Easier way to check day of the week

Hi, I was wondering if there's a easier way where I can check the day of the week on my MacBook Pro (AKA, 1/30/13 is a  Wednesday).It takes time to open up the calender app so I was wondering if there's a easier way to check like Windows system where you just click the date/time on the right hand corner and it will bring up a mini calender.

system preferences> under system, date and time. check show day of the week.

Similar Messages

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    Is there a way to change it back to Monday as the first day of the week?

    Hi! The only way I know of is changing the screen resolution. Tom

  • Is there a way to change the start day for the week?

    So I really like the "Insert Categories from the following" functionality of the Reorganize tool, and I fell in love with it's ability to break down by date automagically. I've encountered one problem with my use of it, though: I start my "work week" on Sunday, and it defaults to Monday as the first day of a week without any seeming way to change it to Sunday. Is there a way to do this?

    Hi Christopher,
    The WEEKDAY function allows specifying either Sunday or Monday as the first day of the week:
    WEEKDAY
    The WEEKDAY function returns a number that is the day of the week for a given date. WEEKDAY(date, first-day)
      date:  The date the function should use. date is a date/time value. The time portion is ignored by this function.
      first-day: An optional value that specifies how days are numbered.
    Sunday is 1 (1 or omitted):  Sunday is the first day (day 1) of the week and Saturday is day 7.
    Monday is 1 (2):  Monday is the first day (day 1) of the week and Sunday is day 7. Monday is 0 (3):  Monday is the first day (day 0) of the week and Sunday is day 6.
    But I think you are referring to the first day of the 'workweek', for which I do not see a means of defining a custom value.
    Since you want to 'insert categories', though, you could easily define your own, using WEEKDAY(date) or WEEKDAY(date,1), plus an IF statement to return the category label appropriate to the day. Here's one for a Sunday to Thursday work week. Dates are in column A, the formula is in whichever column you want as the Category column. For the example, I've placed it in column B.
    B2, and filled down: =IF(WEEKDAY(A)<6,"Work","Off")
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    A10 was left blank intentionally, to determine if the lack of data resulted in an error. The Warning message, flagged by the blue 'warning' triangle, is "The formula uses a number in place of a date." The 'date' assigned to this numerical value of zero was a Friday, but I'm not certain when. Probably best to avoid extra rows with no date shown.
    Regards,
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  • Is there any way to sort the alarms differently in the Clock app? I have alarms for multiple days during the week, all of which overlap each other. It makes no sense to me that the alarms sort by time and not day. Thanks!

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  • Oracle returning incorrect day of the week

    Hi there,
    I have a table named Performance, which includes a date field named PDATE, some other attributes such as title, etc, and a field named WEEKDAY, which includes the numerical value for the day of the week. Here is an example:
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    P#
    THEATRE#
    WEEKDAY
    PDATE
    PHOUR
    PMINUTE
    COMMENTS
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    1
    1
    1
    02-MAR-10
    19
    30
    Normal evening time
    2
    1
    1
    2
    03-MAR-10
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    30
    Normal evening time
    58
    6
    6
    3
    04-MAR-10
    19
    30
    Normal evening time
    5
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    4
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    30
    Normal evening time
    I went to verify the day of the week in a calendar (in fact I checked more than one) and I noticed that the Weekday value seems incorrect. For instance, the 2nd of March was a Tuesday so I would expect WEEKDAY to say 3 (considering Sunday to be the 1st day of the week, which is the universal norm), or perhaps 2 (considering Monday to be the 1st day of the week).
    First thing that came to mind is, since the WEEKDAY is a number field which has been pre-populated, the person who populated it made a mistake.
    So I went to verify this by running a query that would give me the correct day of the week by extracting it from the PDATE field:
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    to_char(to_date(pdate,'DD/MM/YYYY'),'DY') weekdaycalc, weekday
    FROM ops$yyang00.Performance
    ORDER BY pdate
    And to my astonishment, I got the following table as a return:
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    YEAR
    WEEKDAYCALC
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    2010
    SUN
    1
    03-MAR-10
    2010
    MON
    2
    04-MAR-10
    2010
    TUE
    3
    05-MAR-10
    2010
    WED
    4
    06-MAR-10
    2010
    THU
    5
    07-MAR-10
    2010
    FRI
    6
    08-MAR-10
    2010
    SAT
    7
    09-MAR-10
    2010
    SUN
    1
    10-MAR-10
    2010
    MON
    2
    As you can see, all of the above WEEKDAYCALC values are incorrect, and seem to match the incorrect values in WEEKDAY.
    I could perhaps understand some weird WEEKDAY numbering if there is some general database setting where I could specify any day of the week to be the first day. However, I can't think of any logical explanation on why Oracle would call a Tuesday Sunday.
    Could someone please advise what I mght be doing wrong? This is driving me insane!
    Thank you in advance for all the help and support.
    Regards,
    P.

