Date to Month and Year

Hi Guru's
We have a requirement of taking the input in date/month/year format in the DSO and the output to be displayed in the report is in month/year in the report.
We dont want to do any changes/modification in the DSO level.
Any ideas on how to do it.
Thanks
Krishna

Hi,
Using the following code you can do it, but in columns you want to display the month, it is mot possible, i.e. JAN-08, FEB-08 like that it is not possible without adding new InfoObject in DSO. It works for Text variables.
'ZDATE_U' =   Normal Variable for Calday user entry.
'ZMONTH_E'. = Customet Exit for Calmonth
when 'ZMONTH_E'.
DATA: zdtt(8) TYPE c,
            w_mnth(3) TYPE c.
      LOOP AT i_t_var_range INTO loc_var_range WHERE vnam = 'ZDATE_U'.
        CLEAR l_s_range.
        w_day = loc_var_range-low+6(2).
        w_mon = loc_var_range-low+4(2).
        w_year = loc_var_range-low+0(4).
        CASE w_mon.
          WHEN '01'.
            w_mnth = 'JAN'.
          WHEN '02'.
            w_mnth = 'FEB'.
          WHEN '03'.
            w_mnth = 'MAR'.
          WHEN '04'.
            w_mnth = 'APR'.
          WHEN '05'.
            w_mnth = 'MAY'.
          WHEN '06'.
            w_mnth = 'JUN'.
          WHEN '07'.
            w_mnth = 'JUL'.
          WHEN '08'.
            w_mnth = 'AUG'.
          WHEN '09'.
            w_mnth = 'SEP'.
          WHEN '10'.
            w_mnth = 'OCT'.
          WHEN '11'.
            w_mnth = 'NOV'.
          WHEN '12'.
            w_mnth = 'DEC'.
        ENDCASE.
       CONCATENATE w_day '-' w_mnth '-' w_year INTO zdtt.
       CONCATENATE w_mnth '-' w_year INTO zdtt.
        CONCATENATE w_mnth '-' w_year+2(2) INTO zdtt.
        l_s_range-low = zdtt.
        l_s_range-sign = 'I'.
        l_s_range-opt = 'EQ'.
        APPEND l_s_range TO e_t_range.
      ENDLOOP.
Thanks
Reddy

Similar Messages

I want to keep date special month and year.

I want to keep date special month and year.
Example in sqlplus
insert into area(input_time) values(to_date('MAR-04','MON-YY'));
and select
select input_time from area;
the result
01 MAR 2004
in Oracle
01-MAR-2004 12:00:00 AM
I don't keep day, but I want to keep month and year.
Can you do?
Thanks.

An Oracle date column must contain a date down to the second. If you don't specify a day or a time, it will default to the first of the month and midnight.
If you want a column to only contain values at the beginning of a particular month, you can create a CHECK constraint that verifies that
input_time = trunc( input_time, 'MM' )Justin
Distributed Database Consulting, Inc.
http://www.ddbcinc.com/askDDBC

Convert Date to Month and Year

Hi,
I am currently using Function Module CONVERSION_EXIT_LDATE_OUTPUT to convert a date example 20090901 to 01 September 2009.
Using z_date+3 then zdate becomes September 2009 which is what i require.
In the report when I actually sort by month it doesn't really work well example below.
September 2009
September 2010
October 2009
October 2010
November 2009
November 2010
It should really be like the below. I dont want to covert the date to 09.2009 i want it to be September 2009 hence i have taken this approach. Any help would be appreciated.
September 2009
October 2009
November 2009
September 2010
October 2010
November 2010
Regards
Adeel

