Count the no.of of numericals from a string.

Hi team
I would like to count the no.of numericals from a given string.
Ex.
String - '1,23,567 8-9'
The result should be 5.
Eliminate the comma and space and hypen (-) while counting.
1 - is 1
23 - is 2
567 - is 3
8 - is 4
9 - is 5
Kindly help me.
Regards
Nakul Venkatraman

Just one suggestion. Your solution implies single character separators:
select length(regexp_replace('1, 23, 567 8-9','(^|\D)(\d)+','*')) str from dual
       STR
         7Small adjustment makes it separator length independent:
select length(regexp_replace('1, 23, 567 8-9','(^|\D+)(\d)+','*')) str from dual
       STR
         5
SQL> And it will work for 10g, but for 11g regexp_count is still simpler solution.
SY.

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Ok, it is unclear on what is happening here.
Are you saying that when the webclient gets the data that it is not honoring the quote characters? Or the processing of the data buffer is causing issues?
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Hence a garbage in, garbage out situation.
William Wegerson (www.OmegaCoder.Com)

Count the no.of of numericals from a string.

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