Fetching directory structure
Hi,
Along with .jar files I like to fetch other resources like help (.html) and configuration (.xml) files. Actually, I would love to deploy a whole directory structure in the client machine. What is the most efficient way to do it?
Please advice with a sample .jnlp file.
please google..
http://www.exforsys.com/tutorials/websphere/websphere-v5.0-workbench-basics-create-j2ee-projects.html
http://publib.boulder.ibm.com/infocenter/wpfhelp/v6r1m2/index.jsp?topic=/com.bowstreet.designer.doc/designer/c_devenv_dir_structure.htm
Similar Messages
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Problem in retreiving directory structure, code needs correction
hello there
I am trying to fetch the directory structure of a particular directory in a way that the structure of subdirectories is also displayed.
I have the following code:
CODE:
import java.io.*;
public class FetchDir2
static File dirStruct[][] = new File[300][100]; //stores the directory structure at a particular level
static Integer pastIndex[] = new Integer[300]; //Stores index upto which a particular level has been scanned
static String path = "C:/trydir"; //path of user's workspace, change it accordingly
static int level = 0;
static int index = 0;
static int j=0;
static int i=0;
public static void main(String s[])
File fileTry = new File(path);
for(int i=0;i<300;i++)
pastIndex=0;
fetchStr(fileTry);
public static void fetchStr(File fileTry)
dirStruct[level] = fileTry.listFiles(); //fetch list of files and directories at this LEVEL
sort(dirStruct[level]);
for(i=0;i<dirStruct[level].length;i++) //loop to scan each element at this level
if(dirStruct[level][i].isFile()) //if file is encountered
System.out.println("Level:"+level+"\t Index:"+pastIndex[level]+"\t DirStruct.Length:"+dirStruct[level].length);//CHKPOINT
System.out.println("<file>"+dirStruct[level][i].getName()+"</file>"); //print file element
pastIndex[level]++; //increase the index at this level by 1
// if(dirStruct[level].length==0)
// {break;}
// else
if(pastIndex[level]==dirStruct[level].length)
System.out.println("</directory>");
pastIndex[level]=0;
level--;
if(level==-1)
break;
if(dirStruct[level][i].isDirectory())
System.out.println("Level:"+level+"\t Index:"+pastIndex[level]+"\t DirStruct.Length:"+dirStruct[level].length);//CHKPOINT
String path = dirStruct[level][i].getPath();
File f = new File(path);
System.out.println("<directory>PATH:"+path);
pastIndex[level]++;
if(pastIndex[level]==((dirStruct[level].length)-1))
pastIndex[level]=0;
level--;
System.out.println("</directory>");
else
level++;
//System.out.println("</directory>");
fetchStr(f);
public static void sort(File dirStruct[])
for(i=0;i<dirStruct.length;i++)
for(j=0;j<i;j++)
int compare = dirStruct[i].compareTo(dirStruct[j]);
if(compare>0)
swap(dirStruct[i],dirStruct[j]);
public static void swap(File f1,File f2)
File f3;
f3=f1;
f1=f2;
f2=f3;
The dirctory structure used for testing is:
<dir trydir>
<file>f1</file>
<file>f2</file>
<file>f3</file>
<dir d1>
<dir d21>
<file>f</file>
</dir>
<dir d22>
<file>f</file>
</dir>
<file> f21</file>
<file> f22</file>
</dir>
OUTPUT:
Level:0 Index:0 DirStruct.Length:5
<file>a1.txt</file>
Level:0 Index:1 DirStruct.Length:5
<directory>PATH:C:\trydir\d1
Level:1 Index:0 DirStruct.Length:4
<directory>PATH:C:\trydir\d1\d21
Level:2 Index:0 DirStruct.Length:1
<file>f31.txt</file>
</directory>
Level:1 Index:1 DirStruct.Length:4
<directory>PATH:C:\trydir\d1\d21
Level:2 Index:0 DirStruct.Length:1
<file>f31.txt</file>
</directory>
Level:1 Index:2 DirStruct.Length:4
<directory>PATH:C:\trydir\d1\d21
</directory>
Level:0 Index:2 DirStruct.Length:1
<file>f31.txt</file>
Can some one please correct this code.