as you are storing it into one string, its just sorting on the basis of string comparison which starts from first later.
store them to two different fields.
like
data : BEGIN OF gt_dt OCCURS 0,
        mnth type string,
        year type n LENGTH 4,
       end of gt_dt.
DATA : s1 TYPE string,
      i1 type i.
*lets say here you get the values to this table like:
s1 = '01 September 2009'.
shift s1 by 3 PLACES left.
i1 = strlen( s1 ).
i1 = i1 - 4.
gt_dt-mnth = s1+0(i1).
shift s1 by i1 PLACES left.
gt_dt-year = s1.
APPEND gt_dt.
s1 = '01 September 2010'.
shift s1 by 3 PLACES left.
i1 = strlen( s1 ).
i1 = i1 - 4.
gt_dt-mnth = s1+0(i1).
shift s1 by i1 PLACES left.
gt_dt-year = s1.
APPEND gt_dt.
s1 = '01 October 2009'.
shift s1 by 3 PLACES left.
i1 = strlen( s1 ).
i1 = i1 - 4.
gt_dt-mnth = s1+0(i1).
shift s1 by i1 PLACES left.
gt_dt-year = s1.
APPEND gt_dt.
s1 = '01 October 2010'.
shift s1 by 3 PLACES left.
i1 = strlen( s1 ).
i1 = i1 - 4.
gt_dt-mnth = s1+0(i1).
shift s1 by i1 PLACES left.
gt_dt-year = s1.
APPEND gt_dt.
now you can sort as you wish.

Get start and end week date by month and year

How I need the week is by this -- a week always starts on a sunday so for feburary it will be
start week end week
12-02-1 12-02-04
12-02-05 12-02-11
12-02-12 12-02-18
12-02-19 12-02-25
12-02-26 12-29-29
So because the first week does not start on a sunday it goes from
1(wednesday) to 4th(saturday) Just like a calendar.
Thanks in advance
so far from Solomons help I have this
This is for january
WITH t AS (
SELECT TRUNC(TRUNC(to_date('01-01-12','MM-DD-YY'),'YYYY') -1,'W') + (LEVEL-1 ) * 7 week_start_date
FROM DUAL
CONNECT BY LEVEL <= 53
SELECT week_start_date,
LEAST(LAST_DAY(to_date('01-01-12','MM-DD-YY')),week_start_date + 6) week_end_date
FROM t
WHERE week_start_date >= TRUNC(to_date('01-01-12','MM-DD-YY'),'MM')
AND week_start_date < ADD_MONTHS(TRUNC(to_date('01-01-12','MM-DD-YY'),'MM'),1)
start week end week
12-01-02     12-01-08
12-01-09     12-01-15
12-01-16     12-01-22
12-01-23     12-01-29
12-01-30     12-01-31

If week satrts Sunday:
WITH t AS (
           SELECT TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 week_start_date
            FROM DUAL
            CONNECT BY TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 <= LAST_DAY(&dt)
SELECT GREATEST(week_start_date,TRUNC(&dt,'MM')) week_start_date,
        LEAST(LAST_DAY(&dt),week_start_date + 6) week_end_date
FROM t
WHERE week_start_date <= LAST_DAY(&dt)
/For example:
SQL> SET VERIFY OFF
SQL> DEFINE dt="DATE '2012-01-17'" -- January
SQL> WITH t AS (
2             SELECT TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 week_start_date
3              FROM DUAL
4              CONNECT BY TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 <= LAST_DAY(&dt)
5            )
6 SELECT GREATEST(week_start_date,TRUNC(&dt,'MM')) week_start_date,
7          LEAST(LAST_DAY(&dt),week_start_date + 6) week_end_date
8    FROM t
9    WHERE week_start_date <= LAST_DAY(&dt)
10 /
WEEK_STAR WEEK_END_
01-JAN-12 07-JAN-12
08-JAN-12 14-JAN-12
15-JAN-12 21-JAN-12
22-JAN-12 28-JAN-12
29-JAN-12 31-JAN-12
SQL> SET VERIFY OFF
SQL> DEFINE dt="DATE '2012-02-25'" -- February
SQL> WITH t AS (
2             SELECT TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 week_start_date
3              FROM DUAL
4              CONNECT BY TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 <= LAST_DAY(&dt)
5            )
6 SELECT GREATEST(week_start_date,TRUNC(&dt,'MM')) week_start_date,
7          LEAST(LAST_DAY(&dt),week_start_date + 6) week_end_date
8    FROM t
9    WHERE week_start_date <= LAST_DAY(&dt)
10 /
WEEK_STAR WEEK_END_
01-FEB-12 04-FEB-12
05-FEB-12 11-FEB-12
12-FEB-12 18-FEB-12
19-FEB-12 25-FEB-12
26-FEB-12 29-FEB-12
SQL> SET VERIFY OFF
SQL> DEFINE dt="DATE '2012-03-07'" -- March
SQL> WITH t AS (
2             SELECT TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 week_start_date
3              FROM DUAL
4              CONNECT BY TRUNC(TRUNC(&dt,'MM') + 1,'IW') - 1 + (LEVEL - 1) * 7 <= LAST_DAY(&dt)
5            )
6 SELECT GREATEST(week_start_date,TRUNC(&dt,'MM')) week_start_date,
7          LEAST(LAST_DAY(&dt),week_start_date + 6) week_end_date
8    FROM t
9    WHERE week_start_date <= LAST_DAY(&dt)
10 /
WEEK_STAR WEEK_END_
01-MAR-12 03-MAR-12
04-MAR-12 10-MAR-12
11-MAR-12 17-MAR-12
18-MAR-12 24-MAR-12
25-MAR-12 31-MAR-12
SQL> SY.
Edited by: Solomon Yakobson on Jan 12, 2012 1:19 PM

