Dynamic Hierarchy Selection

Ok I read this article and the selection is working. Is it possible to dynamically "Rename Hierarchy After Loading"?
http://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/a03c23b1-1cb4-2d10-f1ae-9f5ed92be246?QuickLink=index&overridelayout=true

I had to modify RSLDPSEL-NEW_HIENM.

Similar Messages

  • How-to Dynamic Hierarchy Selection.

    Hi guys,
    does anyone know how to implement "Dynamic Hierarchy Selection"? I have a main hierarchy but would like to filter it further while loading the hierarchy.
    E.g. I have a financial statement verison with both Balance Sheet and P/L items, i would like to separate the main into two new hierarchies, one BS and P/L hierarchies instead, apparently the infopackage allows you to write small codes to dynamically select which hierarhcy you want.
    Cheers.

    Hi,
    We donot have this type selection at the time of upload. The thing we can do is upload both versions into BIW and in the report we can use Hierarchy variable to have dynamic selection of hierarchy.
    with rgds,
    Anil Kumar Sharma .P

  • Dynamic hierarchy in parent child hierarchy table??

    Do you have any experience to handle the requirement of dynamic hierarchy in universe/webi?
    We have some data in parent child hierarchy as below u201CCustomeru201D table.
    Customer
    Parent          Child
    Z                  A
    Z                  B
    A                  AA
    B                  BB
    AA               AAA
    For example, Company Z is the parent company of Company A.
    Another table, Amount is the amount value of different Customers.
    Amount
    ID               Amt
    AA               10
    AAA            1
    BB                2
    Is there any functionality in Universe designer to build related Classes and objects, So that the web intelligence documents represent the following report with the drilling results?
    When we want to see the ID and Amt, the expected result should be:
    Z                13
    when we drill down Z
    the result should be:
    A                11
    B                2
    when we drill down A:
    the result should be:
    AA              11
    notes **
    the level of hierarchy is dynamic
    Any suggestion is appreciated.  Thanks.

