Display file except 1st character of each line

I'm looking to display the contents of a file, ignoring the 1st character of each line.
Can anyone point me in the right direction, please?

The Advanced Bash Scripting document (in [HTML|http://tldp.org/LDP/abs/html] or [PDF|http://tldp.org/LDP/abs/abs-guide.pdf]) would be a good resource for your quest. This document is not specific to Mac OS X, but it's a very good resource and with a wealth of examples.
The O'Reilly +Learning the bash Shell, 3rd Ed+ book is also a good resource and the O'Reilly +Bash Cookbook+ book would seem well-suited for how you approach your postings.

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Can We Display Image on Hieararichal Report on Each Line item

Dear Gurus ,
I have a Strange Requirement from the Client . They want to display Image on each line item of report with regard to Material in Hierarchal Sequential Report . Is there any solution for the same .
Thanks in advance
regards
Shankar

I am having a path which is stored in SAP database which i have fetched in the reported in both alv heriarchal and also in Alv Grid . The Image is stored from DMS . Now what i am doing is i am trying to load a excel file from program BCALV_BDS_UPLOAD and when i run my report and go to view and select Microsoft Excel option the I am getting an error Bad file format .
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Loading Hex Files with multiple records with each line starting with : record marker, how do I load this hex file into a front panel table ? thanks in advance, Jeff.

I have written a routine that loads a Hex file, checks for record marker,length,address etc then loads the data into a table on front panel. However, my routine only loads single record hex files. I need to be able to load multiple record files, I need to identify the ':' colon record marker start for each record in the hex file, I just can't see how to loop my routine so that all records with ':' prefix marker are loaded.

Jeff,
I'm not exactly sure of what you are trying to do. Is it possible you could post your code, or a screen shot of the diagram in question, so that I can get a better understanding, and possibly offer some assistance?
I am familiar with hex files, but not with the : marker separating records. This may be able to be solved with simple text parsing, and as I am not familiar with how you are retrieving and/or displaying the files, I require more information.
Thanks

How to find a specific word in sentence in each line?

How to find a specific word in sentence in each line and output will show start from the beginning from specific word plus with small description from each sentence?
For example: I need to find a "+Wednesday+" and "+Thursday+" word in each sentence by line by line from "myfile.txt".
Go ballet class next Wednesday.
On the Wednesday is going to swim class.
We have a meeting on Thursday at Panda's.
Then it will show the output:
Wednesday : ballet class
Wednesday : swim class
Thursday: meeting at Panda's
I am going to figure out in Java console to read from a file for specific word from each line and how to make it output in correct way. I know already to make input/file codes.

I got it and understand much better. Thank you very much. There is a problem with it because I knew how to make
a specific word in sentence but how I should make Output for specific word and some words from sentence.
For example:
Input:
+"On Thursday go to ballet class"+
+"Swim class on Friday one time a month at 2 p.m."+
I used the codes for that:
class FindSchedule{
     String firstline = "On Thursday go to ballet class ";
     String secondline = "Swim class on Friday one time a month ";
     FindSchedule(){
          System.out.println(firstline + findTheIndex("Thursday", firstline));
          System.out.println(secondline + findTheIndex("Friday", secondline));
     public int findTheIndex(String word, String sentence){
          int index;
          index = sentence.indexOf(word);
          return index;
     public static void main (String[] args){
          new FindSchedule();
}The output will be:
Thursday: ballet class
Friday: 14:00 swim class one time a week
Notice that time is changing in output complete different from input.
I need to find out how to extract some words from each sentence for output. Do you know how to do it?

How to delete a character at the end of each line in a file

Hi
How to remove a character or symbol at the end of each line in a file?
I am having a file with every end of line conatins special chars @.
I need to remove or delete that sysmbol from file.
Regards

JoeBorland wrote:
File is large about above 20,000 lines.
I need to find the optimum solution.
Like reading a file and find the end of character and writing into a file.
The above way is correct or any other way?Try it and see. Such a program will only be a dozen lines long.

