Count the number of values in a two dimensional array

i am trying to figure out how to count the number of values in a two dimensional array.
numScores = student[i][j].length;This doesn't work, i am trying to find a way of counting the columns

Object[][] o;
int tot = 0;
for(int x = 0 ; x < o.length ; x++)
tot += o[x].length;
}If it's not a jagged array, however, this would be easier:
int tot = o.length * o[0].length;

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Set number of elements in a two dimensional array

Hi,
Does anyone know how to set the number of elements in a two dimensional array directly in teststand.
To set a one dimsional array is simple:
SetNumElements( locals.somearray,4)
Is there a method to do this for a two dimensional array?
Sean

From the help file (TestStand 4.2.0):
PropertyObject.SetNumElements
SetNumElements Method
Syntax
PropertyObject.SetNumElements ( numElements, options = 0)
Purpose
Sets the number of elements of a single dimensional array.
Remarks
This method is only valid for single dimensional arrays. The elements in the array retain their values. Use the PropertyObjectType.ArrayDimensions property to set the number of elements in each dimension of a multi-dimensional array.
Parameters
numElements As Long
[In] New number of elements for the array.
options As Long
[In] Pass 0 to specify the default behavior, or pass one or more PropertyOptions constants. Use the bitwise-OR operator to specify multiple options.
This parameter has a default value of 0.
So you could use, for example: Locals.MultidimensionalArray.Type.ArrayDimensions.SetBounds({1,0},{3,4}) to set an array to have three dimensions (1,2,3), each with five elements (0,1,2,3,4).

Count the number of values selected in a form

Hello
I need to count the number of values selected in a form.
Here is my form dump:
I want to count the values circled in red.
So the number I want in this case is 5.
Any suggestions?

Aegis,
Yeah, good point. Here is a minor tweak:
<cfset total = 0>
<cfloop collection="#FORM#" item="field">
     <cfif field NOT IS "fieldnames">
       <cfset total += ListLen( FORM[ field ] )>
     </cfif>
</cfloop>
<cfoutput>
     <p>Total: #total#</p>
</cfoutput>
-Carl V.

Count the number of values selected in a Dashboard prompt

Hi,
I have a requirement to show the count of the number of values selected in a Dashboard prompt. How to do that?
Thanks in advance.

Hi,
Please follow below steps;
1. create a report(which will show the number of value selected)-
Pull the dimension column in criteria on which the prompt is created, make this column as IS PROMPTED. Edit the FX and put the expresion as; Count(*)2. In report pull narrative view add your custom text like "Number of prompt selected are @1". (@1 is nothing but he count of prompt selected.)
3. Put this report on the dashboard which has prompt.
Mark correct/helpful if it helps.
Regards,
Kashi
Edited by: K N Yadav on 28 May, 2013 2:01 AM

Assigning value to a two dimensional array

Hi,
I am trying to assign value to a two dimesional array the following way.
String [ ] [ ] d2D = new String [10] [ ];
for (int i = 0; i<obj.length; i++){
d2D = { "hello " + i, "here" , "we go" };
but it gives me the error "illegal start of expression " pointing to the line in the loop assigning values to d2D[i].
Any help would be deeply appreciated.

You need to use the syntax for creating an anonymous array: new String[] {..., ...}
String [ ] [ ] d2D = new String [10] [ ];
for (int i = 0; i<obj.length; i++){
d2D[ i ] = new String[] { "hello " + i, "here" , "we go" };
}

How can I count the number of values in one column which answer to a condition in another column?

I'm using Numbers 3.2 and would like to count the names in a column which satisfy a condition in a different column. There are 3 "streams" through which these names have come to me, and I would like to easily identify how many have come from each stream. Any help?

Hi DirtyDawg,
COUNTIF is your friend here.
If your source is in column C and your streams are 1, 2 and 3:
=COUNTIF(C,"=stream1")
=COUNTIF(C,"=stream2")
=COUNTIF(C,"=stream3")
These need to be in a footer or header row or in a different column than C.
hope this helps,
quinn

How do I count the number of 1's in a Boolean Array??

