Display hex and decimal

Hi everybody,
I'm getting real-time data and I would
like to know if it is possible to change the display to show the
results in hex format and decimal, using the same display. I mean, use
a push botton to change between them.
Regards
Felipe

You can also have both in one indicator.
For an example, have a look at this old nugget. The advantage is that you don't need any extra controls and code (such as buttons, property nodes, and associated logic).
Message Edited by altenbach on 07-20-2009 10:49 AM
LabVIEW Champion . Do more with less code and in less time .

Similar Messages

Query to display integer and decimal and integer in the same column

Hello ,
Have a question,
is there a easier way to do this.. is the question
i have a column called units.. and i need to display either a integer in it if the value does not have any value after the decimal point .. so it shud be display as integer. But if it is a float then only display it with decimal values
like
Units
100
.123
1000.55
2000

Check this out although formatting needs to be done in the client application:
DECLARE @t TABLE (units FLOAT)
INSERT INTO @t (units)
VALUES (100)
,(.123)
,(1000.55)
,(2000)
SELECT units
,convert(VARCHAR(30), units) AS DisplayOnly
FROM @t
For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles

Convert hex to Decimal and keep leading zeros..

Hi,
I hope you can help?
How to convert hex to Decimal and keep leading zeros
I read 002C, hex, and I want to convert it to 0044 decimal.
sscanf (MyNum, "%4x", &DecNum); will only give me 44.
It have been working up till I started to get leading zeros.
We will always have a 4 digit hex input in a range
We must have the leading 00 in this case.
How is this best done?
Thanks for the help
Simon
Solved!
Go to Solution.

Hi,
I don't really understand your problem. Is this stuff what you need ?
int main (int argc, char *argv[])
const char MyNum[] = "002C";
int DecNum;
sscanf (MyNum, "%4x", &DecNum);
printf ("%04d", DecNum);
getchar ();
return 0;
"0044" appears on standard output when printf function executes...

Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program

I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii
   public static void main(String[] args)throws IOException
      Scanner input = new Scanner(System.in);
      System.out.println("Enter a binary number: ");
      String binary = input.nextLine(); // store input from user
     if (binary == input.nextLine())
      //int i= Integer.parseInt(hex,2);
      //String hexString = Integer.toHexString(i);
      //System.out.println("Hexa decimal: " + hexString);
      //int finaldecimalvalue = binaryToDecimal(hexString);
      int finaldecimalvalue = binaryToDecimal(hexString);
     if (binary != input.nextLine())
      String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value
      // Create a Scanner object for keyboard input.
      //Scanner keyboard = new Scanner(System.in);
      // Get the number of binary files.
      System.out.print("Enter the Hex value: ");
      hexInput = keyboard.nextLine();
      System.out.println("Original String: "+ hexInput);
      //String hexEquivalent = asciiToHex(demoString);
      String hexEquivalent = asciiToHex(hexInput);
      //Hex value of original String
      System.out.println("Hex String: "+ hexEquivalent);
      String asciiEquivalent = hexToASCII(hexEquivalent);
      //ASCII value obtained from Hex value
      System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
     if (binary != input.nextLine() && hexInput != keyboard.nextLine())
         BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
         System.out.println("Enter the Binary number:");
         String hex = binInput.readLine();
         //String finaldecimalvalue = binaryToDecimal(decimal);
         //long finalhexvalue = BinaryToHexadecimal(num);
         long finalhexvalue = BinaryToHexadecimal();
   public static String BinaryToHexadecimal(String hex)
      //public static void main(String[] args)throws IOException
         //BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
         //System.out.println("Enter the Binary number:");
         //String hex = binInput.readLine();
         long num = Long.parseLong(hex);
         long rem;
         while(num > 0)
         rem = num % 10;
         num = num / 10;
         if(rem != 0 && rem != 1)
         System.out.println("This is not a binary number.");
         System.out.println("Please try once again.");
         System.exit(0);
         int i= Integer.parseInt(hex,2);
         String hexString = Integer.toHexString(i);
         System.out.println("Hexa decimal: " + hexString);
      return num.tolong();
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//} // end BintoDectoHextoAsciil
   //public static String HexAsciiConverter(String hextInput)
      // Get the number of binary files.
      //System.out.print("Enter the Hex value: ");
      //hexInput = keyboard.nextLine();
      //System.out.println("Original String: "+ hexInput);
      //String hexEquivalent = asciiToHex(demoString);
      //String hexEquivalent = asciiToHex(hexInput);
      //Hex value of original String
      //System.out.println("Hex String: "+ hexEquivalent);
      //String asciiEquivalent = hexToASCII(hexEquivalent);
      //ASCII value obtained from Hex value
      //System.out.println("Ascii String: "+ asciiEquivalent);
   //} // End function
   private static String asciiToHex(String asciiValue)
      char[] chars = asciiValue.toCharArray();
      StringBuffer hex = new StringBuffer();
      for (int i = 0; i < chars.length; i++)
         hex.append(Integer.toHexString((int) chars[i]));
      return hex.toString();
   private static String hexToASCII(String hexValue)
      StringBuilder output = new StringBuilder("");
      for (int i = 0; i < hexValue.length(); i += 2)
         String str = hexValue.substring(i, i + 2);
         output.append((char) Integer.parseInt(str, 16));
      return output.toString();
   public static String binaryToDecimal(String binary)
        //Scanner input = new Scanner(System.in);
        //System.out.println("Enter a binary number: ");
        //String binary = input.nextLine(); // store input from user
        int[] powers = new int[16]; // contains powers of 2
        int powersIndex = 0; // keep track of the index
        int decimal = 0; // will contain decimals
        boolean isCorrect = true; // flag if incorrect input
       // populate the powers array with powers of 2
        for(int i = 0; i < powers.length; i++)
            powers[i] = (int) Math.pow(2, i);
        for(int i = binary.length() - 1; i >= 0; i--)
            // if 1 add to decimal to calculate
            if(binary.charAt(i) == '1')
                decimal = decimal + powers[powersIndex]; // calc the decimal
            else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
                isCorrect = false; // flag the wrong input
                break; // break from loop due to wrong input
            } // end else if
            // keeps track of which power we are on
            powersIndex++; // counts from zero up to combat the loop counting down to zero
        } // end for
        if(isCorrect) // print decimal output
            System.out.println(binary + " converted to base 10 is: " + decimal);
        else // print incorrect input message
            System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
        return decimal.toint();
   } // end function
The errors are as follows:
----jGRASP exec: javac BintoDectoHextoAscii.java
BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
   public static String BinaryToHexadecimal(String hex)
                 ^
BintoDectoHextoAscii.java:73: error: class, interface, or enum expected
         long rem;
         ^
BintoDectoHextoAscii.java:74: error: class, interface, or enum expected
         while(num > 0)
         ^
BintoDectoHextoAscii.java:77: error: class, interface, or enum expected
         num = num / 10;
         ^
BintoDectoHextoAscii.java:78: error: class, interface, or enum expected
         if(rem != 0 && rem != 1)
         ^
BintoDectoHextoAscii.java:81: error: class, interface, or enum expected
         System.out.println("Please try once again.");
         ^
BintoDectoHextoAscii.java:83: error: class, interface, or enum expected
         System.exit(0);
         ^
BintoDectoHextoAscii.java:84: error: class, interface, or enum expected
         ^
BintoDectoHextoAscii.java:87: error: class, interface, or enum expected
         String hexString = Integer.toHexString(i);
         ^
BintoDectoHextoAscii.java:88: error: class, interface, or enum expected
         System.out.println("Hexa decimal: " + hexString);
         ^
BintoDectoHextoAscii.java:90: error: class, interface, or enum expected
      return num.tolong();
      ^
BintoDectoHextoAscii.java:91: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:124: error: class, interface, or enum expected
      StringBuffer hex = new StringBuffer();
      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
                      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
                                        ^
BintoDectoHextoAscii.java:128: error: class, interface, or enum expected
      ^
BintoDectoHextoAscii.java:130: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
      ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
                      ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
                                             ^
BintoDectoHextoAscii.java:138: error: class, interface, or enum expected
         output.append((char) Integer.parseInt(str, 16));
         ^
BintoDectoHextoAscii.java:139: error: class, interface, or enum expected
      ^
BintoDectoHextoAscii.java:141: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:144: error: class, interface, or enum expected
   public static String binaryToDecimal(String binary)
                 ^
BintoDectoHextoAscii.java:150: error: class, interface, or enum expected
        int powersIndex = 0; // keep track of the index
        ^
BintoDectoHextoAscii.java:151: error: class, interface, or enum expected
        int decimal = 0; // will contain decimals
        ^
BintoDectoHextoAscii.java:152: error: class, interface, or enum expected
        boolean isCorrect = true; // flag if incorrect input
        ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
        ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
                       ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
                                          ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
        ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
                                         ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
                                                 ^
BintoDectoHextoAscii.java:166: error: class, interface, or enum expected
            else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
            ^
BintoDectoHextoAscii.java:169: error: class, interface, or enum expected
                break; // break from loop due to wrong input
                ^
BintoDectoHextoAscii.java:170: error: class, interface, or enum expected
            } // end else if
            ^
BintoDectoHextoAscii.java:174: error: class, interface, or enum expected
        } // end for
        ^
BintoDectoHextoAscii.java:180: error: class, interface, or enum expected
        else // print incorrect input message
        ^
BintoDectoHextoAscii.java:185: error: class, interface, or enum expected
        return decimal.toint();
        ^
BintoDectoHextoAscii.java:186: error: class, interface, or enum expected
   } // end function
   ^
41 errors
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.