    Hi,
    The only way to do it is to create recursive derived table that flatten you parent child hierarchy with a given maximum depth.
    Here is a sample I built a long time ago to flatten a parent-child hierarchy on Employees table in Foodmart database (SQL Server).
    Didier
    SELECT DISTINCT
         Z.employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         A.supervisor_id_5,
         A.employee_id_5,
         A.full_name_5,
         A.supervisor_id_6,
         A.employee_id_6,
         A.full_name_6,
         Z.supervisor_id AS supervisor_id_7,
         Z.employee_id AS employee_id_7,
         Z.full_name AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              A.supervisor_id_4,
              A.employee_id_4,
              A.full_name_4,
              A.supervisor_id_5,
              A.employee_id_5,
              A.full_name_5,
              Z.supervisor_id AS supervisor_id_6,
              Z.employee_id AS employee_id_6,
              Z.full_name AS full_name_6
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   A.supervisor_id_3,
                   A.employee_id_3,
                   A.full_name_3,
                   A.supervisor_id_4,
                   A.employee_id_4,
                   A.full_name_4,
                   Z.supervisor_id AS supervisor_id_5,
                   Z.employee_id AS employee_id_5,
                   Z.full_name AS full_name_5
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        A.supervisor_id_2,
                        A.employee_id_2,
                        A.full_name_2,
                        A.supervisor_id_3,
                        A.employee_id_3,
                        A.full_name_3,
                        Z.supervisor_id AS supervisor_id_4,
                        Z.employee_id AS employee_id_4,
                        Z.full_name AS full_name_4
                   FROM employee Z,
                        SELECT DISTINCT
                             A.supervisor_id_1,
                             A.employee_id_1,
                             A.full_name_1,
                             A.supervisor_id_2,
                             A.employee_id_2,
                             A.full_name_2,
                             Z.supervisor_id AS supervisor_id_3,
                             Z.employee_id AS employee_id_3,
                             Z.full_name AS full_name_3
                        FROM employee Z,
                             SELECT DISTINCT
                                  A.supervisor_id_1,
                                  A.employee_id_1,
                                  A.full_name_1,
                                  Z.supervisor_id AS supervisor_id_2,
                                  Z.employee_id AS employee_id_2,
                                  Z.full_name AS full_name_2
                             FROM employee Z,
                                  SELECT DISTINCT
                                       supervisor_id AS supervisor_id_1,
                                       employee_id AS employee_id_1,
                                       full_name AS full_name_1
                                   FROM employee
                                   WHERE supervisor_id = 0 OR supervisor_id IS NULL
                             ) A
                             WHERE A.employee_id_1 = Z.supervisor_id
                        ) A
                        WHERE A.employee_id_2 = Z.supervisor_id
                   ) A
                   WHERE A.employee_id_3 = Z.supervisor_id
              ) A
              WHERE A.employee_id_4 = Z.supervisor_id
         ) A
         WHERE A.employee_id_5 = Z.supervisor_id
    ) A
    WHERE A.employee_id_6 = Z.supervisor_id
    UNION
    SELECT DISTINCT
         A.employee_id_6 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         A.supervisor_id_5,
         A.employee_id_5,
         A.full_name_5,
         A.supervisor_id_6,
         A.employee_id_6,
         A.full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              A.supervisor_id_4,
              A.employee_id_4,
              A.full_name_4,
              A.supervisor_id_5,
              A.employee_id_5,
              A.full_name_5,
              Z.supervisor_id AS supervisor_id_6,
              Z.employee_id AS employee_id_6,
              Z.full_name AS full_name_6
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   A.supervisor_id_3,
                   A.employee_id_3,
                   A.full_name_3,
                   A.supervisor_id_4,
                   A.employee_id_4,
                   A.full_name_4,
                   Z.supervisor_id AS supervisor_id_5,
                   Z.employee_id AS employee_id_5,
                   Z.full_name AS full_name_5
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        A.supervisor_id_2,
                        A.employee_id_2,
                        A.full_name_2,
                        A.supervisor_id_3,
                        A.employee_id_3,
                        A.full_name_3,
                        Z.supervisor_id AS supervisor_id_4,
                        Z.employee_id AS employee_id_4,
                        Z.full_name AS full_name_4
                   FROM employee Z,
                        SELECT DISTINCT
                             A.supervisor_id_1,
                             A.employee_id_1,
                             A.full_name_1,
                             A.supervisor_id_2,
                             A.employee_id_2,
                             A.full_name_2,
                             Z.supervisor_id AS supervisor_id_3,
                             Z.employee_id AS employee_id_3,
                             Z.full_name AS full_name_3
                        FROM employee Z,
                             SELECT DISTINCT
                                  A.supervisor_id_1,
                                  A.employee_id_1,
                                  A.full_name_1,
                                  Z.supervisor_id AS supervisor_id_2,
                                  Z.employee_id AS employee_id_2,
                                  Z.full_name AS full_name_2
                             FROM employee Z,
                                  SELECT DISTINCT
                                       supervisor_id AS supervisor_id_1,
                                       employee_id AS employee_id_1,
                                       full_name AS full_name_1
                                   FROM employee
                                   WHERE supervisor_id = 0 OR supervisor_id IS NULL
                             ) A
                             WHERE A.employee_id_1 = Z.supervisor_id
                        ) A
                        WHERE A.employee_id_2 = Z.supervisor_id
                   ) A
                   WHERE A.employee_id_3 = Z.supervisor_id
              ) A
              WHERE A.employee_id_4 = Z.supervisor_id
         ) A
         WHERE A.employee_id_5 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_5 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         A.supervisor_id_5,
         A.employee_id_5,
         A.full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
         NULL AS full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              A.supervisor_id_4,
              A.employee_id_4,
