Exiting the loop.....

Question

I am writing an app that reads an arbitrary # of int's ranging from 0 to 50 inclusive and counts how many times each number is entered. After the input has been processed - prints all the values and number of occurances for each number.
Here is what I have so far. I am having trouble exiting the do..while loop without getting errors. I don't want the user to have to reply "y" or "n" after each entry. Any ideas?????
import cs1.Keyboard;
public class IntegerCount
public static void main (String[] args)
final int MIN = 0;
final int MAX = 50;
int[] numbers = new int[MAX];
int[] numbers2 = new int[MAX];
int index = 0;
int num = 0;
char stop;
System.out.println ("Enter a number between 0 and 50: ");
System.out.println ("To summarize your values enter the = ");
do
stop = Keyboard.readChar();
num = Keyboard.readInt();
numbers[index] = num;
index++;
while ((num>=0 && num<=50) && stop != '=');
index = 0;
for (int i = index; index < numbers.length; index++)
if (numbers[index] != 0)
System.out.println (index + " " + numbers[index]); //test numbers[]
numbers2[numbers[index]] = numbers2[numbers[index]] + 1;
index = 0;
for (int i = index; index < numbers2.length; index++)
if (numbers2[index] != 0)
System.out.println (index + " " + numbers2[index]);

Answer 1

It looks like the limitation requiring the entry of a y or an
n is contained in the Keyboard class. If you will
substitute this code for the do loop, it will take care of
the problem:
String s = "";
int num = 0;
int total = 0;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
do {
     try {
          s = br.readLine().trim();
     catch (IOException ioe) {
          ioe.printStackTrace();
     if (s.charAt(0) != '=') {
          try {
               num = Integer.parseInt(s);
          catch(NumberFormatException nfe) {
               System.out.println("Invalid number.  Zero substituted.");
               num = 0;
          total += num;
while(s.charAt(0) != '=' && (num >= 0 && num <= 50));Mark