Create Partition Table Syntax

I need to create a partition table on target. I am currently using the below code, but it fails when the primary key on the source table has a primary key having more than one column. How can I get the first column name from the source table which can be used as the partitioning key?
create table texdatawarehouse.<%=odiRef.getInfo("TARG_NAME")%>
<%=odiRef.getColList("", "[COL_NAME]\t[DEST_WRI_DT] ", ",\n\t", "", "")%>
partition by range (<%=odiRef.getColList("","[COL_NAME]","","","PK")%>)
(partition a values less than (9999999999))
Thanks,
Dinesh.

Hi Dinesh,
I am little bit confused with your reply...
Please correct me if I am on the wrong way..
The New Key you need to add to the target datastore.
then in interface select the target datastore (diagram tab)
in properties select the new key for update column.
I mean the partion will be created based upon the target column key.
Regards,
Rathish

Similar Messages

Unable to Create Partitioned Table

Hi All,
I was trying to create a partitioned table using following
Create table customers (custcode number(5),
Name varchar2(20),
Addr varchar2(10),
City varchar2(20),
Bal number(10,2))
Partition by list (city),
Partition north_India values (‘DELHI’,’CHANDIGARH’),
Partition east_India values (‘KOLKOTA’,’PATNA’),
Partition south_India values (‘HYDERABAD’,’BANGALORE’,’CHENNAI’),
Partition west India values (‘BOMBAY’,’GOA’);
It is throwing me an error
ORA-00922: missing or invalid option
Will you please tell me what is wrong with this query? Is it possible to create partitioned table using select statement (create table as select... Partition by...)?
Regards
~Pravin

Pravin
Will you please tell me what is wrong with this query?I see 4 errors in the syntax. Therefore, I strongly suggest you to have a lock to this:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/statements_7002.htm#i2146309
In addition, have a look to the error message. If I run your script in SQL*Plus it clearly shows where the problem is. E.g.:
SQL> Create table customers (custcode number(5),
2 Name varchar2(20),
3 Addr varchar2(10),
4 City varchar2(20),
5 Bal number(10,2))
6 Partition by list (city),
7 Partition north_India values (‘DELHI’,’CHANDIGARH’),
8 Partition east_India values (‘KOLKOTA’,’PATNA’),
9 Partition south_India values (‘HYDERABAD’,’BANGALORE’,’CHENNAI’),
10 Partition west India values (‘BOMBAY’,’GOA’);
Partition by list (city),
ERROR at line 6:
ORA-00922: missing or invalid option
Is it possible to create partitioned table using select statement?Yes. With the usual syntax.
HTH
Chris Antognini
Author of Troubleshooting Oracle Performance, Apress 2008 (http://top.antognini.ch)

Error while creating partition table

Hi frnds i am getting error while i am trying to create a partition table using range
getting error ORA-00906: missing left parenthesis.I used the following statement to create partition table
CREATE TABLE SAMPLE_ORDERS
(ORDER_NUMBER NUMBER,
ORDER_DATE DATE,
CUST_NUM NUMBER,
TOTAL_PRICE NUMBER,
TOTAL_TAX NUMBER,
TOTAL_SHIPPING NUMBER)
PARTITION BY RANGE(ORDER_DATE)
PARTITION SO99Q1 VALUES LESS THAN TO_DATE(‘01-APR-1999’, ‘DD-MON-YYYY’),
PARTITION SO99Q2 VALUES LESS THAN TO_DATE(‘01-JUL-1999’, ‘DD-MON-YYYY’),
PARTITION SO99Q3 VALUES LESS THAN TO_DATE(‘01-OCT-1999’, ‘DD-MON-YYYY’),
PARTITION SO99Q4 VALUES LESS THAN TO_DATE(‘01-JAN-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q1 VALUES LESS THAN TO_DATE(‘01-APR-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q2 VALUES LESS THAN TO_DATE(‘01-JUL-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q3 VALUES LESS THAN TO_DATE(‘01-OCT-2000’, ‘DD-MON-YYYY’),
PARTITION SO00Q4 VALUES LESS THAN TO_DATE(‘01-JAN-2001’, ‘DD-MON-YYYY’)
;

