Find duplicate values in a vector???
Hi,
Can somebody help me please?????
I have a little problem, but I can't find it :-(
I have a vector with a lot of values,
The question is, how can I find duplicated values?
Vector VNumber = new Vector();
VNumber.addElement(Bknm);
/**Bknm->values read out of a file**/
for(int j=0;j<VNumber.size();j++){
System.out.printl("Bknm = " + Bknm.elementAt(j));
/**code for find duplicate values????**/
}
Its much easier to check items as they are going in, rather than parsing the Vector and finding dupes.
Vector VNumber = new Vector();
while(true)
// Read next Bknm object here
if(!VNumber.contains(Bknm))
VNumber.add(Bknm);
Similar Messages
-
Finding duplicate values in a column with different values in a different c
I'm finding duplicate values in a column of my table:
select ba.CLAIM_NUMBER from bsi_auto_vw ba
group by ba.CLAIM_NUMBER
having count(*) > 1;
How can I modify this query to find duplicate values in that column where I DON'T have duplicate values in a different specific column in that table (the column CLMT_NO in my case can't have duplicates.)?Well, you can use analytics assuming you don't mind full scanning the table.....
select
count(owner) over (partition by object_type),
count(object_type) over (partition by owner)
from all_objects;You just need to intelligently (i didn't here) find your "window" (partition clause) to sort the data over, then make use of that (the analytics would be in a nested SQL and you'd then evaluate it in outside).
Should be applicable if i understand what you're after.
If you post some sample data we can mock up a SQL statement for you (if what i tried to convey wasn't understandable). -
Find duplicate values in a table based on combination of two columns.
In table which have millions of records -
I have a Table B under Schema A and i have to find the duplicate records in a table. My Table B uses the combination of columns to identify the unique values.
Scenario is something like this-
One SV_Id can have multiple SV_Details_Id and i have to find out if there is any duplicate in the table. (I have to use combination of columns to identify the unique values and there is no Primary Key, Foreign Key or Unique Key on the table)
then wrote the following query -
select SV_Id,SV_Details_Id count (*) from SchemaA.TableB group by SV_Id,SV_Details_Id having Count (*) > 1 ;
Is it correct as after firing the above query it is returning the rows which is not matching to the duplicate.
kindly help me.
Looking forward for some guidance -
Thanks in advance.What is the desired output??
Do you want to see only unique records??
Or you want to see the duplicate records.
Giving an example will make it easier to provide the required querty.
BTW here is an simple query which is used to delete the duplicate records and keep the unique records in table.
DELETE
FROM table_name a
WHERE EXISTS (SELECT 1
FROM table_name b
WHERE a.sv_id = b.sv_id
AND a.sv_detail_id = b.sv_detail_id
AND a.ROWID > b.ROWID
);Regards
Arun -
How can i find duplicate rows in a field of a table
hi all,
how can i able to find duplicate values in a field of a table????
Regardstest@ORA92>
test@ORA92> with x as (
2 select 1 as p, 'a' as q from dual union all
3 select 1 as p, 'b' as q from dual union all
4 select 2 as p, 'c' as q from dual union all
5 select 3 as p, 'd' as q from dual union all
6 select 3 as p, 'e' as q from dual union all
7 select 3 as p, 'd' as q from dual
8 )
9 select p, q,
10 case row_number() over (partition by p order by q)
11 when 1 then null
12 else 'Duplicate value: '||p||' of column p'
13 end as msg
14 from x;
P Q MSG
1 a
1 b Duplicate value: 1 of column p
2 c
3 d
3 d Duplicate value: 3 of column p
3 e Duplicate value: 3 of column p
6 rows selected.
test@ORA92>
test@ORA92>
test@ORA92>cheers,
pratz -
How find out the duplicate value from each columns.
I have below four columns,
How can i find out the duplicate value from each columns.
with All_files as (
select '1000' as INVOICE,'2000' AS DELIVERYNOTE,'3000' CANDELINVOICE,'4000' CANDELIVERYNOTE from dual union all
select '5000','6000','7000','8000' from dual union all
select '9000','1000','1100','1200' from dual union all
select '1200','3400','6700','8790' from dual union all
select '1000','2000','3000','9000' from dual union all
select '1230','2340','3450','4560' from dual
SELECT * FROM All_files
Output should be as per below.
