Extract values with Regular Expression

How to extract values into [ ] using regular expression.
With data As
Select 'AAAAAA[10] AAA: 19C' Txt From Dual Union all
Select 'XX[450]-10A' Txt From Dual Union all
Select '[5]AVC19C' Txt From Dual Union all
Select 'FVD[120]D2AC' Txt From Dual
)I hope this return
10
450
5
120Thanks in advanced

user11118871 wrote:
Thanks for all.
Hi BluShadow, can you explain what this is doing!?
ThanksSure.
Search for ----------------|           /------- Replace the found pattern in the search string with backreference 1
                     /------------\   /\       (the first thing backreferenced in the search string)
regexp_replace(txt, '^.*\[(.*)\].*$','\1')
                     |\/\/\--/\/\/|
                     | \ \ / \ \|
                     | | | | | |\- End of string
                     | | | | | |
                     | | | | | \- Any number of characters
                     | | | | |
                     | | | | \- Right square bracket (escaped)
                     | | | |
                     | | | \- any characters (backreferenced by round brackets)
                     | | |
                     | | \- Left square bracket (escaped)
                     | |
                     | \- Any number of characters
                     |
                     \- Start of stringEdited by: BluShadow on Jun 29, 2009 2:19 PM

Similar Messages

Extracting Content with Regular Expressions

hi all,
i am trying to extract some content from a text file using regular expressions but i am unable to get the exact match that i am expecting
here is the sample text
The passage begins like that (something in text form (some
more embedded text) remaining outer text).
i am expecting to get the following match,
(something in text form (some
more embedded text) remaining outer text)
but my regular expression just returns me a broken section of the text as this one
(something in text form (some
more embedded text)
how can i get this fixed, i mean how can i match evenly across the open parenthesis.
here is my broken reg exp (?:$(?:\\.|[^$\\])*\))
thanks for any help!

Cross-posted. See duplicate http://forum.java.sun.com/thread.jspa?threadID=653042&tstart=0

How to get year value using regular expression

Hi,
I have a different format of date such as 2004-01-03, 2003/01, 05/06/2005, 06-05-2007
How can I get only the year value using regular expression? The year value is always in 4 digits
Thanks in advance

sabre150 wrote:
JosAH wrote:
\d{4}Is this the Jos I knew who poured scorn on anything to do with regex? Is this the Jos I knew who said that the 'pimping lemon' stopped regex being of any real use?It wasn't me; honest, I'm innocent: one of my parrots walked over my keyboard; I wouldn't be able to type such nonsense; naughty parrot! No cookie!
kind regards,
Jos
ps. regexes can only survive the baby-pumping-lemma; they all die a horrible death with the real-men-pumping lemma! So there.

Grouping & Back-references with regular expressions on Replace Text window

I really appreciate the inclusion of the Regular Expressions in the search & replace feature. One thing I am missing is back-references in the replacement expression. For instance, in the unix tools vi or sed, I might do something like this:
s/$firstPart$ $secondPart$ $oldThirdPart$/\2 \1 newThirdPart/g
which would allow me to switch the places of firstPart and secondPart, and totally replace thirdPart. If grouping and back-references are already present in the Replace Text window, how does one correctly invoke them?

duplicate of Grouping & Back-references with regular expressions on Replace Text window

Assistance with Regular Expression and Tcl

Assistance with Regular Expression and Tcl
Hello Everyone,
I recently began learning Tcl to develop scripts for automating network switch deployments.
In my script, I want to name the device with a location and the last three octets of the base mac address.
I can get the Base MAC address by :
show version | include Base
Base ethernet MAC Address       : 00:00:00:DB:CE:00
And I can get the last three octets of the MAC address using the following regular expression.
([0-9a-f]{2}[:-]){2}([0-9a-f]{2}$)
But I have not been able to figure out how to call the regular expression in the tcl script.
I have checked several resources but have not been able to figure it out. Suggestions?
Ultimately, I want to set the last three octets to a variable (something like below) and then call the variable when I name the switch.
set mac [exec "sh version | i Base"] (include the regular expression)
ios_config "hostname location$mac"
Thanks for any assistance in advance.
Chris

This worked for me.
Switch_1(tcl)#set result [exec show ver | inc Base]
Base ethernet MAC Address       : 00:1B:D4:F8:B1:80
Switch_1(tcl)#regexp {([0-9A-F:]{8}\r)} $result -> mac
1
Switch_1(tcl)#puts $mac
F8:B1:80
Switch_1(tcl)#ios_config "hostname location$mac"
%Warning! Hostname should contain at least one alphabet or '-' or '_' character
locationF8:B1:80(tcl)#

How to search with regular expression

I make pdx files so that I can search text quickly. But Acrobat doesn't provide a way to search with regular expression. I'm wondering if there is a way that I don't know to search for regular expression in Acrobat Pro 9?