10 dukes are staright yours if you can.hi
here is the code i work for u
The code is changed and go through it
import java.io.*;
public class FetchDir2 {
final static String path = "C:/web"; //path of user's workspace, change it accordingly
public static void main(String s[]) {
File fileTry = new File("c:/web");
fetchStr(fileTry,0,0);
public static void fetchStr(File fileTry,int level,int idx) {
File dirList[]=fileTry.listFiles();
sort(dirList);
File f=null;
System.out.println("Level:" + level+" Index:"+idx +" DirStruct.length:"+dirList.length);
for(int i=0;i<dirList.length;i++){
f = dirList;
System.out.println("Level:"+level+" Index:"+i );
if(f.isFile()){
System.out.println("<file>"+ f.getName()+"</file>");
else{
System.out.println("<directory> Path:"+fileTry.getPath());
fetchStr(f,level++,i);
System.out.println("</directory>");
public static void sort(File dirStruct[]) {
int compare=0;
for(int i=0;i<dirStruct.length-1;i++) {
for(int j=i+1;j<dirStruct.length;j++) {
compare= dirStruct[i].compareTo(dirStruct[j]);
if(compare>0)
swap(dirStruct[i],dirStruct[j]);
public static void swap(File f1,File f2) {
File f3;
f3=f1;
f1=f2;
f2=f3;
}Hopes it helps you... -
Making a Directory Structure with JTree.
Hello,
Can anyone boss here help me to code to make a
File System Directory structure through JTree?
The outlook should be like the Windows Explorer...
From : [email protected]* HarishTree.java
* Created on September 7, 2004, 2:56 PM
* @author 120002314
import javax.swing.*;
import javax.swing.event.*;
import javax.swing.tree.*;
import java.io.File;
import java.awt.event.ActionListener;
import javax.swing.JToolBar;
import java.lang.System;
import java.awt.BorderLayout;
import java.awt.Component;
import javax.swing.filechooser.FileSystemView;
public class HarishTree {
public static void createAndShowGUI() {
//creating a tree with drives in the toolbar
TreeBar bar = new TreeBar();
JScrollPane scrollpane = new JScrollPane(bar.tree);
JToolBar toolbar = bar.CreatingTreeBar();
JPanel panel = new JPanel(new BorderLayout());
panel.add(toolbar);
// Display it all in a window and make the window appear
JFrame.setDefaultLookAndFeelDecorated(true);
JFrame frame = new JFrame("FileExplorer");
frame.getContentPane().add(scrollpane, "Center");
frame.getContentPane().add(panel,BorderLayout.NORTH);
frame.setSize(400,600);
frame.setVisible(true);
frame.setResizable(false);
public static void main(String[] args) {
javax.swing.SwingUtilities.invokeLater(new Runnable() {
public void run() {
createAndShowGUI();
java.lang.System.gc();
* The methods in this class allow the JTree component to traverse
* the file system tree and display the files and directories.
class FileTreeModel implements TreeModel {
// We specify the root directory when we create the model.
protected JFile root;
public FileTreeModel(){}
public FileTreeModel(JFile root) { this.root = root; }
// The model knows how to return the root object of the tree
public Object getRoot() { return root; }
// Tell JTree whether an object in the tree is a leaf
public boolean isLeaf(Object node) { return ((JFile)node).isFile(); }
// Tell JTree how many children a node has
public int getChildCount(Object parent) {
String[] children = ((JFile)parent).list();
if (children == null) return 0;
return children.length;
// Fetch any numbered child of a node for the JTree.
// Our model returns File objects for all nodes in the tree. The
// JTree displays these by calling the File.toString() method.
public Object getChild(Object parent, int index) {
String[] children = ((JFile)parent).list();
if ((children == null) || (index >= children.length)) return null;
return new JFile((JFile)parent,children[index]);
// Figure out a child's position in its parent node.
public int getIndexOfChild(Object parent, Object child) {
String[] children = ((File)parent).list();
if (children == null) return -1;
String childname = ((File)child).getName();
for(int i = 0; i < children.length; i++) {
if (childname.equals(children)) return i;
return -1;
// This method is invoked by the JTree only for editable trees.