1000 2000 3000 4000
9000 1000 1100 1200
1200 3400 6700 8790
1000 2000 3000 9000
Required to check uniqueness in cross columns.
Thanks.Try this (sorry about the formatting)...
WITH all_files AS (SELECT '1000' AS INVOICE,
'2000' AS DELIVERYNOTE,
'3000' CANDELINVOICE,
'4000' CANDELIVERYNOTE
FROM DUAL
UNION ALL
SELECT '5000',
'6000',
'7000',
'8000'
FROM DUAL
UNION ALL
SELECT '9000',
'1000',
'1100',
'1200'
FROM DUAL
UNION ALL
SELECT '1200',
'3400',
'6700',
'8790'
FROM DUAL
UNION ALL
SELECT '1000',
'2000',
'3000',
'9000'
FROM DUAL
UNION ALL
SELECT '1230',
'2340',
'3450',
'4560'
FROM DUAL),
t_base
AS (SELECT invoice
|| ','
|| deliverynote
|| ','
|| candelinvoice
|| ','
|| candeliverynote
str
FROM all_files),
t_str
AS (SELECT str || ',' AS str,
(LENGTH (str) - LENGTH (REPLACE (str, ','))) + 1
AS no_of_elements
FROM t_base),
t_n_rows
AS ( SELECT LEVEL AS i
FROM DUAL
CONNECT BY LEVEL <=
( SELECT SUM (no_of_elements) FROM t_str)),
t_build AS (SELECT t_str.str,
nt.i AS element_no,
INSTR (t_str.str,
DECODE (nt.i, 1, 0, 1),
DECODE (nt.i, 1, 1, nt.i - 1))
+ 1
AS start_pos,
INSTR (t_str.str,
1,
DECODE (nt.i, 1, 1, nt.i))
AS next_pos
FROM t_str
JOIN
t_n_rows nt
ON nt.i <= t_str.no_of_elements),
t_build2
AS (SELECT RTRIM (str, ',') AS original_string,
SUBSTR (str, start_pos, (next_pos - start_pos))
AS single_element,
element_no
FROM t_build),
t_build3
AS (SELECT single_element,
COUNT( * )
OVER (PARTITION BY single_element
ORDER BY single_element)
ele_count
FROM t_build2)
SELECT DISTINCT INVOICE,
DELIVERYNOTE,
CANDELINVOICE,
CANDELIVERYNOTE
FROM all_files, t_build3
WHERE ele_count > 1
AND ( INVOICE = single_element
OR DELIVERYNOTE = single_element
OR CANDELINVOICE = single_element
OR CANDELIVERYNOTE = single_element)I think this will be faster than the previous solution?
Cheers
Ben
Edited by: Munky on Feb 17, 2011 2:11 PM - "I think this will be faster than the previous solution?", nope - it's not :( -
Avoiding null and duplicate values using model clause
Hi,
I am trying to use model clause to get comma seperated list of data : following is the scenario:
testuser>select * from test1;
ID VALUE
1 Value1
2 Value2
3 Value3
4 Value4
5 Value4
6
7 value5
8
8 rows selected.
the query I have is:
testuser>with src as (
2 select distinct id,value
3 from test1
4 ),
5 t as (
6 select distinct substr(value,2) value
7 from src
8 model
9 ignore nav
10 dimension by (id)
11 measures (cast(value as varchar2(100)) value)
12 rules
13 (
14 value[any] order by id =
15 value[cv()-1] || ',' || value[cv()]
16 )
17 )
18 select max(value) oneline
19 from t;
ONELINE
Value1,Value2,Value3,Value4,Value4,,value5,
what I find is that this query has duplicate value and null (',,') coming in as data has null and duplicate value. Is there a way i can avoid the null and the duplicate values in the query output?
thanks,
Edited by: orausern on Feb 19, 2010 5:05 AMHi,
Try this code.
with
t as ( select substr(value,2)value,ind
from test1
model
ignore nav
dimension by (id)
measures (cast(value as varchar2(100)) value, 0 ind)
rules
( ind[any]= instr(value[cv()-1],value[cv()]),
value[any] order by id = value[cv()-1] || CASE WHEN value[cv()] IS NOT NULL
and ind[cv()]=0 THEN ',' || value[cv()] END
select max(value) oneline
from t;
SQL> select * from test1;
ID VALUE
1 Value1
2 Value2
3 Value3
4 Value4
5 Value4
6
7 value5
8
8 ligne(s) sélectionnée(s).