More than one of them. Try this instead:
CREATE TABLE SAMPLE_ORDERS
(ORDER_NUMBER NUMBER,
ORDER_DATE DATE,
CUST_NUM NUMBER,
TOTAL_PRICE NUMBER,
TOTAL_TAX NUMBER,
TOTAL_SHIPPING NUMBER)
PARTITION BY RANGE(ORDER_DATE) (
PARTITION SO99Q1 VALUES LESS THAN (TO_DATE('01-APR-1999', 'DD-MON-YYYY')),
PARTITION SO99Q2 VALUES LESS THAN (TO_DATE('01-JUL-1999', 'DD-MON-YYYY')),
PARTITION SO99Q3 VALUES LESS THAN (TO_DATE('01-OCT-1999', 'DD-MON-YYYY')),
PARTITION SO99Q4 VALUES LESS THAN (TO_DATE('01-JAN-2000', 'DD-MON-YYYY')),
PARTITION SO00Q1 VALUES LESS THAN (TO_DATE('01-APR-2000', 'DD-MON-YYYY')),
PARTITION SO00Q2 VALUES LESS THAN (TO_DATE('01-JUL-2000', 'DD-MON-YYYY')),
PARTITION SO00Q3 VALUES LESS THAN (TO_DATE('01-OCT-2000', 'DD-MON-YYYY')),
PARTITION SO00Q4 VALUES LESS THAN (TO_DATE('01-JAN-2001', 'DD-MON-YYYY')))In the future, if you are having problems, go to Morgan's Library at www.psoug.org.
Find a working demo, copy it, then modify it for your purposes.

Error in creating partition table in oracle spatial by ankur

Hi,
Am working on Oracle 10.2.0.3
Am not able to create partition table in Oracle
i have all the required columns in node and edge table ......the moment i try to create partition table using exec sdo_router_partition.partion_router i get the following error:
ERROR at line 1:
ORA-00947: not enough values
ORA-06512: at "MDSYS.SDO_ROUTER_PARTITION", line 1510
ORA-06512: at "MDSYS.SDO_ROUTER_PARTITION", line 661
ORA-06512: at line 1
Can someone help ??

hey i have found the solution myself :)

Create partition table upto level 3

Hi All,
I want to create partition table using 3 columns. could you please tell me is that possible to do in oracle 11G. if can please tell me the way to create
PARTITION BY LIST (Acct_type)
SUBPARTITION BY LIST (PERIOD)
and needs to partition this using another column.( account_source)
please help me.
Regards,
krish

Hello,
3 levels of partition are not possible.
But perhaps you can combine 2 levels as follows:
With Oracle 11g you can use a virtual column:
CREATE TABLE F_ACCOUNT_PART
acc_type varchar2(100),
acc_source varchar2(100),
period date,
acc_type_source varchar2(201) as (acc_type||'_'||acc_source) )
PARTITION BY LIST (acc_type_source)
PARTITION FA_AA_ACC1 VALUES ('AA-ACC1') TABLESPACE USERS,
PARTITION FA_BB_ACC1 VALUES ('BB-ACC1') TABLESPACE USERS,
PARTITION FA_CC_ACC1 VALUES ('CC-ACC1') TABLESPACE USERS,
PARTITION FA_DD_ACC1 VALUES ('DD-ACC1') TABLESPACE USERS,
PARTITION FA_AA_ACC2 VALUES ('AA-ACC2') TABLESPACE USERS,
PARTITION FA_BB_ACC2 VALUES ('BB-ACC2') TABLESPACE USERS,
PARTITION FA_CC_ACC2 VALUES ('CC-ACC2') TABLESPACE USERS,
PARTITION FA_DD_ACC2 VALUES ('DD-ACC2') TABLESPACE USERS,
PARTITION all_other VALUES (DEFAULT) TABLESPACE USERS
)For versions prior to 11g you have to build a new column acc_type_source and fill the values cancatenated.
Maik

Create Partition tables in PL/SQL using Execute Immediate

Hi
I have to create a partiton table in PL/SQL using Execute Immediate. I concat the necessary Create Table syntax into a variable and use Execute Immediate variable name. This gives a error ORA-00900: invalid SQL statement. However if i cut and paste the SQL statement from DBMS_OUTPUT, the table creation goes through without any problem.
What could be the issue. Has anyone face this before please.
I am using 10G DB