    Hi,
    1bded5c7-e555-4306-ac86-45da83dff439 wrote:
    Thanks both Frank and Solomon for the help. I am quite new to Oracle and I feel you folks went the extra mile on the explanation
    Based on your explanations, I changed the formula so the date format would be processed as YY rather than YYY.
    SELECT DISTINCT pdate, EXTRACT(year from pdate) year,   
    to_char(to_date(pdate,'DD/MM/YY'),'DY') weekdaycalc, weekday   
    FROM Performance   
    ORDER BY pdate  
    And I got the correct values now:
    PDATE
    YEAR
    WEEKDAYCALC
    WEEKDAY
    02-MAR-10
    2010
    TUE
    1
    03-MAR-10
    2010
    WED
    2
    04-MAR-10
    2010
    THU
    3
    05-MAR-10
    2010
    FRI
    4
    06-MAR-10
    2010
    SAT
    5
    07-MAR-10
    2010
    SUN
    6
    08-MAR-10
    2010
    MON
    7
    The interesting bit here, is the original WEEKDAY field, which clearly has been created with the same mistake I did (this whole table wasn't created by me). I reckon I spotted a design bug.
    Regards,
    P.
    No; you're still calling TO_DATE on something that is already a DATE, and you're still using an implicit conversion (only now you're using a format such that the current NLS settings don't cause you to get punished.  If your DBA changes the NLS settings next week, then you will have similar errors again.)
    If you want to see what day of the week pdate is, then use:
    TO_CHAR (pdate, 'DY')
    or, to make it NLS-independent:
    TO_CHAR (pdate, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH')
    This is simpler than what you posted, it's more efficient and easier to debug and to maintain, and it also gets the results you want in all cases.
    One more time: TO_DATE, as the name hints, converts something (a VARCHAR2, to be precise) TO a DATE.  If pdate is already a DATE, then what do you need to convert?  You're implicitly converting a DATE to a VARCHAR2, then explicitly converting that VARCHAR2 back to a DATE, and then calling TO_CHAR.  That's 3 function calls (1 of them error prone) where only 1 is needed.
    Also if you ever have to reconcile 2-digit years with 4-digit years (and, again, in this problem you don't) the correct way is to convert the 2-digit year to a 4-digit year, not vice-versa.
    Calling Tuesday the 1st day of the week could make sense in a particular application.

  • Day of the week?

    Is there a way to check if the entered date is a certain day of the week?
    I just would like to alert the user if the date that was entered, which i have format "m/d/yy" on the format properties, that the date they entered is not a Sunday date. I tried to use the util.scand function but then was unable to figure out how to script it to look for the value to be Sunday.
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  • Add recurring entries for days of the week

    Hello,
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    If B1 says "Tuesday" can I have one of the cells in that column automatically read "Scarlett" each week?
    I'd like to have it so that all I have to do is put Tuesday up at the top and it automatically creates a list of my Tuesday dogs for me, Lulu, Scarlett, Mark, Dani, Zoe, Sharky, etc.

    Ah, those famous words, "All I have to do..."
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    Table 2 (Index) creates a set of lookup tables from the information recoded on Data. Each table contains a column for the day listing a serial number to represent each dog scheduled to be walked that day and the column containing the names of the dogs, plus any intervening columns. The list of dogs has bee moved to the right as I was considering using VLOOKUP, which requires the search values to be listed to the left of the result values.
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    Index:
    A2: =IF(Data::B,MAX(A$1:A1)+1,"")
    Fill down to row 10, then select A2:A11 and fill right to column G.
    H2: =Data::A
    H2 (enhanced): =IF(LEN(Data::A)>0,Data::A,"")
    Fill down to H11
    (Enhanced version prevents showing a zero on rows where no dog's name has been entered on Data.)
    Days:
    Make a seven column table with one header row.
    A1: Sunday
    Fill right to G1.
    A2: =IF(ROW()-1>MAX(Index :: A),"",LOOKUP(ROW()-1,Index :: A,Index :: $H))
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    To do this:
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    Click one of the column reference tabs to select that column.
    Click the same tab a second time and drag down until the column separates from the rest of the table. Continue to drag until the column is completely separated from the table, then release the mouse button.
    Repeat for the rest of the columns to be separated.
    Each of these tables may be placed on a separate sheet to make printing a single list easier if desired.
    Regards,
    Barry

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