SQL> with
2 t as ( select substr(value,2)value,ind
3 from test1
4 model
5 ignore nav
6 dimension by (id)
7 measures (cast(value as varchar2(100)) value, 0 ind)
8 rules
9 ( ind[any]= instr(value[cv()-1],value[cv()]),
10 value[any] order by id = value[cv()-1] || CASE WHEN value[cv()] IS NOT NULL
11 and ind[cv()]=0 THEN ',' || value[cv()] END
12 )
13 )
14 select max(value) oneline
15 from t;
ONELINE
Value1,Value2,Value3,Value4,value5
SQL> -
Unable to Enforce Unique Values, Duplicate Values Exist
I have list in SP 2010, it contains roughly 1000 items. I would like to enforce unique values on the title field. I started by cleaning up the list, ensuring that all items already had a unique value. To help with this, I used the export
to excel action, then highlight duplicates within Excel. So as far as I can tell, there are no duplicates within that list column.
However, when I try to enable the option to Enforce Unique Values, I receive the error that duplicate values exist within the field and must be removed.
Steps I've taken so far to identify / resolve duplicate values:
- Multiple exports to Excel from an unfiltered list view, then using highlight duplicates feature > no duplicates found
- deleted ALL versions of every item from the list (except current), ensured they were completely removed by deleting from both site and site collection recycle bins
- Using the SP Powershell console, grabbed all list items and exported all of the "Title" type fields (Item object Title, LinkTitle, LinkTitleNoMenu, etc) to a csv and ran that through excel duplicate checking as well.
Unless there's some rediculous hidden field value that MS expects anyone capable of attempting to enforce unique values on a list (which is simple enough for anyone to figure out - if it doesn't throw an error), then I've exhausted anything I can think
of that might cause the list to report duplicate values for that field.
While I wait to see if someone else has an idea, I'm also going to see what happens if I wipe the Crawl Index and start it from scratch.
- JonFirst, I create index for a column in list settings, it works fine no matter duplicate value exists or not;
then I set enforce unique values in the field, after click OK, I get duplicate values error message.
With SQL Server profiler, I find the call to proc_CheckIfExistingFieldHasDuplicateValues and the parameters. After reviewing this stored procedure in content database,
I create the following script in SQL Server management studio:
declare @siteid
uniqueidentifier
declare @webid
uniqueidentifier
declare @listid
uniqueidentifier
declare @fieldid
uniqueidentifier
set @siteid='F7C40DC9-E5D3-42D7-BE60-09B94FD67BEF'
set @webid='17F02240-CE04-4487-B961-0482B30DDA84'
set @listid='B349AF8D-7238-419D-B6C4-D88194A57EA7'
set @fieldid='195A78AC-FC52-4212-A72B-D03144DC1E24'
SELECT
* FROM TVF_UserData_List(@ListId)
AS U1 INNER
MERGE JOIN
NameValuePair_Latin1_General_CI_AS
AS NVP1 WITH (INDEX=NameValuePair_Latin1_General_CI_AS_MatchUserData)
ON NVP1.ListId
= @ListId AND NVP1.ItemId
= U1.tp_Id
AND ((NVP1.Level
= 1 AND U1.tp_DraftOwnerId
IS NULL)
OR NVP1.Level
= 2)
AND NOT((DATALENGTH(ISNULL(NVP1.Value,
= 0)) AND U1.tp_Level
= NVP1.Level
AND U1.tp_IsCurrentVersion
= CONVERT(bit, 1)
AND U1.tp_CalculatedVersion
= 0 AND U1.tp_RowOrdinal
= 0 INNER
MERGE JOIN
NameValuePair_Latin1_General_CI_AS
AS NVP2 WITH (INDEX=NameValuePair_Latin1_General_CI_AS_CI)
ON NVP2.SiteId
= @SiteId AND NVP2.ListId
= @ListId AND NVP2.FieldId
= @FieldId AND NVP2.Value
= NVP1.Value
AND NVP2.ItemId <> NVP1.ItemId
CROSS APPLY TVF_UserData_ListItemLevelRow(NVP2.ListId, NVP2.ItemId,
NVP2.Level, 0)
AS U2 WHERE ((NVP2.Level
= 1 AND U2.tp_DraftOwnerId
IS NULL)
OR NVP2.Level
= 2)
AND NOT((DATALENGTH(ISNULL(NVP2.Value,
= 0))
I can find the duplicate list items based on the result returned by the query above.
