Datagrid/list item saperator need help
hey guys.... so i got another question lol
im trying for a list to look exactly like the image i have attached to this post...
basically space between each item and a dotted line image on the bottom of that image....
anyone have any ideas??
i have the following so far...
<mx:TabNavigator width="275" height="400">
<mx:VBox label="USER OPTIONS" width="100%" height="100%">
<s:List width="100%" height="100%">
<s:dataProvider>
<s:ArrayList>
<fx:Object label="Adjust Volume" />
<fx:Object label="Arm/Disarm System" />
<fx:Object label="Change Mastercode" />
<fx:Object label="Secondary Codes" />
<fx:Object label="Bypass the Sensors" />
<fx:Object label="Record/Delete Messages" />
<fx:Object label="Set Time" />
<fx:Object label="System Status" />
</s:ArrayList>
</s:dataProvider>
</s:List>
</mx:VBox>
<mx:VBox label="TROUBLESHOOTING">
</mx:VBox>
</mx:TabNavigator>
cyber,
I'd look at making a custom item rendererer and then adding a repeating fill BitmapImage at the bottom (or top):
<?xml version="1.0" encoding="utf-8"?>
<s:ItemRenderer xmlns:fx="http://ns.adobe.com/mxml/2009"
xmlns:s="library://ns.adobe.com/flex/spark"
xmlns:mx="library://ns.adobe.com/flex/halo">
<s:Label id="labelDisplay"
left="4" right="4" top="4" bottom="5" />
<s:BitmapImage id="dottedLine"
source="@Embed('../redbluebg.gif')"
fillMode="repeat"
width="100%"
bottom="0" />
</s:ItemRenderer>
And then set the item rederer in your main app:
<?xml version="1.0" encoding="utf-8"?>
<s:Application xmlns:fx="http://ns.adobe.com/mxml/2009"
xmlns:s="library://ns.adobe.com/flex/spark"
xmlns:mx="library://ns.adobe.com/flex/mx">
<s:layout>
<s:VerticalLayout paddingLeft="20" paddingTop="20" />
</s:layout>
<s:controlBarContent>
<s:HSlider id="sl" minimum="20" maximum="600" value="100" />
</s:controlBarContent>
<s:List id="lst" itemRenderer="skins.foo" labelField="firstName" width="{sl.value}">
<s:dataProvider>
<s:ArrayList>
<fx:Object firstName="1.One" lastName="1.Two" />
<fx:Object firstName="2.One" lastName="2.Two" />
<fx:Object firstName="3.One" lastName="3.Two" />
<fx:Object firstName="4.One" lastName="4.Two" />
<fx:Object firstName="5.One" lastName="5.Two" />
<fx:Object firstName="6.One" lastName="6.Two" />
<fx:Object firstName="7.One" lastName="7.Two" />
</s:ArrayList>
</s:dataProvider>
</s:List>
</s:Application>
Peter
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Using JavaScript & Dynamic Lists - ?? need help
Hello all! Sorry to post this under an unrelated topic (JSP & JSTL), but there wasn't a JavaScript forum.
Anyway, before I ask my questions...read the following:
You'll find the code for my example at the end of this post. Also, I've posted my code as html pages in here...but my original code was in the form of servlets.
Here's what I wanted to accomplish:
1) html page has a form with two select lists
2) select one option from the first select
3) javascript code takes care of populating the 2nd list with options stored in an array, based on the first selection made in the 1st list.
4) each <option>'s value is set to the page hello.html
Piece of cake! That all works, but here's the real issue:
Let's say you click on an option from the 1st <select> list, which populates the 2nd <select> list with some options. You then click on the 2nd box, select an option, and it jumps to hello.html.
Now you press the back button - here are some things I observed:
First, let me note, that for my example, I'm using car makes for the 1st list, and car models for the 2nd.
* notice that only the 1st select list is still showing the selection you made, but the 2nd one shows nothing. Plus, when you click on the 2nd list, all that is shown is, in my example, "Then a Model". Not the original options that populated this list, when you had selected a car make from the first.
