Error Accessing an Oracle Function

Question

Hi There,
I am trying to access an oracle function and getting an
error.
CREATE OR REPLACE FUNCTION simple RETURN VARCHAR2 IS
BEGIN
RETURN 'Simple Function';
END simple;
<cfstoredproc procedure="simple" datasource="MySource"
returnCode ="no">
<CFPROCRESULT name="simple_function">
</cfstoredproc>
Error:
Error Executing Database Query. [Macromedia][SequeLink JDBC
Driver][ODBC Socket][Oracle][ODBC]Syntax error or access violation.
I do have access to this function. I tried it from SQL Plus
and it works fine.
any help in this will be highly appreciated.
Regards,

Answer 1

As per Adam Cameron advice, I changed my SQL function:
CREATE OR REPLACE FUNCTION simple RETURN VARCHAR2 IS
a varchar2(10) := '';
BEGIN
select 'Simple' into a from dual;
Return a;
END simple;
As per paross1 advice, I changed my code to:
<cfstoredproc procedure="simple" datasource="MySource"
returnCode ="yes">
<CFPROCRESULT name="simple_function">
</cfstoredproc>
I am still getting the following error:
Error Executing Database Query. [Macromedia][SequeLink JDBC
Driver][ODBC Socket][Oracle][ODBC]Syntax error or access violation.
The error occurred on line 53.
Any advice will be highly appreciated.