              A.full_name_4,
              Z.supervisor_id AS supervisor_id_5,
              Z.employee_id AS employee_id_5,
              Z.full_name AS full_name_5
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   A.supervisor_id_3,
                   A.employee_id_3,
                   A.full_name_3,
                   Z.supervisor_id AS supervisor_id_4,
                   Z.employee_id AS employee_id_4,
                   Z.full_name AS full_name_4
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        A.supervisor_id_2,
                        A.employee_id_2,
                        A.full_name_2,
                        Z.supervisor_id AS supervisor_id_3,
                        Z.employee_id AS employee_id_3,
                        Z.full_name AS full_name_3
                   FROM employee Z,
                        SELECT DISTINCT
                             A.supervisor_id_1,
                             A.employee_id_1,
                             A.full_name_1,
                             Z.supervisor_id AS supervisor_id_2,
                             Z.employee_id AS employee_id_2,
                             Z.full_name AS full_name_2
                        FROM employee Z,
                             SELECT DISTINCT
                                  supervisor_id AS supervisor_id_1,
                                  employee_id AS employee_id_1,
                                  full_name AS full_name_1
                              FROM employee
                              WHERE supervisor_id = 0 OR supervisor_id IS NULL
                        ) A
                        WHERE A.employee_id_1 = Z.supervisor_id
                   ) A
                   WHERE A.employee_id_2 = Z.supervisor_id
              ) A
              WHERE A.employee_id_3 = Z.supervisor_id
         ) A
         WHERE A.employee_id_4 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_4 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         A.supervisor_id_4,
         A.employee_id_4,
         A.full_name_4,
         NULL AS supervisor_id_5,
         NULL AS employee_id_5,
         NULL AS full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
         NULL AS full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              A.supervisor_id_3,
              A.employee_id_3,
              A.full_name_3,
              Z.supervisor_id AS supervisor_id_4,
              Z.employee_id AS employee_id_4,
              Z.full_name AS full_name_4
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   A.supervisor_id_2,
                   A.employee_id_2,
                   A.full_name_2,
                   Z.supervisor_id AS supervisor_id_3,
                   Z.employee_id AS employee_id_3,
                   Z.full_name AS full_name_3
              FROM employee Z,
                   SELECT DISTINCT
                        A.supervisor_id_1,
                        A.employee_id_1,
                        A.full_name_1,
                        Z.supervisor_id AS supervisor_id_2,
                        Z.employee_id AS employee_id_2,
                        Z.full_name AS full_name_2
                   FROM employee Z,
                        SELECT DISTINCT
                             supervisor_id AS supervisor_id_1,
                             employee_id AS employee_id_1,
                             full_name AS full_name_1
                         FROM employee
                         WHERE supervisor_id = 0 OR supervisor_id IS NULL
                   ) A
                   WHERE A.employee_id_1 = Z.supervisor_id
              ) A
              WHERE A.employee_id_2 = Z.supervisor_id
         ) A
         WHERE A.employee_id_3 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_3 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         A.supervisor_id_3,
         A.employee_id_3,
         A.full_name_3,
         NULL AS supervisor_id_4,
         NULL AS employee_id_4,
         NULL AS full_name_4,
         NULL AS supervisor_id_5,
         NULL AS employee_id_5,
         NULL AS full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
         NULL AS full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              A.supervisor_id_2,
              A.employee_id_2,
              A.full_name_2,
              Z.supervisor_id AS supervisor_id_3,
              Z.employee_id AS employee_id_3,
              Z.full_name AS full_name_3
         FROM employee Z,
              SELECT DISTINCT
                   A.supervisor_id_1,
                   A.employee_id_1,
                   A.full_name_1,
                   Z.supervisor_id AS supervisor_id_2,
                   Z.employee_id AS employee_id_2,
                   Z.full_name AS full_name_2
              FROM employee Z,
                   SELECT DISTINCT
                        supervisor_id AS supervisor_id_1,
                        employee_id AS employee_id_1,
                        full_name AS full_name_1
                    FROM employee
                    WHERE supervisor_id = 0 OR supervisor_id IS NULL
              ) A
              WHERE A.employee_id_1 = Z.supervisor_id
         ) A
         WHERE A.employee_id_2 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_2 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         A.supervisor_id_2,
         A.employee_id_2,
         A.full_name_2,
         NULL AS supervisor_id_3,
         NULL AS employee_id_3,
         NULL AS full_name_3,
         NULL AS supervisor_id_4,
         NULL AS employee_id_4,
         NULL AS full_name_4,
         NULL AS supervisor_id_5,
         NULL AS employee_id_5,
         NULL AS full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
         NULL AS full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              A.supervisor_id_1,
              A.employee_id_1,
              A.full_name_1,
              Z.supervisor_id AS supervisor_id_2,
              Z.employee_id AS employee_id_2,
              Z.full_name AS full_name_2
         FROM employee Z,
              SELECT DISTINCT
                   supervisor_id AS supervisor_id_1,
                   employee_id AS employee_id_1,
                   full_name AS full_name_1
               FROM employee
               WHERE supervisor_id = 0 OR supervisor_id IS NULL
         ) A
         WHERE A.employee_id_1 = Z.supervisor_id
    ) A
    UNION
    SELECT DISTINCT
         A.employee_id_1 AS employee_id,
         A.supervisor_id_1,
         A.employee_id_1,
         A.full_name_1,
         NULL AS supervisor_id_2,
         NULL AS employee_id_2,
         NULL AS full_name_2,
         NULL AS supervisor_id_3,
         NULL AS employee_id_3,
         NULL AS full_name_3,
         NULL AS supervisor_id_4,
         NULL AS employee_id_4,
         NULL AS full_name_4,
         NULL AS supervisor_id_5,
         NULL AS employee_id_5,
         NULL AS full_name_5,
         NULL AS supervisor_id_6,
         NULL AS employee_id_6,
         NULL AS full_name_6,
         NULL AS supervisor_id_7,
         NULL AS employee_id_7,
         NULL AS full_name_7
    FROM employee Z,
         SELECT DISTINCT
              supervisor_id AS supervisor_id_1,
              employee_id AS employee_id_1,
              full_name AS full_name_1
          FROM employee
          WHERE supervisor_id = 0 OR supervisor_id IS NULL
    ) A