First, Acrobat must "mount" the PDX.
As "Find" does not use the cataloged index, use Shift+Ctrl+F to open the advanced search dialog.
It may be helpful to first enter Acrobat Preferences and for the Search category tick "Always use advanced search options".
Back to the Search dialog - use the drop down menu for "Look In" to pick "Select Index" then, if no PDXs show, click the Add button.
In the Open Index File dialog, browse to the location of the desired PDX and select it.
OK out and use "Return results containing" to pick a "Match ..." requirement or Boolean.
To become familiar with query syntax, for Acrobat, it is good to review Acrobat Help.
http://help.adobe.com/en_US/Acrobat/9.0/Professional/WS58a04a822e3e50102bd615109794195ff-7 c4b.w.html
Be well...

Problem with Regular Expression

Hi There!!
I have a problem with regular expression. I want to validate that one word and second word are same. For that I have written a regex
Pattern p=Pattern.compile("([a-z][a-zA-Z]*)\\s\1");
Matcher m=p.matcher("nikhil nikhil");
boolean t=m.matches();
if (t)
          System.out.println("There is a match");
     else
          System.out.println("There is no match");
The result I am getting is always "There is no match
Your timely help will be much appreciated.
Regards

Ram wrote:
ErasP wrote:
You are missing a backward slash in the regex
Pattern p = Pattern.compile("([a-z][a-zA-Z]*)\\s\\1");
But this will fail in this case.
Matcher m = p.matcher("Nikhil Nikhil");It is the reason for that *[a-z]*.The OP had [a-z][a-zA-Z]* in his code, so presumably he know what that means and wants that String not to match.

Get the string between li tags, with regular expression

I have a unordered list, and I want to store all the strings between the li tags (<li>.?</li>)in an array:
<ul>
<li>This is String One</li>
<li>This is String Two</li>
<li>This is String Three</li>
</ul>
This is what have so far:
<li>(.*?)</li>
but it is not correct, I only want the string without the li tags.
Thanks.

No one?
Anoyone here experienced with Regular Expression?

How to find sunstring with regular expression?

How can I find a substring in a string with a regular expression?
Example:
I have a original string "<tr><th>RecordId: </th><td valign=middle>A4711</td></tr>"
Now i want to extract the value "A4711" from this string with a regular expression. Everything except "A4711" is fixed, the id "A4711" itself is dynamic. How is it possible to get the substring "A4711" of the original string with a regular expression?

i wrote a little method with the infos above to get such results:
     * Get all substrings of a string that matches a regular expression.
     * @param original String to inspect.
     * @param regExp Regular expression as search criteria.
     * @return All matches of <i>regExp</i> or null if one input parameter is null.
    public static String[] getSubstrings(String original, String regExp) {
        String[] result = null;
        if (original != null && regExp != null) {
            Pattern pattern = Pattern.compile(regExp);
            Matcher matcher = pattern.matcher(original);
            boolean matchFound = matcher.find();
            Vector matches = new Vector();
            while (matchFound) {
                String match = matcher.group();
                matches.addElement(match);
                matchFound = matcher.find();
            }//next match
            int count = matches.size();
            result = new String[count];
            for (int i = 0; i < count; i++) {
                result[i] = (String) matches.elementAt(i);
            }//next match
        }//else: input unavailable
        return result;
    }//getSubstrings()

