Derive YYYYMM from YYYYMMDD with formula variable replacement path

Dear All
For deriving month from date I tried the replacement path variable with the offset 0, length 6 (for YYYYMM). But the YYYYMM displayed as a number i.e. 200502 as 200,502. Tried to divided by 100. It still displayed as 2,005.02. Any idea how to let it as 200502?
Thanks, Jessica
Message was edited by:
jessica sheng

Actually, here's a quick example of a customer exit that I think does what you want (I did it here in this text, so you might need to debug):
        WHEN 'ZDAT_MTH'.
DATA: l_curdate like sy-datum.
*           Initialization
            CLEAR: l_calmonth, l_curdate.
*           Get calmonth from curdate
            CALL METHOD cl_rsar_function=>date_month
              EXPORTING
                i_curdate = l_curdate
              IMPORTING
                e_calmonth = l_calmonth.
*           Return calendar month
            CLEAR l_s_range.
            l_s_range-sign = 'I'.
            l_s_range-opt = 'EQ'.
            l_s_range-low = l_calmonth .
            APPEND l_s_range TO e_t_range.

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---Intros.
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Derive YYYYMM from YYYYMMDD with formula variable replacement path

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