Days in Year Expression

I am looking for an expression that would give me the total number of days in the current year. Any help would be appreciated. Thank you

Hi,
I'm sorry I was calcuating the difference between 01st Jan and 31st dec.
Please use this formula:
datediff("d",cdate(year(currentdate),01,01),cdate(year(currentdate)+1,01,01))
-Abhilash

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My wife and I got Iphone 4S same day 2 years ago. I used the same Apple ID for both. We do not use iCloud, but today after I updated my phone to IOS7 I keep getting her texts on my phone ans vice versa.

My wife and I got Iphone 4S same day 2 years ago. I used the same Apple ID for both. We do not use iCloud, but today after I updated my phone to IOS7 I keep getting her texts on my phone ans vice versa. I turned off imessage in message settings. Seems to have stopped now? Never did this before IOS7. Will I have more troubble when her phone updates to IOS7? Is icloud going to be forced on me then?

This is being caused by using the same Apple ID for iMessage on both phones. To separate your messages, go to Settings>Messages>Send & Receive and do one of the following:
Either uncheck the email address shown under "You can be reached by iMessage at" on both phones; or
If you want to continue to receive iMessages at this email address, on one of the two phones, tap the Apple ID at the top, sign out, then sign back in using a different Apple ID.

Studio : Chart Based on day/month/year

In Studio , There is a requirement for us to display chart based on day/month/year .
Since Date attribute is not displayed as a Dimension in the chart configuration list , I have divided date attribute into day/month/year attributes and based on that I generated a sample chart
But now I'm facing with a problem
Suppose there are records for only July and Sep then the chart shows up for July and Sep , It doesn't show up for august.
I agree that there are no records for august in my data domain that is the reason august is not displayed in the chart . But as per our requirement we should display august as well with zero count.
I'm curious to know if there is any way to do this .

The idea behind the calendar record type is it is a secondary, new record type you're introducing that compliments your "sales" record type. The RECORDs you provided would be your "sales" record type, not your "calendar" record type. To continue with your example, your "sales" records would look like what you provided:
=============== RECORD ==================
Id: 1
sales_amount : 1000
Month: Oct
RecordType: sales
date: 2012-10-01T00:00:00.000Z
day: 01
year: 2012
=============== RECORD ==================
Id: 5
sales_amount: 1000
Month: Dec
RecordType: sales
date: 2012-12-01T00:00:00.000Z
day: 01
year: 2012
==========================================
And your "calendar" record type would be loaded subsequently. I usually provide one Endeca record for every day for this record type:
=============== RECORD ==================
Id: 1
Month: Oct
RecordType: calendar
date: 2012-10-01T00:00:00.000Z
day: 01
year: 2012
=============== RECORD ==================
Id: 2
Month: Oct
RecordType: calendar
date: 2012-10-02T00:00:00.000Z
day: 02
year: 2012
==========================================
(and so on, one for each day up to today...yawn)....
=============== RECORD ==================
Id: 790
Month: July
RecordType: calendar
date: 2013-07-31T00:00:00.000Z
day: 31
year: 2013
==========================================
Thus, when you write an EQL statement like:
RETURN foo AS SELECT
SUM(sales_amount) AS "TotSales"
GROUP BY Month
You will get a Month bucket for every month, where the "calendar" record type will be sure to offer a month where sales don't offer it...aka. fill in any "holes".
HTH,
Dan
http://branchbird.com

How can I finish the last step in the 2 Day Plus Appl Express Developer

Hi,
I try to follow doing the steps the Chapter 8 How to Upload and Download Files in an Application of the 2 Day Plus Application Express Developer, after I had finished
the input to Oracel XE (all steps in this chapter and the procedure in 'Downloading Documents from the Custom Table'), I open the "run Page 1 icon" , the procedure seems no running and cause the error 'Page cannot be found'.
I doubt the type is wrong or correct "#OWNER#.download_my_file?p_file=#ID#".
Are there any one can tell me ?
Regards,
Simon Wong
Message was edited by:
user505611

