Creating one and two Dimensional array

Hi guys my problem is as follows
(1)I want to create a two dimensional array of 10 rows and 20 columns
(2)Populate the array with random integers
(3)convert the two dimensinal array into one dimensional array int[]nums
(4)print the content of one and two dimensional arrays to the screen

You don't learn much about coding if you don't write any code. Without seeing the code that was written it's very difficult to assist a person, since your solution may not be anywhere close to their solution. If the poster just wants the code to hand in or use as is then there is no learning happening.
So, step 1 - post your code, step 1a - ask a clear question.
Just my opinions
Lee

Similar Messages

Variable number of two dimensional arrays into one big array

I have a variable number of two dimensional arrays.
The first dimension is variable, the second dimension is always 7.
i.e.:
Object[][] array0 = {
{"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"},
{"alice", "smith", 42, 160.0, "la", "bub", "[email protected]"},
Object[][] array1 = {
{"john", "sdfs", 34, 15.5, "a", "bl", "[email protected]"},
{"joe", "smith", 42, 16.0, "a", "bub", "[email protected]"},
Object[][] arrayi = ...I'm generating these arrays with a for-loop:
     for (int i = 0; i < filter.length; i++) {
          MyClass c = new MyClass(filter);
          //data = c.getData();
Where "filter" is another array which is filled with information that tells "MyClass" how to fill the arrays.
"getData()" gives back one of the i number of arrays.
Now I just need to have everything in one big two dimensional array.
i.e.:Object[][] arrayComplete = {
{"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"},
{"alice", "smith", 42, 160.0, "la", "bub", "[email protected]"},
{"john", "sdfs", 34, 15.5, "a", "bl", "[email protected]"},
{"joe", "smith", 42, 16.0, "a", "bub", "[email protected]"},
Any idea on how to accomplish this? It's blowing my mind right now.

Just brainstorming here:
Why not put your actual data in a class and store that in a LinkedList (so you know the total number of elements for your multi-dimensional array). Then initalize your multi-dimensional array and populate it? Haven't tested the following, but thinking something along the lines of
public class MyData {
     //data here
     public Object[] toArray() {
          //something similar to this
          return new Object[] = {"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"};
LinkedList<MyData> data = new LinkedList<MyData>();
data.add(mydata1);
//however many times you need
Object[][] arrayComplete = new Object[data.size()][7];
for(int i = 0; i < data.size(); i++) {
     arrayComplete[i] = data.removeFirst().toArray();
}Another option for knowing how many rows you would need might be using something like:
int rows = 0;
rows += array1.length;
rows += array2.length;
//etc...But is not entirely useful if you don't know how many variable arrays you have (although reflections might help if the name of the array variable is incremented systematically, someone told me earlier to avoid reflections since it could make debugging a LOT more difficult).
Edited by: bogdana on Apr 1, 2010 10:38 AM

Creating a Two Dimensional Array in Xcode and populating it with a values f

Whats the easiest way to declare a two dimensional array in Xcode. I am reading an matrix of numbers from a text file from a website and want to take the data and place it into a 3x3 matrix.
Once I read the URL into a string, I create an NSArray and use the componentsSeparatedByString method to strip of the carriage return line feed and create each individual row. I then get the count of the number of lines in the new array to get the individual values at each row. This will give mw an array with a string of characters, not a row of three individual values. I just need to be able to take these values and create a two dimensional array.

I'm afraid you are in the wrong place. Look here for the last two forums on programming. However, XCode support is mostly found at developer.apple.com. You can access their forums by registering. Registration is free.

How to get number of rows and columns in a two dimensional array ?

Hello,
What would be the simplest way to get number of rows and columns in a two dimensional array represented as integers ?
I'm looking for another solution as For...Each loop in case of large arrays.
Regards,
Petri

Hi Petri,
See a attached txt file for obtaining two arrays with upper and lower index values
Regards
Ray
Regards
Ray Farmer
Attachments:
Get2DArrayIndex.txt ‏2 KB

Problem returning a two-dimensional array in web service

Hello. I'm having problems returning a two dimensional array in my web service. The service returns a MyClass[][] correctly, but the client receives a different one.
I've done a test that returns a MyClass[1][1] an the client shows a MyClass[1][20]. All the MyClass objects returned in the array are the same and all it's fields are null. There's even an element of the array containing null instead of the object. As I say, the service creates the array ok, but the client gets other thing.
I have other methods returning one-dimensional arrays MyClass[] and I have no problem.
My system:
WindowsXP
Tomcat 5.5 (Axis 1.3?)
JDK 1.5
Eclipse 3.3
My wsdl is generated with eclipse, although I've had to update my wsdd manually.
Any Ideas?
Thanks.