Program cutting off 1st character in file

Hi I have this weird problem.
My problem takes a file read it and places in into a JTable. It seems that during the read, the 1st character gets chopped off.
public class Main {
    //Variable declarations
    private JFrame f;
    private JPanel p;
    private JLabel lengthLabel, partitionLabel, ladderLabel;
    private JTextField lengthTF, partitionTF;
    private JComboBox ladderLB;
    private JTable table;
    public Main() {
        createTable();
        createPanel();
        createAndShowGUI();
    private void createAndShowGUI() {
        f = new JFrame("Calculate MW");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        f.add(p);
        //f.setSize(250, 400);
        f.setSize(400, 400);
        f.setResizable(false);
        f.setVisible(true);
    private void createPanel() {
        p = new JPanel(new BorderLayout());
        p.add(table.getTableHeader(), BorderLayout.PAGE_START); // Set the table header
        p.add(table, BorderLayout.CENTER);
    private void createTable() {
        // Variables
        String[] colNames = {"One", "Two", "Line"};
        String[][] data = new String[3][30];
        data = getLadder(new File("ladder.txt"));
        table = new JTable(data, colNames);
        JScrollPane sp = new JScrollPane(table);
        // Set 1 column uneditable
        JTextField tf = new JTextField();
        tf.setEditable(false);
        TableColumn distCol = table.getColumnModel().getColumn(0);
        distCol.setCellEditor(new DefaultCellEditor(tf));
        distCol.setCellRenderer(null);
        // Setup table
        table.setColumnSelectionAllowed(false);
        table.getTableHeader().setResizingAllowed(false);
        table.getTableHeader().setReorderingAllowed(false);
        table.setRowSelectionAllowed(false);
    private String[][] getLadder(File file) {
        String[][] sa = new String[30][3];
        try {
            BufferedReader reader = new BufferedReader(
                    new FileReader(file));
            reader.read();
            String line;
            String [] temp;
            int x = 0;
            while ((line = reader.readLine()) != null) {
                if (line.length() > 0) {
                    temp = line.split("\\t");
                    sa[x][0] = temp[0];
                    sa[x][1] = temp[1];
                    sa[x][2] = line;
                    x++;
        catch (IOException e) {
            System.out.println(e.getStackTrace());
            System.out.println(e.getMessage());
        return sa;
    public static void main(String[] args) {
        Main black = new Main();
    }This is the input file:
220     2.1
160     2.7
120     3.4
100     3.75
90     3.95
80     4.35
70     4.85
60     5.3
50     6.15
40     7.2
30     8.45
25     9.25
20     10.0
15     11.5
10     12.95What appears on the 1st row in the JTable is
20     2.1     20 2.1The 1st character was removed. Anyone can help or know what is wrong?
Desmond

        try {
            BufferedReader reader = new BufferedReader(
                    new FileReader(file));
            reader.read();   // <----- Your problem is right here. Why are you doing this?
            String line;
            String [] temp;
            int x = 0;
            while ((line = reader.readLine()) != null) {
                if (line.length() > 0) {
                    temp = line.split("\\t");
                    sa[x][0] = temp[0];
                    sa[x][1] = temp[1];
                    sa[x][2] = line;
                    x++;
        }

Adding a pipe character '|' at the end of each line

How can I add a '|' at the end of each line in a text file?
Please provide an example.
TIA

Using Readers and Writers are often a better choice for text: they are designed for character-based I/O, handling different character set encodings and thus more easily localizable.
BufferedReader and PrintWriter are buffered which in many cases will increase performance.
These classes also provide line-oriented methods, readLine() and println(), which will handle end-of-line delimiters in a platform-independant way.
BufferedReader in = null ;
PrintWriter out = null ;
try {
    in = new BufferedReader(new FileReader("infile.txt")) ;
    out = new PrintWriter(new FileWriter("outfile.txt")) ;
    String line ;
    while ((line = in.readLine()) != null) {
        out.print(line) ;
        out.println('|') ;
    out.flush() ;
} catch (FileNotFoundException e) {
    System.err.println("problem opening file for read: "+e) ;
} catch (IOException e) {
    System.err.println("problem reading file: "+e) ;
} finally {
    try {
        if (out != null) out.close() ;
        if (in != null) in.close() ;
    } catch (IOException e) {
        System.err.println("problem closing files: "+e) ;
}