CFFORM (Flash) Validation with Regular Expressions Not Working

I am having troubles getting regular expression validation to
work in a CFFORM. The below code is an extract of a much larger
form, the first name and last name have a regular expression
validation...and it doesn't work!
I'd appreciate any comments/info for help on this, have
searched high and low on information to get this working...but no
joy.
The code is:
<cffunction name="checkFieldSet" output="false"
returnType="string">
<cfargument name="fields" type="string" required="true"
hint="Fields to search">
<cfargument name="form" type="string" required="true"
hint="Name of the form">
<cfargument name="ascode" type="string" required="true"
hint="Code to fire if all is good.">
<cfset var vcode = "">
<cfset var f = "">
<cfsavecontent variable="vcode">
var ok = true;
var msg = "";
<cfloop index="f" list="#arguments.fields#">
<cfoutput>
if(!mx.validators.Validator.isValid(this,
'#arguments.form#.#f#')) { msg = msg + #f#.errorString + '\n';
ok=false; }
</cfoutput>
</cfloop>
</cfsavecontent>
<cfset vcode = vcode & "if(!ok)
mx.controls.Alert.show(msg,'Validation Error'); ">
<cfset vcode = vcode & "if(ok) #ascode#">
<cfset vcode =
replaceList(vcode,"#chr(10)#,#chr(13)#,#chr(9)#",",,")>
<cfreturn vcode>
</cffunction>
<cfform name="new_form" format="flash" width="600"
height="600" skin="halosilver" action="new_data.cfc">
<cfformgroup type="panel" label="New Form"
style="background-color:##CCCCCC;">
<cfformgroup type="tabnavigator" id="tabs">
<cfformgroup type="page" label="Step 1">
<cfformgroup type="hbox">
<cfformgroup type="panel" label="Requestor Information"
style="headerHeight: 13;">
<cfformgroup type="vbox">
<cfinput type="text" name="reqName" width="300"
label="First Name:" validate="regular_expression" pattern="[^0-9]"
validateat="onblur" required="yes" message="You must supply your
First Name.">
<cfinput type="text" name="reqLname" width="300"
label="Last Name:" validate="regular_expression" pattern="[^0-9]"
validateat="onblur" required="yes" message="You must supply your
Last Name.">
<cfinput type="text" name="reqEmail" width="300"
label="Email:" validate="email" required="yes" message="You must
supply your email or the address given is in the wrong format.">
<cfinput type="text" name="reqPhone" width="300"
label="Phone Extension:" validate="integer" required="yes"
maxlength="4" message="You must supply your phone number.">
</cfformgroup>
</cfformgroup>
</cfformgroup>
<cfformgroup type="horizontal"
style="horizontalAlign:'right';">
<cfinput type="button" width="100" name="cnt_step2"
label="next" value="Next"
onClick="#checkFieldSet("reqName,reqLname,reqEmail,reqPhone","new_form","tabs.selectedInd ex=tabs.selectedIndex+1")#"
align="right">
</cfformgroup>
</cfformgroup>
</cfformgroup>
</cfformgroup>
</cfform>

quote:
Originally posted by:
Luckbox72
The problem is not the Regex. I have tested 3 or 4 different
versions that all work on the many different test sites. The
problem is it that the validation does not seem to work. I have
changed the patter to only allow NA and I can still type anything
into the text box. Is there some issue with useing Regex as your
validation?
Bear in mind that by default validation does not occur until
the user attempts to submit the form. If you are trying to control
the characters that the user can enter into the textbox, as opposed
to validating what they have entered, you will need to provide your
own javascript validation.

DOM Parser fails with regular expression using anchor (carat, dollar)

I'm using version "Oracle XDK Java 9.0.4.0.0 Production"
In trying to parse XML against schema: a regular expression fails to parse the data "8:00" with the following simple regular expression: "^.*$" (used to narrow the error)
The error message is
<Line 14, Column 25>: XSD-2025: (Error) Invalid text '8:00' in element: 'XYZ'
If I remove the anchors and just have ".*", the data is parsed successfully.
I dont understand why the parse fails when I use a anchors in the regular expression, and the java Pattern/Matcher classes succeed with the anchors?

That "ns670" string is an xml namespace prefix. it should have a corresponding xml namespace declaration somewhere in the xml document (i'm guessing you have not shown the whole document). the actual value of an xml namespace prefix is meaningless. if you parse the xml with a namespace aware DOM parser, it should generate Nodes with the correct namespace. the namespace is the value you care about when extracting data from the document, not the namespace prefix.
alternately, if you parse the document using a namespace aware DOM parser, you can just look for nodes based on their "local" name (the part after the ":" separator) and ignore the namespace/prefix.
whatever you do, please do not parse the xml with a regex, see this http://stackoverflow.com/a/1732454/552759 for details (applies to xml as well).

Need help with regular expression

I'm trying to use the java.util.regex package to extract URLs from html files.
The URLs that I am interested in extracting from the HTML look like the following:
<font color="#008000">http://forum.java.sun.com -
So, the URL is always preceeded by:
<font color="#008000">
and then followed by a space character and then a hyphen character. I want to be able to put all these URLs in a Vector object. This doesn't seem like it should be too difficult but for some reason I can't get anywhere with it. Any help would be greatly appreciated. Thanks!

hi gupta am not sure of the java syntax but i can tell u about the regular expression...try this....
<font color="#008000">(http:\/\/[a-zA-Z0-9.]+) [-]
i dont know the java methods to call...just the reg exp...
Sanjay Acharya

Help with Regular Expression for field validation

I'm fairly new to using regular expressions and using Acrobat. This is probably a simple question, but I've been unable to figure it out.
I have a text field on a PDF that I would like to be 9 characters in length. The first 2 characters can only be alphanumeric, the last 7 characters can only be numeric.
At first I was using the following, which allows all the characters to be alphanumeric:
var re = /^[A-Za-z0-9 :\\_]$/;
if (event.change.length >0) {
if (event.willCommit == false) {
    if (!re.test(event.change)) {
        event.rc = false
That works fine, but it's not quite what I needed. With some assistance I changed it (see below) to fit what I was looking for. However, this didn't work; it prevents anything from being entered in the field:
var re = /^[A-Za-z0-9]{2}\d{7}$/;
if (event.change.length >0) {
if (event.willCommit == false) {
    if (!re.test(event.change)) {
        event.rc = false
Any help would be greatly appreciated.
Thanks...

