How to get date difference in terms of years,months and also days

Tool : Eclipse
Framework : JSF & Springs
JRE : jdk1.5.0_06
Iam using oracle 10G DB as back end.I have two date fields in a table.
1)premium_paying_start_date
2)premium_paying_end_date
Iam getting these two dates from the database and storing these values within a entity.Now in the delegate layer,
i have to get the premium_term i.e, the difference between the two dates(premium_paying_end_date-premium_paying_start_date).
The difference should show the year,month and no of days difference.
For example :
premium_paying_start_date : 14-10-1984
premium_paying_end_date : 01-03-2008
Difference should be : 23 Y : 4 M : 15 D (Y = years, M = months , D= days)
So please give me the solution for this.

Difference should be : 23 Y : 4 M : 15 D (Y = years, M = months , D= days)
So please give me the solution for this.How did you determine what the difference should be?
~

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Convert two dates difference to number of years, months and days

Post Author: gigimonu
CA Forum: Formula
I wanted to write a formula (if there is a function I can use) that can convert a date difference to total number of years, months and days example
adate = 10/22/2006
?xdate = current date - adate (answer should be 1 years, 0 months and 0 days)
Please help
Thanks

Post Author: V361
CA Forum: Formula
[Years, Months, Days]
DATEVAR FROMDATE := DATE(2000,01,01); // FROM DATE
DATEVAR TODATE := CURRENTDATE; // TO DATE
NUMBERVAR YEARS;
NUMBERVAR MONTHS;
NUMBERVAR DAYS;
STRINGVAR DIFF;
DATEVAR TEMP;
IF TODATE < FROMDATE THEN
(TEMP := TODATE;
TODATE := FROMDATE;
FROMDATE := TEMP);
YEARS := DATEDIFF('YYYY',FROMDATE,TODATE);
IF YEARS > 2 THEN
(YEARS := YEARS - 2;
TEMP := DATE(DATEADD("M",YEARS * 12,FROMDATE));)
ELSE
(YEARS := 0;
TEMP := FROMDATE);
WHILE TRUE DO
(TEMP := DATE(DATEADD('M',1,TEMP));
IF TEMP > TODATE THEN
EXIT WHILE;
MONTHS := MONTHS + 1);
DAYS := DATEDIFF('D',DATE(DATEADD('M',-1,TEMP)),TODATE);
IF MONTHS > 12 THEN
(YEARS := YEARS + INT(MONTHS/12);
MONTHS := MONTHS MOD 12);
DIFF := IIF(YEARS>0 ,TRIM(TOTEXT(YEARS,0)) & " YEARS " ,"0 YEARS ") &
IIF(MONTHS>0,TRIM(TOTEXT(MONTHS,0))& " MONTHS ","0 MONTHS ")&
IIF(DAYS>0 ,TRIM(TOTEXT(DAYS,0)) & " DAYS" ,"0 DAYS");

How to convert days to years, months and remaining days

Hi All,
I have the number of days for example : 398 days how to
convert 398 days to number of years and number of months and remaining days
like 398 days 1 year , 1 month and 2 days
Regards
rkrao

e.g.
SQL> select sysdate, sysdate - 1234 from dual
2 /
SYSDATE   SYSDATE-1
09-AUG-06 24-MAR-03
SQL> select trunc(trunc(months_between (sysdate, sysdate - 1234))/12) yrs,
2 mod(trunc(months_between(sysdate, sysdate - 1234)), 12) mnths,
3 sysdate - add_months((sysdate - 1234), trunc(months_between(sysdate, sysdate - 1234))) dys
4 from dual
5 /
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SQL>

How to get date difference in data sources

Hi,
In SQL:SELECT DATEDIFF(day, '2005-12-30 23:59:59.9999999', '2005-12-30 00:00:00.0000000');
output :1
As similar way how get the datediffence in SAP business by design of the datasources.
Regards,
Prasad

Hi Prasad,
For this you have to create a Custom DATA SOURCE for the required BO. Then Select all the required fields that you want to use it in the report for that datasource.
The 3rd step of Data Source Wizard is shown in the image, here you can add a extra field that can hold the difference between the DateTime elements present in the BO.
In the left column BUSINESS OBJECT ELEMENT choose DATE element (1st Date).
In the right column TRANSFORMATION choose DateTime To Duration row and in the PARAMETER Column choose the field against which you want to calculate the difference.
In Defined Field Name enter a name, this will hold the value of the calculated difference.
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Shabaz

How to get Date Difference in Query with Replacement Path !