Simon,
here is the full example. Please follow the steps closely. Input exactly what is written in bold characters (without the line numbers though).
Here we go (in a dos command box):
C:\WINDOWS\system32>sqlplus system@xe
SQL*Plus: Release 10.2.0.1.0 - Production on Sun Aug 13 12:48:24 2006
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Connected to:
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Production
*** Show more detailed error information in the browser ***
SQL> exec dbms_epg.set_dad_attribute('APEX', 'error-style', 'DebugStyle');
PL/SQL procedure successfully completed.Now try to run the following url in the browser: http://127.0.0.1:8080/apex/hr.hello_world
This will give you the following error message:
hr.hello_world: PROCEDURE DOESN'T EXIST
DAD name: apex
PROCEDURE : hr.hello_world
URL : http://XDB HTTP Server:8080/apex/hr.hello_world
PARAMETERS :
===========Now continue with the sqlplus - session :
*** Switch session to user HR to create procedure hello world ***
SQL> alter session set current_schema=HR;
Session altered.
SQL> CREATE OR REPLACE procedure hello_world
2 is
3 begin
4 htp.p('hello world');
5 end;
6 /
Procedure created.
*** check to see whether the procedure was created properly ***
SQL> desc hr.hello_world;
PROCEDURE hr.hello_world
*** grant execute on procedure to account ANONYMOUS ***
SQL> begin
2 execute immediate 'grant execute on hello_world to anonymous';
3 end;
4 /
PL/SQL procedure successfully completed.
*** Switch to user FLOWS_020100 ***
SQL> alter session set current_schema=FLOWS_020100;
Session altered.
*** for testing, disable the security mechanism ***
SQL> CREATE OR REPLACE function wwv_flow_epg_include_mod_local(
2 procedure_name in varchar2)
3 return boolean
4 is
5 begin
6 return true;
7 end;
8 /
Function created.Running the url again should work now, the security mechanism is disabled.
If this works, we can enable the security mechanism again:
*** now create the function again, checking for the proper procedure name ***
SQL> CREATE OR REPLACE function wwv_flow_epg_include_mod_local(
2 procedure_name in varchar2)
3 return boolean
4 is
5 begin
6 if upper(procedure_name) in ('HR.HELLO_WORLD') then
7 return true;
8 else
9 return false;
10 end if;
11 end;
12 /
Function created.
*** remove the debugging information ***
SQL> exec dbms_epg.delete_dad_attribute('APEX', 'error-style')
PL/SQL procedure successfully completed.You don't need to restart any services inbetween the outlined steps and you shouldn't have to change any security settings in your browser. It is all done in the database.
If it still doesn't work, please post your error messages from the browser here.
Regards,
~Dietmar.

Is it possible to show the day of year in iCal?

Is it possible to show the day of year in iCal? There are 365 days of year and for example today april 22 is number 112.
If it is possible - how is it done?
thank you!

The Apple iPad apps don't. Check out Photo Manager Pro http://graphicssoft.about.com/od/iphoneandipodtouchapps/fr/Photo-Manager-Pro.htm
 Cheers, Tom

Get amount of megabytes for the message transfer per day, month, year

Dear experts,
can you please tell me the name of the report which can be used to get the amount of megabytes for the message transfer per day, month, year etc.? I can't find it in our system.
Best regards,
David

Hi,
Check this blog: /people/gourav.khare2/blog/2007/12/12/interesting-abap-tables-in-xi-150-part-i
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Regards,
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Convert number of dayes per year to data

Please i need help in Convert number of dayes to date
I have ID's like id
FT*09025*0000000001 date=20090125
FT*01171*0000000002 date=20100620
so should convert first five number after FT to date
example *09025*
09 map to 2009
025 number of dayes per year map to 25 jan
example *01171*
01 map to 2010
171 number of dayes per year map to 20 jun
(jan+feb+mar+apr+may)=(31+28+31+30+31)=151
171-151=20 for the next month
Please need help so will added filter to informatica map with date
Edited by: user8929623 on Jul 4, 2010 7:04 PM