*also, if you select "Then a Model" in the 2nd, it will error out, because there isn't a link set for that option. I would actually prefer that the page doesn't jump anywhere if "Then a Model" was to be selected. But I can probably fix that later.
* If you try to select the car make you had previously selected again in the 1st menu, it still shows the same thing in the 2nd. Not the car models that it showed you when you had first run the example.
*) You can get the model options for, just for example, "Acura" back into the 2nd, but you would have to select Audi or BMW and then select Acura again.
*) if you select the "Select a Make" option in the 1st, it doesn't display "Then a Model" in the second as I would like. But I can probably fix that later.
Now, here are my questions:
1) Does anybody know how I can keep the selections "selected" in the page, when a user comes back to it when they press the "back" button?
2) Do I have to store the options selected somewhere, so the page "remembers" what was selected?
3) Would it help if I used session tracking?
I was told that the problems I've described are because I've implemented a dynamic listbox.
The value is supposed to be lost if I move to the next page and then click back. Would any of you agree?
Any ideas/suggestions at all would be very much appreciated!
************************ HERE'S THE CODE **********************************
This is dynamiclists.html I've commented it probably more than necessary for all you skilled JavaScript programmers, but I thought it would help to have an explanation for each piece of code.
<html>
<head>
<script language=javascript>
//here I create the multi-dimensional array to hold my
//values for each make and model to be put into the
//lists
var cars = new Array();
cars['Acura'] = new Array('Legend');
cars['BMW'] = new Array('740i');
cars['Audi'] = new Array('A4');
//method used for my onChange event in the first select list (Make)
//method accepts the value of the selected index
function createModel(makeName) {
//variables used for short-cutting to form elements
//references the form
var myform = document.selections;
//Make selection list
var Make = myform.Make;
//Model selection list
var Model = myform.Model;
//holds the item selected in the first list -- ex. Acura or Audi
var makeName = myform.Make.options[myform.Make.selectedIndex].value;
//to be set to a new Option
var theOption;
//if Select a Make is selected, clear the Model select list, and just put
// Then a Model in it
if(Make.selectedIndex == 0) {
Model.length = 0;
Model.length = 1;
Model.options[0].text = "Then a Model";
Model.options[0].value="Then a Model";
// if you select Acura from Make
if(makeName == "Acura") {
// fill first position in Model select list with the Then a Model, so the
// user knows to select a Model after a Make
Model.options[0].text = "Then a Model";
Model.options[0].value = "Then a Model";
// loop through the array elements that match makeName (which for example
// could be Acura
for(var i=0; i<cars[makeName].length; i++) {
// create a new Option for each Model available
theOption = new Option(cars[makeName], i);
// put the Model into the Model select list starting at position 1, not 0 because
// position 0 is taken up by Then a Model that was set above.
// Thus why I put (i+1)
Model.options[(i+1)] = theOption;
// set each Model options link to hello.html, just for now.
Model.options[(i+1)].value="hello.html";
}//end for
}//end if
// repeat for BMW and Audi
if(makeName == "BMW") {
Model.options[0].text = "Then a Model";
Model.options[0].value = "Then a Model";
for(var i=0; i<cars[makeName].length; i++) {
theOption = new Option(cars[makeName][i], i);
Model.options[(i+1)] = theOption;
Model.options[(i+1)].value="hello.html";
}//end for
}//end if
if(makeName == "Audi") {
Model.options[0].text = "Then a Model";
Model.options[0].value = "Then a Model";
for(var i=0; i<cars[makeName].length; i++) {
theOption = new Option(cars[makeName][i], i);
Model.options[(i+1)] = theOption;
Model.options[(i+1)].value="hello.html";
}//end for
}//end if
}//end createModel
// this is for the onChange event in the Model selection list.
// this takes care of the jump when you click on a Model.
