Delete charaters from a string

Question

hi friends
i want to delete all the charaters after ".". for example 200.00 to 200
Regards

Answer 1

I'd write this differenly now, but here's my old String utilities class...
package krc.utilz;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
import java.util.List;
import java.util.ArrayList;
* Some handy String manipulation methods
public abstract class Stringz {
   * returns the given string with the characters in the opposite order.
   * @param string String - the string to reverse.
   * @return String backwards.
  public static String reverse(String string) {
    return new StringBuffer(string).reverse().toString();
   * Returns the given string with the first letter in uppercase. Note that
   * the case of the rest of the characters in the string remains unchanged.
  public static String capitalise(String string) {
    return string.substring(0,1).toUpperCase() + string.substring(1);
   * returns a string of howMany spaces, or optionally a string of howMany ch's
  public static String spaces(int howMany) {
    return spaces(howMany, ' ');
  public static String spaces(int howMany, char ch) {
    if (howMany <= 0) return "";
    char[] chars = new char[howMany];
    for(int i=0; i<howMany; i++) chars=ch;
return new String(chars);
* right pad string to width
* @param string String = the string to pad
* @param width int = the desired width of the string
* @return String the right-padded string.
* @deprecated - just use String.format("%-${width}s", string);
@Deprecated
public static String padRight(String string, int width) {
return String.format("%-"+width+"s", string);
//return string + spaces(width - string.length());
* left pad string to width
* @param string String = the string to pad
* @param width int = the desired width of the string
* @return String the left-padded string.
* @deprecated - just use String.format("%${width}s", string);
@Deprecated
public static String padLeft(String string, int width) {
return String.format("%"+width+"s", string);
//return spaces(width - string.length()) + string;
* find the first token in a string starting at start. think strpbrk.
* For example<code>
* String xml = "<tag attr="value">content</tag>"
* int x = firstOf(xml, " >");
* System.out.println(x>0 ? s.substring(1,x) : "UNKNOWN");
* </code>
* Produces:<code>tag</code>
* @param string String = the string to search
* @param tokens String = a logical array of chars to seek
* @param OPTIONAL start int = start searching string here
* @return the index of the fist occurence in string of the first found
* char in tokens, else (no tokens where found) returns -1;
public static int firstOf(String string, String tokens) {
for(int i=0; i<string.length(); i++) {
char ch = string.charAt(i);
for(char token : tokens.toCharArray()) {
if (ch==token) return i;
return -1;
public static int firstOf(String string, String tokens, int startIndex) {
return Stringz.firstOf(string.substring(startIndex), tokens);
* Returns the prefix of the given string which proceeds the first occurrence
* of any of the given tokens... optionally starting at the given startIndex.
* <p>
* For example<code>
* System.out.println(substring("<tag attr=\"value\">content</tag>", "< >"));
* </code>produces<code>tag</code>.
* @param string String - the string to search
* @param tokens String - a list of chars which serve as end markers
* @param start int - OPTIONAL start searching string here, 0 based.
* @return String string[start..token-1], else the empty string
public static String prefixOf(String string, String tokens) {
int end = Stringz.firstOf(string, tokens);
return end==-1 ? "" : string.substring(0,end);
public static String prefixOf(String string, String tokens, int startIndex) {
return(Stringz.prefixOf(string.substring(startIndex), tokens));
* Splits the given string into chunks of the given size.
* @param string String - The string to split up.
* @param size it - The size of each chunk.
public static String[] chunk(String string, int size) {
Pattern pattern = Pattern.compile(".{1," + size + "}");
Matcher matcher = pattern.matcher(string);
List<String> result = new ArrayList<String>();
while ( matcher.find() ) {
result.add(matcher.group());
return result.toArray(new String[result.size()]);
Edited by: corlettk on 3/08/2008 10:54 - gave up chasing dependencies - just post the whole class.