How to search with regular expression

I make pdx files so that I can search text quickly. But Acrobat doesn't provide a way to search with regular expression. I'm wondering if there is a way that I don't know to search for regular expression in Acrobat Pro 9?

First, Acrobat must "mount" the PDX.
As "Find" does not use the cataloged index, use Shift+Ctrl+F to open the advanced search dialog.
It may be helpful to first enter Acrobat Preferences and for the Search category tick "Always use advanced search options".
Back to the Search dialog - use the drop down menu for "Look In" to pick "Select Index" then, if no PDXs show, click the Add button.
In the Open Index File dialog, browse to the location of the desired PDX and select it.
OK out and use "Return results containing" to pick a "Match ..." requirement or Boolean.
To become familiar with query syntax, for Acrobat, it is good to review Acrobat Help.
http://help.adobe.com/en_US/Acrobat/9.0/Professional/WS58a04a822e3e50102bd615109794195ff-7 c4b.w.html
Be well...

Similar Messages

Search with regular expression like this "[^\(]+mytype"

I tried regular expression which find me line which has "mytype" but does not precede with "("
I wrote it like this: [^\(]+mytype
It works perfectly with python reg exp. But it does not work in MSVC 2013 search(ctrl+shift+f). Do you know why? Is it bug?
Is there a way to find variable definition with search function through whole project

Hi Vit,
According to your description, you mean that when you use the
ctrl+shift+f shortcut key to search which line has "mytype" word in the whole project from VS2013 IDE like the following screen shot, but it does not work
in VS2013 IDE, am I right?
If yes, could you please provide me a screen shot about how you search the
mytype?
Generally, when we used the
ctrl+shift+f shortcut key to search, it works fine in VS IDE. Therefore, to check if you install some third-party Add-ins impact your VS IDE, I suggest you can search
the mytype in VS safe mode check if you get same issue.
Reference:
http://msdn.microsoft.com/en-us/library/ms241278.aspx
(1)If you did not get same issue, I doubt that you may be install some Add-ins impact the VS IDE, so I suggest
you can try to disable or un-install them and then check this issue again.
(2)If you still get same issue, I suggest you can try to reset the VS setting file or you can try to repair your
VS check this issue again.
In addition, I suggest you can try to use Ctrl + F shortcut key to search the mytype word.
If I misunderstand your issue, please provide me more detail message about your issue.
Best Regards,
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Searching in reverse with regular expressions

I have recently constructed a "Find" dialog for my editor and would like to support the use of regular expressions (for people who know more about them than I do.) I have radio buttons that allow the user to search down (from the current caret position to the end of the document) or up (from the current caret position to the beginning of the document.)
I have it working fine with literal text via String.indexOf() and String.lastIndexOf(), but I'm not sure how to implement an "upwards" search using regular expressions. It seems that java.util.regex only provides for searching from the current caret position downwards. Any suggestions?

two not-very-good-for-big-document suggestions
1) search up by searching down (from the beginning) to the last match before the position searched from
2) when the user asks for a search find all matches, number them and keep the index in the doc where they were found, then look up the largest index less than the carets index
you might try constructing succesively larger strings that end at the current caret position, and matching them one by one. If you're near the bottom, and theres no matches, this is also likely to be sloow..
asjf

Grouping & Back-references with regular expressions on Replace Text window

I really appreciate the inclusion of the Regular Expressions in the search & replace feature. One thing I am missing is back-references in the replacement expression. For instance, in the unix tools vi or sed, I might do something like this:
s/$firstPart$ $secondPart$ $oldThirdPart$/\2 \1 newThirdPart/g
which would allow me to switch the places of firstPart and secondPart, and totally replace thirdPart. If grouping and back-references are already present in the Replace Text window, how does one correctly invoke them?

duplicate of Grouping & Back-references with regular expressions on Replace Text window

Checking a number sequence with regular expressions

Hello,
Suppose I have a text in the pattern:
A1=ha,A2=bla,A3=cha,...
I don't know how many sections of "A#=$" (# denotes number, $ denotes text) will be in the text, but I want to verify that the numbers of the A's form the natural ascending number sequence (i.e 1,2,3,...). I prefer to use regular expressions to do this, but if there's another way, I will be glad to hear it too.
Therefore my question is: How can I use regular expressions to check for a sequence of numbers? I know I can search for groups I've caught previously in the expression, but how can I compute the next number in the sequence from the group and search for the result?
Thank you very much!

What I'd do--and I'm not saying this is optimal, just what pops immediately to mind--is have a regex that matches "A(\\d+)=" (assuming the ha, bla, cha can never be "A1" etc.--if they can, you can still do it, but it's more complicated), then you iterate with the Matcher, and each time, you get the Integer.valueOf what you matched. You keep track of the last value, and compare the current to the last. If current is < last (or <= last, depending on your requirements), fail.
Something like this. I don't recall Matcher's methods off the top of my head, so you'll have to fix the details.
Matcher m = Pattern.matcher("A(\\d+)=");
int maxSoFar = Integer.MIN_VALUE;
while (m.matches(input)) {
    int current = Integer.parseInt(m.getMatchedField("$1"));
    if (current <= maxSoFar) {
        // fail
    else {
        maxSoFar = current;
} maxSoFar =

How to write the regular expression for Square brackets?