// you will be taken to hello.html, which has been set in each option above
function MM_jumpMenu(targ,selObj,restore){
eval(targ+".location='"+selObj.options[selObj.selectedIndex].value+"';")
if (restore) selObj.selectedIndex=0;
</script>
</head>
<body>
<form name="selections">
<select name="Make" onChange="createModel(this.options[this.selectedIndex].value);">
<option value="Select Make" selected>Select Make
<option value="Acura">Acura
<option value="BMW">BMW
<option value="Audi">Audi
</select>
<select name="Model" onChange="MM_jumpMenu('parent',this,0)">
<option value="Then a Model" selected>Then a Model
</select>
</form>
</body>
</html>
***************************** END OF DYNAMICLISTS.HTML ***********************************
Here's my simple hello.html
<html>
<body>
Hello to all!
</body>
</html>I have a html:
<html>
<head>
<script>
var store = new Array();
store[0] = new Array(
'labas11',
'labas12',
'labas13');
store[1] = new Array(
'labas21',
'labas22',
'labas23');
// Funkcija skirta dedant naujienu
// irasa formuoti sarasa kuriems vartotojams bus siunciama zinute
function populate()
var box = document.forms[0].first;
var number = box.options[box.selectedIndex].value;
if (!number) return;
var list = store[box.selectedIndex];
if (list.length==null) return;
var box2 = document.forms[0].second;
box2.options.length = 0;
for(i=0;i<list.length;i++)
box2.options[i] = new Option(list,list[i]);
function addGroup()
var box = document.forms[0].first;
var number = box.selectedIndex;
if (number>-1)
document.forms[0].third.options[document.forms[0].third.options.length]=new Option('[G] '+box.value,document.forms[0].third);
function addUser()
var box = document.forms[0].second;
var number = box.selectedIndex;
if (number>-1)
document.forms[0].third.options[document.forms[0].third.options.length]=new Option('[V] '+box.value,document.forms[0].third);
function removeOne()
var box = document.forms[0].third;
var number = box.selectedIndex;
if (number>-1)
box.remove(box.selectedIndex);
function removeAll()
// alert(document.forms[0].third.options[0].text);
var box = document.forms[0].third;
box.options.length=0;
function selectToList()
//this code selects all the elements in the select field
for(var i=0;i<document.forms[0].third.length;i++)
document.forms[0].third.options[i].selected=true;
alert(document.forms[0].third.options[i].text);
</script>
</head>
<body>
<form action='servlet/List' method=Post>
<select size=4 name="first" style="width:200px" onchange="populate()">
<option value="0">html</option>
<option value="1">css</option>
</select>
<select size=4 name="second" style="width:200px">
</select>
<select size=4 name="third" style="width:200px" multiple>
</select>
<input type=submit value=spausk onClick="selectToList();" />
</form>
<table>
<tr><td><button onclick="addGroup()"> Įdėti grupę </button></td></tr>
<tr><td><button onclick="addUser()"> Įdėti vartotoją</button></td></tr>
<tr><td><button onclick="removeOne()"> �alinti </button></td></tr>
<tr><td><button onclick="removeAll()"> I�valyti </button></td></tr>
</table>
</body>
</html>
and servlet:
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class List extends HttpServlet
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{ doAction(request,response);}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{ doAction(request,response);}
public void doAction(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
response.setContentType("text/html;charset=windows-1257");
PrintWriter out = response.getWriter();
String[] strArray=request.getParameterValues("third");
out.print("Value: "+strArray[0]);
So what is wrong because servlet prints bad value [object]
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drawItem looks like:
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List item display in Oracle forms 10g
hi,
I have created the list item with pop-list in forms.When i retrieve the data using record group in the list item ,i need to display two column data in single list item i.e emp id , emp name .
select emp_id,emp_name from emp where mgr_id = 100;
i tried this query in record group but its coming emp id only, not name .