Does it have to be stored in an array?
Because you could use the java.awt.Point class, and a
java.util.Set to create random points until you have
the correct number of unique points.Of course it is no must to store it in an array. it was just my first thought of approaching the problem. I will try the Point.class. Thanks for that hint.

Assigning two dimensional array to each other

Hi All,
I have two two-dimensional arrays and I want to assign one's second dimension's values as the other's second dimension's values in this way:
        int userCounter = 0;
        for (int userID : mostCommonUsers) {
            reducedTrainingVectorForSimilarity[userCounter] = trainingVectorForSimilarity[userID];
            userCounter++;
        }In the above code, I have an *"ArrayList<Integer> mostCommonUsers"*, and iterate through this. I'm using the values inside this array list, as a first dimension's index number of the *"trainingVectorForSimilarity"*, and assigning all the values in the second dimension to the left-hand-side array's second dimension. Both array has fixed length of second dimension. So, am I right by doing this, or I should make a for-loop to iterate over the individual values on the second dimensions of both arrays?
Another similar question: In the below code, *"trainingVectorForSimilarity"* is an *"float[][]"*, so basically I assign all the second dimensions' values into a newly created array named *"trainingUserRatings"*. Again, I assumed that if the corresponding first dimesion's second dimension values will be assign without any iteration over each values.
for (int i = 0; i < trainingVectorForSimilarity.length; i++) {
            float[] trainingUserRatings = trainingVectorForSimilarity;
similarity[i] = calculateCosineSimilarity(testingVectorForSimilarity, trainingUserRatings);
Am I right for both cases?

Here is the output for the code that you sent:
[[1, 2, 3], [4, 5, 6]]
[[1, 2, 3], [4, 5, 6]]
[[1, 2, 3], [4, 5, 6]]
[[1, 2, 3], [4, 5, 6]]
[[1, 2, 3], [4, 999999, 6]]
[[1, 2, 3], [4, 999999, 6]]
[[1, 2, 3], [4, 999999, 6]]
[[1, 2, 3], [4, 5, 6]]
[null, [4, 999999, 6]]
[null, [4, 999999, 6]]
[[1, 2, 3], [4, 999999, 6]]
[[1, 2, 3], [4, 5, 6]]I confused that even making an array copy still refers the same object but not a copy of that object. For example:
float[][] trainingVectorForSimilarity is defined and initialized.
            float[] trainingUserRatings = new float[trainingVectorForSimilarity.length];
trainingUserRatings = trainingVectorForSimilarity[i];
is the same withfloat[] trainingUserRatings = new float[trainingVectorForSimilarity[i].length];
System.arraycopy(trainingVectorForSimilarity[i], 0, trainingUserRatings, 0, trainingUserRatings.length);

How can I use two dimensional array ?

Could some one show me how to use two dimentional array ?
I am know how to right a single ...but not two dimentional....please help,
Thanks,
Flower
public class Exam5
public static void main(String[] args)
int[][] numbers =
     {     {1,2,3,4,5,6,7,8,9,10},
{1,2,3,4,5,6,7,8,9,10} };
for(int i = 1; i < 11; ++i)
System.out.println(i + "\t" + i * 2 + "\t" + i * 3 + "\t" + i * 4 + "\t" + i * 5 +
"\t" + i * 6 + "\t" + i * 7 + "\t" + i * 8 + "\t" + i * 9 + "\t" + i * 10);
Display #
1     2     3     4     5     6     7     8     9     10
2     4     6     8     10     12     14     16     18     20
3     6     9     12     15     18     21     24     27     30
4     8     12     16     20     24     28     32     36     40
5     10     15     20     25     30     35     40     45     50
6     12     18     24     30     36     42     48     54     60
7     14     21     28     35     42     49     56     63     70
8     16     24     32     40     48     56     64     72     80
9     18     27     36     45     54     63     72     81     90
10     20     30     40     50     60     70     80     90     100

First, try not to ask someone to do your homework for you and then tell them they are wrong. The code posted may not have been exactly what you were looking for, but it was not wrong because it did exactly what the poster said it would do - print out the multiplication table.
Second, in the future if you ask specific questions rather than posting code and hoping someone will fix it for you, you may one day be able to complete the assignments on your own.
Here is code that prints what you want and uses a two dimensional array. Please ask questions if you do not understand the code. You will never learn if you just use someone else's code without taking the time to examine or understand it.
public class MultiTable{
    public static void main(String[] args)   {
        int rows = 10;
        int columns = 10;
        int [][] numbers = new int [rows] [columns];
        for(int j = 0; j < rows; j++)   // for each of 10 rows
            for(int k = 0; k < columns; k++)    // for each of 10 columns
                numbers[j][k] = (j+1) * (k+1); // calculate row+1 * col+1
        for (int j = 0; j < rows; j++) // for each of 10 rows
            for (int k = 0; k < columns; k++)   // for each of 10 columns
                System.out.print(numbers[j][k]+" ");    // print out result
                if (numbers[j][k] < 10)     // for single digit numbers
                    System.out.print(" "); // print extra space for better formatting
            System.out.println();       // skip to next line
}

