FILE UPLOAD PROBLEM SHOWING THE CONTENTS IN THE SAME BROWSER WINDOW
Hi,
This is amit Joshi
I have uploaded content using input tag of type file and posted to jsp as multipart/form-data type
in that jsp i am using following code to display the content in browser but only first content is displayed How can i modify it to show all content in the file ..
<html>
<head>
<title>File Upload Display</title>
</head>
<body>
<%
//ServletOutputStream sout=response.getOutputStream();
StringBuilder strBuilder = new StringBuilder();
int count=0;
String f;
f=request.getParameter("filedb");
DBManager dbm = new DBManager();
//dbm.createTable("mms3");
//log.info("In JSP : "+ f);
//dbm.insert_data(f,"mms3");
%>
<%
if (ServletFileUpload.isMultipartContent(request)){
ServletFileUpload servletFileUpload = new ServletFileUpload(new DiskFileItemFactory());
List fileItemsList = servletFileUpload.parseRequest(request);
strBuilder.append("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>").append('\r').append('\n').append("<xpage version=\"1.0\">").append('\r').append('\n');
String optionalFileName = "";
FileItem fileItem = null;
Iterator it = fileItemsList.iterator();
ServletOutputStream outputStream=null;
while (it.hasNext()){
FileItem fileItemTemp = (FileItem)it.next();
if (fileItemTemp.isFormField()){
%>
<b>Name-value Pair Info:</b>
Field name: <%= fileItemTemp.getFieldName() %>
Field value: <%= fileItemTemp.getString() %>
<%
if (fileItemTemp.getFieldName().equals("filename"))
optionalFileName = fileItemTemp.getString();
else
fileItem = fileItemTemp;
if (fileItem!=null){
String fileName = fileItem.getName();
%>
<b>Uploaded File Info:</b>
Content type: <%= fileItem.getContentType() %>
Field name: <%= fileItem.getFieldName() %>
File name: <%= fileName %>
<%
if(fileItem.getContentType().equals("image/jpeg")) { %>
File : <p><%
//response.setContentType("image/gif");
byte[] bArray=fileItem.get();
response.setContentType("image/jpeg");
outputStream=null;
outputStream= response.getOutputStream();
outputStream.write(bArray);
outputStream.flush();
outputStream.close();
else if(fileItem.getContentType().equals("text/plain"))
%> File : <%= fileItem.getString() %>
<%
byte[] bArray=fileItem.get();
response.setContentType("text/plain");
outputStream = response.getOutputStream();
out.println();
outputStream.write(bArray);
outputStream.flush();
outputStream.close();
%> </p> <%
%>
</body>
</html>
Edited by: Amit_Joshi on Nov 13, 2007 10:58 PM
Well Well Well..
That would not work...
What you have to do is save the uploaded file content on to a location and then pass the fileName as a request parameter to a deidicated which displays the contents of that file.
Just as an example
<html>
<head>
<title>File Upload Display</title>
</head>
<body>
<%
//ServletOutputStream sout=response.getOutputStream();
StringBuilder strBuilder = new StringBuilder();
int count=0;
String f;
f=request.getParameter("filedb");
DBManager dbm = new DBManager();
//dbm.createTable("mms3");
//log.info("In JSP : "+ f);
//dbm.insert_data(f,"mms3");
%>
<%
if (ServletFileUpload.isMultipartContent(request)){
ServletFileUpload servletFileUpload = new ServletFileUpload(new DiskFileItemFactory());
List fileItemsList = servletFileUpload.parseRequest(request);
strBuilder.append("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>").append('\r').append('\n').append("<xpage version=\"1.0\">").append('\r').append('\n');
String optionalFileName = "";
FileItem fileItem = null;
Iterator it = fileItemsList.iterator();
ServletOutputStream outputStream=null;
while (it.hasNext()){
FileItem fileItemTemp = (FileItem)it.next();
%>
Name-value Pair Info:
Field name: <%= fileItemTemp.getFieldName() %><br/>
Field value: <%= fileItemTemp.getString() %><br/>
<%
if (fileItemTemp.getFieldName().equals("filename"))
optionalFileName = fileItemTemp.getString();
if(!fileTempItem.isFormFiled()){
String fileName = fileItem.getName();
fileItem.write(optionalFileName);
%>
Uploaded File Info:
Content type: <%= fileItem.getContentType() %><br/>
Field name: <%= fileItem.getFieldName() %><br/>
File name: <%= fileName %><br/>
<%
if(fileItem.getContentType().equals("image/jpeg") || fileItem.getContentType().equals("image/pjeg")) {
%>
<img src="FileServlet?fileName=<%=optionalFileName%>"
<%
%>
</body>
</html>a sample code snippet for FileServlet.
String fileName = request.getParameter(fileName);
File file = new File(fileName);
if(!file.exists())
return;
// If JSP
String mimeType = application.getMimeType("fileName");
If you are using servlet
String mimeType = this.getServletContext().getMimeType(fileName);
response.setContentType(mimeType);
response.setHeader("Content-Disposition","inline;filename=\\"+fileName+"\\");
BufferedOutputStream out1 = null;
InputStream in = null;
if(mimeType == null)
mimeType = "application/octet-stream";
try{
in = new FileInputStream(f);
response.setContentLength(in.available());
BufferedOutputStream out1 = new BufferedOutputStream(response.getOutputStream(),1024);
int size = 0;
byte[] b = new byte[1024];
while ((size = in.read(b, 0, 1024)) > 0)
out1.write(b, 0, size);
}catch(Exception exp){
}finally{
if(out1 != null){
try{
out1.flush();
out1.close();
}catch(Exception e){}
if(in != null){
try{in.close();}catch(Exception e){}
} Hope that might answer your question :)
However,this is not the recommended way of doing this make use of MVC pattern.Would be a better approach.
you might think of googling on this and can findout what is the best practise followed for problems of this sort
REGARDS,
RaHuL
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I am using a input box to get the path of the file to be uploaded.(I am not using FILE UPLOAD UI Element).Could you please let me know how to get the content of the uploaded file.
Regards,
Arun>
ARUN KUMAR.S wrote:
> Hi Experts,
>
> I am using a input box to get the path of the file to be uploaded.(I am not using FILE UPLOAD UI Element).Could you please let me know how to get the content of the uploaded file.
>
> Regards,
> Arun
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