// This TreeModel does not allow editing, so we do not implement
// this method. The JTree editable property is false by default.
public void valueForPathChanged(TreePath path, Object newvalue) {}
// Since this is not an editable tree model, we never fire any events,
// so we don't actually have to keep track of interested listeners
public void addTreeModelListener(TreeModelListener l) {}
public void removeTreeModelListener(TreeModelListener l) {}
class TreeBar implements ActionListener{
public JTree tree = new JTree();
public File[] roots = File.listRoots();
JToolBar toolbar = new JToolBar();
public TreeBar(){
FileTreeModel model = new FileTreeModel(new JFile(System.getProperty("user.home")));
tree.setModel(model);
tree.setCellRenderer(new MyRenderer());
public JToolBar CreatingTreeBar(){
for(int i=0;i<roots.length;i++){
JButton button = new JButton(roots[i].getPath(),new MyRenderer().inicon);
button.addActionListener(this);
button.setActionCommand(roots[i].getPath());
toolbar.add(button);
toolbar.setFloatable(false);
toolbar.setRollover(true);
return(toolbar);
public void actionPerformed(java.awt.event.ActionEvent e) {
FileTreeModel model = new FileTreeModel(new JFile(e.getActionCommand()));
tree.setModel(model);
class MyRenderer extends DefaultTreeCellRenderer {
ImageIcon inicon = createImageIcon("1.gif");
ImageIcon exicon = createImageIcon("2.gif");
ImageIcon leaficon = createImageIcon("3.gif");
public ImageIcon createImageIcon(String path) {
java.net.URL imgURL = TreeIconDemo2.class.getResource(path);
if (imgURL != null) {
return new ImageIcon(imgURL);
} else {
System.err.println("Couldn't find file: " + path);
return null;
public Component getTreeCellRendererComponent(
JTree tree,
Object value,
boolean sel,
boolean expanded,
boolean leaf,
int row,
boolean hasFocus) {
super.getTreeCellRendererComponent(tree, value, sel, expanded, leaf, row, hasFocus);
if (leaf){
setIcon(leaficon);
}else
if(expanded)
setIcon(exicon);
else
setIcon(inicon);
return this;
class JFile extends File{
public JFile(String path){
super(path);
public JFile(File parent,String child){
super(parent,child);
public String toString(){
FileSystem fs = new FileSystem();
if(fs.isFileSystemRoot(this))
return(this.getPath());
else
return(fs.getSystemDisplayName(this));
class FileSystem extends FileSystemView{
public File createNewFolder(File containingDir) throws java.io.IOException {
return(this.createFileObject(containingDir,"harish")); -
Import statement and directory structure
First of all, sorry for such a long post, I believe part of it is because I am unsure of the concept of importing in Java. Secondly, Thanks to anyone who can ultimately enlighten me to the concept of import. I did ask this question before in the "erorr and error handling" forum, and the people who have helped me there did a great job. But, I believe I require a little more clarification and thus have decided to post here.
Anyhow, my question..
Could someone explain to me the concept of the import statement, or direct me to a webpage with sort of explanation for newbies? For some reason, I am having a hard time grasping the concept.
As I understand it, the import statement in Java, is very similar to the namespace keyword in C. That is to say, import doesn't actually "import" any source code, the way that the #include statement does in C.
So I suppose what my question is, say I have a java class file like below:
//filename: sentence.java
//located: c:\school\csc365
package csc365;
class sentence
//some variables here..
//some constructor here..
//some methods here..
And some sample program like the one below which implements the above..
//filename: test.java
//located: c:\school\csc365
import csc365.*;
import java.io.*;
class test.java
//creates some sentence object
//uses the object's methods
//some other things.