Reg. Special Character at end of each line

Hello Experts,
I have an internal table of type string which has to be uploaded into the directories
Each line has to be ended with a comma and for which I concatenated the work area and ',' before appending to the internal table. This is fine till this point.
After downloading the file from the directory, when opened with a notepad, i could see a special character (LINE FEED rectangular box) at the end of each line.
I couldn't understand why this character got appended at the end of each record. Pl suggest me on how i can overcome this special character.
Thanks
RK

Hi,
I am developing one HRMS report for sending salaries to bank. Bank has given one format, there should be 24 spaces at the end of each line in the report. But I am not getting any spaces in the report at the end of line. I have tried soo many ways to get that, but I unable to get spaces. If I put any character it is coming, but if I put space that is not coming. For the line that is set the height of the Repeating Frame long enough to have the blank space. Vertical Elasticity should be expand.
Also you can try by setting the property *"Vert. Space between frames"* for the Repeating frame.
Hope this helps.
Best Regards
Arif Khadas

How would you read in each line of data and display them to message box?

How would you read in each line of data from the _.txt file_ and display the whole data using an information-type message box?
I know how to display each line of the .txt file data, but I do not know how to display the whole thing.
Here is how I did to display each line of data using the message box:
import javax.swing.JOptionPane;          // Needed for the JOptionPane class
import java.io.*;                         // Needed for file classes
public class problem3
     public static void main(String[] args) throws IOException
          String filename;          // Needed to read the file
          String categories;          // Needed to read the categories
          // Get the filename.
          filename = JOptionPane.showInputDialog("Enter the filname.");
          // Open the file.
          FileReader freader = new FileReader(filename);
          BufferedReader inputFile = new BufferedReader(freader);
          // Read the categories from the file.
          categories = inputFile.readLine();
          // If a category was read, display it and
          // read the remainig categories.
          while(categories != null)
               // Display the last category read.
               JOptionPane.showMessageDialog(categories);
               // Read the next category.
               categories = inputFile.readLine();
          // Close the file.
          inputFile.close();
}I think I need to change here:
// If a category was read, display it and
          // read the remainig categories.
          while(categories != null)
               // Display the last category read.
               JOptionPane.showMessageDialog(categories);
               // Read the next category.
               categories = inputFile.readLine();
          }but I don't know how to.
Could you please help me?
Thank you.

kyorochan wrote:
jverd wrote:
What is not understood about your question is which part of "read a bunch of lines and display them in a textbox" do you not understand.
First thing's first though: You do recognize that "read a bunch of lines and display them in a textbox" has a few distinct and completely independent parts, right?I'm sorry. I'm not good at English, so I do not understand what you said...
What I was trying to say is "How to display the whole lines of .txt file in single dialog box."We know that.
Do you understand that any problem can be broken down into smaller pieces?
Do you understand that your problem has the following pieces?
1. Read lines from the file.
2. Put the lines together into one String.
3. Put the String into the message box.
and maybe
4. Make sure the message box contents are split into lines exactly as the file was.
(You didn't make it clear if that last one is a requirement.)
Do you understand that 1-4 are completely independent problems and can be solved separately from each other?
Do you understand that you have stated that you already know how to do 1 and 3?
Therefore, you are NOT asking "How to display the whole lines of .txt file in single dialog box." Rather, you ARE asking either #2 or #4 or both.
If you say once more "display all the lines of the file in one dialog box," then it is clear that we are unable to communicate with you and we cannot help you.

Find files that match with given string, except one character in a fixed position

Hi,
I want to find files in a directory with a given string (ss-20140129-process-000*.sdx), where only one character will be mismatched, so have to use wildcard for that character. This means I am looking for filenames where everything needs to be matched except
one character in position of "*". For the samples given below: 1st 3 files matched with the given string, but last 3 files have not matched, so first 3 files will be counted.
ss-20140129-process-0001.sdx
ss-20140129-process-0004.sdx
ss-20140129-process-0009.sdx
zx-20140129-process-0001.sdx
bt-20140129-process-0002.sdx
zx-20140129-process-0001.sdx
I can use the command like (GCI -path $folder -filter ss-20140129-process-000?.sdx), BUT problem is i am building a string for the filter (code given below), where i DO NOT know how to use "?" within the string to make a character exception.
Code:
$datevalue = [datetime]::parseexact($trandate,"MMddyy",$null)
$yyyymmdd = $datevalue.tostring('yyyyMMdd')
$FileToCheck = ("ss-"+$yyyymmdd+"-process-000?.sdx")
GCI -path $folder -filter $FileToCheck
But it's definitely NOT working for syntax problem.
Any help?