Select-options split date into month and assign to low and high

Hi,
   In my select-options i am giving BEDAT (01.04.2004 TO 30.10.2005).I need to split month and
year in separate fields.that is
select-option_low-month in one field
select-option_high-month in second field
select-option_low-year in third field
select-option_high-year in fourth field.
Finally i need to move these four fields to it_final.
select * from mbewh into corresponding fields of table it_mbewh
           for all entries in it_final where matnr = it_final-matnr and
           bwkey = it_final-werks and lpmon = ? and lfgja = ?
           and bklas <> ' '.
what input i have to give in lpmon and lfgja in select query to get for lfmon (04 to 10)
and lfgja (2004 to 2005).
suggest some ideas.

Hi ,
Can you please check the following code.
Hi ,
data : l_low_yr(4),
          l_high_yr(4),
          l_low_mon(2),
          l_high_mon(2).
Splitting the select option date to month and year into low and higher values
l_low_yr        =   s_date-low+00(04). " Year low value from the date range
l_low_mon    =   s_date-low+04(02). " Month low value from the date range
l_high_yr      =   s_date-high+00(04)." Year high value from the date range
l_high_mon   =   s_date-high+04(02)." Month high value from the date range
selecting the data from the table mbewh based on some conditions.
select * from mbewh into corresponding fields of table it_mbewh
           for all entries in it_final where matnr = it_final-matnr and
           bwkey = it_final-werks and lfmon BETWEEN l_low_mon and l_high_mon
and lfgja BETWEEN l_low_yr and l_high_yr   and bklas EQ ' '.
This select will retrive the desired data records from the table MBEWH.
Please let me know if this works according to your requirement.
Thanks and Regards
Saritha

How to get Week,Month and Year details from a date column

Hi frenz,
I've a column like tran_date which is a date column..... I need the next week details based on this column and so on...
I need month and year details as well based on this tran_date column.... can any one tell me how...
Thanks in advance

My example for objects:
create or replace type date_object as object
centure number,
year    number,
month   number,
day     number,
hour    number,
minute number,
second number,
daypart number,
week    number,
constructor function date_object(p_dt date)
    return SELF as result
create or replace type body date_object is
constructor function date_object(p_dt date)
    return SELF as result
as
begin
    SELF.centure:= trunc(to_char(p_dt,'YYYY')/100);
    SELF.year:=    to_char(p_dt,'YYYY');
    SELF.month:=   to_char(p_dt,'MM');
    SELF.day:=     to_char(p_dt,'DD');
    SELF.hour:=    to_char(p_dt,'HH24');
    SELF.minute:= to_char(p_dt,'MI');
    SELF.second:= to_char(p_dt,'SS');
    SELF.daypart:= p_dt-trunc(p_dt,'DD');
    SELF.week:=    to_char(p_dt,'IW');
    return;
end;
end;
select date_object(sysdate),
       date_object(sysdate).year
from dual;Regards,
Sayan M.

