELECT 'C AAA 1234567891234567' FROM DUAL
UNION ALL SELECT 'C OAX 378292999991000' FROM DUAL
UNION ALL SELECT 'MAUIIIIIIIIIINNNNNNNNNNNNNB' FROM DUAL
UNION ALL SELECT 'M O' FROM DUAL
UNION ALL SELECT 'CCVI/1234567891097193D0613/N0000' FROM DUAL
UNION ALL SELECT 'CCVI/1234561234567193D0613/N0000' FROM DUAL
UNION ALL SELECT 'NONREF-YW12345' FROM DUAL
UNION ALL SELECT 'EXT000380801812' FROM DUAL
UNION ALL SELECT 'AX375101123451002/1219/N9999' FROM DUAL
UNION ALL SELECT 'VI4243731234568479/1112*CVA/A411819' FROM DUAL
UNION ALL SELECT 'DC36148812343015/0413/A000743' FROM DUAL
UNION ALL SELECT 'O/CCCA1234567891026547/1215/N1111' FROM DUAL
UNION ALL SELECT 'TP122093123451067/0213/N1111' FROM DUAL
UNION ALL SELECT 'O/CCVI+/VI4925561234569699/1013*CVA/A033292' FROM DUAL
UNION ALL SELECT 'O/EXT+/EXT369395514' FROM DUAL
UNION ALL SELECT 'TV7160BT136726OCTDB' FROM DUAL
UNION ALL SELECT 'FFYCD909255325' FROM DUAL
UNION ALL SELECT 'PP 532453' FROM DUAL
SELECT
STR , REGEXP_REPLACE( STR, '[0-9]', NULL ) AS INTERMEDIATE_STRING ,
NVL( LENGTH( REGEXP_REPLACE( STR, '[0-9]', NULL ) ), 0 ) AS PATTERN_COUNT ,
ABS(NVL( LENGTH( REGEXP_REPLACE( str, '[0-9]', NULL ) ), 0 ) - LENGTH (str))
from
t
;

dbuser wrote:
I would also like to have the value of those continuous digits in my output and just replace except first 6 and last 4 digits with X
WITH T AS (
select 'CVIUSD00.00/1234567891097193T/1115/N194940*34739292' str from dual
UNION ALL SELECT 'CCDC123456789109719/0213/A001781' FROM DUAL
UNION ALL SELECT 'C AAA 1234567891234567' FROM DUAL
UNION ALL SELECT 'C OAX 378292999991000' FROM DUAL
UNION ALL SELECT 'MAUIIIIIIIIIINNNNNNNNNNNNNB' FROM DUAL
UNION ALL SELECT 'M O' FROM DUAL
UNION ALL SELECT 'CCVI/1234567891097193D0613/N0000' FROM DUAL
UNION ALL SELECT 'CCVI/1234561234567193D0613/N0000' FROM DUAL
UNION ALL SELECT 'NONREF-YW12345' FROM DUAL
UNION ALL SELECT 'EXT000380801812' FROM DUAL
UNION ALL SELECT 'AX375101123451002/1219/N9999' FROM DUAL
UNION ALL SELECT 'VI4243731234568479/1112*CVA/A411819' FROM DUAL
UNION ALL SELECT 'DC36148812343015/0413/A000743' FROM DUAL
UNION ALL SELECT 'O/CCCA1234567891026547/1215/N1111' FROM DUAL
UNION ALL SELECT 'TP122093123451067/0213/N1111' FROM DUAL
UNION ALL SELECT 'O/CCVI+/VI4925561234569699/1013*CVA/A033292' FROM DUAL
UNION ALL SELECT 'O/EXT+/EXT369395514' FROM DUAL
UNION ALL SELECT 'TV7160BT136726OCTDB' FROM DUAL
UNION ALL SELECT 'FFYCD909255325' FROM DUAL
UNION ALL SELECT 'PP 532453' FROM DUAL)
select str original,regexp_replace(str,'\d{6}(\d{2,9})\d{4}','XXXXXX\1XXXX') new from t
where regexp_like(str,'\d{12,19}')
ORIGINAL                                            NEW
CVIUSD00.00/1234567891097193T/1115/N194940*34739292 CVIUSD00.00/XXXXXX789109XXXXT/1115/N194940*34739292
CCDC123456789109719/0213/A001781                    CCDCXXXXXX78910XXXX/0213/A001781
C AAA 1234567891234567                              C AAA XXXXXX789123XXXX
C OAX 378292999991000                               C OAX XXXXXX99999XXXX
CCVI/1234567891097193D0613/N0000                    CCVI/XXXXXX789109XXXXD0613/N0000
CCVI/1234561234567193D0613/N0000                    CCVI/XXXXXX123456XXXXD0613/N0000
EXT000380801812                                     EXTXXXXXX80XXXX
AX375101123451002/1219/N9999                        AXXXXXXX12345XXXX/1219/N9999
VI4243731234568479/1112*CVA/A411819                 VIXXXXXX123456XXXX/1112*CVA/A411819
DC36148812343015/0413/A000743                       DCXXXXXX1234XXXX/0413/A000743
O/CCCA1234567891026547/1215/N1111                   O/CCCAXXXXXX789102XXXX/1215/N1111
ORIGINAL                                            NEW
TP122093123451067/0213/N1111                        TPXXXXXX12345XXXX/0213/N1111
O/CCVI+/VI4925561234569699/1013*CVA/A033292         O/CCVI+/VIXXXXXX123456XXXX/1013*CVA/A033292
13 rows selected.
SQL> SY.

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charu.

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<img src="http://i963.photobucket.com/albums/ae116/Barry_images/iWork09screen/Countw eekdaysinMonth.png" border="0" alt="Count of weekdays in month(s)">
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Edit:
Direct address to image for use if not showing above.
http://i963.photobucket.com/albums/ae116/Barry_images/iWork09screen/Countweekday sinMonth.png
Message was edited by: Barry

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Attachments:
Read Dig Chan-Change Detection_stop.vi ‏120 KB

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