  • Dynamic Hierarchy Reporting function

    Hi All,
    i was looking through the help and found:
    You can choose also whether to view dynamic hierarchies or standard Groups and Entity dimensions in the current view by making the appropriate selecting in the Current View selector. Thereafter, when the application type is consolidation, the dynamic hierarchy replaces Groups and Entity in the Current View. In addition, when you select the Group dimension in the Current View, the dynamic hierarchy stored with ownership application displays instead of the normal dimension hierarchy.
    from http://help.sap.com/saphelp_bpc75/helpdata/en/5A/69200C88AA40C9B18844A25259F147/frameset.htm
    under dynamic hierarchies > reporting on dynamic hierarchies.
    My question is:
    The help indicates there is a 'setting' to make in the current view selector, thereafter when the app type is consolidation, the dynamic hierarchy replaces group/entity - where is setting and how do i set it?
    I have bpc 7.5 sp4
    Edited by: Hiren Amin on Dec 16, 2010 3:13 PM

    Hi Hiren,
    I'm afraid I can't give you good news, as we have the same issue (same version).  We have been told by SAP that this is bug in the MS version, which I believe they are working on, however no news as yet as to when they expect to issue a fix for it.
    Thanks,
    Steve

  • Dynamic Hierarchy  - Error

    Hi Friends,
    When I opened the Dynamic Hierarchy to edit  ( Esubmit-->Manage open Dynamic Hierarchy) .. I am getting the error.
    This key is already associate with an element of this collection.
    Pls send your thoughts on this..
    Regards
    CSM Reddy

    Hi Guys,
    I found the  following relevant notes for this error.
    Visual Basic for Applications Reference - Visual Studio 6.0
    This key is already associated with an element of this collection (Error 457)
    A key is a string specified in the Add method that uniquely identifies a specific member of a collection. This error has the following cause and solution:
    u2022     You specified a key for a collection member that already identifies another member of the collection.
    Choose a different key for this member.
    For additional information, select the item in question and press F1.
    But how to  choose a different key for this member........
    Any thoughts on this pls..........
    Regards
    CSM Reddy

  • Dynamic Hierarchy - SAP BPC 7.5 MS

    Hello everyone. I am running SAP BPC 7.5 on the Microsoft Platform.
    The issue I am running into is that I have children entities that have two parent entities. The Entity Dimension has our traditional organization chart. However, our reports require an alternate hierarchy.
    Example:
    Company A is a child of Company ABC in the org chart
    however for reporting purposes
    Company A is a child of Company XYZ
    I need to pull in company XYZ in the report so that Company A is reported as being a part of it.
    I need to be able to set up something using a dimension property that will allow me to pull in this hierarchy into our reports, WITHOUT using expansions.
    The reason I cannot use expansions is some of the report will use the traditional org chart and the other portion of the report will use the alternate hierarchy.
    I there some way to do this without using expansions?
    I have setup a dimension property called "GROUP" that identifies the alternate hierarchy. However, the only way I know to pull it in the report is through the use of expansions in the "MembersSet" filter.
    I have also tried to use the "Dynamic Hierarchy Editor" only to discover that you have to define hierarchies for specific time periods, and still use expansions.
    Any suggestions? I feel like I am missing something.
    Thank you in advance.
    Will