Note that you need to change the parameter values accordingly, and change the name of NameValuePair_Latin1_General1_CI_AS table based on the last parameter of the
proc_CheckIfExistingFieldHasDuplicateValues stored procedure. You can review the code of this stored procedure by yourself.
Note that direct operation on the content database in production environment is not supported, please do all these in test environment. -
hi,
Please see the tabl;e structure below
-- Create table
create table RN_RPT_FIG
DT DATE not null,
RPT_ID NUMBER(8) not null,
RPT_ROW_ID NUMBER(4) not null,
RPT_COL_ID NUMBER(4) not null,
FIG NUMBER(20,2)
tablespace TS_IRS
pctfree 10
initrans 1
maxtrans 255
storage
initial 64K
minextents 1
maxextents unlimited
-- Create/Recreate primary, unique and foreign key constraints
alter table RN_RPT_FIG
add constraint PK_RN_RPT_FIG primary key (DT, RPT_ID, RPT_ROW_ID, RPT_COL_ID)
using index
tablespace TS_IRS
pctfree 10
initrans 2
maxtrans 255
storage
initial 128K
minextents 1
maxextents unlimited
I would like to find any duplicate values that have been entered in this table. how can i write this query Keeping in mind the constraint PK_RN_RPT_FIG ?I am actually tryin to find out which are those columns
below is the data in that table
DT RPT_ID RPT_ROW_ID RPT_COL_ID FIG
1 31-Mar-11 2000101 1 2 8157500.00
2 31-Mar-11 2000101 1 1 17.00
3 31-Mar-11 2000101 1 4 530000.00
4 31-Mar-11 2000101 1 3 5.00
5 31-Mar-11 2000101 2 2 96500.00
6 31-Mar-11 2000101 2 1 6.00
7 31-Mar-11 2000101 3 2 8301000.00
8 31-Mar-11 2000101 3 1 7.00
9 31-Mar-11 2000101 3 4 669000.00
10 31-Mar-11 2000101 3 3 6.00
11 31-Mar-11 2000101 5 2 25184500.00
12 31-Mar-11 2000101 5 1 61.00
13 31-Mar-11 2000101 5 4 22609000.00
14 31-Mar-11 2000101 5 3 19.00
15 31-Mar-11 2000101 6 2 14103500.00
16 31-Mar-11 2000101 6 1 24.00
17 31-Mar-11 2000101 7 5 9153500.00
18 31-Mar-11 2000102 1 1 6.00
19 31-Mar-11 2000102 1 2 664000.00
20 31-Mar-11 2000102 1 3 1.00
21 31-Mar-11 2000102 1 4 18500.00
22 31-Mar-11 2000102 2 1 4.00
23 31-Mar-11 2000102 2 2 4800000.00
24 31-Mar-11 2000102 2 3 1.00
25 31-Mar-11 2000102 2 4 98000.00
26 31-Mar-11 2000102 3 3 1.00
27 31-Mar-11 2000102 3 4 98000.00
28 31-Mar-11 2000102 4 1 18.00
29 31-Mar-11 2000102 4 2 16476000.00
30 31-Mar-11 2000102 4 3 10.00
31 31-Mar-11 2000102 4 4 21257000.00
32 31-Mar-11 2000102 5 1 9.00
33 31-Mar-11 2000102 5 2 6069000.00
34 31-Mar-11 2000102 5 3 6.00
35 31-Mar-11 2000102 5 4 79000.00
36 31-Mar-11 2000102 6 1 26.00
37 31-Mar-11 2000102 6 2 2938000.00
38 31-Mar-11 2000102 6 3 2.00
39 31-Mar-11 2000102 6 4 1167500.00
40 31-Mar-11 2000102 7 1 2.00