Data element for Month and Year

Hello All,
Is there any data element which will have only Month and Year.
I have to introduce this field in a table. It should have convesion exits also.
Ex: If i give 092009, it sould come like 09.2009
Thank you.
Best Regards,
Sasidhar Reddy Matli.

Kindly Try this code for Month and year as input and having standard F4 help..
INCLUDE RMCS0F0M.
TYPES : BEGIN OF TY_SELECT,
MONTH TYPE FTI_MONTH_YEAR,
END OF TY_SELECT.
DATA : WA_SELECT TYPE TY_SELECT.
SELECTION-SCREEN : BEGIN OF BLOCK SANDEEP WITH FRAME.
SELECT-OPTIONS : S_MONTH FOR WA_SELECT-MONTH OBLIGATORY NO INTERVALS NO-EXTENSION.
SELECTION-SCREEN : END OF BLOCK SANDEEP.
AT SELECTION-SCREEN ON VALUE-REQUEST FOR S_MONTH-LOW.
PERFORM MONAT_F4.
SANDEEP JAIN

Problem to insert only month and year instead of full date

select b.penjara_id, p.penj_lokasi, a.no_daftar, b.episod, b.nama1,to_char(a.trkh_mula_prl,'dd/mm/yyyy') as trkh_mula_prl, to_char(bulan_proses,'mm/yyyy') as bulan_proses,
b.epd, b.lpd
from prl_daftar_proses a, senarai_pesalah b, penjara p
where a.no_daftar=b.no_daftar
and a.episod=b.episod
and b.penjara_id = p.penjara_id
and a.setuju_jplp is null
and a.bulan_proses between to_date(:FROM,'dd/mm/yyyy') and to_date(:TO,'dd/mm/yyyy')
order by b.penjara_id, a.bulan_proses,a.no_daftarHi,anyone can help me how i can insert only month and year from the value that have full date in the database??
for example,the date is 09/18/2012, but i just want to insert 09/2012 as parameter. If i want to insert only one parameter, i can do that..But i have problem when I want to insert two parameters..

jeneesh wrote:
Welcome to the forum..
This..?
Assuming bulan_proses is a date without time part
select b.penjara_id, p.penj_lokasi, a.no_daftar, b.episod, b.nama1,to_char(a.trkh_mula_prl,'dd/mm/yyyy') as trkh_mula_prl, to_char(bulan_proses,'mm/yyyy') as bulan_proses,
b.epd, b.lpd
from prl_daftar_proses a, senarai_pesalah b, penjara p
where a.no_daftar=b.no_daftar
and a.episod=b.episod
and b.penjara_id = p.penjara_id
and a.setuju_jplp is null
and a.bulan_proses between to_date(:FROM,'mm/yyyy') and last_day(to_date(:TO,'mm/yyyy'))
order by b.penjara_id, a.bulan_proses,a.no_daftar
i got another problem..
before that.may i know what is the function of last_day?

To get first date and end date after entering any month and year

Hi,
I need to to get first date and end date of a month and year in yyyyMMdd format. I am reading month and year from a properties file. But I don't know how to get the first date and End date in given format. The properties file gives me just text. But I don't know how to get the date format using this. I need this urgently. Can anyone help me to get code for this?
I am reading the fields as,
Properties props = new Properties();
props.load(new FileInputStream("AnyMonthVolume.properties"));
String date_month = props.getProperty("date_month");
String date_year = props.getProperty("date_year");
Thanks.

