Double is giving the garbage value

Question

The following code:
public class Hello
public static void main(String[] args)
double d = 12.12345678235467F;
System.out.println("d = " + d);
When the above code runs, then i am getting the garbage value.
The first 8 decimal digits are correct but after that rest of the digits are garbage value. Why?
This problem occurs only when the double value has more than 8 decimal digits and the value is appended with "F".
any answer?

Answer 1

J2ME_discussion wrote:
Can you explain it in simpler terms.
When the value is not appended with "F" then i am getting the correct value i.e. the value declare is same as the value printed in the console output (16 significant decimal digits)
But, if it gets appended with "F" then the problem starts.Float (32 bits) can handle a smaller range of numbers than double (64 bits). Put F at the end, and it is a float.
Also, neither store numbers as X number of significant decimal places. I don't understand the math behind it all, and for general use you don't need to. You really only need to know that both float and double do not store numbers are X number of significant decimal places, so some numbers (0.1 I believe is one) will only be an approximation of the actual value. If you absolutely require X number of significant decimal places then you don't want to be using either double or float, you either want to roll your own using two ints, or use BigDecimal class.