Explain Method Overriding with respect to following program

Question

Hello all,
Can anybody explain method overriding with respect to following program.
I couldn't understand output of the program
class Parent
public String s = "This is Parent";
private void method1()
System.out.println("Parent's method1()");
public void method2()
System.out.println("Parent's method2()");
method1();
class Child extends Parent
public String s = "This is Child";
public void method1()
System.out.println("Child's method1()");
public static void main(String args[])
Parent p = new Child();
p.method2();
System.out.println(p.s);          
output:
Parent's method2()
Parent's method1()
This is Parent

Answer 1

In method2() of parent class, there is a call to method1().
My doubt is how it will resolve which method to call i.e., method1() in parent or child class.
In other words...
if method1() in parent class is declared as public or protected then output of above program is
parent's method2()
child's method1()
But if method1() in parent class is declared as private then output of above program is
parent's method2()
parent's method2()
..no matter with what object/reference variable you are calling method2()
What is the reason behind it??