Here's a function you can call form the field's custom Format script. It should be placed in a document-level JavaScript:
function custom_ks1() {
    // Define non-commited regular expression
    var re = /^[A-Za-z0-9]{0,2}([0-9]{0,7})?$/;
    // Get all of the characters the user has entered
    var value = AFMergeChange(event);
    // Allow field to be cleared
    if(!value) return;
    if (event.willCommit) {
        // Define commited regular expression
        var re = /^[A-Za-z0-9]{2}[0-9]{7}$/;
        if (!re.test(value)) { // If final value doesn't match, alert user
            app.alert("Your error message goes here.");
            // event.rc = false
    } else { // not commited
        // Only allow characters that match the regular expression
        event.rc = re.test(value);
Call it like this:
// Custom Keystroke script
custom1_ks();

Match beginning of line with Regular Expression

I'm confused about dreamweaver's treatment of the characters
^ and $ (beginning of line, end of line) in regex searches. It
seems that these characters match the beginning of the file, not
the beginning of the various lines in the file. I would expect it
to work the other way around. A search like:
(^.)
should match every line in the file, so that a find/replace
could be performed at the beginning of each line, like this:
HELLO$1
which would add 'HELLO' at the start of each line in the
file.
Instead, this action only matches the first character of the
file, sticks 'HELLO' in front of it, and then quits (or moves on to
the next file). The endline character $ behaves in a similar
fashion, matching only the end of the file, not the end of each
line.
I've searched, and all the literature about regular
expressions in dreamweaver seems to indicate that I'm expecting the
correct behavior:
www.adobe.com/devnet/dreamweaver/articles/regular_expressions_03.html
quote:
^ Beginning of input or line ^T matches "T" in "This good
earth" but not in "Uncle Tom's Cabin"
$ End of input or line h$ matches "h" in "teach" but not in
"teacher"
Thanks for any insight, folks.

Hi Winston,
I am still digesting the material from the regular expression book and will take sometime to become proficient with it.
It seems that using groupCount() to eliminate the unwanted text does not work in this case, since all the lines returned the same value. Ie 3 posted earlier. This may be because the patterns are complex and only a few were grouped together. Otherwise, could you provide an example using the string posted as opposed to a hyperthetic one. In the meantime, at least one solution have been found by defining an additional special pattern “\\A[^%].*\\Z”, before combining / intersecting both existing and the new special pattern to get the best of both world. Another approach that should also work is to evaluate the size of String.split() and only accept those lines with a minimum number of tokens.
Anyhow, I have come a crossed another minor stumbling block in the mean time with the following line, where some hidden characters is preventing the existing pattern from reading it:
o;?Mervan Bay 40 Boyde St 7 br t $250,000 X West Park AE
Below is the existing regular expression that works for other lines with the same pattern but not for special hidden characters such as “o;?”:
\\A([A-Z][a-z]*){1,2} [0-9]{0,4}/?[0-9]{0,4}-?[0-9]{0,4} ([A-Z][a-z]*){1,2} St|Rd|Av|Sq|Cl|Pl|Cr|Gr|Dr|Hwy|Pde|Wy|La [0-9] br [h|u|t] \\$\\d+,\\d+|\\$\\d*\\,\\d+,\\d+ ([A-Z][a-z]*){1,}\\ZIs it possible to come up with a regular expression to ignore them so that this line could be picked up? Would also like to know whether I could combine both the special pattern “\\A[^%].*\\Z” with existing one as opposed to using 2 separate patterns altogether?
Many thanks,
Jack

input with regular expression

I am wondering how to use the _regex in a hidden
<input>. i have searched every where but there is no examples
on how to use this cfml form validation. Its not that i want
alternatives to do the regular expression just how to use it like
this......
if i had the form....
<form.........>
<input name="email">
<input type="hidden" name="email_regex"
value="*/.............">
</form>
How can i have a message if the input email does not coincide
with the regular expression. would i need to use a second
<input type="hidden" name="email_regex_Required"
value="please insert a valid email adress>

i am trying to get it to work like this. The validation type
is valid but i have not found anything on how to use it properly.
it like using the
<input type="hidden" name="email_required" value="the
field is blank, please go back and enter a filed">
I know javascript is the best option but if the browser does
not support this then at least in can attempt a alternative method.
All i would like to know is how do i use this validation type and
how can i get it also to produse a error message. as the "value"
field will contain the regular expresion itself.

Extract values with Regular Expression

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