Can u tell the solution as soon as possibleHi,
In List Item, the First column will show in the list, and the Second column will be stored. To show both columns in list, u have to concatenate both fields and make it as first column. And i think you have to save the EMP_CODE, not EMP_NAME in database.
So the record group will be
SELECT EMP_ID || ' - ' || EMP_NAME EMP_NAME, EMP_ID FROM EMP WHERE MGR_ID = 100; Or you can use LOV to display multiple columns.
Regards,
Manu.
If this answer is helpful or correct, please mark it. Thanks. -
How to get values/data stored in the database into a list-item.
how to get values/data stored in the database into a list-item.
i tried to make a list item without any values assigned to it...but i got the below error.
FRM-30191: No list items defined for required poplist.
or
FRM-32082: Invalid value for given item type.
List EMPNO
Item: EMPNO
Block: EMP
Form: MODULE5
FRM-30085: Unable to adjust form for output.
then according to some docs, i tried the the following for the trigger
when-new-form-instance
declare
rg_name varchar2(40) := 'emp_rec';
status number;
groupid recordgroup;
it_id item;
begin
it_id := Find_Item('empno');
groupid := create_group_from_query(rg_name, 'select empno from emp');
status := populate_group(groupid);
populate_list(it_id, groupid);
end;
but yet didnt work... :(
so how the heck do i get values fetched from the database table into the list item?for list items you need to values in the record group, one is the shown value and one is the returned value.
Check out the online help for the populate_list built-in.
You'll need something like select ename,ename from emp as the record group query. -
List item - Population - Based on Data setup
Dear All,
I need to populate the list item based on data defined at the database level.
Tables Used:
Table 1 : JBCAI_JOB_COM_ADD_INFO
Column Name Pk Null? Data Type Default
JBEDC_UID 1 N NUMBER (22)
JBCAI_ADD_INFO_CODE 2 N VARCHAR2 (2 Char)
JBCAI_INFO_CODE_SEQUENCE 3 N NUMBER (3,1) 1
JBCAI_ADD_INFO_TEXT Y VARCHAR2 (35 Char)
SHIPCOMP_CODE N VARCHAR2 (4 Char)
Table 2 :CODES
CODE_TYPE CODE_VALUE DESCRIPTION NEXT_VALUE CODE_FLAG
MCAR 01 Customs References 01 NULL N
MCAR 02 Customs References 02 NULL N
MCAR 03 Value of Commodities NULL N
MCAR 04 Currency of commodities NULL N
MCAR 05 Purchase Order Number NULL N
MCAR 06 Other NULL N
MCAR 07 Consignee Name NULL N
MCAR 08 VIN NULL N
FORMS Section
=========
JBCAI_ADD_INFO_CODE are the list items which needs to be populated; JBCAI_ADD_INFO_TEXT(free text) which user can enter any descriptions.
References - Label of the Block
JBCAI_ADD_INFO_CODE JBCAI_ADD_INFO_TEXT
Customs References 01 - Free Text()
Customs References 02 - Free Text()
Value of Commodities - Free Text()
Currency of commodities - Free Text()
Purchase Order Number - Free Text()
Other - Free Text()
Consignee Name - Free Text()
VIN - Free Text()
VIN - Free Text()
Business Rules:
If JBCAI_ADD_INFO_CODE has the flag as 'N' in CODES table then user can select only one time from the list item.
If JBCAI_ADD_INFO_CODE has the flag as 'Y' in CODES table then user can do multi-selection from the list item e.g; VIN
How the records are fetched:
Value for the list item are been populated from CODES table ; which am doing through the below query.