    Hi Will,
    From what you describe I think an alternate (second/ H2) hierarchy is needed.
    You can try adding a second hierarchy to your Entity dimension member sheet (PARENTH2) to see if that meets your requirement.
    You can only create reports that have a hard-coded row or column key range or a dynamic row/column key range  defined in the memberset field.
    HTH,
    John

  • WriteTreeData: Error while saving Dynamic Hierarchy Changes

    Hi Experts,
    I'm encountering an error "writeTreeData: Error in clsMain::writeData : Type mismatch" when I save the changes that I've made in the Dynamic Hierarchy Editor, does anyone encountered this error before? I'm using BPC 7.0 MS.
    Thanks,
    MVS

    HI gUYS
    i've encountered this problem and my only solution is to see if all the fields in the above portion of the DHE is a base member
    example
    for my time dimension i've noticed that it is in the parent member
    time = 2008.yr
    if just replace it with
    time = 2008.dec
    and then it works
    Thanks
    CSD

  • Hierarchy selection tab missing in infopackage

    Hi Experts,
    i am looking how to load multiple hierarchies to Bi so inorder to know available hierarchies from OLTP in hierarchy selection tab in infopackage which was not available at all. i had only data selection tab.i am using version Bi 7.0
    how can i found  hierarchy selection tab in infopackage
    Regards,
    narasimha.

    Hierarchy loading is the same for info object which is created under the info object itself.
    loading is uploading the data to the hierarchy, creating hierarchy is you will be maintaing the structure of the hierarchy under that info object
    Are you sure you have Hierarchy maintained for your info object?
    If the hierarchies are maintained you will find the Bell type symbol under the info objects in info providers tab.
    As told by mti - drill down till you find the data source --right click on it and select create info package - here you can find the tab hierarchy selection tab (which is the second tab in that screen).
    Check the below link to know more abt hierarchies
    http://help.sap.com/saphelp_nw04/helpdata/en/0e/fd4e3c97f6bb3ee10000000a114084/frameset.htm

  • Dynamic bandwidth selection for PPPoE over Ethernet/VLAN

    Hello all, hope you are doing great.
    I'm planning to deploy PPPoE Server (Cisco Router 7609) for a ISP. This ISP will provide Internet connection for customer over Ethernet.
    I have to provide a solution to assign bandwidth to each customer by RADIUS and I find some clues that Dynamic Bandwidth Selection (DBS) should be the answer. Unfortunately, DBS only support PPPoA or PPPoE over ATM.
    If you have any experience with equivalent function, please help me. Thank you very much.
    Regards,
    Hiep Nguyen.

