Explain plan using v$sql_plan

Question

Hi can I get explain plan by using v$sql_plan. I was trying to do:
select e.first_name, e.last_name, d.department_name from employees e
left join departments d on e.department_id=d.department_id;
select * from(select sql_id, hash_value from v$sql where sql_text = 'select e.first_name, e.last_name, d.department_name from employees e
left join departments d on e.department_id=d.department_id' order by last_load_time desc)where rownum=1
this select return me 0 records :(
so i cant do this :(
select operation, object_owner, object_name, object_type,options, cost, cardinality, bytes, cpu_cost, io_cost, depth from v$sql_plan where SQL_ID='value1' and HASH_VALUE='value2'
I dont know what am I doing wrong

Answer 1

bcm@bcm-laptop:~$ sqlplus hr/hr
SQL*Plus: Release 11.2.0.1.0 Production on Tue Jul 31 11:02:04 2012
Copyright (c) 1982, 2009, Oracle.  All rights reserved.
Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
11:02:05 SQL> set autotrace trace explain
11:02:23 SQL> select e.first_name, e.last_name, d.department_name from employees e
left join departments d on e.department_id=d.department_id;
11:02:38   2 
Execution Plan
Plan hash value: 2296652067
| Id  | Operation        | Name      | Rows  | Bytes | Cost (%CPU)| Time
|
|   0 | SELECT STATEMENT   |           |   107 |  3638 |     7  (15)| 00:00:01
|
|*  1 |  HASH JOIN OUTER   |           |   107 |  3638 |     7  (15)| 00:00:01
|
|   2 |   TABLE ACCESS FULL| EMPLOYEES      |   107 |  1926 |     3   (0)| 00:00:01
|
|   3 |   TABLE ACCESS FULL| DEPARTMENTS |    27 |   432 |     3   (0)| 00:00:01
|
Predicate Information (identified by operation id):
   1 - access("E"."DEPARTMENT_ID"="D"."DEPARTMENT_ID"(+))
11:02:39 SQL>