Fast ESP Combining two navigator columns in index profile

Can we union or combine two Navigators columns result in one column using index profile or FQL?
For example:I have 2 navigators ,KBReleasesNav (refers field KBReleases) and DOCrealeasesNav( refers DOCreleases).there are some common releases in both.I want to show these as one navigator and count as sum of both in UI.

I don't think is possible out of the box. May be some kind of customization can do it.

Similar Messages

  • I need to combine two Excel columns into one.

    Specifically I've exported a .csv file from another web app and it has First Names and Last Names in separate columns. I need them combined into a single column which includes both first and last names. I can't seem to remember how to get it come without the delimiter. I've already had to specify which columns to "skip" and other things in the dialogue box brought up when I "Get external data." Any way to do this cleanly?
    Thanks in advance,
    Dan

    Easiest way, when already in Excel, is to use the CONCANTENATE function in a new column that will then have the combined text of the separate columns...
    For example column A has the first name and column B has the last name...
    use the following formula in any empty column cell:  =CONCANTENATE(A1, " ", B1)
    (note added the literal space surrounded by quotes as thats how you would normally see the names.
    then you select and copy the formula of the cell (Cmd-C), then select/highlight the rest of the column and paste (Cmd-V) and you're done.

  • Combine Two table columns

    SELECT providerid, SUM(COUNT) FROM appdev.usercounts
    WHERE counttime BETWEEN SYSDATE - 30/1440 AND SYSDATE- 15/1440 GROUP BY providerid ORDER BY providerid
    W     697
    U     813
    T     143
    S     2
    SELECT providerid, SUM(COUNT) FROM appdev.usercounts
    WHERE counttime BETWEEN (SYSDATE -1) - 30/1440 AND (SYSDATE-1)- 15/1440 GROUP BY providerid ORDER BY providerid;
    W     450
    U     571
    T     80
    S     2
    I wnat output as like
    W     697 450
    U     813 571
    T     143 80
    S     2 2
    please help
    Thanks
    Praveen

    "COUNT", is that the real column name? It could become very confusing.
    Not tested for obvious reasons, but this should be close :
    SELECT providerid
         , sum(
             case when counttime between sysdate - 30/1440 and sysdate - 15/1440 then count end
           ) as cnt1
         , sum(
             case when counttime between (sysdate-1) - 30/1440 and (sysdate-1) - 15/1440 then count end
           ) as cnt2
    FROM appdev.usercounts
    WHERE ( counttime between sysdate - 30/1440 and sysdate - 15/1440 )
       OR ( counttime between (sysdate-1) - 30/1440 and (sysdate-1) - 15/1440 )
    GROUP BY providerid
    ORDER BY providerid
    ;

  • Combining two single recordset into one two column recordset

    Hi Forum
    Assume we have three types , each 'table of'
    CREATE OR REPLACE type type1 as table of number ;
    CREATE OR REPLACE type type2 as table of varchar2 (255);
    CREATE OR REPLACE TYPE TYPEVALUE AS OBJECT
    (object_type number ,
    object_value varchar2(255)
    resultset1 type1 := type1() ;
    resultset2 type2 := type2() ;
    resultset3 typevalue := typeValue3() ;
    I want to populate records of resultset3 from resultset1 and resultset2 , using resultset1 for first column of record and resultset2 for second column.
    One way is to do for loop but I don't want to use this.
    I need something similar to resultset3 to use it dynamically in select statement to do MINUS operation with another resultset . I think things like MULTISET, COLLECT, CAST can achieve what I want to do.
    Can you please help me to have a select statement that combines two single column rowset and put into a two column recordset.
    Thanks

