Difference between 2 dates in form of years,months and days.

Question

Hi friends,
  i need one function module for finding difference between 2 dates and the output is
no. of years
no.of months
no. of days.
it means the input is begin date and end date
output is no.of years,no.of months and no.of days.
for example begin date is today i.e., 08/02/2008 (dd/mm/yyyy) and end date is 07/03/2008 then the output is
no.of years -
  0,
no.of months----
  1,
no.of days----
  0.
and one more example if begin date 08/02/2008
(dd/mm/yyyy) and end date is 01/02/2008 then the output is
no.of years -
0,
no.of months----
  0,
no.of days----
-7..
Please help me it's very urgent

Answer 1

Hi,
Use FM HR_AUPBS_MONTH_DAY.
It Calculate the years, months, days & cal days between 2 dates.
Hi,
The FM is 'FIMA_DAYS_AND_MONTHS_AND_YEARS'
Check the following example:
DATA: EDAYS LIKE VTBBEWE-ATAGE,
EMONTHS LIKE VTBBEWE-ATAGE,
EYEARS LIKE VTBBEWE-ATAGE.
PARAMETERS: FROMDATE LIKE VTBBEWE-DBERVON,
TODATE LIKE VTBBEWE-DBERBIS DEFAULT SY-DATUM.
call function 'FIMA_DAYS_AND_MONTHS_AND_YEARS'
exporting
i_date_from = FROMDATE
i_date_to = TODATE
I_FLG_SEPARATE = ' '
IMPORTING
E_DAYS = EDAYS
E_MONTHS = EMONTHS
E_YEARS = EYEARS.
WRITE:/ 'Difference in Days ', EDAYS.
WRITE:/ 'Difference in Months ', EMONTHS.
WRITE:/ 'Difference in Years ', EYEARS.
INITIALIZATION.
FROMDATE = SY-DATUM - 60.
Also You can write your own function module for this..
just extract day and month and year from the two dates and then get the difference.
suppose date 1 - y1m1d1
date 2 = y2m2d2
data : y1(2) type n,
m1(2) type n,
d1(2) type n,
y2(2) type n,
m2(2) type n,
d2(2) type n,
y1 = date1(4).
m1 = date1+4(2).
d1 = date1+6(2).
y2 = date2(4).
m2 = date2+4(2).
d2 = date2+6(2).
then get the differnce between years and days and months and store them in ur variables
Reward Points if found helpfull..
Cheers,
Chandra Sekhar.