Well, I do not follow why when 09 maps into 2009, 01 maps into 2010, not into 2001. Assuming it should be 2001, use YYDDD format:
SQL> with t as (
2             select 'FT*09025*0000000001' id from dual union all
3             select 'FT*01171*0000000002' from dual
4            )
5 select to_date(substr(id,4,5),'yyddd') dt
6    from t
7 /
DT
20090125
20010620
SQL> SY.

Conversion of days to year&months (HR)

Hi friends,
I'm working for one BI HR report, where i'm getting employee experience in days. I want to convert days into years& months. Eg: 850 days means 2 yrs 4months. At cube level i'm getting number of days, how can i get it at query level?
thanks,
Sridhar

please find the complete code
DATA: L_DATE TYPE D,
        L_TIME TYPE T,
        E_TIMESTMP like RSGENERAL-TIMESTMP,
        FINAL_DATE(16),
        INDATE LIKE PSO02-ZFBDT,
        DD TYPE i,
        MM TYPE i,
        yy TYPE i.
PARAMETERS: I_DAYS TYPE i.
GET TIME STAMP FIELD E_TIMESTMP.
CONVERT TIME STAMP E_TIMESTMP TIME ZONE 'UTC+12' INTO
          DATE L_DATE TIME L_TIME.
SUBTRACT I_DAYS FROM L_DATE.
CONVERT DATE L_DATE TIME L_TIME INTO
          TIME STAMP E_TIMESTMP TIME ZONE 'UTC+12'.
FINAL_DATE = E_TIMESTMP.
INDATE = FINAL_DATE+1(8).
CALL FUNCTION 'FI_PSO_FULL_DAY_MONTH_YEAR_GET'
    EXPORTING
      I_DATE_FROM          = SY-DATUM
      I_DATE_TO            = INDATE
   IMPORTING
     E_DAYS               = DD
     E_MONTHS             = MM
     E_YEARS              = YY .
WRITE:/ yy, mm, dd.
but FM 'FI_PSO_FULL_DAY_MONTH_YEAR_GET' is not avialble in BI side, it is there in R/3 . You need to create in BI, then you can use it.
bhaskar

2 Day Plus Application Express Developer Guide - error?

Good day !
In "Oracle Database Express Edition 2 Day Plus Application Express Developer Guide" chapter 8 "How to Upload and Download Files in an Application" at the topic "Store the Document in a Custom Table" ( page 8-10, 8-11) is recommended:
6. Under Source, replace the process with the following:
IF ( :P1_FILE_NAME is not null ) THEN
INSERT INTO file_subjects(id,NAME, SUBJECT, BLOB_CONTENT, MIME_TYPE)
SELECT ID,:P1_FILE_NAME,:P1_SUBJECT,blob_content,mime_type
FROM HTMLDB_APPLICATION_FILES WHERE name = :P1_FILE_NAME;
WHERE name = :P1_FILE_NAME;
DELETE from HTMLDB_APPLICATION_FILES WHERE name = :P1_FILE_NAME;
END IF;
7. Scroll up to the top of the page and click Apply Changes.
After this I receive Error Message:
ORA-06550: line 6, column 1: PLS-00103: Encountered the symbol "WHERE" when expecting one of the following: begin case declare else elsif end exit for goto if loop mod null pragma raise return select update while with << close current delete fetch lock insert open rollback savepoint set sql execute commit forall merge pipe
Now I can't find mistake. Please, help me ( if difficulties not so big )
Winni

Replace by:IF ( :P1_FILE_NAME is not null ) THEN
INSERT INTO file_subjects(id,NAME, SUBJECT, BLOB_CONTENT, MIME_TYPE)
SELECT ID,:P1_FILE_NAME,:P1_SUBJECT,blob_content,mime_type
FROM HTMLDB_APPLICATION_FILES WHERE name = :P1_FILE_NAME;
DELETE from HTMLDB_APPLICATION_FILES WHERE name = :P1_FILE_NAME;
END IF;The second WHERE clause is superfluous.
Regards, Marc

HT201328 I do travel to Europe several day a year. It is true that I can use the Iphone 5 in other country with no trouble ??