    Hi,
    You can do something like this:
    SQL> create or replace type type1 as table of number;
      2  /
    Type created.
    SQL> create or replace type type2 as table of varchar2(255);
      2  /
    Type created.
    SQL> create or replace type typevalue as object(object_type number, object_value varchar2(255));
      2  /
    Type created.
    SQL> create type typevalue_tab as table of typevalue;
      2  /
    Type created.
    SQL> ed
      1  declare
      2     resultset1 type1 := type1(1, 2, 3, 4, 5);
      3     resultset2 type2 := type2('one', 'two', 'three', 'four', 'five');
      4     resultset3 typevalue_tab;
      5  begin
      6     for l_res in (
      7        select typevalue(t1.col1, t2.col2) as col
      8        from (
      9           select column_value col1
    10           , rownum rn
    11           from table(cast(resultset1 as type1))
    12        ) t1
    13        , (
    14           select column_value col2
    15           , rownum rn
    16           from table(cast(resultset2 as type2))
    17        ) t2
    18        where t1.rn = t2.rn
    19     )
    20     loop
    21        dbms_output.put_line(
    22           'Object Type:  '||l_res.col.object_type||' '||
    23           'Object Value: '||l_res.col.object_value
    24        );
    25     end loop;
    26* end;
    SQL> /
    Object Type:  1 Object Value: one
    Object Type:  2 Object Value: two
    Object Type:  3 Object Value: three
    Object Type:  4 Object Value: four
    Object Type:  5 Object Value: five
    PL/SQL procedure successfully completed.All the work here is done in SQL so it should work similarly if you have these things defined as nested table columns in the database.
    However, there is a caveat here: the lines highlighted in bold above are defining an arbitrary ordering for the nested table elements using rownum, as there is no concept of ordering within a nested table. You should change this part of the query to whatever makes sense in your environment, otherwise this solution cannot be guaranteed to be correct. Another option would be to use VARRAYs, as they will retain the order of elements.
    cheers,
    Anthony

  • Facing the issue Incomplete results (due to index-reload or timeout). Query will be resubmitted in 0 ms. 0 tries left. in FAST ESP 5.3

    Hi ,
    I am getting the following problem in my FAST ESP 5.3 , after recently updating the new Index profile. It was a Hot Update. Have already reset the index, but still this message keeps coming every  6 hrs. Please suggest.
    Its a 2 node setup with 5 active partitions.
    Thanks in Advance
     [2014-08-25 11:59:53] 
     WARNING 
     qrserver 
     Server1 
     15100 
     systemmsg 
     Error received while searching tcp/manufsis1.manu:15150. Error: [18] No engine available for partition 3  
     [2014-08-25 11:59:52] 
     WARNING 
     qrserver 
      Server2 
     15100 
     systemmsg 
     Error received while searching tcp/manufsis2.manu:15150. Error: [18] No engine available for partition 3  
     [2014-08-25 11:59:52] 
     WARNING 
     qrserver 
      Server1 
     15100 
     systemmsg 
     Error received while searching tcp/manufsis1.manu:15150. Error: [18] No engine available for partition 3  
     [2014-08-25 11:59:52] 
     WARNING 
     qrserver 
      Server2 
     15100 
     systemmsg 
     Incomplete results (due to index-reload or timeout). Query will be resubmitted in 0 ms. 0 tries left.   

    If there was an index profile update, could you try to clear qrserver cache and redeploy views:
    - stop the qrserver,
    -delete the qrserver cache ($FASTSEARCH/var/qrserver),
    -start qrserver and run the following two commands from bin:
    view-admin -m deploy -a
    view-admin -m refresh –a
    You might want to do this during off peak hours.
    Also, from the server(s)  running topfdispatcher can you check if you have duplicate entries in the enginerc-tld_0 file(located in %FASTSEARCH/var/searchctrl/etc)

  • Combine two columns data in single field STRAS

    Hi experts,
    I have to upload vendor master using direct method LSMW,
    I have been given an excel file having number of fields along with data and  House number and Street the data is in two different columns, but in master table there is only one field called STRAS which is combined for House number and street.
    How do i combine data of this two columns in single field STRAS
    Regards,
    Vijaya B.

    field-symbols: <fs> type line of itab_excel.
    loop at itab_excel assigning <fs>.
       concatenate <fs>-house <fs>-street into <fs>-newfield.
    endloop.
    by the end of the loop new filed will hold value needed for STRAS

  • Databound Drop Down List combine two or more column with customize format

    Hi all
    I am writing a project have Databound Drop Down List like example in http://www.oracle.com/technology/products/jdev/tips/mills/databound_lists.html, but my Databound Drop Down List combine 2 column with format "Name | DepartName" or something like that. I mean how can I change format when I combine two or more column display value in drop down (default is space between columns, ex: "Name DepartName")

    You could add a transient (calculated) attribute to your view object and use this one in your list binding.
    hth, Markus

