Extracting time from date and adding it to another date.

Dear All,
The values of two fields in my table are as follows:
n_date n_time
12/7/2007 1/1/1970 5:50:23 PM
Both of these fields are of date data type.
How can i add the time from n_time to n_date so that n_date will reflect a date with time added?
The problem is that i want to sort on n_date and i am not getting result when two dates are having same values for n_date but different for n_time.
How can i create a new expression for sorting these values?
Thanks in advance.
Regards,
Sameer

Hi,
Check this.
with data as
( select to_date('12/7/2007','dd/mm/yyyy') as ndate, to_date('1/1/1970 5:50:23','dd/mm/yyyy hh24:mi:ss') ntime from dual)
select ndate + (ntime - trunc(ntime)) from data
Regards
RK

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As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
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Hope you are doing well.
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select sysdate - level/24 t from dual
connect by level <11
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, to_char(t, 'DD-MM-YYYY HH24:MI:SS') t from testdata
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S     T
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