I know this has been posted a while ago but incase someone looking for it, here is the code to get the end of current month date.
Calendar cal = Calendar.getInstance();
     cal.setTime(new java.util.Date());
     cal.set(Calendar.DATE, 1); //set the date to start of month
     cal.add(Calendar.MONTH,1);
     cal.add(Calendar.DATE,-1);
System.out.println(cal.getTime());

Is there a way to change the date format so that delegates have to choose a day, month and year from a drop down menu as my delegates keep forgetting to change the year of their information

When my delegates are filling in a event form i have put together, a large number of them forget to change either the month or year on the date field. Is there a way to have a date field that has drop down boxes for day, month and year so they have to choose rather than a date been already on the screen??
Thanks

Hi Christopher,
The WEEKDAY function allows specifying either Sunday or Monday as the first day of the week:
WEEKDAY
The WEEKDAY function returns a number that is the day of the week for a given date. WEEKDAY(date, first-day)
Â date: The date the function should use. date is a date/time value. The time portion is ignored by this function.
Â first-day: An optional value that specifies how days are numbered.
Sunday is 1 (1 or omitted): Sunday is the first day (day 1) of the week and Saturday is day 7.
Monday is 1 (2): Monday is the first day (day 1) of the week and Sunday is day 7. Monday is 0 (3): Monday is the first day (day 0) of the week and Sunday is day 6.
But I think you are referring to the first day of the 'workweek', for which I do not see a means of defining a custom value.
Since you want to 'insert categories', though, you could easily define your own, using WEEKDAY(date) or WEEKDAY(date,1), plus an IF statement to return the category label appropriate to the day. Here's one for a Sunday to Thursday work week. Dates are in column A, the formula is in whichever column you want as the Category column. For the example, I've placed it in column B.
B2, and filled down: =IF(WEEKDAY(A)<6,"Work","Off")
The top table shows the weekday numbers returned for each day of the week for each of the three permitted values for the optional second argument. The bottom table shows the results from the formula above, used to define a category label for each date:
A10 was left blank intentionally, to determine if the lack of data resulted in an error. The Warning message, flagged by the blue 'warning' triangle, is "The formula uses a number in place of a date." The 'date' assigned to this numerical value of zero was a Friday, but I'm not certain when. Probably best to avoid extra rows with no date shown.
Regards,
Barry

Anyone help me ...I am writing to get Date, Month and Year...I got errors

Could some body help me:
I am try to get Date, Month and Year
I got stuck, Anyone help me this:
public class DateMonth
public static void main(String[] args)
toDay = new toDay("February 21, 2002");
dayofWeek = today.getDay();
System.out.println("Current month is " + toDay.getMonth());
System.out.println("Current day is " + getDate());
System.out.println("Current year is " + toDay.getYear());
toDay.setDate(toDay.getDate()+60)
System.out.println("Sixty days from now is ");
System.out.println(toDay);
}

Try something like this:
import java.util.*;
public class DateMonth {
     public static void main(String[] args) {
          // Note: 0 = January
          Calendar calendar = new GregorianCalendar();
          System.out.println("YEAR: " + calendar.get(Calendar.YEAR));
          System.out.println("MONTH: " + calendar.get(Calendar.MONTH));
          System.out.println("WEEK_OF_YEAR: " + calendar.get(Calendar.WEEK_OF_YEAR));
          System.out.println("WEEK_OF_MONTH: " + calendar.get(Calendar.WEEK_OF_MONTH));
          System.out.println("DATE: " + calendar.get(Calendar.DATE));
          System.out.println("DAY_OF_MONTH: " + calendar.get(Calendar.DAY_OF_MONTH));
          System.out.println("DAY_OF_YEAR: " + calendar.get(Calendar.DAY_OF_YEAR));
          System.out.println("DAY_OF_WEEK: " + calendar.get(Calendar.DAY_OF_WEEK));
          // 60 days from now
          calendar.add(calendar.DATE, 60);
          System.out.println("\nSixty days from now");
          System.out.println("MONTH: " + calendar.get(Calendar.MONTH));
          System.out.println("DATE: " + calendar.get(Calendar.DATE));
          System.out.println("YEAR: " + calendar.get(Calendar.YEAR));
}Remember that January is 0!
Take a look at the GregorianCalendar class:
http://java.sun.com/j2se/1.3/docs/api/java/util/GregorianCalendar.html
Hope this helps!
DesQuite

Find the difference between two dates for the specific month and year

Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?