41 31-Mar-11 2000102 7 2 257000.00
42 31-Mar-11 2000103 1 1 3.00
43 31-Mar-11 2000103 1 2 169500.00
44 31-Mar-11 2000103 2 3 3.00
45 31-Mar-11 2000103 2 4 2266500.00
46 31-Mar-11 2000103 3 1 4.00
47 31-Mar-11 2000103 3 2 6400000.00
48 31-Mar-11 2000103 4 1 17.00
49 31-Mar-11 2000103 4 2 9369500.00
50 31-Mar-11 2000103 4 3 8.00
51 31-Mar-11 2000103 4 4 20149000.00
52 31-Mar-11 2000103 5 1 25.00
53 31-Mar-11 2000103 5 2 7307000.00
54 31-Mar-11 2000103 5 3 3.00
55 31-Mar-11 2000103 5 4 125500.00
56 31-Mar-11 2000103 6 1 7.00
57 31-Mar-11 2000103 6 2 194500.00
58 31-Mar-11 2000103 6 3 5.00
59 31-Mar-11 2000103 6 4 68000.00
60 31-Mar-11 2000103 7 1 2.00
61 31-Mar-11 2000103 7 2 247000.00
62 31-Mar-11 2000103 8 1 2.00
63 31-Mar-11 2000103 8 2 1375000.00
64 31-Mar-11 2000103 11 1 1.00
65 31-Mar-11 2000103 11 2 122000.00
66 31-Mar-11 2000104 3 4 432500.00
67 31-Mar-11 2000104 3 3 27.00
68 31-Mar-11 2000104 3 6 115000.00
69 31-Mar-11 2000104 3 5 8.00
70 31-Mar-11 2000104 4 4 172000.00
71 31-Mar-11 2000104 4 3 4.00
72 31-Mar-11 2000104 4 6 294000.00
73 31-Mar-11 2000104 4 5 3.00
74 31-Mar-11 2000104 5 4 7030000.00
75 31-Mar-11 2000104 5 3 23.00
76 31-Mar-11 2000104 5 6 1150000.00
77 31-Mar-11 2000104 5 5 1.00
78 31-Mar-11 2000104 6 4 17550000.00
79 31-Mar-11 2000104 6 3 7.00
80 31-Mar-11 2000104 6 6 21050000.00
81 31-Mar-11 2000104 6 5 7.00
82 31-Mar-11 2000105 5 4 664000.00
83 31-Mar-11 2000105 5 3 6.00
84 31-Mar-11 2000105 5 6 18500.00
85 31-Mar-11 2000105 5 5 1.00
86 31-Mar-11 2000105 6 4 4800000.00
87 31-Mar-11 2000105 6 3 4.00
88 31-Mar-11 2000105 7 6 98000.00
89 31-Mar-11 2000105 7 5 1.00
90 31-Mar-11 2000105 8 4 16525500.00
91 31-Mar-11 2000105 8 3 23.00
92 31-Mar-11 2000105 8 6 21325000.00
93 31-Mar-11 2000105 8 5 15.00
94 31-Mar-11 2000105 9 4 2938000.00
95 31-Mar-11 2000105 9 3 26.00
96 31-Mar-11 2000105 9 6 1167500.00
97 31-Mar-11 2000105 9 5 2.00
98 31-Mar-11 2000105 10 4 257000.00
99 31-Mar-11 2000105 10 3 2.00
100 31-Mar-11 4000100 3 3 0.00
101 31-Mar-11 4000100 3 4 18.00
102 31-Mar-11 4000100 3 5 18.00
103 31-Mar-11 4000100 4 3 0.00
104 31-Mar-11 4000100 4 4 7.00
105 31-Mar-11 4000100 4 5 7.00
106 31-Mar-11 4000100 5 3 0.00
107 31-Mar-11 4000100 5 4 10.00
108 31-Mar-11 4000100 5 5 10.00
109 31-Mar-11 4000100 6 4 8.00
110 31-Mar-11 4000100 6 5 8.00
111 31-Mar-11 4000100 7 4 27.00
112 31-Mar-11 4000100 7 5 27.00
113 31-Mar-11 4000100 8 4 41.00
114 31-Mar-11 4000100 8 5 41.00
115 31-Mar-11 4000100 9 3 0.00
116 31-Mar-11 4000100 9 4 4.00
117 31-Mar-11 4000100 9 5 4.00
118 31-Mar-11 4000100 10 3 0.00
119 31-Mar-11 4000100 10 4 2.00
120 31-Mar-11 4000100 10 5 2.00