    Hiep,
    I think I have figured this out.  Here is the test config on my PPPoE server:
    int lo1
      ip address 172.25.25.25 255.255.255.255
    ip radius source-interface Loopback1
    aaa new-model
    radius-server host 172.16.1.55 auth-port 1812 acct-port 1813 key cisco$$$
    aaa group server radius RADIUS-ACT
     server 172.16.1.55 auth-port 1812 acct-port 1813  
    aaa authentication login default group RADIUS-ACT local
    aaa authorization exec default group RADIUS-ACT local
    aaa accounting exec default start-stop group RADIUS-ACT
    aaa accounting delay-start
    aaa authentication ppp default if-needed group RADIUS-ACT local
    aaa authorization network default group RADIUS-ACT local
    aaa accounting network default start-stop group RADIUS-ACT
    aaa accounting update periodic 5
    bba-group pppoe global
     virtual-template 1
    interface fa0/1
     pppoe enable group global
     ip address 172.30.0.1 255.255.0.0
     no shut
    interface Virtual-Template1
     mtu 1492
     ip unnumbered FastEthernet0/1
     peer default ip address pool GLOBALPOOL
     ppp authentication chap
    ip local pool GLOBALPOOL 172.30.0.2 172.30.127.255
    policy-map POLICE-128K
     class class-default
        police 128000
    policy-map POLICE-512K
     class class-default
        police 512000
    Here are the attributes on the radius server, for a group the PPPoE customer belonged to:
    Service-Type = Framed
    Framed-Protocol = PPP
    cisco-avpair="ip:sub-policy-In=POLICE-128K"
    cisco-avpair+="ip:sub-policy-Out=POLICE-512K"
    Here is the show policy-map on the virtual-access interface the client connected on:
    sho policy-map int virtual-a 3
     Virtual-Access3
      Service-policy input: POLICE-128K
        Class-map: class-default (match-any)
          1000 packets, 1402000 bytes
          5 minute offered rate 0 bps, drop rate 0 bps
          Match: any
          police:
              cir 128000 bps, bc 4000 bytes
            conformed 799 packets, 1120198 bytes; actions:
              transmit
            exceeded 201 packets, 281802 bytes; actions:
              drop
            conformed 0 bps, exceed 0 bps
      Service-policy output: POLICE-512K
        Class-map: class-default (match-any)
          911 packets, 1137746 bytes
          5 minute offered rate 0 bps, drop rate 0 bps
          Match: any
          police:
              cir 512000 bps, bc 16000 bytes
            conformed 799 packets, 1136178 bytes; actions:
              transmit
            exceeded 0 packets, 0 bytes; actions:
              drop
            conformed 0 bps, exceed 0 bps
    I was able to generate enough traffic with ping to meet the exceed action in and have it drop packets.

  • Dynamic Date selection inactive

    Hi,
    I am not able to give dynamic date selection in a variant. (D: Dynamic date calculation).The traffic light is displayed in red and there is no options such as
    current date etc. is there any need to do some settings to get these options.

    Hi,
    have a look at the below link..  ( they have mentioned the steps of customer exit variable fassigning for reporting agent)
    https://websmp110.sap-ag.de/~form/sapnet?_FRAME=CONTAINER&_OBJECT=011000358700003598422003E
    Regards,
    Siva.

  • Dynamic parameter selection from infoview not storing the sql password

    We are having the problem of dynamic parameter selection from infoview not storing the sql password as it does for the actual report. We are using Crystal Reports XI Release 2 version 11.5.3.438 (Not sure of SP level, asked in separate thread).
    To be more specific.
    We have created a report that dynamically populates the parameters of the report by pulling the records from the Informix sql database and allowing selection from there.
    In the Central Management Console for the report object we have set as follows:
    Process - Database:
    Use original database logon information from the report - the sql username and pw etc
    Use same database logon as when report is run
    Process - Parameters
    In selecting a default selection there is the option to put in the sql password, however, this does not stick and clears after update.
    As such the end result is that every time this report is run from infoview and a user chooses a parameter (there are 5), crystal goes through some timeout for about a minute or so and then requests the sql password, if a user then selects the next parameter, the same timeout and password dialog appears.
    We need the crystal report to handle to the sql password for fetching the parameters as well as for the database section of running the report, however, the parameters insists on the end user always putting the password in.
    This is 100% replicatable on our system.
    Any way that we can fix this?
    Will an update fix this issue? If so could you please advise which one?
    Thanks

    Hi,
    I am having the exact same problem. Any help?
    And what does "Use same database logon as when report is run" mean? For me that would be that no prompt is needed for getting values in a dynamic parameter...
    Regards
    Magnus

  • Dynamic RadioList selection

    I am building a radio list dynamically in TOOL code based upon certain
    criteria. I can get the list built no problem. But, I want to "select" a
    certain element based on an attribute I check on the object. So the element
    I want to appear selected may be element 2 or element 5 or element x. Has
    anyone ever done this? I can't seem to find anything in the Forte help that
    will allow me to do this?? Any help would be greatly appreciated.
    Thanks!!
    Doug Scurr
    HealthPartners
    8100 34th Avenue South
    Minneapolis, MN 55440-1309
    (612)883-7317
    [email protected] <[email protected]>