In WHEN-NEW-FORM-INSTANCE am using the below code:
PROCEDURE p_fetch_code_value
IS
l_query VARCHAR2(200) ;
l_rg_name VARCHAR2(40) := 'CODES';
l_errcode NUMBER;
l_rg RECORDGROUP;
BEGIN
l_query := 'SELECT adcod.description description,adcod.code_flag code_flag FROM codes adcod WHERE adcod.code_type = ''MCAR'' AND adcod.code_value IN (''01''''02'',''03'',''04'',''05'',''06'',''07'',''08'') ORDER BY code_value';
l_rg := FIND_GROUP( l_rg_name );
IF ID_NULL(l_rg) THEN
l_rg := CREATE_GROUP_FROM_QUERY(l_rg_name, l_query);
END IF;
l_errcode := POPULATE_GROUP( l_rg );
POPULATE_LIST('BLK_CONTROL.JBCAI_ADD_INFO_CODE',l_rg);
EXCEPTION
Handled WHEN OTHERS exception
END p_fetch_code_value;
Saving of Record:
List value selection are saved to JBCAI_JOB_COM_ADD_INFO.JBCAI_ADD_INFO_CODE column.
Free Text is saved to JBCAI_JOB_COM_ADD_INFO.JBCAI_ADD_INFO_TEXT column.
Doubt:
When i select the first list item value i.e Customs References 01 and then enter some description i.e free text and moved to the next list item; the value Custom reference 01 should not be visible wheras the other values should have to be visible e.g; Customs Reference 02,Value of Commodities.....
Please help and let me know how can i acccomplish this task?
Thanks....
Regards,
Sunil.GHi Sarah,
Thanks for your reply.
There is no issue in the population of the list item; it is working fine with the query which i have pasted.
My doubt is:
There are few places where i have set the code_flag as 'Y' / 'N'.
For the first time when user selects the list item; all the values should be shown.....
If user has selected the first list item i.e Customs Reference 01 for which the code_flag is 'N' from a multi-record block; then when he moves to the further lines the previous selection for which the flag is set as 'N' should not be shown(if user has already selected once) e.g; 'Customs Reference 01' should not be shown again if user has made the selection before.
Plz revert incase more explanations required.
Thanks...
Regards,
Sunil.G
Edited by: Sunil G on Nov 29, 2009 12:16 AM -
Shortcut to mark up list item in DW CS5
Hi,
Forgive me if this is an easy one, but I have checked the knowledgebase without success. In my last version of DW I had a shortcut programmed so that I could type the text for a list item, highlight it, and use the shortcut to append opening and closing <li> tags to either end - much as you still can with CTRL+Shift+P for paragraph tags.
I used this a lot as I often receive long lists which need to be marked up and it's the quickest way - except I can't figure out how to do this now. I tried the advice here: http://help.adobe.com/en_US/dreamweaver/cs/using/WSc78c5058ca073340dcda9110b1f693f21-7cd9a .html but DW will only append <ul> tags to either end of the text, not <li> tags to each list item.
Any help very much appreciated.
Thanks
KatieYou can define a snippet to do that, and then create a shortcut to execute that snippet. I believe that was how you had to do it before, too.
I'm assuming you want to change this -
here is a line of text
to this -
<li>here is a line of text</li>
right? -
Hi,
I have a List Item on my form in which I am populating data in tree format...and that list item populates the data based on a check box value...my form is like this
Account # : ___________
Description : ____________________________
[ X ] Sub Account of : __________________(<------ this is my List item (Pop item)
and when user selects the value it returns the code and save it on COMMIT;
now my problem is whenever I do the execute_query the list box element doesnt set accordingly ...hummm. let me explain this way...i have accounts like this
10000 - Assets
11000 Current Asset
11101 Cash in hand
11102 Petty Cash
12000 Fixed Assett
12100 Building
12101 Building # 1
now if am creating a sub account I will fill my form like this
Account # : 11101
Description : Cash in hand
[ X ] Sub Account of : __________________(<------ this is my List item (Pop item)
now if i want a sub account I fill this pop list and it appeared like this
--------------------------------------------------------------------------+
10000 - Assets |
11000 Current Asset |
11101 Cash in hand |
11102 Petty Cash |
12000 Fixed Assett |
12100 Building |
12101 Building # 1 |
-------------------------------------------------------------------------+
suppose I select 11000 - Current Asset (make it parent account) from the list and
in the pop list this entry remains there...now after commit and clear_block it clears the block and ready for a new record...