I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition.

Find month and year of a given date

Hi,
How to find the month and year of a given date.
month ( sy-datum) year ( sy-datum )
--Bala

hi
DATA: EDAYS LIKE VTBBEWE-ATAGE,
EMONTHS LIKE VTBBEWE-ATAGE,
EYEARS LIKE VTBBEWE-ATAGE.
PARAMETERS: FROMDATE LIKE VTBBEWE-DBERVON,
TODATE LIKE VTBBEWE-DBERBIS DEFAULT SY-DATUM.
Call Function 'FIMA_DAYS_AND_MONTHS_AND_YEARS'
exporting
    i_date_from          = FROMDATE
    i_date_to            = TODATE
I_FLG_SEPARATE       = ' '
IMPORTING
    E_DAYS               = EDAYS
    E_MONTHS             = EMONTHS
    E_YEARS              = EYEARS.
WRITE:/ 'Difference in Days   ', EDAYS.
WRITE:/ 'Difference in Months ', EMONTHS.
WRITE:/ 'Difference in Years ', EYEARS.
INITIALIZATION.
FROMDATE = SY-DATUM - 60.
Using teh abiove u can get difference but when u pass previous year u wont get the exact.
There is no seperate FM for this, u have to use three FM.
If possible using these three FM code u can create an FM.
For years and months between two days:
DATA:   EYEARS LIKE VTBBEWE-ATAGE.
PARAMETERS: FROMDATE LIKE PREL-BEGDA,
                 TODATE   LIKE PREL-BEGDA DEFAULT SY-DATUM.
CALL FUNCTION 'COMPUTE_YEARS_BETWEEN_DATES'
EXPORTING
    first_date                        = fromdate
MODIFY_INTERVAL                   = ' '
    second_date                       = todate
IMPORTING
   YEARS_BETWEEN_DATES               = EYEARS
EXCEPTIONS
SEQUENCE_OF_DATES_NOT_VALID       = 1
OTHERS                            = 2
IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
Write:/ eyears.
DATA:       EMONTHS LIKE VTBBEWE-ATAGE.
PARAMETERS: FROMDATE LIKE SY-DATUM,
            TODATE   LIKE SY-DATUM
DEFAULT SY-DATUM.
CALL FUNCTION 'MONTHS_BETWEEN_TWO_DATES'
EXPORTING
    i_datum_bis         = fromdate
    i_datum_von         = todate
I_KZ_INCL_BIS       = ' '
IMPORTING
   E_MONATE            = emonths
write:/ emonths
CALL FUNCTION 'DAYS_BETWEEN_TWO_DATES'
EXPORTING
I_DATUM_BIS = x_faede-zfbdt
I_DATUM_VON = p_fdat
I_KZ_EXCL_VON = '0'
I_KZ_INCL_BIS = '0'
I_KZ_ULT_BIS = ' '
I_KZ_ULT_VON = ' '
I_STGMETH = '0'
I_SZBMETH = '1'
IMPORTING
E_TAGE = dias_v.
IF SY-SUBRC <> 0.
ENDIF.
x_faede-zfbdt -> 20050915
p_fdat -> 20050811
dias_v = 4
try this and let me know.
regards
ravish
<b>plz dont forget to reward useful points</b>

Date must be truncated to month and year

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I have a date field
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Hallo,
I try to configure the Date Picker. For the users it should only be possible to select Month and Year. The column should be automaticly completed with the first day of the select month and a static time (00:00:00).
How can I do this?
Sincerly

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http://htmldb.oracle.com/pls/otn/f?p=31517:9
Denes Kubicek
http://deneskubicek.blogspot.com/
http://www.opal-consulting.de/training
http://apex.oracle.com/pls/otn/f?p=31517:1
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