Create and Schedule Job - Problem

Question

hi everyone,
I'm trying to write an Job which I would like to schedule. Function of this Job is to delete all entries older than 1 Month in the table "tabelle1". As I understand, you can put in job_action the procedure statement.
BEGIN
DBMS_SCHEDULER.create_job (
job_name => 'delete_all_entries',
job_type => 'PLSQL_BLOCK',
job_action => 'BEGIN DELETE FROM tabelle1 WHERE last_date < (SYSDATE - INTERVAL '1' MONTH) AND (status = 'processed'); END;',
start_date => SYSTIMESTAMP,
repeat_interval => 'FREQ=WEEKLY;BYDAY=SAT;BYHOUR=10;BYMINUTE=00',
end_date => NULL,
enabled => TRUE,
comments => 'Job defined entirely by the CREATE JOB procedure.');
END;
I get the following error message:
ORA-06550: Zeile 5, Spalte 118:
PLS-00103: Encountered the symbol "1" when expecting one of the following:
) , * & = - + < / > at in is mod remainder not rem
<an exponent (**)> <> or != or ~= >= <= <> and or like like2
like4 likec between || multiset member submultiset
06550. 00000 - "line %s, column %s:\n%s"
*Cause: Usually a PL/SQL compilation error.
*Action:
What am I doing wrong?.
Thx in advance!

Answer 1

Hi,
If you want to include a single-quote in a string literal, then use 2 single-qutoes in a row, like this:
'BEGIN DELETE FROM tabelle1 WHERE last_date < (SYSDATE - INTERVAL ''1'' MONTH) AND (status = ''processed''); END;',or use Q-notation:
Q'{BEGIN DELETE FROM tabelle1 WHERE last_date < (SYSDATE - INTERVAL '1' MONTH) AND (status = 'processed'); END;}',As you posted it, the single-quote right before the 1 indicated that the string literal ended there, and that 1 was outside of the qutoes.
By the way,
SYSDATE - INTERVAL '1' MONTH isn't always a valid date (when SYSDATE is October 31, for example).
Use
ADD_MONTHS (SYSDATE, -1)instead.
Edited by: Frank Kulash on Sep 18, 2012 9:41 AM