Thanks for your reply. It is a big code. I am pasting the part required.
v_sqlstmtout :='CREATE TABLE a_10(MYDATE DATE NOT NULL,ID NUMBER(14) NOT NULL)';
v_sqlstmtout := v_sqlstmtout || ' PARTITION BY RANGE (MYDATE) ';
v_sqlstmtout := v_sqlstmtout || 'SUBPARTITION BY HASH(id) ';
v_sqlstmtout := v_sqlstmtout || 'SUBPARTITION TEMPLATE(';
v_sqlstmtout := v_sqlstmtout || 'SUBPARTITION SP1,SUBPARTITION SP2) ';
v_sqlstmtout := v_sqlstmtout || '(PARTITION mth_dummy VALUES LESS THAN ';
v_sqlstmtout := v_sqlstmtout || '('||V_SQLSTMT3||')' || v_sqlstmt||')';
EXECUTE IMMEDIATE ''''||v_sqlstmtout||'''';
variables are substituted through data from different tables.
The output looks like the following
CREATE TABLE a_10(MYDATE DATE NOT NULL,ID NUMBER(14) NOT NULL)
PARTITION BY RANGE (mydate) SUBPARTITION BY HASH(id) SUBPARTITION
TEMPLATE(SUBPARTITION SP1,SUBPARTITION SP2) (PARTITION mth_dummy VALUES
LESS THAN ('01-MAY-2006'), PARTITION mth_JAN2007 VALUES LESS THAN
('01-FEB-2007'))
The above is the output from DBMS_OUTPUT. If i run this statement the table is created. Please help..

Create Partition table using CTAS

Hi there,
Is it possible to create a duplicate partition table from a existing partition table using CTAS method? If yes, could you explain how ?If No , how to make a duplicate partition table?
Thanks in advance?
Rajesh Marath

Easily:
conn / as sysdba
CREATE TABLESPACE part1
DATAFILE 'c:\temp\part01.dbf' SIZE 50M
BLOCKSIZE 8192
EXTENT MANAGEMENT LOCAL UNIFORM SIZE 256K
SEGMENT SPACE MANAGEMENT AUTO
ONLINE;
CREATE TABLESPACE part2
DATAFILE 'c:\temp\part02.dbf' SIZE 50M
BLOCKSIZE 8192
EXTENT MANAGEMENT LOCAL UNIFORM SIZE 256K
SEGMENT SPACE MANAGEMENT AUTO
ONLINE;
CREATE TABLESPACE part3
DATAFILE 'c:\temp\part03.dbf' SIZE 50M
BLOCKSIZE 8192
EXTENT MANAGEMENT LOCAL UNIFORM SIZE 256K
SEGMENT SPACE MANAGEMENT AUTO
ONLINE;
ALTER USER uwclass QUOTA UNLIMITED ON part1;
ALTER USER uwclass QUOTA UNLIMITED ON part2;
ALTER USER uwclass QUOTA UNLIMITED ON part3;
conn uwclass/uwclass
CREATE TABLE hash_part (
prof_history_id NUMBER(10),
person_id NUMBER(10) NOT NULL,
organization_id NUMBER(10) NOT NULL,
record_date DATE NOT NULL,
prof_hist_comments VARCHAR2(2000))
PARTITION BY HASH (prof_history_id)
PARTITIONS 3
STORE IN (part1, part2, part3);
CREATE TABLE duplicate_hash_part
PARTITION BY HASH (prof_history_id)
PARTITIONS 3
STORE IN (part1, part2, part3) AS
SELECT * FROM hash_part;Follow the same logic for list and range partitions