  • Combining two tables without any distinct columns between them

    Folks,

    Hi sidy2j,
    According to your description, we need to verify your table structures, and the actual results which you want to get from your tables. Please post more information for analysis.
    Assume, if you want to a one to one record mapping between  two tables without any common column between them for joining, you can refer to the following scripts to implement your requirement. For more information, see:
    http://sqlhints.com/2013/09/07/joining-two-tables-without-any-common-column-between-them-sql-server/
    If you want to match every row in the first table with every row in the second table, you can refer to the following detail.
    http://stackoverflow.com/questions/1198124/combine-two-tables-that-have-no-common-fields
    Hope it can help you.
    Regards,
    Sofiya Li
    Sofiya Li
    TechNet Community Support

  • Combining two Characteristics in one column for a Bex query

    Hi experts,
    I'm reproducing a Bex query ver. 3.x, with a new query version 7.0.
    Within 3.x query there are two char as rows, where the first has a hierarchy.
    The char are Product(Books) and Volume(book's series), where Volume rapresents a detail of Product.
    When I execute this query, both char are combined and are showed in a single column, not in two distinct columns.
    *NODE 1*
    *--NODE PRODUCT 1A*
       *--NODE PRODUCT 1AA*
          *-- VOLUME 1AA*
          *-- VOLUME 1BB*
          *-- VOLUME 1CC*................
    Instead my new query 7.0 shows me the two char into two distinct columns, not in one like example above.
    Besides, both two version of the master data are exacly alike.
    I'd like to reproduce the first query scenario.
    How can I do?
    Thanks in advance.
    Claudia

    Hi Simon,
    yes, the original 3.5 query have the hierarchy switched on.
    Have you any idea?
    Thanks.

  • Multiple index profile or cluster on FAST ESP 5.3

    Can we more than one index profile in like one index profile per collection or multiple cluster pointing to different  index profile.

    One per collection would mean one cluster per collection, which may be doable but tricky  to operate.
    The cluster is tied to only one index profile , so collections within the same cluster share the same Index profile.
    So, you can have a farm with multiple clusters, but usually this kind of setup in the past was done with the help of FAST consulting services.

  • Multi-column BITMAP index vs. multiple BITMAP indices?

    Given the table (simple, made-up example):
    CREATE TABLE applicant_diversity_info (
    applicant_diversity_id NUMBER(12), PRIMARY KEY(applicant_diversity_id),
    apply_date DATE,
    ssn_salted_md5 RAW(16),
    gender CHAR(1), CHECK ( (gender IS NULL OR gender IN ('M','F')) ),
    racial_continent VARCHAR2(30), CHECK ( (racial_continent IS NULL
    OR racial_continent IN ('Europe','Africa','America','Asia_Pacific')) ),
    ethnic_supergroup VARCHAR2(30), CHECK ( (ethnic_supergroup IS NULL OR ethnic_supergroup IN ('Latin American','Other')) ),
    hire_salary NUMBER(11,2),
    hire_month DATE,
    termination_salary NUMBER(11,2),
    termination_month DATE,
    termination_cause VARCHAR2(30), CHECK ( (termination_cause IS NULL
    OR termination_cause IN ('Resigned','Leave of Absence','Laid Off','Performance','Cause')) )
    Oracle (syntactically) allows me to create either one BITMAP index over all four small-cardinality columns
    CREATE BITMAP INDEX applicant_diversity_diversity_idx ON applicant_diversity_info (
    gender, racial_continent, ethnic_supergroup, termination_reason );
    or four independent indexes
    CREATE BITMAP INDEX applicant_diversity_gender_idx ON applicant_diversity_info ( gender );
    CREATE BITMAP INDEX applicant_diversity_race_idx ON applicant_diversity_info ( raceial_continent );
    etc.
    What is the difference between the two approaches; is there any meaningful difference in disk-space between the one multi-colum index and the four single-column indexes? Does it make a difference in what the query-planner will consider?
    And, if I define one multi-column BITMAP index, does the order of columns matter?

