File Open using Hyperlink

Hello Experts,
I am a new user to BEA Weblogic App server and need help from your side.
I have developed a web application in which i have given a hyperlink of a file inside a jsp
<p>Expiry Report</p>
but when i am clicking on the above hyperlink instead of opening the file with option ( open, save etc), its opening the file in same browser.
That was not the case when i was using any other application server like JBOSS and Tomcat.
So for opening a file thru hyperlink do we have to do any configuration in weblogic.

Sounds like a mime type issue.
Have you set the mime types appropriately by extension in web.xml?
This page shows an example that has Excel in it:
http://www.developer.com/img/2006/06/web.xml.html

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Linking KN9 files together using hyperlinks, fades to black

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I've checked all the setting and it even does it on 2 empty pages I tested with no transitions or document settings.
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The History
I reported the hyperlinking problem over a year ago when I updated Keynote from version 5.0.5 to version 5.1. According to the Apple tech that I wroked with at that time the Apple engineers had reproduced the issue and had put it on the fix list (Case 235638615). I then worked with Apple in December 2011 to test a version that supposedly fixed the problem, but did not, so Apple sent me a data logging monitor program which I ran and sent back. The Apple tech asked me to be patient as it might take awhile for the Apple engineers to fix the issue. When version 5.2 came out I reran my testing suite of presentations and found that the hyperlinking issue had still not been fixed. I have tried to contact Apple about my case since July 26th - my emails to the Apple tech with whom I worked back in December bounce back as undeliverable and he does not answer his phone (I have left messages with no replies) plus when I try to use Apple support to follow up on the case, all I get is a message to contact my Apple tech (Doh!). If Apple techs or Apple engineers watch the forums I hope they look into unresolved Case 235638615.
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Pardha,
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Hi,
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          // TODO Auto-generated catch block
          e.printStackTrace();
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temporarily suppress Alerts
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Maybe it behaves differently on a network.
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set thefile to "Western 4:photos ???:PA030012.JPG"
tell application "System Events" to get URL of disk item thefile
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%20 is the description of the space character
%3F is the description of the question mark character
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After Export to Excel File error while opening using xmlwriter in silverlight

