Extract root name of an XML packet

Question

Hi,
I thought this would be simple, but cant work out how I can extract the name of the root node for an XML packet
I was planning just to use xmltype.extract, but I cant work out the xpath paameter to get this to work.
Any of you clever folks got an idea?

Answer 1

how I can extract the name of the root node for an XML packettry
Connected to Oracle Database 10g Enterprise Edition Release 10.2.0.1.0
Connected as scott
SQL>
SQL> with t as
  2   (select xmltype('<RESULTS>
  3  <ROW>
  4  <COLUMN NAME="ID">12688f8ac8aa6310VgnVCM10000078ccc70a____</COLUMN>
  5  <COLUMN NAME="BRANCH_NAME">Brooklyn</COLUMN>
  6  </ROW>
  7  </RESULTS>') xml
  8      from dual)
  9  select x.*
10    from t,
11         xmltable('for $i in $d/*
12             return element r {
13               element tag_name    {local-name($i)}, element tag_name2 {name($i)}
14            }' passing t.xml as "d" columns tag_name
15                  varchar2(30) path 'tag_name',
16                  tag_name2 varchar2(30) path 'tag_name2') x
17  /
TAG_NAME                       TAG_NAME2
RESULTS                        RESULTS
SQL>