Count the no. of dots in a string

Hi Friends
I have a column named Hiercode in table A which has a column hier_code with data like 1234.56.56.3
I need to insert this data into table B in different columns
Like
Level1 Level 2 Level3 Level 4 ........ Max_level
1234 56 56 3 4
We don't know in advance how many periods the hier_code data has
Could you please suggest me or gimme a small piece of code of how to do it in PL/SQL...I would really appreciate it and it has to be submitted today...So it will help me a lot...
Thankyou
Mohit

This isn't elegant, but maybe its what you are looking for?
create table dottab (hier_code varchar2(200));
insert into dottab values ( '101') ;
insert into dottab values ( '101.102') ;
insert into dottab values ( '101.102.103') ;
insert into dottab values ( '101.102.103.104') ;
insert into dottab values ( '101.102.103.104.105') ;
insert into dottab values ( '101.102.103.104.105.106') ;
insert into dottab values ( '101.102.103.104.105.106.107');
insert into dottab values ( '101.102.103.104.105.106.107.108');
insert into dottab values ( '101.102.103.104.105.106.107.108.109');
insert into dottab values ( '101.102.103.104.105.106.107.108.109.110');
commit;
column level1 format a6;
column level2 format a6;
column level3 format a6;
column level4 format a6;
column level5 format a6;
column level6 format a6;
column level7 format a6;
column level8 format a6;
column level9 format a6;
column level10 format a7;
SELECT substr(hier_code,1,decode(instr(hier_code,'.',1,1),0,length(hier_code),instr(hier_code,'.',1,1)-1)) level1,
       decode(instr(hier_code,'.',1,1),0,NULL,substr(hier_code,instr(hier_code,'.',1,1)+1,
           decode(instr(hier_code,'.',1,2),0,length(hier_code),instr(hier_code,'.',1,2)-instr(hier_code,'.',1,1)-1))) level2,
       decode(instr(hier_code,'.',1,2),0,NULL,substr(hier_code,instr(hier_code,'.',1,2)+1,
           decode(instr(hier_code,'.',1,3),0,length(hier_code),instr(hier_code,'.',1,3)-instr(hier_code,'.',1,2)-1))) level3,
       decode(instr(hier_code,'.',1,3),0,NULL,substr(hier_code,instr(hier_code,'.',1,3)+1,
           decode(instr(hier_code,'.',1,4),0,length(hier_code),instr(hier_code,'.',1,4)-instr(hier_code,'.',1,3)-1))) level4,
       decode(instr(hier_code,'.',1,4),0,NULL,substr(hier_code,instr(hier_code,'.',1,4)+1,
           decode(instr(hier_code,'.',1,5),0,length(hier_code),instr(hier_code,'.',1,5)-instr(hier_code,'.',1,4)-1))) level5,
       decode(instr(hier_code,'.',1,5),0,NULL,substr(hier_code,instr(hier_code,'.',1,5)+1,
           decode(instr(hier_code,'.',1,6),0,length(hier_code),instr(hier_code,'.',1,6)-instr(hier_code,'.',1,5)-1))) level6,
       decode(instr(hier_code,'.',1,6),0,NULL,substr(hier_code,instr(hier_code,'.',1,6)+1,
           decode(instr(hier_code,'.',1,7),0,length(hier_code),instr(hier_code,'.',1,7)-instr(hier_code,'.',1,6)-1))) level7,
       decode(instr(hier_code,'.',1,7),0,NULL,substr(hier_code,instr(hier_code,'.',1,7)+1,
           decode(instr(hier_code,'.',1,8),0,length(hier_code),instr(hier_code,'.',1,8)-instr(hier_code,'.',1,7)-1))) level8,
       decode(instr(hier_code,'.',1,8),0,NULL,substr(hier_code,instr(hier_code,'.',1,8)+1,
           decode(instr(hier_code,'.',1,9),0,length(hier_code),instr(hier_code,'.',1,9)-instr(hier_code,'.',1,8)-1))) level9,
       decode(instr(hier_code,'.',1,9),0,NULL,substr(hier_code,instr(hier_code,'.',1,9)+1,length(hier_code))) level10
FROM   dottab;
LEVEL1 LEVEL2 LEVEL3 LEVEL4 LEVEL5 LEVEL6 LEVEL7 LEVEL8 LEVEL9 LEVEL10
101
101    102
101    102    103
101    102    103    104
101    102    103    104    105
101    102    103    104    105    106
101    102    103    104    105    106    107
101    102    103    104    105    106    107    108
101    102    103    104    105    106    107    108    109
101    102    103    104    105    106    107    108    109    110Obviously, you will need to turn this into an insert statement from just a select.
Greg Pike
http://www.singlequery.com

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Like this.
james_t_dk wrote in message
news:[email protected]..
> I need to count the number of * in a string of carakters. And the
> return the number. 0 for no *'s in the string 2 for two *'s in the
> string and so on.
>
> It's probably quite simple but I can't figure out how!
[Attachment Untitled 10.vi, see below]
Attachments:
Untitled_10.vi ‏18 KB

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typedef struct timeval TIMESTAMP;
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hi gurs
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As an alternative or if you're using 9i or below you can use this:
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Hi,
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Criticism is welcomed
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Fastest way to count the number of occurences of string in file

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BufferedReader bout = new BufferedReader (new FileReader (sourcefile));
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544064
real     0m4.449s
user     0m3.880s
sys     0m0.544s
martin@martin-laptop:~$ time java WordCounter Desktop/moresequences.gb
SearchCount = 544064
real     0m42.719s
user     0m40.843s
sys     0m1.232sI suspect that dealing with the file as a whole, rather than line-by-line, might be quicker, based on previous experience with Perl.

Reading lines is very slow. If your file has single byte character encoding then use something like the KMP algorithm on an BufferedInputStream to find the byte sequence of "//\n".getBytes(). If the file has a multi-byte encoding then use the KMP algorithm on a BufferedReader to find the chars "//\n".getCharacters() .
The basis for this can be found in reply #12 of http://forum.java.sun.com/thread.jspa?threadID=769325&messageID=4386201 .
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Count the occurance of a character in a string

What is the function to count the occurance of a character in a string.
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instr will give the first one, replace will change the all... and what's for the occurance (number of white spaces, which is 3 in this case) count
Message was edited by:
gladnn

SQL> var a varchar2(25)
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&nbsp
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