I have a boolean array of 1000 0's or 1's and want to know the number of times this array is in the 1 position.
The array is repeated within a structure and i need a number for each iteration to be passed onto the next (using a shift register).
Never really used boolean arrays before so none of the standard things i use seem to work?
Thanks in Advance.
Ross

Ross,
The quick easy way is to convert the boolean array to a 0-1 array from the boolean menu, then sum the array using "sum array elements" from the numerical menu.
Bruce
Bruce Ammons
Ammons Engineering

Counting the number of values selected in a list box

I'm trying to add a counter to a form that tells the user how many values have been selected from a list box... I tried adding a FormCalc formula to a calculate event in the "counter" field as follows:
count(form1.#subform[0].ListBox1.rawValue)
But for some reason it's not adding them up. It only gives me a value of 0 when none are selected, or 1 where any number of selections are made.
Can anyone help me out?
Thanks in advance

Try putting this in the calculate event of your counter field:
var num=0;
for (var a=0;a<ListBox1.items.nodes.length;a++){
if (ListBox1.getItemState(a))
num++;
this.rawValue=num;
Exit the list box and the field will calculate.
Kyle

How can i count the number of data patches in a numeric array

Hi All

BobLondn wrote:
Can I build a 2d array where I can store on one column the index of each data patch and on the second column to store the length of elements of relevant data patch.
Here's a quick example (LabVIEW 9.0) that stores the start index and length of all negative patches in a 2D array.
(modified from this old code)
LabVIEW Champion . Do more with less code and in less time .
Attachments:
FindNegativeSegments.JPG ‏30 KB
GetNegativeStretches.vi ‏16 KB
FindNegativeSegmentsFP.JPG ‏52 KB

Creating a Two Dimensional Array in Xcode and populating it with a values f

Whats the easiest way to declare a two dimensional array in Xcode. I am reading an matrix of numbers from a text file from a website and want to take the data and place it into a 3x3 matrix.
Once I read the URL into a string, I create an NSArray and use the componentsSeparatedByString method to strip of the carriage return line feed and create each individual row. I then get the count of the number of lines in the new array to get the individual values at each row. This will give mw an array with a string of characters, not a row of three individual values. I just need to be able to take these values and create a two dimensional array.

I'm afraid you are in the wrong place. Look here for the last two forums on programming. However, XCode support is mostly found at developer.apple.com. You can access their forums by registering. Registration is free.

Return a two dimensional array

Hi,
I'm probably doing this wrong from the start, but I have an two dimensional array with only integers. These are the result of some mathematical calculations (aren't they always? :-) ) and I need to use those in another class. So I placed this array in a Vector and used this as a return value.
It looks like this:
final int[][] somArray = new int[aantalSommen][3];
Vector maalSommen= new Vector();
somArray[counter][0] =A;
somArray[counter][1] =B;
maalSommen.add(somArray[counter]);
return maalSommen;So now I have this array into a vector, I can't get the values out.
in the code below Vector sommen is the vector containing the array.
for (int i =0;i<sommen.size(); i++ ) {
int [][] som=(int[][]) sommen.elementAt(i);
}The above code is not working.It gives me a cast error..

ok, this is my attempt for the sscce...
This class generates the results I need..
public Vector MaalSommen(int aantalSommen, int[] TafelReeks) {
          final Vector maalSommen = new Vector();
          final int[][] somArray = new int[aantalSommen][3];
          boolean dupesCheck=false;
          int A = 1;
          int B=1;
          for (int counter=0; counter<aantalSommen; counter++) {
               A=generator.nextInt(10);
               B=randomizeArray(TafelReeks);
               // check for dupes..
               while ( ! dupesCheck) {
                    if (!( dupesCheck=checkDupes(A,B, counter,somArray))) {
                         A=generator.nextInt(10);
                         B=randomizeArray(TafelReeks);
               dupesCheck=false;// reset the checker
               somArray[counter][0] =A;
               somArray[counter][1] =B;
               somArray[counter][2] =somArray[counter][0]* somArray[counter][1];
                 maalSommen.add(somArray[counter]);
          return maalSommen;
     }What I think is happening is I put the array into the vector..But it turn out this is not the case..

Two-dimensional array

heLLo,,!!
cAn u pLease givE mE thE codE of this oUtpUt usina two-dimensional array?
thAnks a lot,,,
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@

cUte_09 wrote:
heLLo,,!!
cAn u pLease givE mE thE codE of this oUtpUt usina two-dimensional array?
thAnks a lot,,,
...Sure:
char[][] triangles = {
};

Count the number of records between two key values (BTREE)

How can I count the number of keys between two values?
I'm using python driver, and BTREE access method.
====>
ideally what I want is to average a whole time-series data set (the intervals can change) to a given number of points. The keys are the time stamps and the values are the data that needs to be averaged. I need to count the number of records between two time stamps so that I can divide that number by the number of points i need, and average the data. What is the best way to do this? Or should I just keep the intervals for the time stamp constant and use RECNO access method?
Thank you
(first post btw.. and why aren't there many people in stackoverflow who answer Berkeley DB questions?)