Saving two dimensional array to a file

I am trying to save a two dimensional array to a file.
If I write a part of the whole array like Filename[1] it works fine.
But the whole array will cause an Errormessage to appea:
"cannot find symbol"
Here is the Code:
RandomAccessFile output = null;
    try
      output = new RandomAccessFile( "TestPlan.plan", "rw" );
      output.seek( output.length() );       // Dateizeiger an das Ende
      output.write( Karte ); // Zeile schreiben

Seems that OutputStreamWriter and ByteArrayOutputStream can only handle one dimensional arrays, too.in that case, break down the arrays to single objects, and serialize them individually

How to copy data in text file into two-dimensional arrays?

Greeting. Can somebody teach me how to copy the input file into two-dimensional arrays? I'm stuck in making a matrix with number ROWS and COLUMNS according to the data in "input.txt"
import java.io.*;
import java.util.*;
public class array
    public static void main (String[] args) throws FileNotFoundException
    { Scanner sc = new Scanner (new FileReader("input.txt"));
        PrintWriter outfile = new PrintWriter("output.txt");
    int[][]matrix = new int[ROWS][COLUMNS];
}my input.txt :
a,b,c
2,2,1
1,1,1
2,2,1
3,3,1
4,4,1
5,5,1
1,6,2
2,7,2
3,8,2
4,9,2
5,10,2

import java.io.*;
import java.util.*;
public class array {
    public static void main(String[] args) throws IOException {
        FileInputStream in = null;
        FileOutputStream out = null;
try {
    in = new FileInputStream("input.txt");
    BufferedReader reader = new BufferedReader(new InputStreamReader(in));
    String line = null;
    while ((line = reader.readLine()) != null) {
        String split[]=line.split(",");
catch (IOException x) {
    System.err.println(x);
} finally {
    if (in != null) in.close();
}}}What after this?

Set number of elements in a two dimensional array

Hi,
Does anyone know how to set the number of elements in a two dimensional array directly in teststand.
To set a one dimsional array is simple:
SetNumElements( locals.somearray,4)
Is there a method to do this for a two dimensional array?
Sean

From the help file (TestStand 4.2.0):
PropertyObject.SetNumElements
SetNumElements Method
Syntax
PropertyObject.SetNumElements ( numElements, options = 0)
Purpose
Sets the number of elements of a single dimensional array.
Remarks
This method is only valid for single dimensional arrays. The elements in the array retain their values. Use the PropertyObjectType.ArrayDimensions property to set the number of elements in each dimension of a multi-dimensional array.
Parameters
numElements As Long
[In] New number of elements for the array.
options As Long
[In] Pass 0 to specify the default behavior, or pass one or more PropertyOptions constants. Use the bitwise-OR operator to specify multiple options.
This parameter has a default value of 0.
So you could use, for example: Locals.MultidimensionalArray.Type.ArrayDimensions.SetBounds({1,0},{3,4}) to set an array to have three dimensions (1,2,3), each with five elements (0,1,2,3,4).

Two dimensional array in JSP with struts

Is it possible to use two dimensional array in an web application
based on struts. I am using JSP and to get data from two dimensional
array im using
property = "array[0][0]";I read on the internet that bean utils does not support two dimensional array?
I have a table like spreadsheet with 30 rows and 20 columns and i was
planning to use two dimensional array? is there any other way to get
this stuff done easily?
any ideas welcome.

HI ,
i have the same problem you had
did you get any solution for this?
if so you can help me out

How can I do two dimensional arrays?

I am a C++ programmer and in C++ I am able make a two dimensional array and input the values that correspond to those cells.
After I saw the proposals that you (experts) made I am going to share a little of the classified information that I was working for the undefeatable XO game.
First step:My idea was to make a two dimensional array(in C++ we use the following syntex for two dimensional array{array[i][j]})
I was wondering if I am able to make a two dimensional array using LABVIEW .
Second step: Store the values of X or O inside the 2D array.And use maybe boolean variables(in C++ we use inaddition to that if statement).
My second question :What can I do inorder to minimize the number of boolean vaariables?(also if statements in C++)
Jupiter
extinct when hell froze over