Jdev 11g defect: Error creating partition table diagram

I'm running Jdev 11.1.1.0.2 on JDK 1.6.0_06
When attempting to drag partitioned table from DB connection onto a DB Diagram I'm getting the following exception. Anybody got similar experience?
Also every time I create new diagram or off-line DB JDev starts spinning at 40 - 50 % CPU and gets stuck, so I have to "kill" the process and restart it. After which it works fine. Could it be some JDK compatibility issue?
May 13, 2009 4:09:54 PM oracle.ide.db.transfer
SEVERE: Prepare failed
java.lang.NullPointerException
     at oracle.javatools.db.ora.OracleTableBuilder.getOracleTablePartitions(OracleTableBuilder.java:584)
     at oracle.javatools.db.ora.OracleTableBuilder.buildNonBaseProperties(OracleTableBuilder.java:406)
     at oracle.javatools.db.ora.OracleTableBuilder.fillInObject(OracleTableBuilder.java:76)
     at oracle.javatools.db.AbstractDBObjectBuilder.buildObject(AbstractDBObjectBuilder.java:36)
     at oracle.javatools.db.dictionary.DictionaryDBObjectBuilder.buildObject(DictionaryDBObjectBuilder.java:55)
     at oracle.javatools.db.AbstractSchemaObject.checkInitEx(AbstractSchemaObject.java:229)
     at oracle.javatools.db.AbstractSchemaObject.checkInit(AbstractSchemaObject.java:144)
     at oracle.javatools.db.AbstractSchemaObject.checkInit(AbstractSchemaObject.java:267)
     at oracle.javatools.db.AbstractSchemaObject.copyToImpl(AbstractSchemaObject.java:64)
     at oracle.javatools.db.Table.copyTo(Table.java:81)
     at oracle.javatools.db.AbstractDBObject.copyTo(AbstractDBObject.java:90)
     at oracle.jdevimpl.offlinedb.transfer.OffToOffPolicy.copyForTransfer(OffToOffPolicy.java:192)
     at oracle.jdevimpl.offlinedb.transfer.OnToOffPolicy.copyForTransfer(OnToOffPolicy.java:134)
     at oracle.ide.db.transfer.TransferManager.prepare(TransferManager.java:158)
     at oracle.ide.db.transfer.TransferManager.prepareAndTransfer(TransferManager.java:418)
     at oracle.ideimpl.db.transfer.TransferRunnable.run(TransferRunnable.java:79)
     at oracle.ide.dialogs.ProgressBar.run(ProgressBar.java:643)
     at java.lang.Thread.run(Thread.java:619)

Hi nfk,
Are the tables in the question reference-partitioned?
I am able to reproduce the exception when copying to project the online reference partitioned tables to offline , and I have logged a bug for it.
Please give the details of the tables like partition type if your scenario is different.
As for the other issue , I have not seen any performance issues with DB diagram ..I have tried on jdk1.6.0_06 and jdk160_11.if it is reproducible, please add your machine configuration.
Many Thanks,
Geetha
Edited by: user647112 on May 15, 2009 5:19 AM

Create partitioned table

Hi All,
I wish to create a table which may exist for next 100 years (how pessimistic I am), or perhaps for next 1000 years (now I have broadened my mind) in Oracle 9i (... ohh I can't help it). I want to create a partitioned table which will store data in partitions on yearly basis and sub-partitions on monthly basis, can I create a table with such partitions? If yes... then how?
*009*

Yes, see an example
Range Partitioning Example
CREATE TABLE sales_range
(salesman_id NUMBER(5),
salesman_name VARCHAR2(30),
sales_amount NUMBER(10),
sales_date DATE)
PARTITION BY RANGE(sales_date)
PARTITION sales_jan2000 VALUES LESS THAN(TO_DATE('02/01/2000','DD/MM/YYYY')),
PARTITION sales_feb2000 VALUES LESS THAN(TO_DATE('03/01/2000','DD/MM/YYYY')),
PARTITION sales_mar2000 VALUES LESS THAN(TO_DATE('04/01/2000','DD/MM/YYYY')),
PARTITION sales_apr2000 VALUES LESS THAN(TO_DATE('05/01/2000','DD/MM/YYYY'))
);

How to create PARTITION table by?

