CreateQuery() using LIKE and % wildcard: wrong parameter Name :(

Question

Hi, I cant find an example of an EJB-QL that uses a LIKE statement and wildcards surrounding a parameter.
I`d tried this:
queryString = "SELECT p FROM Prestadores p WHERE p.nombre LIKE '%?1%'"and also:
queryString = "SELECT p FROM Prestadores p WHERE p.nombre LIKE '%:nombre%'"in ths code.
try {
            Query q = em.createQuery("queryString");
            //q.setParameter(1, nombre);
            q.setParameter("nombre", nombre);
            listaPres = q.getResultList();
            cargarBusquedaPrestadores(listaPres);
            return listaBPres;
        } catch (Exception e) {
            System.err.println("PrestadoresBean.getDatosPestadorxNombre(String Nombre) Exception Inesperada");
            System.err.println(e.getMessage());
            return null;
        }but i get:
You have attempted to set a parameter at position 1 which does not exist in this query string SELECT p FROM Prestadores p WHERE p.presNombre LIKE '%?1%'or
You have attempted to set a parameter value using a name of nombre that does not exist in the query string SELECT p FROM Prestadores p WHERE p.presNombre LIKE '%:nombre%'.respectively from the SUN App server log.
any help would be appreciated.
Thanks in advance!

Answer 1

If you use wildcards inside parameters and fix other bugs the problem will disappear.
Try this:
queryString = "SELECT p FROM Prestadores p WHERE p.nombre LIKE ?1";  //quotes aren't necessary
Query q = em.createQuery(queryString); //Of course there can't be "queryString"
q.setParameter(1, "%" + nombre + "%");
listaPres = q.getResultList();