Extract the Files names Procedure for Linux????

hi,
i have installed ODI 11g on windows. & load the multiple file. as you can see this procedure (script) is used to get the files name. using technology "Operating System"
cmd /c dir D:\test\*.* /b /a:-d > D:\\Filesname.txt. it working fine on windows. Now i want to load these files names that are on Linux Server.
what will be the script for that
as my files directory name is Test>>>>containing the files
Filename.txt>> Extract the names of files in test directory.
In Linux.
Thanks,
Regards

Did you use the tool "OdiOSCommand" ?
In the first parameter, you write the LS command :
ls -1In the second parameter, you write the location of the target file, with the directory :
/home/your_user/test/Filename.txt With the 4eme parameter, you can decide to append the list in the existing file, or override the file.
In the 5eme parameter, you set the directory :
/home/your_user/test/If the directory is defined on your topology as a physical and a logical schema, you can use the logical schema in the parameters :
for instance :
<%=odiRef.getSchemaName("FILE_TEST", "D")%>/instead of "/home/your_user/test/"
where FILE_TEST is the name of the logical schema
Thanks to that, you will be able to use different directories depending on your contexts.

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Hello All
Here´s what we´re trying to do:
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Sales_2013-02-04.csv
Sales_2013-02-03.csv
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Sales_2013-02-01.csv
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If we could get the proper file name in each row (from where they got extracted), we could split the column and get the date from there. But I don´t know how put the filename there properly.
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let
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in
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in
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Finally, I need to expand out the columns in the table, which I can do by clicking on the expand icon next to the Content column header. The resulting query looks like this:
let
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in
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Hi,
There sound like functions in say LabVIEW or CVI.
I have attached a small example which may help. (I have not allowed for any error trapping, if say you dont find the file and cancel)
Regards
Ray Farmer
Message Edited by Ray Farmer on 10-16-2006 10:04 PM
Regards
Ray Farmer
Attachments:
Sequence File1.seq ‏33 KB

File adapter polling and getting the file name 11g Jdeveloper

I am using JDeveloper 11g. My process is something like;
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I have to get the file name that is read by file adapter.
How to do that? Any help is appreciated.
I have seen couple of answers like bellow in forum but did not help me much
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2. Open the Receive activity in your bpel project.
3. Scroll down to jca.file.FileName and double click on the value column, click on the browse button (...), select Variable, then click the search icon
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*************************/

hi,
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1. create a variable of type string
2. after configuring the file adapter , go to corresponding receive activity , go to properties tab
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HTH,
Ketan

Need to get the file name at the time of polling

Hi...
I am transferring the data from csv file to database.
I put the file in a directory. File adapter will read that file for every 2 minutes. I have a column name in database to which I need to map the incoming file name.
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Thank you very much...any help is appreciated.

This is a very simple task in JDeveloper 11g, file adapters are linked to the receive activity, here there is a tab called Properties which you can use to extract the file name. Please follow the steps below:
1. Create a Simple Type variable of string type, call it fileName_var or any name you wish.
2. Open the Receive activity in your bpel project.
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4. Locate your recently created variable
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Hope this helps.
Jhon Castro

Changing the file name dynamicallly in file Adapter

Hi i want to change the file name directly from Java Mapping in the file adapter
for this i have written this code
DynamicConfiguration dynamicConfiguration = (DynamicConfiguration)map.get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
 DynamicConfigurationKey keyFile = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");
 DynamicConfigurationKey keyDir = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","Directory");
 dynamicConfiguration.put(keyFile,fileName);
 dynamicConfiguration.put(keyDir,outputpath);
but it gives a null pointer exception at dynamicConfiguration.put(keyFile,fileName);
please suggest.
regards
Nilesh Taunk.

Hi Nilesh,
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Just check this link out,
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Regards,
Bhavesh

Create a derived column based on a value within the file name

I am importing a CSV file which is easy enough, but I have an issue where I need to manufacture a couple of column values based on the filename of the input. So this same process will import different types of records to the same table in sql server.
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For instance, say I can use the same package to input two different CSV files. One is named Input_M02_Data.csv and one named Input_B15_Data.csv. I need to create a derrived column and store the record code there (i.e.: M02 or B15) based
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fyi-
I also need to create a second column for Dept based off of the file name as well. M02 is dept 45 and B15 is dept 99 which I also need to insert into this table when I import the data from the .csv file.
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Hi Jason,
According to your description, you want to add two derived columns based on the file name to also insert into table. One stores the value between two “_” within file name, another stores the department based on that column.
If in this scenario, we can add a variable FileName that stores the filename, then add the two variables as derived columns like below in the Derived Column Transformation:
Name:
SUBSTRING(@[User::FileName],FINDSTRING(@[User::FileName],"_",1)+1,FINDSTRING(@[User::FileName],"_",2)-(FINDSTRING(@[User::FileName],"_",1)+1))
Dept:
@[User::Name] =="M02"?"dept 45":@[User::Name] =="B15"?"dept 99":"dept 00"
The following screenshot is for your reference:
If there are any other questions, please feel free to ask.
Thanks,
Katherine Xiong
If you have any feedback on our support, please click
here.
Katherine Xiong
TechNet Community Support

Get the File Name from DB

I have values stored in the database with relative ads
"/partners/41394/Ads/offers_41394_1by2.jpg"
I only need to extract the file name itself any time this
kind of record is encountered. I am not interested in the relative
path of the record.
eg extract only "offers_41394_1by2.jpg"
Thanks

List functions are very helpful, be sure to check out the
full range in
the documentation.
listLast("/partners/41394/Ads/offers_41394_1by2.jpg","/")

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Hi,
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data: begin of i_req occurs 0,
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endselect.
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if sy-subrc = 0.
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 EXPORTING
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 INFOCUBE = <datatargetname>
 EXCEPTIONS
 REQUEST_NOT_IN_CUBE = 1
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 REQUEST_ALREADY_AGGREGATED = 3
 REQUEST_ALREADY_COMDENSED = 4
 NO_ENQUEUE_POSSIBLE = 5
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endif.
let me know if you get any problem in this logic.
regards,
Raju

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In the SAP system, there is no uniform rule for the structure of the actual text key Textname. However, in order to be able to maintain the structures and fields, you have to know what the structure of text name as well as the values for text object and text ID are.
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Cannot Open Attachments in PDF
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Extract the Files names Procedure for Linux????

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