I do travel to Europe several day a year. It is true that I can use the Iphone 5 in other country with no trouble ??

If your phone is locked to AT&T, you can certainly travel & use your phone, but you'll have to get AT&T to provision your account for International use...select the country/countries & plan. This is very expensive, as the roaming partners set the rates & you generally pay through the nose.
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How to convert days to years, months and remaining days

Hi All,
I have the number of days for example : 398 days how to
convert 398 days to number of years and number of months and remaining days
like 398 days 1 year , 1 month and 2 days
Regards
rkrao

e.g.
SQL> select sysdate, sysdate - 1234 from dual
2 /
SYSDATE   SYSDATE-1
09-AUG-06 24-MAR-03
SQL> select trunc(trunc(months_between (sysdate, sysdate - 1234))/12) yrs,
2 mod(trunc(months_between(sysdate, sysdate - 1234)), 12) mnths,
3 sysdate - add_months((sysdate - 1234), trunc(months_between(sysdate, sysdate - 1234))) dys
4 from dual
5 /
       YRS      MNTHS        DYS
         3          4         16
SQL>

Current date / day of year in formula

Dear all,
For a calculation, I need the day of the year in order to calculate a year-to-date budget (derived from the full year budget).
[ YTD budget = Full year budget * day of year / 365 ]
The full year budget is in my infocube, as is 0FISCYEAR and 0FISCPER and 0CALMONTH2.
The infocube provides actual and budget data per month (0FISCPER) as most detailed level (so 0calday is not part of my cube).
In order to make the calculation I presume I need the variable 0DAT (SAP Exit) but I am not sure if that is correct.
Problem is: I am not able to and/or don't no how to use this variable. The documentation says that 0DAT is part of 0calday, and I am not using that characteristic...
And when I try to create a new variable, and specify that I want to use a SAP exit and enter the name '0DAT' I get a message in return that the name is already in use....
It seems to be a waste of space to add 0calday to my cube, just to be able to get the current date for my calculation...
So, suggestions would really help me:
How can I use the 'current day of the year' in a formula - preferably without addomg 0calday to my cube...

Hi Ansem,
The defalut 0DAT variable is charecterstic variable which you can't use it in formula(only formula variables can be used in formulas).
So, you need to create a new formula variable with customer exit procssing type. In the customer exit code you assign day of the year to the variable .
Then use this formula varibale in your formula in place of day of year.
If this helps to solve your problem, do not forget to assign points.
Regards
MB

Setting 'Day Month Year'.

The system pref. is set to 'Day-Month-Year' but iCal shows
'Month-Day-Year' how can this be changed

Welcome to the discussions, Edward. Have you quit and restarted iCal since setting the system pref?
AK

Converting date into day of year

I'm trying to write a program that prints the day of the year, given the date is in "month day year" form ie: 1 1 05, is day number 1 and 12 25 05 is day number 359.
the program should also check for a leap year.
I found this in a Google search and it's rediculously close to what i'm looking to achive, but instead of "today's date" i need it to read a day that was entered using Scanner or JOptionPane... and it would have to be in the above format when being entered.
import java.util.Calendar;
public class CalendarExample
public static void main(String[] args)
Calendar cal = Calendar.getInstance();
int day = cal.get(Calendar.DATE);
int month = cal.get(Calendar.MONTH) + 1;
int year = cal.get(Calendar.YEAR);
int dow = cal.get(Calendar.DAY_OF_WEEK);
int dom = cal.get(Calendar.DAY_OF_MONTH);
int doy = cal.get(Calendar.DAY_OF_YEAR);
System.out.println("Current Date: " + cal.getTime());
System.out.println("Day: " + day);
System.out.println("Month: " + month);
System.out.println("Year: " + year);
System.out.println("Day of Week: " + dow);
System.out.println("Day of Month: " + dom);
System.out.println("Day of Year: " + doy);
this if for a begining level java class, and I have no idea where to get started. Any help would be appreciated.