BDB is an embedded db and it does not have any internal counters or statistics that you could grap to use for this. You will need to do it manually.
You can create a cursor, grap the records you want, each time you get the next record you bump a counter.
If you are using RECNO, you can use a cursor to get the record number of the record (DB_GET_RECNO), and if all you data is in
sequentail records with no missing records you can figure out the total count by take last rec # - initial rec # + 1 to get a total count.
If you switch over to the SQL API, you can issue a SQL query to give you a count. Select count(*) Where .......
Since you have to grab the data anyway, then best may be to count records as you go along.
thanks
mike

How to Count the number of TAB chars value '0A' in a line?

I have a requirement to count the number of TABs in a text file that I am processing (they must equal 75) to ensure that all the fields have been submitted on the file I am reading?
How do I identify the TABs in a line?
I have this so far:
         CONCATENATE gv_unix_file gv_lstfiles-name INTO gv_unix_file.
          OPEN DATASET gv_unix_file for INPUT IN TEXT MODE ENCODING NON-UNICODE.
          IF sy-subrc <> 0 .
            message e000(zz) with 'Cannot access in_uk files'.
          ENDIF.
          CONCATENATE gv_unix_file_arc gv_lstfiles-name INTO gv_unix_file_arc.
          OPEN DATASET gv_unix_file_arc FOR OUTPUT IN TEXT MODE ENCODING NON-UNICODE.
          IF sy-subrc <> 0 .
            message e000(zz) with 'Cannot access in_uk files'.
          ENDIF.
          DO.
            READ DATASET gv_unix_file into lv_str.
            IF sy-subrc <> 0.
              exit. "exit do loop, file is done.
            else.
              TRANSFER lv_str to gv_unix_file_arc.
            ENDIF.
          ENDDO.

Here is a sample code:
DATA: lv_string TYPE string,
      lv_tab TYPE c VALUE cl_abap_char_utilities=>horizontal_tab,
      lv_i TYPE i.
DATA: result_tab TYPE match_result_tab.
DO 3 TIMES.
CONCATENATE 'A' lv_string INTO lv_string SEPARATED BY lv_tab.
ENDDO.
" this is how you need to find how many tabs are in your transfer work area...
FIND ALL OCCURRENCES OF lv_tab IN lv_string RESULTS result_tab.
DESCRIBE TABLE result_tab LINES lv_i.
WRITE:'No. of tabs found:', lv_i.

How to count the number of Fridays and Saturdays between two dates

Hi every one ... If we want to count the number of Fridays and Saturdays between two dates, how would we do that ? !
Dates are ( 11-Feb-2010) to (19-May-2010)
how to do it in SQL
Edited by: khalidoracleit on Jul 28, 2010 5:51 AM

some nice coding here, I'm still amazed with what some people can do with "connect by". But I agree with some statements here that this can take "time", and to be honest, it's funny to see it working, but if you do not have a computer, just a calendar and some paper, would you go for "counting" so there must be a better solution?
The best working math in here is done by Aketi Jyuuzou, who writes so good English that I wonder why he still insists that he doesn't ;-)
Anyhow I "translated" that code to English, and I really like that math. Math is math and data is data.
ALTER SESSION SET NLS_DATE_LANGUAGE='ENGLISH';
WITH my_dates AS (
SELECT to_date('20100211','yyyymmdd') start_date,to_date('20100519','yyyymmdd') end_date FROM DUAL
UNION ALL
SELECT to_date('20100211','yyyymmdd') start_date,to_date('20100214','yyyymmdd') end_date FROM DUAL
UNION ALL
SELECT to_date('20100211','yyyymmdd') start_date,to_date('20100213','yyyymmdd') end_date FROM DUAL
UNION ALL
SELECT to_date('20100211','yyyymmdd') start_date,to_date('20100212','yyyymmdd') end_date FROM DUAL
SELECT to_char(start_date,'DD.MM.YYYY') start_date,to_char(end_date,'DD.MM.YYYY') end_date,
       to_char(start_date,'DAY') start_weekday,to_char(end_date,'DAY') end_weekday,
       end_date-start_date day_difference,
       (next_day(end_date,'FRIDAY')-7
       -next_day(start_date -1,'FRIDAY'))/7+1
       +(next_day(end_date,'SATURDAY')-7
       -next_day(start_date -1,'SATURDAY'))/7+1 as count_of_fr_and_sat
FROM my_dates;
START_DATE END_DATE   START_WEEKDAY                        END_WEEKDAY                          DAY_DIFFERENCE         COUNT_OF_FR_AND_SAT
11.02.2010 19.05.2010 THURSDAY                             WEDNESDAY                            97                     28
11.02.2010 14.02.2010 THURSDAY                             SUNDAY                               3                      2
11.02.2010 13.02.2010 THURSDAY                             SATURDAY                             2                      2
11.02.2010 12.02.2010 THURSDAY                             FRIDAY                               1                      1                      -- andy

Count the number of values in a two dimensional array

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