I have huge table(1million records) which affect query performance. I notice it may help by partitioning it into two. One contains heavily used records and another the rest. However Partition By Range seems applicable to LESS THAN. What I want to do is something like ' EST_TYP in ('L','N')' etc.
Anyone can help? Any other advice on perf improvement? What I have done: 1>Reduced the no of EXT. 2>Created Index.
Thanks in Advance
Yiguang

I have huge table(1million records) which affect query performance. I notice it may help by partitioning it into two. One contains heavily used records and another the rest. However Partition By Range seems applicable to LESS THAN. What I want to do is something like ' EST_TYP in ('L','N')' etc.
Anyone can help? Any other advice on perf improvement? What I have done: 1>Reduced the no of EXT. 2>Created Index.
Thanks in Advance
Yiguang

How can I create my own tag name while creating a partition table.

I have X4500 running Solaris 10. I have formatted a disk and created partition table as given below.
Specify disk (enter its number): 0
selecting c0t0d0
[disk formatted]
/dev/dsk/c0t0d0s0 is part of active ZFS pool zpool1. Please see zpool(1M).
FORMAT MENU:
disk - select a disk
type - select (define) a disk type
partition - select (define) a partition table
current - describe the current disk
format - format and analyze the disk
fdisk - run the fdisk program
repair - repair a defective sector
label - write label to the disk
analyze - surface analysis
defect - defect list management
backup - search for backup labels
verify - read and display labels
inquiry - show vendor, product and revision
volname - set 8-character volume name
!<cmd> - execute <cmd>, then return
quit
format> partition
PARTITION MENU:
0 - change `0' partition
1 - change `1' partition
2 - change `2' partition
3 - change `3' partition
4 - change `4' partition
5 - change `5' partition
6 - change `6' partition
select - select a predefined table
modify - modify a predefined partition table
name - name the current table
print - display the current table
label - write partition map and label to the disk
!<cmd> - execute <cmd>, then return
quit
partition> print
Current partition table (original):
Total disk sectors available: 1953508749 + 16384 (reserved sectors)
Part Tag Flag First Sector Size Last Sector
0 usr wm 34 4.00GB 8388641
1 usr wm 8388642 2.00GB 12582945
2 usr wm 12582946 200.00GB 432013345
3 usr wm 432013346 175.00GB 799014945
4 usr wm 1166180386 375.43GB 1953508748
5 usr wm 799014946 175.00GB 1166016545
6 usr wm 1166016546 80.00MB 1166180385
8 reserved wm 1953508749 8.00MB 1953525132
partition>
I am unable to specify my own tag name. How can I change the tag name to one of my interest.
I need to create 3 partitions as told below
partitions:
/earth
/mars
/work
/earth and /work should be roughly equal in size, /mars should be twice the size of the others, if that is possible. If not 3 partitions of equal size will do.
Please, help me .
Thank you.

Exactly 1TB? Slightly under/slightly over?
Traditional Solaris disk labels are in VTOC format, but this format cannot describe disks larger than 1TB. So EFI labels must be used on disks larger than 1TB. Setup is slightly different.
Are these physical disks or LUNs from a SAN array? If they are array LUNS, it is often the case that they don't have a Sun label of any type. So...
#1 Apply a Solaris label
If the LUNS don't have a label (when selected in 'format', it gives a warning that no label is present and offers to apply a label immediately). When run non-interactively, format assumes "yes" for any questions. So all you'd have to do is select every disk to have it apply labels to any unlabled disk. Run 'format' once and find the highest number (maybe it's 50 for you). Create a text file that looks like this:
disk 1
disk 2
disk 3
disk 50Then feed that to format like this:
# format -f /tmp/disklist or whatever you've named the file.
#2 Apply the partition layout to all disks you want.
You asked if you should do the same procedure, but I don't see that you've actually done anything above other than print out the existing layout. Take one of your 48 drives and partition it the way you want manually (set the slices to the sizes that you want). Then you can copy the layout of that disk to others. You only want to do this between disks/LUNs of the same size. As an example, if you've explicitly partitioned c1t0d0 and you want to apply this to c1t1d0, do this:
# prtvtoc /dev/rdsk/c1t0d0s2 | fmthard -s - /dev/rdsk/c1t1d0s2Repeat for all of your other disks.
Darren

How to create index on specific partition table?

Hi Experts,
we created 4 partitions on table .
Table Name : test
partitions : Test_prt1
                   Test_prt2
                   Test_prt3
                  Test_prt4
Our requiremnt create the index on specific partition (ex : Test_prt2) only.