Hi,
I want regular expression for the [] Square brackets.
I have tried to insert in the below code but the expression not validate the [] square brackets.
If anyone knows please help me how to write the regular expression for [] Square brackets.
private static final Pattern DESC_PATTERN = Pattern.compile("({1}[a-zA-Z])" +"([a-zA-Z0-9\\s.,_():}{/&#-]+)$");Thanks
Raghav

Since square brackets are meta characters in regex they need to be escaped when they need to be used as regular characters so prefix them with \\ (the escape character).

Assistance with Regular Expression and Tcl

Assistance with Regular Expression and Tcl
Hello Everyone,
I recently began learning Tcl to develop scripts for automating network switch deployments.
In my script, I want to name the device with a location and the last three octets of the base mac address.
I can get the Base MAC address by :
show version | include Base
Base ethernet MAC Address       : 00:00:00:DB:CE:00
And I can get the last three octets of the MAC address using the following regular expression.
([0-9a-f]{2}[:-]){2}([0-9a-f]{2}$)
But I have not been able to figure out how to call the regular expression in the tcl script.
I have checked several resources but have not been able to figure it out. Suggestions?
Ultimately, I want to set the last three octets to a variable (something like below) and then call the variable when I name the switch.
set mac [exec "sh version | i Base"] (include the regular expression)
ios_config "hostname location$mac"
Thanks for any assistance in advance.
Chris

This worked for me.
Switch_1(tcl)#set result [exec show ver | inc Base]
Base ethernet MAC Address       : 00:1B:D4:F8:B1:80
Switch_1(tcl)#regexp {([0-9A-F:]{8}\r)} $result -> mac
1
Switch_1(tcl)#puts $mac
F8:B1:80
Switch_1(tcl)#ios_config "hostname location$mac"
%Warning! Hostname should contain at least one alphabet or '-' or '_' character
locationF8:B1:80(tcl)#

Problem with Regular Expression

Hi There!!
I have a problem with regular expression. I want to validate that one word and second word are same. For that I have written a regex
Pattern p=Pattern.compile("([a-z][a-zA-Z]*)\\s\1");
Matcher m=p.matcher("nikhil nikhil");
boolean t=m.matches();
if (t)
          System.out.println("There is a match");
     else
          System.out.println("There is no match");
The result I am getting is always "There is no match
Your timely help will be much appreciated.
Regards

Ram wrote:
ErasP wrote:
You are missing a backward slash in the regex
Pattern p = Pattern.compile("([a-z][a-zA-Z]*)\\s\\1");
But this will fail in this case.
Matcher m = p.matcher("Nikhil Nikhil");It is the reason for that *[a-z]*.The OP had [a-z][a-zA-Z]* in his code, so presumably he know what that means and wants that String not to match.

Get the string between li tags, with regular expression

I have a unordered list, and I want to store all the strings between the li tags (<li>.?</li>)in an array:
<ul>
<li>This is String One</li>
<li>This is String Two</li>
<li>This is String Three</li>
</ul>
This is what have so far:
<li>(.*?)</li>
but it is not correct, I only want the string without the li tags.
Thanks.

No one?
Anoyone here experienced with Regular Expression?

How to find sunstring with regular expression?

How can I find a substring in a string with a regular expression?
Example:
I have a original string "<tr><th>RecordId: </th><td valign=middle>A4711</td></tr>"
Now i want to extract the value "A4711" from this string with a regular expression. Everything except "A4711" is fixed, the id "A4711" itself is dynamic. How is it possible to get the substring "A4711" of the original string with a regular expression?

i wrote a little method with the infos above to get such results:
     * Get all substrings of a string that matches a regular expression.
     * @param original String to inspect.
     * @param regExp Regular expression as search criteria.
     * @return All matches of <i>regExp</i> or null if one input parameter is null.
    public static String[] getSubstrings(String original, String regExp) {
        String[] result = null;
        if (original != null && regExp != null) {
            Pattern pattern = Pattern.compile(regExp);
            Matcher matcher = pattern.matcher(original);
            boolean matchFound = matcher.find();
            Vector matches = new Vector();
            while (matchFound) {
                String match = matcher.group();
                matches.addElement(match);
                matchFound = matcher.find();
            }//next match
            int count = matches.size();
            result = new String[count];
            for (int i = 0; i < count; i++) {
                result[i] = (String) matches.elementAt(i);
            }//next match
        }//else: input unavailable
        return result;
    }//getSubstrings()

[CC] Search&Replace: Bug only with Regular Expressions

Can you confirm the following behaviour/bug?
Steps to reproduce:
1 Create a new document in DW CC
2 Enter that text in the source code view:
<p>€</p>
3 Open Search&Replace
Field Search in: Current document
Field Search: Text
Field Search (3rd Field): €
Start Search
Result: As expected the "€" is found.
4 [x] Regular Expressions
Start Search
Result: "€" isn't found
Can you reproduce that?
Do you regard that as a bug like me?
If not, why please?
Do you think it is technically impossible for the developers to solve the task?
Do you think the developers forgot to gray out "text" in the choice box and allow regular expressions only in source code?
Thanks.