As I understand it, the test.java file should not compile because the csc365 package is not in the correct directory. (assuming of course, the classpath is like c:\school\csc365;c:\school )
But, ... where then should the sentence.java be located? In a subdirectory of c:\school called csc365 (i.e c:\school\csc365\) ?
And thus that would mean the test.java file could be located anywhere on the hard drive?
I suppose, I just need a little clarification on the correlation between a package's "name" (i.e package csc365; ) and its corresponding directory's name, and also how the javac compiler searches the classpath for java classes.
..So, theoretically if I were to set the classpath to look in every conceivable directory(provided the directory names were all unique) of the harddrive, then I could compile a test.java anywhere?
As a note: I have been able to get the test.java file to compile, by leaving out the import statement in the test.java file, and also leaving out the package statement for the sentence class, but I assume this is because the files are defaulted to the same package?Hi Mary,
No, import isn't analogous to C++ namespace - Java package is closer to the namespace mark.
import is just a convenience for the programmer. You can go your whole Java career without ever writing an import statement if you wish. All that means is that you'll have to type out the fully-resolved class name every time you want to use a class that's in a package other than java.lang. Example:
// NOTE: No import statements
public class Family
// NOTE: fully-resolved class names
private java.util.List children = new java.util.ArrayList();
}If you use the import statement, you can save yourself from typing:
import java.util.ArrayList;
import java.util.List;
public class Family
// NOTE: fully-resolved class names
private List children = new ArrayList();
}import isn't the same as class loader. It does not bring in any source code at all.
import comes into play when you're compiling or running your code. Java will check to make sure that any "shorthand" class names you give it live in one of the packages you've imported. If it can't find a matching fully-resolved class name, it'll give you a message like "Symbol not found" or something like that.
I arrange Java source in a directory structure that matches the package structure in the .class files.
If I've got a Java source file like this:
package foo.bar;
public class Baz
public static void main(String [] args)
Baz baz = new Baz();
System.out.println(baz);
public String toString()
return "I am a Baz";
}I'll store it in a directory structure like this:
root
+---classes
+---src
+---foo
+---bar
+---Baz.javaWhen I compile, I go to root and compile by typing this:
javac -d classes foo/bar/*.javaI can run the code from root by typing:
java -classpath classes foo.bar.BazI hope this wasn't patronizing or beneath you. I don't mean to be insulting. - MOD -
Organize iTunes file list by Directory Structure instead of artist/album?
Hello, I have searched for different audio players for os x which might have this feature but so far have had no luck. What I'm looking for is a feature similar to that of foobar2000 for win32 where I can organize my music by directory structure without the iTunes automatic organization by artist/album. Is there a way I can accomplish this in iTunes with some sort of xml config or hidden options? Thanks.
You don't have to have iTunes move music around on your hard drive (Preferences>Advanced>General, uncheck Keep iTunes Music folder organized and Copy files to iTunes Music folder when adding to library) but I suspect that's not what you're asking. You can't automatically view music from within iTunes by directory structure. iTunes organizes by ID3 tags ("mp3 tags"). You could, I suppose, spend a lot of time replicating your directory structure by using folders and playlists within iTunes but you'd probably have to do it all by hand.
You could check out Doug's Scripts to see if there are some scripts that might help.
http://dougscripts.com/itunes/index.php -
How to create a tree based on directory structure
I want to create a hierarchical tree in Forms 6i based upon a file system directory structure (similar to Windows Explorer). How can I populate a tree with this information, is there something that I can call or write that would return the file system structure in a format that I can populate my tree?
Any advice would be greatly appreciated.
Thanks
RichardYour link does not seem to work.They're re-jigging all the links to accomodate the hot poop on Oracle's latest and greatest, 10G. So at least the website is on schedule even if the actual software delivery dates have slipped :P
We can still get D2KWUTIL from here: http://te chnet.oracle.com/software/products/forms/content.html
Cheers, APC -
Directory Structure for multiple applications at one host
Can I have multiple (more than one) WEB-INF directory structures in the public_html directory for different web applications? If I do this, how do setup the url-pattern in the Servlet Mapping tag in the web.xml file? How do I setup the URL that calls the servlet from the HTML that has been send to the user�s browser?