My question is that when I execute the query all the values comes exactly but the list item perticular element should also be set accordingly ..how can I set the list item element according to the rest.
Hope I am describing my problem well otherwise plz ask me again.as the list item is a control item, it won't be auto-queried while executing query on the base table block. what you can do is, write the post-query trigger to assign the value of parent_account (sub_account_of) to this list item.
hope it helps. -
Update a list item after a task is completed
Hi,
I have a sharepoint workflow, where I am creating a workflow and the workflow steps involves assigning a task. How do I Update a list item after the task is completed? So after the task assignment step, how do I check that the task is completed so I can
update a list item?
Please help.
techieHi,
According to your description, you might want to update a list item after a task is completed in SharePoint Designer workflow.
By default, the workflow will stuck at a “Assign a task” action. When the “Task Status” become “Completed”, other actions afterwards will go on.
Here is a demo about how to update a list item after a task is completed in my environment:
You can follow the steps above to make a test in your environment to see if this is what you want.
Thanks
Patrick Liang
Forum Support
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support,
contact [email protected]
Patrick Liang
TechNet Community Support -
Help needed in list item...need to display employee of a selected dept
Hi All,
I am very beginner in D2K technology.I am using 10g Forms.
Could you please help me...
I have created a list item which contains dept_id=10,20,30....
My requirement is when i will change the value of dept_id(select dept_id=20),the employees belong to that dept will display(need to display 5 employees of dept 20).
I hav created two block--block2 and block3
In block2,there is a list item
In block3,there is a display item and i changed the properties number of record displayed to 10 of the block.
I atteched a trigger when-list-changed and the code is :
select last_name into :block3.item14 from employees where department_id=:block2.item4;
But It is not working.....
Thanks in Advance,
Tapan.
Edited by: user630863 on Aug 8, 2010 9:20 PM
Edited by: user630863 on Aug 8, 2010 9:55 PMokk..well still i don't know the purpose of the form on which you are working why not the database block for emp?..but the requirement you are asking can be done through following code...
Trigger - WHEN-LIST-CHANGED
DECLARE
CURSOR F_Cur IS
SELECT ename
FROM emp
WHERE deptno = :list_item_name;
BEGIN
GO_BLOCK('BLOCK3');
FIRST_RECORD;
CLEAR_BLOCK;
FOR G_CUR IN F_CUR LOOP
:block3.item_name:=G_CUR.ename;
NEXT_RECORD;
END LOOP;
FIRST_RECORD;
END;
Note: in the BLOCK3 there should be one item navigable by cursor. I mean if block3 is having only one item which is name item and it is display item then GO_BLOCK built-in will not work. So, you will need to create one more in block3 or make that name item as text item and set update_allowed to NO from the items' property.
-Ammad -
Need help using list item as to filter hire_date
hi to all, how can i use the list item as to filter hire_date based on the elements inside the list item
it goes something like this
HIRE_DATE----------------LIST_ITEM=JAN
01-JAN-10
02-JAN-10
03-JAN-10
HIRE_DATE----------------LIST_ITEM=FEB
01-FEB-10
02-FEB-10
03-FEB-10
the sorting will do after i press the button
thanks in advance :)sir i tried the code and it says: FRM-41003: This function cannot be performed here.
what im really want to do is that after retrieving the dates from a push button, (remember yesterday where you help me retrieving multiple data).... i have a list_item where it has the elements JAN,FEB,MAR,APR,MAY.
and then after selecting different month from the list_item the values that ive retrieve will be filter according to the value in the list_item
it looks something like this:
stud_id = 1001
time_in
01-JAN-10
02-JAN-10
03-JAN-10
01-FEB-10
02-FEB-10
03-FEB-10
after selecting FEB from the list_item it will goes like this
time_in
01-FEB-10
02-FEB-10
03-FEB-10
thanks..
-charles
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