Can one help me in fixing following issue after to export to excel had done iam getting following error message
"The file you are trying to open, 'test.xls', is in a different format than specified by the file extension. Verify that the file is not corrupted and is from a trusted source before opening the file. Do uou want to open the file now ?"
If i click Yes file opens correctly but it shows above message . Can any one suggest me how to avoid this programatically with the following code.
I tried by changing the file saving as .xls to .xlsx but it doesnt works.
Public Sub Export()
Dim ss As String = "urn:schemas-microsoft-com:office:spreadsheet"
Dim DataType As String
Dim DataValue As Object
'Dim DataView As C1.Silverlight.Data.DataView = m_DataGrid.ItemsSource
'Dim ItemsSource As C1.Silverlight.Data.DataTable = DataView.Table
Dim XmlSettings As XmlWriterSettings
Dim ColumnBinding As Binding
Dim FieldName As String
Dim DataGridColumn As C1.Silverlight.DataGrid.DataGridColumn
Dim ColumnIndex As Integer
Dim J As Integer
Dim DataGridRow As C1.Silverlight.DataGrid.DataGridRow
Dim CommonUtil As New GoldCRM.Core.Common.Util
Dim PropertyInfo As System.Reflection.PropertyInfo
Dim CellFormat As String
Try
If m_DataGrid.Rows.Count = 0 Then Exit Try
XmlSettings = New XmlWriterSettings
XmlSettings.Indent = True
XmlSettings.NewLineOnAttributes = False
Using myXML As XmlWriter = XmlWriter.Create(m_Stream, XmlSettings)
With myXML
.WriteStartDocument()
.WriteProcessingInstruction("mso-application", "progid=" & ControlChars.Quote & "Excel.Sheet" & ControlChars.Quote)
.WriteStartElement("Workbook", ss)
.WriteStartElement("DocumentProperties", "urn:schemas-microsoft-com:office:office")
.WriteElementString("Author", m_DocumentProperties.Author)
.WriteElementString("LastAuthor", String.Format("{0} {1}", Application.Current.Resources("EmpFirstName"), Application.Current.Resources("EmpLastName")))
.WriteElementString("Created", m_DocumentProperties.Created)
.WriteElementString("LastSaved", m_DocumentProperties.LastSaved)
.WriteElementString("Company", Application.Current.Resources("REPORTINGSITENAME"))
.WriteElementString("Version", m_DocumentProperties.Version)
.WriteEndElement() 'Document Properties
.WriteStartElement("ExcelWorkbook", "urn:schemas-microsoft-com:office:excel")
.WriteElementString("WindowHeight", m_WorkbookProperties.WindowHeight)
.WriteElementString("WindowWidth", m_WorkbookProperties.WindowWidth)
.WriteElementString("WindowTopX", m_WorkbookProperties.WindowTopX)
.WriteElementString("WindowTopY", m_WorkbookProperties.WindowTopY)
.WriteElementString("ProtectStructure", m_WorkbookProperties.ProtectStructure)
.WriteElementString("ProtectWindows", m_WorkbookProperties.ProtectWindows)
.WriteEndElement() 'Excel Workbook
.WriteStartElement("Styles")
For I As Integer = 0 To m_Styles.Count - 1
.WriteStartElement("Style")
.WriteAttributeString("ss", "ID", ss, m_Styles(I).ID)
If m_Styles(I).Name <> "" Then
.WriteAttributeString("ss", "Name", ss, m_Styles(I).Name)
End If
'ALIGNMENT LOGIC:
.WriteStartElement("Alignment")
If Not m_Styles(I).Alignment Is Nothing Then
If m_Styles(I).Alignment.Horizontal <> 0 Then
.WriteAttributeString("ss", "Horizontal", ss, m_Styles(I).Alignment.Horizontal.ToString)
End If
If m_Styles(I).Alignment.Vertical <> 0 Then
.WriteAttributeString("ss", "Vertical", ss, m_Styles(I).Alignment.Vertical.ToString)
End If
If m_Styles(I).Alignment.WrapText = True Then
.WriteAttributeString("ss", "WrapText", ss, "1")
End If
End If
.WriteEndElement()
'BORDER LOGIC:
.WriteStartElement("Borders")
.WriteStartElement("Border")
.WriteAttributeString("ss", "Position", ss, "Bottom")
.WriteAttributeString("ss", "LineStyle", ss, "Continuous")
.WriteAttributeString("ss", "Weight", ss, "1")