I don't think it's a syntax issue in the filter. This works fine for me:
$yyyymmdd = '20140129'
$FileToCheck = ("ss-"+$yyyymmdd+"-process-000?.sdx")
Get-ChildItem -Path . -Filter $FileToCheck
<#
Output:
Directory: C:\source\Temp\sdxtext
Mode LastWriteTime Length Name
-a--- 1/30/2014 10:16 AM 0 ss-20140129-process-0001.sdx
-a--- 1/30/2014 10:16 AM 0 ss-20140129-process-0004.sdx
-a--- 1/30/2014 10:16 AM 0 ss-20140129-process-0009.sdx
#>
You can try adding some debug output right before the call to Get-ChildItem. Check the values of $Folder and $FileToCheck, make sure they're correct. You can also fiddle with the values and call Get-ChildItem manually until it works, which would then tell you
how the code needs to be changed.

Display Purchase order, PO Item , Order Number ,entry sheet quantity ,entry sheet price ,invoice quantity, invoice price against each line number

hello all,
i have an ALV report requirement like this,
on the initial screen i have displayed(for a given agreement number like in ME33K )
in the selection screen i have taken agreement number as EKPO-EBELN.
purchase document number        item number        short text        target quantity      net price
5400000019                                  1                      xxx                  1.000                  304300.00
                                                    2                     xxxx                 1.000                  500000.00
the above fields i have taken from EKPO table.....
and on double clicking the item number i have displayed
line number          service number       short text           quantity    units    gross price   quantity released
1                           swr10                   xxxx                 2.00          kg          500             2
2                           swr11                    xxxx                5.00          EA         500             2
the above fields i have taken from ESLL (esll-extrow, esll-srvpos, esll-ktext1 , esll-menge etc......)
this i have done by passing EBELN to ESLH and getting PACKNO and passed this PACKNO to ESLL.
now my question is i need to display Purchase order, PO Item , Order Number ,entry sheet quantity ,entry sheet price ,invoice quantity, invoice price
against each line number above.....
from which table do i need to take these fields.....
please guide me....
thankq....

Thanks Andra,
The problem is the multiple invoices is for non goods receipt item so there will be no delivery.At the time of creating a PO the GR is not checked so there will be no delivery .
Also this setting is for invoices which are comming from Vendors.But if we are genrating the invoices manually it is not blocking those invoices.Also i there is nowhere mentioned in Incomming invoice to set tolerence for incomming invoice.Are you talking about Vendor tolerences?
Thanks in advance
Edited by: Metroid01 on May 14, 2009 6:52 PM

Read the first word of each line in a text file

i need to read the first word of each line of a text file.
i know of line.split() but not actually sure how i would go about using it
Any help most appreciated
Many Thanks
Ben

Hi thanks for the reply!
this is what i tried... and it still doesn't get me the first word of each line!
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
import java.awt.Color;
import java.awt.event.ActionEvent;
import java.io.*;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import javax.swing.text.*;
import javax.swing.event.*;
import java.util.Calendar;
import java.util.Scanner;
import java.util.Vector;
import java.text.SimpleDateFormat;
import java.net.InetAddress;
import java.net.UnknownHostException;
import java.io.BufferedReader;
public class testing {
     Vector progs=new Vector();
     Vector rand=new Vector();
     String[] tmp = new String [2];
     String str;
     String str2="ewerwer";
     String str3;
     public void programTest()
               try
                         BufferedReader in = new BufferedReader(new FileReader("progList.log"));
                         while ((str = in.readLine()) != null)
                              progs.add(str);
                    catch(IOException e)
                         System.out.println("cannot read file");
     //////THE ISSUES IS HERE....I WANT TO GET THE FIRST WORD FROM EACH LINE OF THE FILE!!!
          try
                         BufferedReader in2 = new BufferedReader(new FileReader("eventLog.log"));
                         while ((str = in2.readLine()) != null)
                              tmp = str.split(" ");
                              System.out.println(tmp[0]);
                    catch(IOException e)
                         System.out.println("cannot read file");
public static void main(String[] args)
             testing B = new testing();
             B.programTest();
           // B.fileToVector();
             //B.LoginWindow();
           //B.anomDetect();
}//end class