    >
    What is the difference between the two approaches; is there any meaningful difference in disk-space between the one multi-colum index and the four single-column indexes? Does it make a difference in what the query-planner will consider?
    And, if I define one multi-column BITMAP index, does the order of columns matter?
    >
    You may want to read this two-part blog, that answers that exact question, by recognized expert Richard Foote
    http://richardfoote.wordpress.com/2010/05/06/concatenated-bitmap-indexes-part-i-two-of-us/
    http://richardfoote.wordpress.com/2010/05/12/concatenated-bitmap-indexes-part-ii-everybodys-got-to-learn-sometime/
    As with many things Oracle the answer is 'it depends'.
    In short the same considerations apply for a concatenated index whether it is bitmap or b-tree: 1) will the leading column usually be in the predicate and 2) will most or all of the index columns be specified in the queries.
    Here are some quotes from part 1
    >
    Many of the same issues and factors in deciding to create a single, multi-column index vs. several, single column indexes apply to Bitmap indexes as they do with B-Tree indexes, although there are a number of key differences to consider as well.
    Another thing to note regarding a concatenated Bitmap index is that the potential number of index entries is a product of distinct combinations of data of the indexed columns.
    A concatenated Bitmap index can potentially use less or more space than corresponding single column indexes, it depends on the number of index entries that are derived and the distribution of the data with the table.
    >
    Here is the lead quote from part 2
    >
    The issues regarding whether to go for single column indexes vs. concatenated indexes are similar for Bitmap indexes as they are for B-Tree indexes.
    It’s generally more efficient to access a concatenated index as it’s only the one index with less processing and less throwaway rowids/rows to contend with. However it’s more flexible to have single column indexes, especially for Bitmap indexes that are kinda designed to be used concurrently, as concatenated indexes are heavily dependant on the leading column being known in queries.

  • How many columns to index

    Hi,
    I have a table t1 which has nearly 20000 rows. It is accessed by a query which has 3 columns in its where clause lets say col1, col2 and col3. the table doesn't have any index so it does a full table scan. Now if I put an index on all the 3 columns it uses the index and avoids the FTS. Also if I index just 2 columns instead of three then also it uses index (something that I don't know why). my question is should I index the two coulmns or three columns? the third column which i left out has nearly 8000 distinct values.
    the query is of the form:
    select col5 from table1 where col1=value1 and col2=value2 and col3=value3 and rownum=1
    the execution plan with index on three columns is:
    Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
    0 | SELECT STATEMENT | | 1 | 24 | 2 (0)| 00:00:01 |
    * 1 | COUNT STOPKEY | | | | | |
    * 2 | TABLE ACCESS BY INDEX ROWID| table1     | 1 | 24 | 2 (0)| 00:00:01 |
    * 3 | INDEX RANGE SCAN | ind-3col | 1 | | 1 (0)| 00:00:01 |
    Predicate Information (identified by operation id):
    2 - access("col1"=6003 AND "col2"=1532 AND
    "col3"=267)
    the execution plan with index on two columns is:
    ======
    | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
    | 0 | SELECT STATEMENT | | 1 | 24 | 2 (0)| 00:00:01 |
    |* 1 | COUNT STOPKEY | | | | | |
    |* 2 | TABLE ACCESS BY INDEX ROWID| table1 | 1 |     24 | 2 (0)| 00:00:01 |
    |* 3 | INDEX RANGE SCAN | ind-2col | 1 | | 1 (0)| 00:00:01 |
    Predicate Information (identified by operation id):
    1 - filter(ROWNUM=1)
    2 - filter("col3"=267)
    3 - access("col1"=6003 AND "col2"=1532)
    I don't know if I should index on 2 columns or 3 columns...can someone suggest?
    Thanks
    Edited by: orausern on Feb 8, 2010 5:28 AM
    Edited by: orausern on Feb 8, 2010 5:29 AM

    Hi,
    To index or not to index on columns would totally depends on type of query(update/delete/select) being run on that table.
    So you need to check all/majority of the query that would be running on this table to decide which column should be indexed.
    eg:
    If i have just one query which you posted that would be running against this table then I would have index on all the three columns.
    But only 10-20% of the query would be making use of all the three columns, and rest 70-80% of the queries are making use of same 2 out of these 3 columns then I would be indexing only 2 columns.
    I suppose you would also like to understand that queries also determines which column would be leading column in index.
    Index makes select queries to run faster in most of the case, but it also makes insert statements run slower and utilized space. So keeping all this factor in mind it should be decided on which columns and in which order should we index.
    Regards
    Anurag

  • Text query using a Multi Column datastore index slow

    I have created a text index using multi column datastore preference. I have specified two clob columns in my preference. Searching on this new index works, but it is slower than I expected.
    I have done the following comparison:
    My original two clob columns are: DocumentBody and DocumentFields. I have built an individual text index on each column. My new column with Multi Column index is DocumentBodyAndFields;
    I did two queries:
    1. search 'dog' on DocumentBody UNION search 'dog' on DocumentFields;
    2. search 'dog' on DocumentBodyAndFields;
    I would think the second search should be faster than the first one because it is a single query. But this is not the case. The second query is consistently slower than the first query by about 10-20%.
    Things are getting much worse when I search on preceding wildcards. If I search '%job', the multi column index is twice as slow as the first query! I am very confused by this result. Is this a bug?