.WriteEndElement() 'Border
.WriteStartElement("Border")
.WriteAttributeString("ss", "Position", ss, "Left")
.WriteAttributeString("ss", "LineStyle", ss, "Continuous")
.WriteAttributeString("ss", "Weight", ss, "1")
.WriteEndElement() 'Border
.WriteStartElement("Border")
.WriteAttributeString("ss", "Position", ss, "Right")
.WriteAttributeString("ss", "LineStyle", ss, "Continuous")
.WriteAttributeString("ss", "Weight", ss, "1")
.WriteEndElement() 'Border
.WriteStartElement("Border")
.WriteAttributeString("ss", "Position", ss, "Top")
.WriteAttributeString("ss", "LineStyle", ss, "Continuous")
.WriteAttributeString("ss", "Weight", ss, "1")
.WriteEndElement() 'Border
.WriteEndElement() 'Borders
'FONT LOGIC:
.WriteStartElement("Font")
Dim myFont As Excel.Styles.Font = m_Styles(I).Font
.WriteAttributeString("ss", "FontName", ss, myFont.FontName.ToString)
.WriteAttributeString("ss", "Size", ss, myFont.Size)
.WriteAttributeString("ss", "Color", ss, myFont.Color.ToString.Remove(1, 2))
If myFont.Bold = True Then .WriteAttributeString("ss", "Bold", ss, "1")
If myFont.Italic = True Then .WriteAttributeString("ss", "Italic", ss, "1")
If myFont.Underline <> 0 Then .WriteAttributeString("ss", "Underline", ss, myFont.Underline.ToString)
.WriteEndElement()
Dim myInterior As Excel.Styles.Interior = m_Styles(I).Interior
.WriteStartElement("Interior")
.WriteAttributeString("ss", "Color", ss, myInterior.Color.ToString.Remove(1, 2))
.WriteAttributeString("ss", "Pattern", ss, "Solid")
.WriteEndElement()
.WriteStartElement("NumberFormat")
.WriteEndElement()
.WriteStartElement("Protection")
.WriteEndElement()
.WriteEndElement() 'Style
Next I
.WriteStartElement("Style")
.WriteAttributeString("ss", "ID", ss, "DateStyle")
.WriteStartElement("NumberFormat")
.WriteAttributeString("ss", "Format", ss, "General Date")
.WriteEndElement() 'NumberFormat
.WriteEndElement() 'Style
.WriteStartElement("Style")
.WriteAttributeString("ss", "ID", ss, "HeaderStyle")
.WriteStartElement("Font")
.WriteAttributeString("x", "Family", ss, "Swiss")
.WriteAttributeString("ss", "Bold", ss, "1")
.WriteEndElement() 'Font
.WriteEndElement() 'Style
.WriteEndElement() 'Styles
'WORKSHEETS:
.WriteStartElement("Worksheet")
.WriteAttributeString("ss", "Name", ss, "WORKSHEET")
.WriteStartElement("Table")
.WriteAttributeString("ss", "ExpandedColumnCount", ss, m_DataGrid.Columns.Count)
.WriteAttributeString("ss", "ExpandedRowCount", ss, m_DataGrid.Rows.Count + 100) 'Temporary fix: sometimes 1 row is not added.
.WriteAttributeString("ss", "FullColumns", ss, m_DataGrid.Columns.Count)
.WriteAttributeString("ss", "FullRows", ss, m_DataGrid.Rows.Count + 100) 'Temporary fix: sometimes 1 row is not added.
.WriteAttributeString("ss", "DefaultRowHeight", ss, 15)
For Each DataGridColumn In m_DataGrid.Columns
If DataGridColumn.Visibility = Visibility.Visible Then
.WriteStartElement("Column")
If TypeOf DataGridColumn Is C1.Silverlight.DataGrid.DataGridNumericColumn Then
.WriteAttributeString("ss", "AutoFitWidth", ss, 1)
ElseIf TypeOf DataGridColumn Is C1.Silverlight.DataGrid.DataGridDateTimeColumn Then
.WriteAttributeString("ss", "AutoFitWidth", ss, 1)
Else
.WriteAttributeString("ss", "AutoFitWidth", ss, 0)
End If
If DataGridColumn.Width.Value <= 100 Then
.WriteAttributeString("ss", "Width", ss, 100)
Else
.WriteAttributeString("ss", "Width", ss, DataGridColumn.Width.Value)
End If
.WriteEndElement()
End If
Next
J = 0
For Each DataGridRow In m_DataGrid.Rows
J += 1
If TypeOf DataGridRow Is GoldCRM.Controls.Filter.clsFilterRow Then
.WriteStartElement("Row")
.WriteAttributeString("ss", "Index", ss, J)
.WriteAttributeString("ss", "AutoFitHeight", ss, 0)
.WriteAttributeString("ss", "Height", ss, 15)
ColumnIndex = 0