If I understand your question, you want multiple contexts. All App Servers/Web Servers allow you to setup multiple contexts. Normally if your root context is in /home/myhome/app_server/
then you would setup multiple contexts by creating a folder for each context:
/home/myhome/app_server/context1/
/home/myhome/app_server/context2/
Each would have their own full application/website. And the way to reference these would be as such:
if the domain, www.mydomain.com, is mapped to /home/myhome/app_server/
www.mydomain.com/context1/
www.mydomain.com/context2/
I think that is what you were asking. Hope it helps -
I migrated from WebLogic 5.1 to 7.0.2 Something I used to have set-up in 5.1 no
longer
works.
I am using the weblogic.servlet.FileServlet and have the URL "/cxedocs/" mapped
to this
servlet. So whenever the URL http://localhost:7001/cxedocs/en_US/index.html
is used it would use the docHome associated with the /cxedocs/ URL and then append
the "en_US/index.html" on to it. So let's say d:\temp\en_US\index.html
But now for WL 7.0.2 it appears that the URL also needs to be in the directory
structure.
So it now takes the docHome "d:\temp" adds the URL "/cxedocs/" and then appends
the
rest - so d:\temp\cxedocs\en_US\index.html.
I can't require that the "cxedocs" directory be there. Is there anyway to map
a certain URL
without requiring it in the directory structure. I looked at virtual directory
mapping too but
it still seemed to require this.
Any help would be appreciated!
Thanks!
-Lori
I opened up a case with support on this. After some research they came back with
that
NO there is no way to do this. In 6.0 it was changed to follow the spec which
restricts this.
The URL must be part of the directory path.
-Lori
"Lori Ronning" <[email protected]> wrote:
>
>I migrated from WebLogic 5.1 to 7.0.2 Something I used to have set-up
>in 5.1 no
>longer
>works.
>
>I am using the weblogic.servlet.FileServlet and have the URL "/cxedocs/"
>mapped
>to this
>servlet. So whenever the URL http://localhost:7001/cxedocs/en_US/index.html
>is used it would use the docHome associated with the /cxedocs/ URL and
>then append
>the "en_US/index.html" on to it. So let's say d:\temp\en_US\index.html
>
>But now for WL 7.0.2 it appears that the URL also needs to be in the
>directory
>structure.
>So it now takes the docHome "d:\temp" adds the URL "/cxedocs/" and then
>appends
>the
>rest - so d:\temp\cxedocs\en_US\index.html.
>
>I can't require that the "cxedocs" directory be there. Is there anyway
>to map
>a certain URL
>without requiring it in the directory structure. I looked at virtual
>directory
>mapping too but
>it still seemed to require this.
>Any help would be appreciated!
>Thanks!
>-Lori
-
I have copied many photo's from another laptop to my Mac. The older photo's are in directories with names that help me select what I need to view. I would like to have all my imported new photo's also bee added to the directory structure I have in Finder but my new photo's are all in iPhoto. I want to use directories for storing and iPhoto for viewing. Is this possible or do I need to have all my photo's in iPhoto??
MitchiPhoto is not a Photo Viewer. It's a Photo Manager and designed for looking after the files while you organise the Photos. It really works much better if you let it manage those files. If you use iPhoto you never go near those files because iPhoto is your start point for anything you want to do with your Photos - the point of the pplication.
You can run iPhoto in Referenced mode, where it does not copy the files to the Library, but I caution you that you are making life a lot more difficult for yourself by doing that.
How to, and some comments on why you shouldn't, are in this thread
https://discussions.apple.com/thread/3062728?tstart=0
Regards
TD -
Export images to a directory structure based on a collection tree?
A question:
Will lightroom have the capability to export images to a directory structure which mirrors a collections logical structure?
The reason I ask this is that when I create websites using third party tools (eg, Jalbum) I typically generate a flash or HTML based site with an menu structure for navigating the images.
So, the image interface is not simply a "flat-file" display as per the templates in Lightroom beta.
