Exception Handling related problem

Question

Can anybody tell me why it is not giving ArithmeticException.
package pckg1;
* @author anil_saini
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import java.io.FileNotFoundException;
public class Average7 {
     public static void main(String[] args) throws InterruptedException,FileNotFoundException {
     try {                                                      // (1)            System.out.println(printAverage(100, 0));                                  // (2)
     } catch (ArithmeticException ae) {                         // (3)
     Thread.sleep(1000);
          ae.printStackTrace(); // (4)
System.out.println("Exception handled in " + // (5)
     "main().");
     finally {
     System.out.println("Finally in main()."); // (6)
     System.out.println("Exit main()."); // (7)
public static int printAverage(int totalSum, int totalNumber) {
     int average=0;
     try {                                                      // (8)
average = computeAverage(totalSum, totalNumber); // (9)
     System.out.println("Average = " + // (10)
     totalSum + " / " + totalNumber + " = " + average);
     return average;
     } catch (IllegalArgumentException iae) {                   // (11)
          iae.printStackTrace(); // (12)
System.out.println("Exception handled in " + // (13)
     "printAverage().");
     } finally {
System.out.println("Finally in printAverage()."); // (14)
     return average;
     }     // (15)
public static int computeAverage(int sum, int number) {
     System.out.println("Computing average.");
     if (number == 0) // (16)
throw new ArithmeticException("Integer division by 0");// (17)
     return sum/number; // (18)
Output
=======================
Computing average.
Finally in printAverage().
0
Finally in main().
Exit main().

Answer 1

Because return statements in finally blocks are evil!
int average = 0;
try
{ // (8)
     average = computeAverage(totalSum, totalNumber); // (9)
     System.out.println("Average = " + // (10)
               totalSum + " / " + totalNumber + " = " + average);
     return average;
catch (IllegalArgumentException iae)
{ // (11)
     iae.printStackTrace(); // (12)
     System.out.println("Exception handled in " + // (13)
               "printAverage().");
     throw new IllegalArgumentException();
finally
     System.out.println("Finally in printAverage()."); // (14)
     return average; // (15)
}You get an exception at (9), but finally is guaranteed to be executed, so the JVM executes it. Now you return in your finally block (15), and the JVM is left with the choice of executing your return statement or propagating the exception. Since, as said, finally is guaranteed to be executed, it returns and swallows the exception.
That's why IMHO return statements in finally blocks should not be allowed.
(Some compilers issue warnings)
If you move your return statement out of the finally block, it will work as you'd expect it.