For Each DataGridColumn In m_DataGrid.Columns
If DataGridColumn.Visibility = Visibility.Visible Then
FieldName = String.Empty
If TypeOf DataGridColumn Is DataGridBoundColumn Then
ColumnBinding = TryCast(DataGridColumn, DataGridBoundColumn).Binding
If ColumnBinding.Path IsNot Nothing Then
FieldName = ColumnBinding.Path.Path
End If
ElseIf TypeOf DataGridColumn Is DataGridTemplateColumn Then
If DataGridColumn.FilterMemberPath IsNot Nothing Then
FieldName = DataGridColumn.FilterMemberPath.Trim
End If
End If
If Not FieldName.Equals(String.Empty) Then
ColumnIndex += 1
.WriteStartElement("Cell")
.WriteAttributeString("ss", "Index", ss, ColumnIndex)
.WriteAttributeString("ss", "MergeAcross", ss, 0)
.WriteAttributeString("ss", "StyleID", ss, "HeaderStyle")
.WriteStartElement("Data")
.WriteAttributeString("ss", "Type", ss, "String")
If DataGridColumn.Header IsNot Nothing Then
.WriteValue(DataGridColumn.Header.ToString)
Else
.WriteValue("")
End If
.WriteEndElement() 'Data
.WriteEndElement() 'Cell
End If
End If
Next
.WriteEndElement() 'Row
End If
If Not (TypeOf DataGridRow Is GoldCRM.Controls.Filter.clsFilterRow) Then
.WriteStartElement("Row")
.WriteAttributeString("ss", "Index", ss, J + 1)
.WriteAttributeString("ss", "AutoFitHeight", ss, 0)
.WriteAttributeString("ss", "Height", ss, 15)
ColumnIndex = 0
For Each DataGridColumn In m_DataGrid.Columns
If DataGridColumn.Visibility = Visibility.Visible Then
FieldName = String.Empty
If TypeOf DataGridColumn Is DataGridBoundColumn Then
ColumnBinding = TryCast(DataGridColumn, DataGridBoundColumn).Binding
If ColumnBinding.Path IsNot Nothing Then
FieldName = ColumnBinding.Path.Path
End If
ElseIf TypeOf DataGridColumn Is DataGridTemplateColumn Then
If DataGridColumn.FilterMemberPath IsNot Nothing Then
FieldName = DataGridColumn.FilterMemberPath.Trim
End If
End If
If Not FieldName.Equals(String.Empty) Then
ColumnIndex += 1
Dim DataCellValue As Object = Nothing
If Not (TypeOf DataGridRow Is GoldCRM.Controls.Filter.clsFilterRow) Then
PropertyInfo = CommonUtil.GetProperty(DataGridRow.DataItem, FieldName)
If PropertyInfo IsNot Nothing Then
DataCellValue = PropertyInfo.GetValue(DataGridRow.DataItem, Nothing)
End If
End If
CellFormat = String.Empty
If DataCellValue IsNot Nothing Then
Select Case DataCellValue.GetType.Name.ToUpper
Case "BitmapImage".ToUpper
DataValue = "Image"
DataType = "String"
Case "Hyperlink".ToUpper
DataType = "String"
DataValue = "Hyperlink"
Case "Decimal".ToUpper
DataType = "Number"
DataValue = DataCellValue
Case "DateTime".ToUpper
If CType(DataCellValue, Date).Year > 1900 Then
DataType = "DateTime"
DataValue = DataCellValue
CellFormat = "DateStyle"
Else
DataType = "String"
DataValue = DataCellValue
End If
Case Else
DataType = "String"
DataValue = DataCellValue
End Select
Else
DataType = "String"
DataValue = String.Empty
End If
.WriteStartElement("Cell")
.WriteAttributeString("ss", "Index", ss, ColumnIndex)
.WriteAttributeString("ss", "MergeAcross", ss, 0)
If Not CellFormat.Equals(String.Empty) Then
.WriteAttributeString("ss", "StyleID", ss, CellFormat)
End If
.WriteStartElement("Data")
.WriteAttributeString("ss", "Type", ss, DataType)
.WriteValue(DataValue)
.WriteEndElement() 'Data
.WriteEndElement() 'Cell
End If
End If
Next
.WriteEndElement() 'Row
End If
Next
.WriteEndElement() 'Table
.WriteEndElement() 'Worksheet
.WriteEndElement() 'Workbook
.WriteEndDocument()
.Close()
End With
End Using
Catch ex As Exception
Throw New Exception(ex.Message, ex)
Finally
If m_Stream IsNot Nothing Then
m_Stream.Close()
m_Stream.Dispose()
End If
m_Stream = Nothing
m_DataGrid.IsLoading = False
DataValue = Nothing
'DataView = Nothing
'ItemsSource = Nothing
XmlSettings = Nothing
ColumnBinding = Nothing
DataGridColumn = Nothing
End Try
End Sub
Krishna