PI 7.1 Receiver file adapter - Spaces are truncated at end of each line

In Receiver file adapter, I specified file content conversion parameters. My file structure is as below:
Header
Field1 10
Field2 20
Field3 8
Filler   20
Detail
Field1 10
Field2 8
Filler    8
In both Header and Details structures I have to fill 20 and 8 spaces at end of each line. In XML (Payload) I can view the spaces. But when the text file is created all the spaces are truncated.
Could you please solve this issue.
Regards

Recordset Structure: ns1:MT_SAP,REC,Header,Detail
ns1:MT_SAP.fieldSeparator          '0'
ns1:MT_SAP_PNC_PPAY.fieldContentFormatting     nothing
REC.fieldContentFormatting          nothing
REC.fieldSeparator               '0'
REC.processConfiguration               FromConfiguration
Header.fieldFixedLengths               10,20,8,20
Header.endSeparator               'nl'
Header.fixedLengthTooShortHandling          Ignore
Header.fieldNames               Field1,Field2,Field3,Filler
Header.fieldContentFormatting          nothing
Detail.fieldFixedLengths               10,8,8
Detail.endSeparator               'nl'
Detail.fieldNames               Field1,Field2,Filler
Detail.fieldContentFormatting          nothing
Detail.fixedLengthTooShortHandling          Ignore

