Displaying a column and sorting on another

See
http://htmldb.oracle.com/pls/otn/f?p=24317:90
Common problem, I want the date displayed in a certain format but when I sort-enable the column, I want it sorted by the real date column.
I selected both the "raw" date column and the formatted date column, unchecked the Show checkbox on the formatted column and put its value using #COLUMN# syntax in the raw date column.
Seems to work ok, can someone please confirm that this is the recommended way to do this?
[I am sure this has come up before, but I am not sure if I am doing it the right way]
Thanks

Vikas,
For numeric or date columns you don't need 2 columns. Just specify the format using the Number/Date Format of the column spec.
jd

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=IF(SMALL(Main :: $G,ROW()-1)>999,"",OFFSET(Main :: $A$1,MATCH(SMALL(Main::$G,ROW()-1),Main :: $G,0)-1,3))
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Regards,
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This is what I am trying to do:
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Hi j&s,
Numbers uses a data base model that treats each row of a table as a single record. You can sort all or selected rows on the values in one or more column(s), but the whole row moves to maintain the integrity of each record.
If you want some columns to be excluded from a sort, you need to remove those columns (or their data) from the table. Jerry has offered a way to do that for the rankings, but that solution will not resolve the issue of the 'leader board' cells acting badly in a sort.
Here's an alternate. The first view is of the table(s) (with the participants in alphabetical order), just after the current totals had been entered.
At this point, the Leader board, which pulls names and totals from the first three body rows of the data table, shows the correct cells, but these don't include the correct information.
Note that column A does show the correct placing for each participant.
The second view shows the same table(s) after the data table has bee sorted. The sort may be descending on column C (Totals) or ascending on column A (Place).
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A2: =RANK(C2,C,largest-is-high)
Fill down into the rest of the cells in column A. Any empty rows should be removed from the bottom of the table, or have zeros entered into their total column cells.
The Leader board table has two formulas:
A2: =OFFSET(Data :: $A$1,ROW()-1,1)
Fill down to A4.
This returns the name of the participant in the top body cell of column B of the data table.
B2 contains the word "Leader"
B3: =IF((OFFSET(Data :: $A$1,1,2)-OFFSET(Data :: $A$1,ROW()-1,2))>0,OFFSET(Data :: $A$1,1,2)-OFFSET(Data :: $A$1,ROW()-1,2),"Leader")
Fill down to B4
The root of this formula is OFFSET(Data :: $A$1,1,2)-OFFSET(Data :: $A$1,ROW()-1,2)
This returns the total value from the first and second body cells in the total column, and subtracts the second from the first.
The rest of the formula is an IF statement tohandle the occasions where there's a two or three-way tie for the lead. (image below) If the result is greater than zero, the subtraction is repeated and the result returned to the cell (B3); if the result is zero, the word :Leader: is returned to this cell.
Placing the calculation in a separate table and using OFFSET, with a base cell (Data::A1) that is in a row defined as a Header row makes this table and its formulas immune from sorting of the Data table.
Here's the tie, which arose when i added another 11 particpants to check sorting of the Place column:
Regards,
Barry
Message was edited by: Barry (added image and notes on Tie case)

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Hi,
The distinct is destructive meaning that the duplicate rows
are removed and you can't access them anymore unless you reload the
XML (and remove the distinct restriction first).
The distinct() call without no parameter will use all the
columns, once you specify an array of columns the functionality
will limit in filtering only values for those columns to be
distinct.
You can check a single field to be distinct:
dsDundeeUniverse.distinct("Analyst") or a combination of multiple
columns:
myDataSet.distinct(["firstName", "lastName"]).
This last behavior has a limitation as you can't rely on the
values that exists in additional fields that are not used in
distinct algorithm. If you have two records in your dataset where a
person name will appear twice but the department column associated
will have a different value for each record the result will contain
the value of the department from the first row found. In this case
will not make much sense to display the value for the department.
Regards,
Cristian MARIN

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Displaying a column and sorting on another

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