I need to get nr of days between two days. I knew that we can do this by replacement path in the queries. But when Iam trying to use replacement path with
this two chars and put it in a formula the result is not showing correctly.
Eg: I have dates Date1, Date 2 and I created two variables calles DateA ,Date B with reference to Date1 and Date2.
Now Iam creating a formula sayint that (Date2 <> 0) * (Date1 - Date2) ...Here Date2 has sometimes balnk value...Iam getting the values when there is dates for both chars...But if there is one value is blank
then Iam getting a strange value ....
can any body send me step by step on how to fix this...
Thanks

Hi Sam,
another important think you have to remember when having aggregated information is to divide the date1 and date2 key figures with the number of lines used in aggregation.
Remember that date1 (internally) is a numerical value from some initial date which is used as reference. E.g., if the reference date is 01/01/0001 and you have the date 15/01/0001 then key fig. date1 internally stores just the value 14. So if you have something like:
                         date1       date2        diff
customer1 material1       14          18           4 <- correct
customer2 material1       14          18           4 <- correct
and then you make an aggregation by removing customer from your report then you will have the following situation:
                         date1       date2        diff
material1                  28          36           8    <- wrong
So, you would have to divide by 2 in the second case. Please try to check the above and proceed accordingly. Let us now if something else weird appears.
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How to get data occured on less than 12 months gap, please

Hello Good Afternoon,
How can i get ssns that are occured in less than 12 month period
create table #mytemp (SSN varchar(9), planID vcarchar(8), period varchar(7))
Insert Into #mytemp values ('123456789', '200R1','2013-04')
Insert Into #mytemp values ('123456789', '200R5','2014-09')
Insert Into #mytemp values ('123456789', '200R1','2012-05')
Insert Into #mytemp values ('123456789', '200R3','2013-11')
Insert Into #mytemp values ('123456789', '200R1','2014-01')
Insert Into #mytemp values ('213456789', '400R1','2014-04')
Insert Into #mytemp values ('213456789', '400R5','2014-09')
Insert Into #mytemp values ('213456789', '400R1','2013-05')
Insert Into #mytemp values ('213456786', '700R5','2014-05')
Insert Into #mytemp values ('213456786', '400R1','2013-05')
Insert Into #mytemp values ('215556786', '400P1','2013-05')
i am trying to get the below two results
1) How to find out the duplicate SSN's that were having period of less than 12 month difference
2) How to find out the duplicate SSN's that were having period of less than 12 month difference with same planID
Please Help me
expected results for Query 1
create table #ans1 (SSN varchar(9))
Insert Into #ans1 values ('123456789') --- had more than one record in 12 month span
Insert Into #ans1 values ('213456789') -- had more than one record in 12 month span
expected results for Query 2
create table #ans2 (SSN varchar(9))
Insert Into #ans2 values ('123456789') --- had more than one record in 12 month span for plan 200R1
Please help me here with your valuable advise
Thank you in Advance
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1) How to find out the duplicate SSN's that were having period of less than 12 month difference
2) How to find out the duplicate SSN's that were having period of less than 12 month difference with same planID
Below is one method. The second query also returns '213456789' because your sample data has more than one row for planID 400R1 within 12 months.
SELECT DISTINCT
a.SSN
FROM #mytemp AS a
WHERE EXISTS ( SELECT *
FROM #mytemp AS b
WHERE b.SSN = a.SSN
AND CAST(b.period + '-01' AS date) > CAST(a.period
+ '-01' AS date)
AND CAST(b.period + '-01' AS date) < DATEADD(YEAR, 1,
CAST(a.period
+ '-01' AS date)) );
SELECT DISTINCT
a.SSN
FROM #mytemp AS a
WHERE EXISTS ( SELECT *
FROM #mytemp AS b
WHERE b.SSN = a.SSN
AND b.planID = a.planID
AND CAST(b.period + '-01' AS date) > CAST(a.period
+ '-01' AS date)
AND CAST(b.period + '-01' AS date) < DATEADD(YEAR, 1,
CAST(a.period
+ '-01' AS date)) );
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Hello Please.,
i would like to see the 2014-06 matched results (3rd query),
if the same ssn and acctno is exist in 2012-06 and 2013-06 and 2014-06 then eliminate from results, otherwise show it
select ssn, acctno From jnj.drgSamples where Channel ='KM' and TrailMonth ='2012-06'
select ssn, acctno From jnj.drgSamples where Channel ='KM' and TrailMonth ='2013-06'
select ssn, acctno From jnj.drgSamples where Channel ='KM' and TrailMonth ='2014-06'
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Please Help me with this
Thank you very much in Advance
Asitti

This is a relational division problem T-SQL:
Relational Division
Try:
;with cte as (select ssn, acctno, count (distinct(TrailMonth)) as cntMonths
from jnj.drgSamples WHERE Channel = 'KM' AND TrailMonth IN ('2012-06','2013-06',2014-06'))
GROUP BY ssn, acctno)
delete from jnj.drgSamples S where exists (select 1 from cte where S.ssn = cte.ssn and S.acctno = cte.acctno and cte.cntMonths = 3)
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How to get the difference of two dates in years,months and days

Hi friends,
how to get the difference of two dates in years,months and days
for ex 2 years 3 months 13 days
select (sysdate-date_Start) from per_periods_of_service
thanks

Something like this...
SQL> ed
Wrote file afiedt.buf
1 with t as (select to_date('17-nov-2006','dd-mon-yyyy') as c_start_date, to_date('21-jan-2008','dd-mon-yyyy') as c_end_date from dual union all
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How to get the difference of two dates?

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60 for the 2nd row.

ooops i tried this one:
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hehehehe!!!!!!
problem solved! :)

Get Date Difference between 2 date values as days

Hi,
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Hi,
You can do it in XSLT since the dates are in ISO 8601 format...
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http://xslttest.appspot.com/
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It is considered good etiquette to reward answerers with points (as "helpful" - 5 pts - or "correct" - 10pts)
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How to get date difference in terms of years,months and also days

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