Creating a JButton for each line in a txt file

I need to know how to creating a JButton for each line in a txt file then add an actionListener to the number of buttons (note they are in a JTable). Here is a clipet of code thanx for the help (note that this is one part of a program i am making there are 2 more classes. If u need them just ask) Thanx:
class Diary extends JFrame implements ActionListener {
     private JTextArea note;
     private JTextField name;
     private JMenuBar menu = new JMenuBar();
     private JMenu file, edit, font, background, tcolor, settings, help;
     private JMenuItem nu, copy, paste, save, exit, b8, b10, b12, b14, b16, b18, b20, b24, b30, bblue, bred, bgreen, bpink, cblue, cred, cgreen, cpink, eset, nver, using, about;
     private String[] columnNames = {
          "File"
     private Vector dat = new Vector();
     private JTable filetable;
     public Diary() {
          setSize(new Dimension(500, 500));
          setTitle("Diary 2.00");
          file = new JMenu("File");
          menu.add(file);
          nu = new JMenuItem("new");
          nu.addActionListener(this);
          file.add(nu);
          file.add(new JSeparator());
          copy = new JMenuItem("copy");
          copy.addActionListener(this);
          file.add(copy);
          paste = new JMenuItem("paste");
          paste.addActionListener(this);
          file.add(paste);
          file.add(new JSeparator());
          save = new JMenuItem("Save");
          save.addActionListener(this);
          file.add(save);
          file.add(new JSeparator());
          exit = new JMenuItem("exit");
          exit.addActionListener(this);
          file.add(exit);
          edit = new JMenu("Edit");
          menu.add(edit);
          font = new JMenu("font");
          edit.add(font);
          b8 = new JMenuItem("8");
          b8.addActionListener(this);
          font.add(b8);
          b10 = new JMenuItem("10");
          b10.addActionListener(this);
          font.add(b10);
          b12 = new JMenuItem("12");
          b12.addActionListener(this);
          font.add(b12);
          b14 = new JMenuItem("14");
          b14.addActionListener(this);
          font.add(b14);
          b16 = new JMenuItem("16");
          b16.addActionListener(this);
          font.add(b16);
          b18 = new JMenuItem("18");
          b18.addActionListener(this);
          font.add(b18);
          b20 = new JMenuItem("20");
          b20.addActionListener(this);
          font.add(b20);
          b24 = new JMenuItem("24");
          b24.addActionListener(this);
          font.add(b24);
          b30 = new JMenuItem("30");
          b30.addActionListener(this);
          font.add(b30);
          background = new JMenu("background");
          edit.add(background);
          bblue = new JMenuItem("blue");
          bblue.addActionListener(this);
          background.add(bblue);
          bred = new JMenuItem("red");
          bred.addActionListener(this);
          background.add(bred);
          bgreen = new JMenuItem("green");
          bgreen.addActionListener(this);
          background.add(bgreen);
          bpink = new JMenuItem("pink");
          bpink.addActionListener(this);
          background.add(bpink);
          tcolor = new JMenu("text color");
          edit.add(tcolor);
          cblue = new JMenuItem("blue");
          cblue.addActionListener(this);
          tcolor.add(cblue);
          cred = new JMenuItem("red");
          cred.addActionListener(this);
          tcolor.add(cred);
          cgreen = new JMenuItem("green");
          cgreen.addActionListener(this);
          tcolor.add(cgreen);
          cpink = new JMenuItem("pink");
          cpink.addActionListener(this);
          tcolor.add(cpink);
          settings = new JMenu("Settings");
          menu.add(settings);
          eset = new JMenuItem("Edit Settings");
          eset.addActionListener(this);
          settings.add(eset);
          help = new JMenu("Help");
          menu.add(help);
          using = new JMenuItem("Using");
          using.addActionListener(this);
          help.add(using);
          about = new JMenuItem("About");
          about.addActionListener(this);
          help.add(about);
          help.add(new JSeparator());
          nver = new JMenuItem("new Versions");
          nver.addActionListener(this);
          help.add(nver);
          note = new JTextArea("");
          try {
               BufferedReader filein = new BufferedReader(new FileReader("files.txt"));
               String sfile;
               while ((sfile = filein.readLine()) != null) {
                    //add buttons per each line of the txt file and show em
          catch (FileNotFoundException ioe) {
               JOptionPane.showMessageDialog(null, "Iternal Error, contact [email protected] if the error persists", "", JOptionPane.WARNING_MESSAGE);
          catch (IOException ioe) {
               JOptionPane.showMessageDialog(null, "Iternal Error, contact [email protected] if the error persists", "", JOptionPane.WARNING_MESSAGE);JOptionPane.showMessageDialog(null, "Iternal Error, contact [email protected] if the error persists", "", JOptionPane.WARNING_MESSAGE);
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          for (int x = 0; x < dat.size(); x++) {
               data[x] = (String[])dat.get(x);
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          filetable.setPreferredScrollableViewportSize(new Dimension(100, 500));
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          name = new JTextField("diary");
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               if (nuask == JOptionPane.YES_OPTION) {
                    note.setText("");
                    note.setBackground(Color.WHITE);
                    note.setForeground(Color.BLACK);
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               note.copy();
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               note.paste();
          if (e.getSource() == save) {
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                setTitle("Diary 1.00 : " + sn);
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                 System.out.println("IOException");
          if (e.getSource() == exit) {
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               if (exitask == JOptionPane.YES_OPTION) {
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          if (e.getSource() == b8) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),8));
          if (e.getSource() == b10) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),10));
          if (e.getSource() == b12) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),12));
          if (e.getSource() == b14) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),14));
          if (e.getSource() == b18) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),18));
          if (e.getSource() == b20) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),20));
          if (e.getSource() == b24) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),24));
          if (e.getSource() == b30) {
               note.setFont(new Font(note.getFont().getName(),note.getFont().getStyle(),30));
          if (e.getSource() == bblue) {
               note.setBackground(Color.BLUE);
          if (e.getSource() == bred) {
               note.setBackground(Color.RED);
          if (e.getSource() == bgreen) {
               note.setBackground(Color.GREEN);
          if (e.getSource() == bpink) {
               note.setBackground(Color.PINK);
          if (e.getSource() == cblue) {
               note.setForeground(Color.BLUE);
          if (e.getSource() == cred) {
               note.setForeground(Color.RED);
          if (e.getSource() == cgreen) {
               note.setForeground(Color.GREEN);
          if (e.getSource() == cpink) {
               note.setForeground(Color.PINK);
          if (e.getSource() == eset) {
               new UserSettings().setVisible(true);
          if (e.getSource() == about) {
               JOptionPane.showMessageDialog(null, "Created by Collin Doering 2005 in Gr.9\n\nErrors:\n------------------------------------------------------------------\n1. No File Encryption\n2. No user and password Encryption", "", JOptionPane.INFORMATION_MESSAGE );
          if (e.getSource() == nver) {
               JOptionPane.showMessageDialog(null, "New Version |3.00| expected July, 2005\n\nNew Features\n----------------------------------------------\n1. File Encryption\n2. User File Encryption\n3. Full help dialog\n4. More Text changing features", "", JOptionPane.INFORMATION_MESSAGE);
          if (e.getSource() == using) {
               JOptionPane.showMessageDialog(null, "Go ask Collin Doering\[email protected]", "", JOptionPane.INFORMATION_MESSAGE );
THANK YOU