    I am unable to reproduce the performance problem. In my tests, the search that uses the multicolumn_datastore performs better, as demonstrated below. Can you provide a similar test case that shows the table structure, datastore, index creations, and explain plan?
    SCOTT@orcl_11g> CREATE TABLE your_tab
      2    (DocumentId            NUMBER,
      3       DocumentBody            CLOB,
      4       DocumentFields            CLOB,
      5       DocumentBodyAndFields  VARCHAR2 (1))
      6  /
    Table created.
    SCOTT@orcl_11g> INSERT ALL
      2  INTO your_tab VALUES (-1, 'adog', 'bdog', NULL)
      3  INTO your_tab VALUES (-2, 'adog', 'whatever', NULL)
      4  INTO your_tab VALUES (-3, 'whatever', 'bdog', NULL)
      5  SELECT * FROM DUAL
      6  /
    3 rows created.
    SCOTT@orcl_11g> INSERT INTO your_tab
      2  SELECT object_id, object_name, object_name, NULL
      3  FROM   all_objects
      4  /
    69063 rows created.
    SCOTT@orcl_11g> BEGIN
      2    CTX_DDL.CREATE_PREFERENCE
      3        ('your_datastore', 'MULTI_COLUMN_DATASTORE');
      4    CTX_DDL.SET_ATTRIBUTE
      5        ('your_datastore', 'COLUMNS', 'DocumentBody, DocumentFields');
      6  END;
      7  /
    PL/SQL procedure successfully completed.
    SCOTT@orcl_11g> CREATE INDEX your_idx1 ON your_tab (DocumentBody)
      2  INDEXTYPE IS CTXSYS.CONTEXT
      3  /
    Index created.
    SCOTT@orcl_11g> CREATE INDEX your_idx2 ON your_tab (DocumentFields)
      2  INDEXTYPE IS CTXSYS.CONTEXT
      3  /
    Index created.
    SCOTT@orcl_11g> CREATE INDEX your_idx3 ON your_tab (DocumentBodyAndFields)
      2  INDEXTYPE IS CTXSYS.CONTEXT
      3  PARAMETERS ('DATASTORE your_datastore')
      4  /
    Index created.
    SCOTT@orcl_11g> EXEC DBMS_STATS.GATHER_TABLE_STATS (USER, 'YOUR_TAB')
    PL/SQL procedure successfully completed.
    SCOTT@orcl_11g> SET TIMING ON
    SCOTT@orcl_11g> SET AUTOTRACE ON EXPLAIN
    SCOTT@orcl_11g> SELECT DocumentId FROM your_tab
      2  WHERE  CONTAINS (DocumentBody, '%dog') > 0
      3  UNION
      4  SELECT DocumentId FROM your_tab
      5  WHERE  CONTAINS (DocumentFields, '%dog') > 0
      6  /
    DOCUMENTID
            -3
            -2
            -1
    Elapsed: 00:00:00.65
    Execution Plan
    Plan hash value: 4118340734
    | Id  | Operation                     | Name      | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT              |           |     4 |   576 |     2 (100)| 00:00:01 |
    |   1 |  SORT UNIQUE                  |           |     4 |   576 |     2 (100)| 00:00:01 |
    |   2 |   UNION-ALL                   |           |       |       |            |          |
    |   3 |    TABLE ACCESS BY INDEX ROWID| YOUR_TAB  |     2 |   288 |     0   (0)| 00:00:01 |
    |*  4 |     DOMAIN INDEX              | YOUR_IDX1 |       |       |     0   (0)| 00:00:01 |
    |   5 |    TABLE ACCESS BY INDEX ROWID| YOUR_TAB  |     2 |   288 |     0   (0)| 00:00:01 |
    |*  6 |     DOMAIN INDEX              | YOUR_IDX2 |       |       |     0   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       4 - access("CTXSYS"."CONTAINS"("DOCUMENTBODY",'%dog')>0)
       6 - access("CTXSYS"."CONTAINS"("DOCUMENTFIELDS",'%dog')>0)
    SCOTT@orcl_11g> SELECT DocumentId FROM your_tab
      2  WHERE  CONTAINS (DocumentBodyAndFields, '%dog') > 0
      3  /
    DOCUMENTID
            -1
            -2
            -3
    Elapsed: 00:00:00.28
    Execution Plan
    Plan hash value: 65113709
    | Id  | Operation                   | Name      | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT            |           |     4 |    76 |     0   (0)| 00:00:01 |
    |   1 |  TABLE ACCESS BY INDEX ROWID| YOUR_TAB  |     4 |    76 |     0   (0)| 00:00:01 |
    |*  2 |   DOMAIN INDEX              | YOUR_IDX3 |       |       |     0   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - access("CTXSYS"."CONTAINS"("DOCUMENTBODYANDFIELDS",'%dog')>0)
    SCOTT@orcl_11g>