Creating Partitioned Tables and Indexes
http://technet.microsoft.com/en-us/library/ms187526(v=sql.105).aspx
you can create a aligned index, the index will be spread over the filegroups
Create NonClustered Index IX_orders_aligned
On dbo.orders(order_id)
On test_monthlyDateRange_ps(orderDate);
OR
Unaligned parition, you can create index on any filegroups
Create NonClustered Index IX_orders_unpartitioned
On dbo.orders(order_id)
On [Test_prt2_FileGroup];
For more information refer the below link
http://sqlfool.com/2008/12/indexing-for-partitioned-tables/
Or
You can try Creating a filtered index (I've not tried it though)
http://www.mssqltips.com/sqlservertip/1785/sql-server-filtered-indexes-what-they-are-how-to-use-and-performance-advantages/
--Prashanth

Partition Table Query taking Too Much Time

I have created partition table and Created local partition index on a column whose datatype is DATE.
Now when I Query table and use index column in the where clause It is scaning all the table (Full scan) . The quey is :
Select * From mytable
where to_char(transaction_date, 'DD-MON-YY') = '01-Aug-07';
I have to use to_char function not to_date due to Front end application problem.

Before we go too far with this, if you manually query with TO_DATE on the variable instead of TO_CHAR on the column, does the query actually use the index?
The TO_CHAR on the column will definitely stop Oracle from using any index on the column. If the query will use the index if you TO_DATE the variable, as I see it, you have three options. First, fix the application problem that won't let you use TO_DATE from the application. Second, change the application to call a function returning a ref cursor, get the date string as a parameter to the function, and do the TO_DATE in the function.
Third, you could consider creating a function-based index on TO_CHAR(transaction_date, 'dd-Mon-yy'). This would be the least desirable option, particularly if you would also be selecting records based on a range of transaction_dates, since it loses a lot of information that the optimizer could use in devising an efficient query plan. It could also change your results for a range scan.
John

Partition an Non Partition Table in 11.2.0.1

Hi Friends,
I am using Oracle 11.2.0.1 Oracle Database.
I have a table with 10 Million records and it's a Non Partitioned Table.
1) I would like to partition the table (with partition by range ) without creating new table . I should do it in the existing table itself (not sure DBMS_REDEFINITION is the only option ) (or) can i use alter table ...?
2) Add one partition which will have data for the unspecified range.
Please let me know the inputs on the above
Regards,
DB

Hi,
what is the advantage of using DBMS_REDEFINITION over normal method (create partition table,grant access,insert records)You can't just add a partition in a non-partitioned table. You need to recreate existing table to have it partitioned (you can't just start adding new partitions to existing non-partitioned table). Advantage of dbms_redefinition is that it is online operation to re-create an existing table and and your data always remains available during table recreation
I would like to know how to copy the object privileges,constraints,indexes from Non Partitioned table (sales) to Partitioned table (sales_part) which i am creating. will >DBMS_REDEFINITION.COPY_TABLE_DEPENDENTS help on this?First you need to tell us what method you are using to partition an existing table? If you are using dbms_redifiniiton, you really don't need to worry about triggers, indexex or constraints at all. Just follow any document which explains how to use dbms_redifinition. Dr. Tim has done a lot of work for dummys like us by writing documents for us. Follow this document.
http://www.oracle-base.com/articles/misc/partitioning-an-existing-table.php
If so can i use DBMS_REDEFINITION.COPY_TABLE_DEPENDENTS alone for copying the table dependents alone after i create partition table (or) it should be used along with >DBMS_REDEFINITION.START_REDEF_TABLE only?See above document which i mentioned.
Salman

Partitioning tables in Oracle 10g

Hi,
I have a table that already contains more than a million of records, I am considering partitioning it, I am new with the web based console of oracle 10g, so I am not finding the way to do it.
can any one help me?

Well, search on "Creating Partitioned Tables" in OEM help and that will tell you how to get to the partitions page for when you are creating a new table. I figured modifying an existing table would be in the Storage tab of that area but I didn't see it. For an existing table, it might be easier just to use SQL Plus.
Or you can use OEM to create a new empty table with partitions and just do a select into... on it.
Gaff

Create Partition Table Syntax

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