End result
import java.util.Scanner;
public class dayoftheYear
     public static void main(String[] args)
          //Declare variables
          int day, month, year, doy=0, Jan=31, Feb=28, Febleap=29, Mar=31;
          int Apr=30, May=31, Jun=30, Jul=31, Aug=31, Sep=30, Oct=31, Nov=30, Dec=31;
          //Description
          System.out.println("************************************************************");
          System.out.println("This application will"
                              + " use input for month and day "
                              + "\nto determine what day of the year "
                              + "it is. It will also check "
                              + "\nto see if it's a leap year and adjust "
                              + "\nthe day of the year accordingly");
          System.out.println("************************************************************");
          System.out.println();
          //Create a Scanner object to read input.
          Scanner keyboard = new Scanner(System.in);
          //Input and print number.
          System.out.print("Input month: ");
          //Assign input
          month = keyboard.nextInt();
          //Input and print number.
          System.out.print("Input day: ");
          //Assign input
          day = keyboard.nextInt();
          //Input and print number.
          System.out.print("Input year: ");
          //Assign input
          year = keyboard.nextInt();
          //If leapyear, Feb has 29 days
          if(isLeap(year)==1)
                    Feb =29;
          //Determine day of year
          switch (month)
                     case 1: doy=day; break;
                     case 2: doy=Jan+day; break;
                  case 3: doy=Jan+Feb+day; break;
                  case 4: doy=Jan+Feb+Mar+day; break;
                  case 5: doy=Jan+Feb+Mar+Apr+day; break;
                  case 6: doy=Jan+Feb+Mar+Apr+May+day; break;
                  case 7: doy=Jan+Feb+Mar+Apr+May+Jun+day; break;
                  case 8: doy=Jan+Feb+Mar+Apr+May+Jun+Jul+day; break;
                  case 9: doy=Jan+Feb+Mar+Apr+May+Jun+Jul+Aug+day; break;
                  case 10: doy=Jan+Feb+Mar+Apr+May+Jun+Jul+Aug+Sep+day; break;
                  case 11: doy=Jan+Feb+Mar+Apr+May+Jun+Jul+Aug+Sep+Oct+day; break;
                  case 12: doy=Jan+Feb+Mar+Apr+May+Jun+Jul+Aug+Sep+Oct+Nov+day; break; //hey! that looks pretty!
                  default: System.out.println("Invalid month.");break;
          //Print day of year
          System.out.println("Day of year: " +doy);
          }//endmain
          //beginmethod
          public static int isLeap(int y)
               //Assuming Y2K compliancy is not an issue, all dates will be based in the year 2000+
               y += 2000;
               //Check if year is a leap year
               if(y%4==0&&y%100!=0)
                    return 1;      //yes
               else if(y%100==0&&y%400==0)
                    return 1;     //yes
               else
                    return 0;     //no
          }//endmethod
}

Day/Month appearing as Day of Year/Month

When I look at dates displayed for Time Machine (right hand date bar) I notice they display as Wednesday, 132 May 2010 then Wednesday, 139 May 2010 etc. Is there a way to get back to the actual day/month/year format I specify for an Australian machine? I have noticed similar date displays within Software Update and iSync.

Thanks, the Region under Language and Text>Formats was listed as Custom. I changed it to Australia and this had rectified the problem when I Restarted and checked Time Machine.
Cheers Gavin

Days in Year Expression

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