so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped.
Yes - YOU CAN!
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
Excellent! Commenting out code is EXACTLY how you troubleshoot problems like yours.
Comment out sections of code until the problem goes away. Then start adding back ONE SECTION of code at a time until the problem occurs. When it does you have just FOUND the problem.
If you do that you wind up with code that looks like this:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii {
      public static void main(String[] args)throws IOException      {
         Scanner input = new Scanner(System.in);
         System.out.println("Enter a binary number: ");
         String binary = input.nextLine(); // store input from user
              public static String BinaryToHexadecimal(String hex)     {     } // end function
Notice ANYTHING UNUSUAL?
You have a complete CLASS definition followed by a method definition.
Methods have to be INSIDE the class - you can NOT define methods on their own.
Write modular code.
Write EMPTY methods - just the method signature and maybe a RETURN NULL if you need to return something.
Then add calls to those empty methods.
When everything compiles and runs find you can start adding code to the methods ONE METHOD AT A TIME.
Test compile and run after you add the code for each method.

How to display integer values and decimal values in same column in a table

hi
in my report amount column is there in that column integer values (2234) and decimal values (3562.34)
i want to print this values as 1000 separate as like 2,234 as integer and 3,562.34 as decimal
but this values print like 2,234.00 as integer and 3,562.34 as decimal

Hi akilreddy,
Per my understanding you have an field which data type may be "float" in the DB, so it have value which format like "2234" and "3562.34" in the same column, now you want to format them differently in the report, right?
I have tested on my local environement and you can use the expression in the custom format in the Textbox properties to do this:
Right click the field which you want to add the format and select the "Text Box Properties"
Select the "Number" on the left pane and using expression below in the Custom format:
=IIF(Split(Fields!yourfieldname.Value,".").Length=2,"#,###.##",Nothing)
Or you can just use "#,###.##" in the format.
Preview you will go the result like below:
If you still have any problem, please feel free to ask.
Regards
Vicky Liu
Vicky Liu
TechNet Community Support

