Debugging with Visual Studio 6 (VC++) under Windows 7 64-bit-Version

I must develop some older applications (for some older customers) with VC++ (Visual Studio 6). My actual environment is Windows 7 in the 64-bit - version.
So, an old developement-environment on in a new world.
Now I have the problem, that everytime i close a debugging-session (with shift f5 or stop debugging by the corresponding menu-entry or any other keystrokes), the IDE tells me:  ".... myStupidExe.exe has exited with code (0)" but the corresponding console-windows stays, and stays, and stays and can't be killed either by itself nor by any process-tool (windows-task-manager, process-explorer e.g.).
Always first closing the IDE and than starting it again gives me new access to my "stupid.exe" and a new "stupid"-debugging-session.
Who is the name of the process, that takes the handle to my "stupid.exe" and lets a very normal vs60-debugging-process "alone" .
Can anybody help?

Hi,
I am not sure if for VS6 vs hosting process is available or not, but this sounds like it: the VS hosting process keeps  a handle on your exe and it keeps running on the machine
More details about VS hosting process here:
http://msdn.microsoft.com/en-us/library/ms185331(VS.80).aspx
To disable it, just go to Project Properties ->Debug tab  and uncheck the option “Enable the Visual Studio hosting process”.
hope that this helps,
Alina

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