Find and remove files

Question

Hi,
I was given a task to do some housekeeping of users directory
Basically, the structure is of below.
/User DIR
---UserA
---UserB
---UserC
---UserD
---UserE
Each user contain several type of files.
I wan to do a housekeep of the directories to remove *.txt, *.log, *.wk1 that are more than 5 days old.
Pls kindly assist.
i need to search for several type of extension .wk1 , .log , .txt etc. how do i incorporate it in? . Another thing is
ls -l | find . -name "*.txt" -mtime +3 -exec ls {} \; it actually returns me all the subdirectories as well. y is that so?
in my office, i have existing scripts that have similiar syntax
find . ! -type d -ctime -5 -name '*.txt' -exec ls {} \;
find . ! -type d -ctime -5 -name '*.txt' -exec rm -f {} \;
what does find . ! -type d means?
Pls kindly assist.

Answer 1

cghcgh wrote:
echo "\n Foldername = ${DIRNAME}"
cd ${DIRNAME}
USERFILE=`ls -1 *.xls *.wk1 *.txt`
for USERFILENAME in ${USERFILE}; do
echo "\n Checking whether file is more than 7 days"
echo " Filename = ${USERFILENAME}"
echo " Removing this file = `find . -mtime +${KEEP} -a -name ${USERFILENAME} -exec ls -l {} \;`"
find . -mtime +${KEEP} -a -name ${USERFILENAME} -exec rm
UGH You are looking for files with an ls, then going back and running two separate finds for every file. But every find will do a full descent/search run of all data in that directory. That's horribly inefficient. The more data under that directory and the more files the 'ls' hands off, the more time and IO it will consume.
Why not just replace that section above with:
echo "\n Foldername = ${DIRNAME}"
find ${DIRNAME} ! -type d \(-name "*.xls" -o -name "*.wk1" -o -name "*.txt" \) -mtime +${KEEP} -exec rm {} +
One find, no 'ls', no problems with spaces.
Add in a '-print' before the '-exec' if you want to print or capture the filenames as you're removing them.
Darren