How to change the Display Pattern for Decimal Fields dynamically

hi all,
Can any one help me how to change the display pattern for decimal fields dynamically???
Currently I am using z,zzz,zzz,zz9.999 Display pattern for Quantity Field. If the value is blank it is displaying as 0.000 on the Screen. But I don't want this to be printed.
Please help me how to solve this ASAP.
Thanks,
Prabhu

Hi,
Alternatively you can handle it in the context.
In the context area, click on the quantity. In the bottom, click on the conditions tab, and put a condition
<quan field> NE initial.
So the field will not be printed if there is no value.
Regards,
Vidya Chowdhary A.

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Hi
I am wondering what the best way to display hex values in a JTable is. At the moment I am using the Integer.toHexString method to convert an integer to hex but the problem with this is that it gets rid of leading zeros.
Is there a way to keep the number of digits in a hex number column.
I would be greatful for your help.
Thanks

Hi derek,
I've had to do this as well, and the only solution I could come up with is to create a method that would prepend the zeros to the hex string. For example:
public String pad(String str, int len) {
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   for(int i = 0; i < (len - str.length()); i++) {
      buff.insert(0, '0');
   return buff.toString();
}Hope this helps,
Bud

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Hi, I'd like to allow my user to choose between hex/binary/decimal formats in his number input. I'm happy to do the radio button stuff and the code to "hear" what he wants, but I can't find a property of my variable which selects the format at run-time - there is of course the "Format & Precision..." which I can get at by right mouse click BEFORE running, so I know it's likely to be available at run-time. Any suggestions welcome. Thanks, Richard.

It's not necessary to use property node because you can use the builtin
property of the indicator.
Click the rigth mouse button over the indicator and select show radix.
On the left side of the indicator appear radix that you can push to choose
between hex, binary, octal and decimal.
Bye
Golzio
"R" ha scritto nel messaggio
news:[email protected]..
> Hi, I'd like to allow my user to choose between hex/binary/decimal
> formats in his number input. I'm happy to do the radio button stuff
> and the code to "hear" what he wants, but I can't find a property of
> my variable which selects the format at run-time - there is of course
> the "Format & Precision..." which I can get at by right mouse click
> BEFORE run
ning, so I know it's likely to be available at run-time. Any
> suggestions welcome. Thanks, Richard.

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> I don't mean to display digitals in Hex ways but to display it in a
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> some like the following graph.
> __________________ ________ _____________ ________________________
> _______
> \/ \/ \/
> \/
> ___9F_____________/\___8A___/\_____12______/\________5C______________/\___6D__
>
You don't say what version you are using, but I believe that starting
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there is any function to convert from hex to decimal and vis versa in PL/SQL?
Regeards
eng. Amn2000