To do this, with previous image management tools (eg, iMatch) I create a hierarchy of images based on the categories (or collections) that the images are assigned to, export the images in a folder tree reflecting their categories (or collection), then use, say, Jalbum, to generate the website with the menu tree reflecting the folders/images.
This is extremely useful for more complicated image websites with categories and a large no of images.
If this function was built into Lightroom I guess it would be in the export function such that the "write to folder" box could take an argument {collection name} which would create a folder tree reflecting the collections logical tree which is being exported.
Apologies if this topic has been raised previously. But this function is extremely useful if you are using third party html tools or simply building websites by hand.
Regards
AlistairI started simmilar thread in Lightroom Feature Requests few months ago, but can't find it anymore since new forum version...
What I can suggest as a new feature is export to directory structure from collections or second option from keywords. Probably more usable and easier to implement would be from collections.
What I need it to export many photos to different directories pretty often, and this would be great help since I could arrange them in collections and collection sets. Then select collection set and export it in a manner that collection set would be main export directory, and each collection within the set would be exported to its own folder within main collection set export folder.
This would be much appreciated feature in near future
Thank you for great product by the way -
Creating a Standby Database with the Same Directory Structure
Hello gurus,
I am self-learning the feature Oracle Data Guard, so I am testing it on Oracle 10g R2.
At Oracle documentation there is a section F.4.: Creating a Standby Database with the Same Directory Structure*, that explains how to create a standby database with RMAN but there is something that I don´t understand:
In the standby server, I created a database with the SID equal to production database* with the objetive to have the same directory structure, but when I try to startup nomount the standby database with pfile appear this expected error:
ORA-16187: LOG_ARCHIVE_CONFIG contains duplicate, conflicting or invalid attributes
So my question is: Is possible have the Same Directory Structure on both: Production and StandBy server?
Thanks in advanced.Uwe and mseberg: thanks for your quick answers
I have a doubt: How can you have the same directory structure if you have differents SIDs?, for example if you follow the OFA suggestions you would must have:
On Production server: */u01/app/oracle/oradata/PRIMARY/system.dbf*
On StandBy server: */u01/app/oracle/oradata/STANDBY/system.dbf*
Or you created the directory structure manually on StandBy server? For example replacing the string STANDBY* to PRIMARY* before create the database using dbca.
Do you understand my doubt? Excuse me for my english.
Thanks. -
Directory structure for ABAP+JAVA Dialog Instance
Hello,
Can any one clarify how will be the directory structure in a case where we have ABAP+Java System?
For Central Instance,DVEBMGS<instance no>
Central Services,SCS<instance no+1>
Ex:DVEBMGS20
SCS21
If I have another dialog instance,can I have only ABAP or only Java in that?What will be the directory structure?But I read that they will be in 1:1 ratio
Will it be D22(Only ABAP) or J22(Java only).
As a dialog instance,can ABAP exist with out JAVA.
or can JAVA exist without ABAP
Please explain the directory structure with an example.
Thanks,
Sudheer.Sudheer,
http://www.redbooks.ibm.com/redpapers/pdfs/redp4200.pdf page No 24 should help you... -
Directory structure for a J2SE+J2EE project: suggestions are very welcome
Hi, I have to start coding and organizing the CVS tree of an already mature project which is J2SE. This J2SE project can be described as a "core engine" for something else, and is a quite large project, and up to now has only a command line User Interface. I organized the dir structure as this:
/build.xml
/src/
/src/java/<package>/...../*.java
/src/demo/<package/...../*.java
/src/test/<package>/....../*.java
when I ant compile, all the .classes will be done in the "build" directory (reflecting the structure in the "src" dir):
/build/
/build/java/<package>/....../*.class
/build/demo/<package/...../*.class
/build/test/<package>/..../*.class
I am happy with this, but now comes the issue: a web interface to use this core engine (it will have the same package namespace) is in developing progess, so I have to put somewhere the *.jsp, the WEB-INF dir with web.xml and servlet sources: how would you do this? And where would you let Ant put the compiled servlet classes?
I can modify the previous directory structure to accomodate the J2EE part, this is really not a problem!