so i still do not understand how i would create one
button per each line in a txt flle then read in the
file that the txt file specified.This assumes you know how many lines there are in the file.
If not, modify as per my prior post
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
class Testing extends JFrame
String[] linesInFile = {"Hello","World","Goodbye","Now"};
JButton[] btn = new JButton[linesInFile.length];
public Testing()
    setLocation(200,200);
    setDefaultCloseOperation(EXIT_ON_CLOSE);
    JPanel jp = new JPanel(new GridLayout(0,1));
    for(int x = 0; x < btn.length; x++)
      btn[x] = new JButton(linesInFile[x]);//<---this would be where file.readLine() goes
      jp.add(btn[x]);
      btn[x].addActionListener(new ActionListener(){
        public void actionPerformed(ActionEvent ae){
          JOptionPane.showMessageDialog(getContentPane(),ae.getActionCommand());}});
    getContentPane().add(jp);
    pack();
public static void main(String[] args){new Testing().setVisible(true);}
}

Java write/append to each line of a text file

I have spent numerous hours trying to figure out what I am doing wrong. If anyone more experienced could tell me what is wrong with my code.
I have a very simple text file with 5 lines:
line1
line2
line3
line4
line5
All I am trying to do is append some string to the end of each of those lines. Everytime I run my code, it erases all content but does not write/append anything to the file. Any help is greatly appreciated.
Thanks! I am about to throw this monitor out the window!!
package Chapter6;
import java.io.*;
public class fileNavigation2 {
     public static void main(String[] args) {
          File dir = new File("C:\\testing");
          System.out.println(dir.isDirectory());
          try {
               File file = new File(dir, "Test.txt");
               FileReader fr = new FileReader(file);
               BufferedReader br = new BufferedReader(fr);
               FileWriter fw = new FileWriter(file);
               BufferedWriter bw = new BufferedWriter(fw);
               String s = "Add1,";
               String s2 = "Add2\n";
               String str;
               while((str = br.readLine()) != null) {
               StringBuffer sb = new StringBuffer(str);
               sb.append(s + s2);
               String y = sb.toString();
               System.out.println(sb);
               System.out.println("Appending");
               bw.write(y);
               bw.close();
               System.out.println("Done");
          }catch(IOException e) {}
}

First, thanks a lot for your feedback. The code makes a lot of sense but it does not update the content of my Test.txt file.
I only edited the line of code that creates the new file so that it could find the location of the file.
Scanner file = new Scanner(new File("C:\\testing",fileName));==============================
The code now looks like:
import java.io.*;
import java.util.*;
public class Main {
    static void appendTo(String fileName, String[] newLines) throws IOException {
        List<String> allLines = getLinesFrom(fileName);
        for(String line : newLines) {
            allLines.add(line);
        writeLinesTo(fileName, allLines);
    static List<String> getLinesFrom(String fileName) throws IOException {
        List<String> lines = new ArrayList<String>();
        Scanner file = new Scanner(new File("C:\\testing",fileName));
        while(file.hasNextLine()) {
            lines.add(file.nextLine());
        file.close();
        System.out.println(lines);
        return lines;
    static void writeLinesTo(String fileName, List<String> lines) throws IOException {
        BufferedWriter out = new BufferedWriter(new FileWriter(fileName));
        for(String line : lines) {
            out.write(line);
            out.write(System.getProperty("line.separator"));
        out.close();
    public static void main(String[] args) {
        String fileName = "Test.txt";
        String[] extraLines = {
                "a new line",
                "and yet another new line"
        try {
            appendTo(fileName, extraLines);
            System.out.println("Done.");
        } catch (IOException e) {
            e.printStackTrace();
}Again, thanks for the help.

Display file except 1st character of each line

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