create or replace function sf_sys_hex_to_dec (
p_hexadecimal in varchar2
) return number as
v_character varchar2(1);
v_decimal number(10);
v_number pls_integer;
v_position pls_integer;
v_length pls_integer;
begin
if p_hexadecimal is null then
sp_sys_internal_error('Hexadecimal value cannot be null.');
end if;
v_length := length(p_hexadecimal);
if v_length > 8 then
sp_sys_internal_error('Hexadecimal value too big - maximum allowed is "FFFFFFFF".');
end if;
v_position := v_length;
v_decimal := 0;
loop
v_character := substr(p_hexadecimal,v_position,1);
if v_character = '0' then
v_number := 0;
elsif v_character = '1' then
v_number := 1;
elsif v_character = '2' then
v_number := 2;
elsif v_character = '3' then
v_number := 3;
elsif v_character = '4' then
v_number := 4;
elsif v_character = '5' then
v_number := 5;
elsif v_character = '6' then
v_number := 6;
elsif v_character = '7' then
v_number := 7;
elsif v_character = '8' then
v_number := 8;
elsif v_character = '9' then
v_number := 9;
elsif v_character = 'A' then
v_number := 10;
elsif v_character = 'B' then
v_number := 11;
elsif v_character = 'C' then
v_number := 12;
elsif v_character = 'D' then
v_number := 13;
elsif v_character = 'E' then
v_number := 14;
elsif v_character = 'F' then
v_number := 15;
else
sp_sys_internal_error('Invalid hexadecimal character found.');
end if;
v_decimal := v_decimal + v_number * 16 ** (v_length - v_position);
v_position := v_position - 1;
if v_position = 0 then
exit;
end if;
end loop;
return(v_decimal);
end;
create or replace function sf_sys_dec_to_hex (
p_decimal in number
) return varchar2 as
v_hexadecimal varchar2(8);
v_character varchar2(1);
v_number pls_integer;
v_integer pls_integer;
v_module pls_integer;
v_first_time boolean;
begin
if p_decimal is null then
sp_sys_internal_error('Decimal value cannot be null.');
end if;
if p_decimal > 4294967295 then
sp_sys_internal_error('Decimal value too big - maximum value is 4294967295.');
end if;
v_first_time := true;
v_number := p_decimal;
loop
v_integer := trunc(v_number / 16);
v_module := mod(v_number,16);
if v_module = 0 then
v_character := '0';
elsif v_module = 1 then
v_character := '1';
elsif v_module = 2 then
v_character := '2';
elsif v_module = 3 then
v_character := '3';
elsif v_module = 4 then
v_character := '4';
elsif v_module = 5 then
v_character := '5';
elsif v_module = 6 then
v_character := '6';
elsif v_module = 7 then
v_character := '7';
elsif v_module = 8 then
v_character := '8';
elsif v_module = 9 then
v_character := '9';
elsif v_module = 10 then
v_character := 'A';
elsif v_module = 11 then
v_character := 'B';
elsif v_module = 12 then
v_character := 'C';
elsif v_module = 13 then
v_character := 'D';
elsif v_module = 14 then
v_character := 'E';
elsif v_module = 15 then
v_character := 'F';
end if;
if v_first_time = true then
v_hexadecimal := v_character;
else
v_hexadecimal := v_character| |v_hexadecimal;
end if;
if v_integer = 0 then
exit;
end if;
v_number := v_integer;
v_first_time := false;
end loop;
return(v_hexadecimal);
end;
null

Grouping and Decimal characters in rtf templates.

Hi guys and girls,
I’m really struggling with a problem here regarding the decimal characters for the prices in my output.
I'm using XML Publisher 5.6.3.
My goal is to control the grouping and decimal character from my template.
The numbers in the XML data file can either be 10.000,00 or 10,000.00. The format is handled by the users nls_numeric_characters profile option.
The output of the template shall be based on the locale and not the data generated by Oracle Reports. For example: Reports to US customers shall show the numbers in the following format 10,000.00. Reports to our European customers shall show the numbers in this format 10.000,00.
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Thank you in advance.
Kenneth Kristoffersen
Edited by: Kenneth_ on May 19, 2009 1:30 AM

Hi,
Thank you for your reply.
The problem is that the report is generating the output based on the users profile option nls_numeric_characters.
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BR Kenneth