Thanks to who can suggest me a clean solution
AlessioCreate a web-inf folder at the same level of src and
jsp folder inside src
i mean
/build.xml
/src/
/src/java/<package>/...../*.java
/src/demo/<package/...../*.java
/src/test/<package>/....../*.java
/src/jsp
/web-infSo, would you put in /src/jsp only the *.jsp?
And what in /WEB-INF ? What woud you put there? Would you do something like:
/WEB-INF/web.xml
/WEB-INF/src/<package>/..../<my_servlets_and_j2ee_stuff>.java
/WEB-INF/classes/<package>/..../<my_servlets_and_j2ee_stuff>.java
In this manner sources and classes are in the same tree, it does not seem very clean to me, expecially if you consider that probably I must have a "test" directory to unit test some j2ee stuff (as for the j2se stuff in "src"): how would you do that?
Is this directory structure anyway what you meant or not?
alessio -
I just created a network installer for Q4 Release. We have Developers, Full, and Debug licenses. The DVDs were copied to the VLM computer's harddrive. When I created the Debug configuration, the Network Installer reported the the DVDs did not have to be modified and would copy them directly. When the network installed was done, it did not create the directory structure similiar to what the help file below shows.
LabVIEW 8.0
\_SourceFiles
\Fourth Floor Engineering
\Client
vlmclient.exe
other files
setup.exe
\Applications Group
\Client
vlmclient.exe
other files
setup.exe
Figure 1. Network Installer Directory Structure
I would have expected
LabView 8.6
\Source Files
\Debug
\Client
vlmclient.exe
setup.exe
Only the \DISK1, \DISK2, \DISK3, \DISK4 were created. The vlmclient.exe was not created.
Paul
Solved!
Go to Solution.When you were creating the VLI, did you get a popup message that said the source did not need modification? If you saw that popup, that means VLM was not pointed to a valid source file location, which will cause a direct copy of the files with no additions.
If you select a valid source location, you should not see that message and the Product Name field should automatically populate. If you are using the Dev Suite or Platform DVDs, you will need to follow the steps in the KnowledgeBase article I refered to in my previous post.
Here is an example of what copying the installer directory could look like if you just copy the LabVIEW 8.6 Platform DVD 1:
LabVIEW 8.6 Platform DVD 1\_SourceFiles
\(the _SourceFiles directory will contain a copy of DVD 1)
\LV PDS (License Set name)
\setup.exe
\Client
\vlmclient.exe (as well as some other vlm files)
On the client machine, you would want to run "setup.exe" to begin the installation. -
In TechTools ( came with Applecare ) i got a failed on Directory Structure, second time since owning my couple month old machine, first time apple recomended reloading.
i dont mishandle it, dont bump, dent, etc, the laptop.
but all of a sudden sometimes my USB keyboard/mouse wont register as being plugged in all the time / techtools HDD errors.
only recent think if done is instal Onyx to look over the logs, and little while after ( days ) the issues started hapening,, same with last time, but didnt think it was Onyx, now im starting to wonder, anybody else have any issues like this, and Would Onyx couse it ( doubt it, but since onyx goes deep into the system, no idea )It is an interesting coincidence that I came across this thread today because I had the exact same issue myself last night.
I have plenty of space available on my HDD 73.1GB.
I downloaded the latest Onyx last night and when it starts it checks the disk. I got an error on the startup volume so I ran Tech Tools as well.
TechTools came up with that same failed Directory Structure error.
I next tried to reboot the comptuer holding down Apple/S and entering fsck -fy
That resulted in errors. Tried re-running it 3-4 tims to see if it would resolve anything but got the same error with every attempt.
I then booted from DiskWarrior and ran that. It seemed to correct a number of issues and now TechTools, Onyx, Disk Utility etc. find no problems. But it was kind of an odd occurance and interesting to find I was not alone in getting that last night.
The odd thing though is that I also checked my Mac Pro while I was wating on this one to finish and had directory errors on that one as well so had to run DiskWarrior on both.
I was kind of concerned about that to say the least.
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