    Dale,
    I knew it would be something easy!! I obviously can't read very well!!
    Thanks for the help!!
    Doug Scurr
    HealthPartners
    8100 34th Avenue South
    Minneapolis, MN 55440-1309
    (612)883-7317
    [email protected] <[email protected]>
    -----Original Message-----
    From: Dale V. Georg [SMTP:[email protected]]
    Sent: Tuesday, April 27, 1999 2:34 PM
    To: [email protected]
    Cc: [email protected]
    Subject: Re: Dynamic RadioList selection
    > [email protected] wrote:
    >
    > I am building a radio list dynamically in TOOL code based upon
    certain
    > criteria. I can get the list built no problem. But, I want to
    "select" a
    > certain element based on an attribute I check on the object. So
    the element
    > I want to appear selected may be element 2 or element 5 or element
    x. Has
    > anyone ever done this? I can't seem to find anything in the Forte
    help that
    > will allow me to do this?? Any help would be greatly appreciated.
    > Thanks!!
    This should be as simple as setting the IndexValue of the radio list
    to
    the item that you want to have selected. For example:
    self.<theRadioList>.IndexValue = 2;
    to select the second item. Make sure your window is already open
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    you do this, though. ie, make sure self.Open() has already been
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    Hope this helps,
    Dale
    ===================================
    Dale V. Georg
    Senior Systems Analyst
    Indus Consultancy Services
    [email protected]
    ===================================
    To unsubscribe, email '[email protected]' with
    'unsubscribe forte-users' as the body of the message.
    Searchable thread archive <URL:http://pinehurst.sageit.com/listarchive/>

  • Report Designer - Summary page based on 3 queries with dynamic hierarchy?

    Dear All,
    I am trying to build a workbook based on 3 queries with a summary page that pulls in the query data into one page.
    Each query is based on one key figure that is split by profit centre hierarchy.
    i.e.
    Turnover
    -Profit Centre Node A
    -Profit Centre Node B
    -Profit Centre Node C
    > Profit Centre C1
    > Profit Centre C2
    The user can dril-down into each query at whatever level of the PC Hierarchy they wish.
    My issue is trying to structure a dynamic summary page that pulls in all rows from the individual queries regardless of the number of profit centre hierarchies contained in each. i.e. The summary could have 5 PCs for queries 1,2 & 3 in one execution, but then 10 for all queries in another execution.
    Question:
    Can report designer be used to make a dynamic summary sheet that will capture all rows from the individual query? or would an excel macro summary be the only way of doing this?

    Hi Ingo,
    After much testing and looking into trace etc. we have got this thing to behave as desired. Basically, following two things,
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    - making sure that on query Cost center restriction is placed in Characteristic Restriction area of Filter tab of query, as oppose to default value area filter tab.
    With above in place, the published report in infoview behave as desired, i.e. proper hierarchy structure in cost center prompt and group tree and only desired nodes showing on report.
    Thank you for all you pointers
    Regards
    IMS

  • Printing a Dynamic Hierarchy in BPC 5.1

    Hi,
    I am trying to print the graphic representation of a dynamic hierarchy in BPC 5.1.  There is no apparent way to print the hierarchy from the DHE and when I check the documentation, they suggest the use of a EVDRE report.  However, based on my testing, I can't seem to see any function in EVDRE that would be able to pull the graphical representation of the org structure that I have keyed into DHE out.  Am i missing something here?  Appreciate any help and feedback, thanks.
    Best Regards
    Adrian Yeo

    Hi Adrian,
    We have the same problem. We need to have a report with the perimeter (DHE) of the companies as intuitive and graphical as possible. Have you solve your problem?
    any idea of someone?
    thanks,
    Jorge

  • BMBC Dynamic Date selection Variant

    Hello Team,
    I want to create variant in BMBC -Batch Information Cockpit with Dynamic Date Selection. But it do not find the screen the to set-up variant attributes
    This is the field where I want to have dynamic date selection, 1st Day of the month to Last day of the month.
    Field name and program
    I am using SE80
    As you can see screen number 0100 is not showing up. and I have gone though all available screen but i could not find the field.
    Please advise if dynamic date selection for this field is possible at all or there is other way.
    Thanks

    I don't think that it is possible to have dynamic date selection here. The whole selection screen is just dynamic, it has only place holders and you define in customizing which field is on the selection screen.
    You actually save a selection variant via this extra big button for selection variants, which is quite different to the disc icon where you usually save your selection variants and where  you have the option to define dynamic date fields.

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