This is a subroutine I use to check for a winner in a XO game.
While playing, the main code replaces default 0's by 1's inside the 2D array of a single player.
Then the main code calls this VI with the 2D array of that player and check for a winning game.
Any board size is ok as long as you have equal number of cols & rows.
So, enter 1's at any location in the "Score" 2D array and the code will check for a winning game.
As you can see I don't use any boolean variables, except the return value of this VI (read function)
So to answer your second question; I minimized the use of boolean variables to 0 1! Is that ok for you?
Attachments:
TTT-Check4Winner.vi ‏20 KB

Return a two dimensional array

Hi,
I'm probably doing this wrong from the start, but I have an two dimensional array with only integers. These are the result of some mathematical calculations (aren't they always? :-) ) and I need to use those in another class. So I placed this array in a Vector and used this as a return value.
It looks like this:
final int[][] somArray = new int[aantalSommen][3];
Vector maalSommen= new Vector();
somArray[counter][0] =A;
somArray[counter][1] =B;
maalSommen.add(somArray[counter]);
return maalSommen;So now I have this array into a vector, I can't get the values out.
in the code below Vector sommen is the vector containing the array.
for (int i =0;i<sommen.size(); i++ ) {
int [][] som=(int[][]) sommen.elementAt(i);
}The above code is not working.It gives me a cast error..

ok, this is my attempt for the sscce...
This class generates the results I need..
public Vector MaalSommen(int aantalSommen, int[] TafelReeks) {
          final Vector maalSommen = new Vector();
          final int[][] somArray = new int[aantalSommen][3];
          boolean dupesCheck=false;
          int A = 1;
          int B=1;
          for (int counter=0; counter<aantalSommen; counter++) {
               A=generator.nextInt(10);
               B=randomizeArray(TafelReeks);
               // check for dupes..
               while ( ! dupesCheck) {
                    if (!( dupesCheck=checkDupes(A,B, counter,somArray))) {
                         A=generator.nextInt(10);
                         B=randomizeArray(TafelReeks);
               dupesCheck=false;// reset the checker
               somArray[counter][0] =A;
               somArray[counter][1] =B;
               somArray[counter][2] =somArray[counter][0]* somArray[counter][1];
                 maalSommen.add(somArray[counter]);
          return maalSommen;
     }What I think is happening is I put the array into the vector..But it turn out this is not the case..

When I open iTunes it is slow to open for one, and two when it does see my iPhone and i go to sync it this is what I get in return... The iPhone "My Name here" could not be synced because the iPhone could not be found on the network. that is a pop up box

When I open iTunes it is slow to open for one, and two when it does see my iPhone and i go to sync it this is what I get in return... The iPhone "My Name here" could not be synced because the iPhone could not be found on the network. that is a pop up box in middle of screen that says that it does it like every time I go to sync the phone after i do app updates. I am getting very frustrated by this can someone please help. I have made 2 other discussion topics about this and no replies on them. Please if anyone can help I ask for help. This has occurred ever since the iOS 5.1 update and the iTunes 10.6.0 and still continues with the iTunes 10.6.1 update just yesterday and perhaps even worse now. PLEASE HELP IF YOU CAN. I have looked through my network settings etc and everything looks good here on my side.

When I open iTunes it is slow to open for one, and two when it does see my iPhone and i go to sync it this is what I get in return... The iPhone "My Name here" could not be synced because the iPhone could not be found on the network. that is a pop up box in middle of screen that says that it does it like every time I go to sync the phone after i do app updates. I am getting very frustrated by this can someone please help. I have made 2 other discussion topics about this and no replies on them. Please if anyone can help I ask for help. This has occurred ever since the iOS 5.1 update and the iTunes 10.6.0 and still continues with the iTunes 10.6.1 update just yesterday and perhaps even worse now. PLEASE HELP IF YOU CAN. I have looked through my network settings etc and everything looks good here on my side.

A friend set me up with icloud and in the process he lost some of the book i was listening to. I can't find it in my ipod or on my computer. It is part one and two of a book; interest part three showed up hough.

A friend set me up with icloud on my ipod touch and in the process lost part one and two of the book I had purchased from itunes. I searched for it and it is not in my ipod any longer, although part 3 is there. I tried to download it again from itunes store but they said I already purchased it and I didn't want to be charged again. What can I do? I am not happy at all because all I did with my Ipod was listen to my book and now I can't.

Hi.
If you've bought it from iTunes, you should be able to re-download it for free.
Download directly from iPod by going to the iTunes Store-App and find the "Purchased"-menu. From here you should get a complete list of all your bought items and the ability to re-download.
Download from iTunes on PC/Mac by opening iTunes > Go to iTunes Store > Go to the menubar on the left and choose "Purchased". Now, from the appearing window select the proper categori on top of the screen.
I hope this was helpful.

Creating one and two Dimensional array

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