Hi,
i have the same issue now where i need to populate the xport file name as report name. can you send me your solution please.

Unable to edit XLSM files in SharePoint using hyperlink?

Hi All,
Unable to edit .xlsm files using hyperlink, please guide me.
Thanks
Ramanjulu Naidu N

Hi Ramanjulu,
Did this happen to all users?
Did the "Read Only/Edit" dialog pop up when you click the .xlsm Name link from SharePoint 2010?
Could you see the yellow message bar with "Edit Workbook" button when you open the .xlsm file in your Excel Application?
You can check if the following kb article could solve yellow message bar missing problem, set "Browser File Handling" as Permissive for your web application, or update the registry for client Office application.
Also check if the add-on "SharePoint OpenDocuments Class" is enabled in your IE 32-bit browser.
http://support.microsoft.com/kb/2661910
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Is there some sort of security permission that is not allowing a pdf file to open a hyperlinked password protected PDF file in Windows 7.
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I think this may have something to do with your dns settings. From a shell type ipconfig /flushdns and try again.

Use hyperlink to open another page , and pass some parameters to that page

Hi
Thank you for reading my post.
How i can use hyperlink to open another jsp file in a new window meanwhile pass some parameters to it.
for example i need something like this :
http://127.0.0.1:8080/myProj/faces/Viewmessage.jsp?messageID=10
i can not use session bean because i must open that in a new window and use hyperlink not Action
Thank you

I tried the following in the equivalent of your Viewmessage (page bean):
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        Map requestParams = eContext.getRequestParameterMap();
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I hope this helps.
-- Marco

Office documents do not open from hyperlink or from File Open

I have several users, including myself, that have an issue opening MS Office 2013 documents. The issue can happen in one of two ways. 1st, often when there is already a Word or Excel document open and you try to open another either by File > Open or going
to the folder and double- clicking the file. It seems that Office just hangs on it and never opens the file.
2nd, clicking on a hyperlink in an IE browser. The file doesn't open but the icon for the file (either Word or Excel) shows on the taskbar as if there is an open document.
No errors are given and sometimes if you repeat the process a few times the file will eventually open. All users having the issue are on Windows 7 Pro both 32bit and 64bit.

Hi,
We can perform a clean boot to determine whether background programs are interfering with Office applications:
http://support.microsoft.com/kb/929135
In case it is due to some sort of macro running on your system, or it could be due to a problem with Word itself. Try to run Word and disable any add-ins that may be loaded by using the following from the command line:
winword.exe /a
You can also try to disable any macros that are automatically run when Word is started by using this command:
winword.exe /m
Let it me know if this helps.
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Melon Chen
TechNet Community Support

Opening child report through master report using hyperlink

HI Experts,
I have a requirement where, I need to create a child report which will open through a master report using hyperlink.
I have to use BIP desktop (MS word) and need to create a RTF template using XML file.
Can you please guide me, how I can achieve this?
Regards,
Suhasini
Edited by: 942451 on Jun 28, 2012 9:48 PM

Take a look at this blog post: http://bipconsulting.blogspot.com/2010/02/drill-down-to-detail-or-another-report.html
Thanks,
Bipuser

Opening PDF files using preview on some PDF file result in the content not displaying properly. The file I tried to look at has pictures and text. The pictures are displayed ok but the text is shown as pixalated boxes. The same file opens ok via a PC.

Solutions please. Accessing PDF files online using preview normally works ok. However there are a clutch of files on the mothers union web site that although can be opened, present text as pixalated boxes. The pictures contained in the documents are however displayed OK. I experience the same problem on my Imac and my wifes laptop that runs Lion. The same site has other PDF files that can be opend OK. If I access the same problem files using a PC laptop running microsoft windows, they are opened OK with the text displayed as it should be. This is driving me mad....

Raymondo1 wrote:
The offending PDF files were created using word
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<http://www.adobe.com/support/security/bulletins/apsb12-01.html>
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