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Since July, 16th 2012 the Web Analytics Daily Unique Visitors reports started to show almost the double of visitors we used to have on our Web Application. Here are some of the data (I intentionally deleted the weekend data):
10/7/2012 2.497
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12/7/2012 2.722
13/7/2012 2.699
16/7/2012 5.055
17/7/2012 4.963
18/7/2012 4.954
19/7/2012 4.998
20/7/2012 4.965
23/7/2012 5.117
24/7/2012 5.012
25/7/2012 5.071
As you may notice the data jumped from around 2.700 unique visitors to around 5.000 unique visitors. As the number of permissioned users remains constant it is pretty odd. I also checked the Number of Page Views report and see no change on its behavior.
The number of page views remained constant.
So I went to look the Top Visitors report and understand why the visitors number almost doubled. The analytics started to count the users Display Name and Account name as two different visitors with a different number of page views. Let me show you an example
from yesterday (July, 25th) Top Visitors report:
#    Visitor                  Page Views   %
1   Cinthia XXXXXXXXXX    359      0,55%
5   Giselle XXXXXXXXXX     143        0,22%
7    Aline XXXXXXXXXX       138        0,21%
15 nt\cmazevedo              111        0,17%
60 nt\gbsantana                 69        0,11%
73 nt\aglsiqueira                 65      0,10%
"Cinthia" and the account "nt\cmazevedo" are the same person. The same is applied to "Giselle" / "nt\gbsantana" and "Aline" / "nt\aglsiqueira".
As I stated this is an example from July, 25th. If I checked the same report from a period before July, 16th I can only see the users Display Name as "Visitors". No account name is displayed or counted as a different visitor.
About the environment:
We have two SharePoint 2010 farms: a "corporate" and a "enterprise". The corporate farm contains four web servers and a central administration servers with publishing services. The enterprise farm contains two servers running User Profile Services, Search
Services and some others. Our main version is the SP1 with June/2011 Cumulative Update with a few more hotfixes applied.
This behavior on analytics is affecting all web applications (we have more than 20) installed on this farm and my company Support team said that no change were made on SharePoint on the weekend the problem started.
Does anyone have any tip about what is going on?
Thanks in advance!

Hi, Manas!
First of all thanks for your interest on this issue but I don't think it is related to the User Profile or the Active Directory.
I checked both records and there was no change on the Display Names. All the users have "full names" as display names (first + middle + last name) and not logins as SharePoint is displaying on this report.
But I did a test yesterday and checked the results today confirming that just the access been made using a specific server are causing this. Explaining it better:
I have four web servers on my farm named from P01 to P04. Then I created this test script:
Step 1: Change local HOSTS file to point the web application on the server P01.
Step 2: Access site "A"
Step 3: Access site "B"
Step 4: Close the browser.
Step 1: Change local HOSTS file to point the web application on the server P02.
Step 2: Access site "C"
Step 3: Access site "D"
Step 4: Close the browser.
Step 1: Change local HOSTS file to point the web application on the server P03.
Step 2: Access site "E"
Step 3: Access site "F"
Step 4: Close the browser.
Step 1: Change local HOSTS file to point the web application on the server P04.
Step 2: Access site "G"
Step 3: Access site "H"
Step 4: Close the browser.
I asked three users to execute that script. The results: All access to the sites "C" and "D" were registered on Web Analytics with the user account name such as "nt\cmazevedo". All the other sites registered the user Display Name correctly such as "Cinthia
XXXXXXXXXX".
With this test we could isolate the problem just on the server P02. It doesn't occur on the others. Now my support team is trying to find any configuration difference between this server and the other three that could point for the root cause.
I am also looking for some information regarding the service responsible for this task ("transform the account name into a display name") to understand why it doesn't work on one server and works on the others.
Thanks!

I was recently sent a very large emoji message amd now when i try to acces messages it will not display mesagges and then will bring me back to the home page

was recently sent a very large emoji message amd now when i try to acces messages it will not display mesagges and then will bring me back to the home page

Quit the messages app and reset your phone.
Go to the Home screen and double click the Home button. That will reveal the row of recently used apps at the bottom of the screen. Tap and hold on the app in question until it jiggles and displays a minus sign. Tap the minus sign to actually quit the app. Then tap anywhere on the screen above that bottom row to return the screen to normal. Then restart the app and see if it works normally. Then reset your device. Press and hold the Home and Sleep buttons simultaneously ignoring the red slider should one appear until the Apple logo appears. Let go of the buttons and let the device restart.
After the phone restarts go into Messages and delete the thread containing the problem message.

Display hex and decimal

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