  • Combine two resultset sidebyside in coulmn using mdx

    hi i am new to mdx,
    i want to combine two select statement resultset (side by side like union) using mdx query,please any body help me to solve this query
    first query:
     SELECT
    { [Last Year] }
    ON COLUMNS,
     { {[Location].[Location].&[7], [Location].[Location].&[12], [Location].[Location].&[11],
    [Location].[Location].&[19], [Location].[Location].&[17], [Location].[Location].&[16],
    [Location].[Location].&[9], [Location].[Location].&[18] },{[Location].[Location].[All]}}
    ON ROWS
    FROM [Cube1]
    WHERE ( [Measures].[Labour %] )
    here [Last Year] is a calculated set
    {STRTOMEMBER("[Date].[Month].&["+ cstr(year(now())-2) +"-11-01T00:00:00]"):
            (STRTOMEMBER("[Date].[Month].&["+ cstr(year(now())-1) +"-10-01T00:00:00]"))}
    2nd query:
    WITH MEMBER [Measures].[Budget ] AS IIF(avg([Last Year],IIF(([Measures].[Budget]>0),[Measures].[Budget],null)),
                                            avg([Last Year],IIF(([Measures].[Budget]>0),[Measures].[Budget],null)),0.00),
    MEMBER [Measures].[YTD] AS IIF(avg([Last Year], IIF(([Measures].[Labour %]>0),[Measures].[Labour %],null))<>null,
                                  avg([Last Year], IIF(([Measures].[Labour %]>0),[Measures].[Labour %],null)),0.00),
    FORMAT_STRING = "Standard",
    BACK_COLOR = CASE WHEN [YTD] = 0  THEN /*White*/16777215 /*White*/  
    WHEN [YTD] <= [Measures].[Budget ] THEN 65408
         WHEN [YTD]<= [Measures].[Budget ] +5 THEN 65535
         WHEN [YTD]> [Measures].[Budget ] +5 THEN 255
    END,
    VISIBLE = 1
    SELECT
    {  [Measures].[YTD], [Measures].[Budget ] }
    ON COLUMNS,
    { { [Location].[Location].&[7], [Location].[Location].&[12], [Location].[Location].&[11], [Location].[Location].&[19], [Location].[Location].&[17], [Location].[Location].&[16], [Location].[Location].&[9], [Location].[Location].&[18]
    },{[Location].[Location].[All]} }
    ON ROWS
    FROM [Cube1]
    here   ==> [Measures].[YTD], [Measures].[Budget ] are calculated member
    i want result like in
    coulmns===> ytd,budget,nov,dec,jan,feb.,,,,,,,,,,out
    rows ====> are only locations and total(average of all locations)
    please guide me to get solution like mdx query

    Hi Vsp,
    According to your description, you want to create a calculated member to combine two members, and then set it as Default member, right?
    In SQL Server Analysis Services, we can use the script below to create a calculated members.
    create member currentcube.[Date].[Day of Week].[weekend]
    as
    {[Date].[Day of Week].&[6],[Date].[Day of Week].&[7]
    Every attribute in a dimension in Microsoft SQL Server Analysis Services has a default member, which you can specify by using the
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    http://technet.microsoft.com/en-us/library/ms174822(v=sql.105).aspx
    Regards,
    Charlie Liao
    TechNet Community Support

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