Nice that you like the nick
Sure, I know that I can file a feature wish.
But my main interest in this forum is to know, what other users think about certain features, why they think so, which they miss, which they regard as a bug, ...
When I remember it right, you told me some time ago, that you don't use RegEx.
Than I understand, that everything around that feature is not important for you.
What I like to understand is, why you think the behaviour is logically.
For me it is the opposite.
You get a result with "Scope: Text", "[ ]RegEx".
And you get no result with "Scope: Text", "[x]RegEx".
Incredible strange.
I would appreciate, if you could explain more detailed your view.

How to split a string with regular expression

Hi.
I need to split a string with a regular expression.
Example
String = "this is; a test";rune haavik;12345;
And I want the output to be:
"this is; a test"
rune haavik
12345
If I use this code:
private void test1()
String str = "\"this is; a test\";rune haavik;12345;";
int i=0;
String[] tmp = str.split(";");
while(i<tmp.length)
System.out.println(tmp);
i++;
Then it splits also in the "" text.
Regards
Rune haavik

Rune haavik:
The most effective way to achieve the end result is, I believe, to read the characters one by one, using a flag that indicates if we are inside quotation or not.
Well, if we are in a mind game, then the following should do.
String[] tmp = str.split(";(?![^\"]*\";)");

input with regular expression

I am wondering how to use the _regex in a hidden
<input>. i have searched every where but there is no examples
on how to use this cfml form validation. Its not that i want
alternatives to do the regular expression just how to use it like
this......
if i had the form....
<form.........>
<input name="email">
<input type="hidden" name="email_regex"
value="*/.............">
</form>
How can i have a message if the input email does not coincide
with the regular expression. would i need to use a second
<input type="hidden" name="email_regex_Required"
value="please insert a valid email adress>

i am trying to get it to work like this. The validation type
is valid but i have not found anything on how to use it properly.
it like using the
<input type="hidden" name="email_required" value="the
field is blank, please go back and enter a filed">
I know javascript is the best option but if the browser does
not support this then at least in can attempt a alternative method.
All i would like to know is how do i use this validation type and
how can i get it also to produse a error message. as the "value"
field will contain the regular expresion itself.

Extract values with Regular Expression

How to extract values into [ ] using regular expression.
With data As
Select 'AAAAAA[10] AAA: 19C' Txt From Dual Union all
Select 'XX[450]-10A' Txt From Dual Union all
Select '[5]AVC19C' Txt From Dual Union all
Select 'FVD[120]D2AC' Txt From Dual
)I hope this return
10
450
5
120Thanks in advanced

user11118871 wrote:
Thanks for all.
Hi BluShadow, can you explain what this is doing!?
ThanksSure.
Search for ----------------|           /------- Replace the found pattern in the search string with backreference 1
                     /------------\   /\       (the first thing backreferenced in the search string)
regexp_replace(txt, '^.*\[(.*)\].*$','\1')
                     |\/\/\--/\/\/|
                     | \ \ / \ \|
                     | | | | | |\- End of string
                     | | | | | |
                     | | | | | \- Any number of characters
                     | | | | |
                     | | | | \- Right square bracket (escaped)
                     | | | |
                     | | | \- any characters (backreferenced by round brackets)
                     | | |
                     | | \- Left square bracket (escaped)
                     | |
                     | \- Any number of characters
                     |
                     \- Start of stringEdited by: BluShadow on Jun 29, 2009 2:19 PM

Extended Replace with Regular Expressions

I am trying to figure out how to user regular expressions in
HomeSite 5.5 extended search and replace.
I am trying to find all matches to: <span
class="someClass">FooText</span>
And replace with: <sometag>FooText</sometag>
I have been able to get the find part working with reg ex:
<span class=\"someClass\">*[A-Za-z0-9_
><.="']*</span>
However, I have not been able to figure out what to put in
the replace box. I have tried different combinations of syntax with
"\1" for the first match of the reg ex in the search field, but
nothing has worked.
Can someone help me out with the syntax for what I should
enter in the replace field?

SQL>with t as(
2   select 1 id,'a   aa ---- ss-ee -' str from dual union
3   select 2, 'a        aa -------- ss-ee ---- - - -' str from dual union
4   select 3, '-' str from dual union
5   select 4, '----- -- -a -' str from dual union
6   select 5, '-a-a-a-a----a-a-a-' str from dual
7 )
8 select id,
9 str,
10 trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1'))) new_str,
11 length(str) len,
12 length(trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1')))) new_len
13 from t;
ID STR                                 NEW_STR                      LEN          NEW_LEN
1 a   aa ---- ss-ee -                 a aa ss-ee                    19               10
2 a     aa -------- ss-ee ---- - - - a aa ss-ee                    34               10
3 -                                                                  1
4 ----- -- -a -                       a                             13                1
5 -a-a-a-a----a-a-a-                  a-a-a-a-a-a-a                 18               13

How to search with regular expression

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