121 31-Mar-11 4000100 11 3 0.00
122 31-Mar-11 4000100 11 4 0.00
123 31-Mar-11 4000100 11 5 0.00
124 31-Mar-11 4000100 12 3 0.00
125 31-Mar-11 4000100 12 4 4.00
126 31-Mar-11 4000100 12 5 4.00
127 31-Mar-11 4000100 13 3 0.00
128 31-Mar-11 4000100 13 4 2.00
129 31-Mar-11 4000100 13 5 2.00
130 31-Mar-11 4000100 14 3 0.00
131 31-Mar-11 4000100 14 4 0.00
132 31-Mar-11 4000100 14 5 0.00
133 31-Mar-11 4000100 15 3 0.00
134 31-Mar-11 4000100 15 4 6.00
135 31-Mar-11 4000100 15 5 6.00
136 31-Mar-11 4000100 16 5 0.00
137 31-Mar-11 4000100 17 5 0.00
138 31-Mar-11 4000100 18 5 0.00
139 31-Mar-11 4000100 19 5 212.81
140 31-Mar-11 4000100 20 5 0.00
141 31-Mar-11 4000100 21 5 39.20
142 31-Mar-11 4000100 22 5 0.00
143 31-Mar-11 4000100 23 5 0.00
144 31-Mar-11 4000100 26 5 0.00
145 31-Mar-11 4000100 27 5 92.96
146 31-Mar-11 4000100 28 5 21.07
147 31-Mar-11 4000100 29 5 0.00
148 31-Mar-11 4000100 30 5 44.24
149 31-Mar-11 4000100 31 5 10.09
150 31-Mar-11 5000100 3 3 57700.00
151 31-Mar-11 5000100 4 3 137900.00
152 31-Mar-11 5000100 5 3 41700.00
153 31-Mar-11 5000100 6 3 20900.00
154 31-Mar-11 5000100 7 3 32800.00
155 31-Mar-11 5000100 8 3 188100.00
156 31-Mar-11 5000100 9 3 372730.00
157 31-Mar-11 5000100 10 3 63100.00
158 31-Mar-11 5000100 11 3 126200.00
159 31-Mar-11 5000100 12 3 65100.00
160 31-Mar-11 5000100 13 3 157200.00
161 31-Mar-11 5000100 15 3 61100.00
162 31-Mar-11 5000100 16 3 38900.00
163 31-Mar-11 5000100 17 3 208500.00
164 31-Mar-11 5000100 18 3 1167700.00
165 31-Mar-11 5000100 19 3 67100.00
166 31-Mar-11 5000100 20 3 68100.00
167 31-Mar-11 5000100 21 3 81100.00
168 31-Mar-11 5000100 22 3 82100.00
169 31-Mar-11 5000100 24 3 90500.00
170 31-Mar-11 5000100 25 3 20800.00
171 31-Aug-11 3000107 3 4 1000.00
172 31-Aug-11 3000107 3 3 1.00
173 31-Aug-11 3000107 3 6 1000.00
174 31-Aug-11 3000107 3 5 1.00
175 31-Aug-11 3000108 8 3 4.00
176 31-Aug-11 3000108 8 4 45100.00
177 31-Aug-11 3000108 15 3 4.00
178 31-Aug-11 3000108 15 4 60000.00
179 31-Aug-11 3000108 16 3 3.00
180 31-Aug-11 3000108 16 4 71020.56
181 31-Aug-11 3000108 17 3 4.00
182 31-Aug-11 3000108 17 4 97038.72
183 31-Aug-11 3000108 18 3 4.00
184 31-Aug-11 3000108 18 4 17096.91
185 31-Aug-11 3000108 19 3 8.00
186 31-Aug-11 3000108 19 4 106569.85
187 31-Aug-11 3000108 20 3 3.00
188 31-Aug-11 3000108 20 4 30456.12
189 31-Aug-11 3000108 21 3 4.00
190 31-Aug-11 3000108 21 4 63805.83
191 31-Aug-11 3000108 22 3 4.00
192 31-Aug-11 3000108 22 4 60000.00
193 31-Aug-11 3000108 23 3 4.00
194 31-Aug-11 3000108 23 4 16208.52
195 31-Aug-11 3000108 24 3 4.00
196 31-Aug-11 3000108 24 4 57784.26
197 31-Aug-11 3000108 25 3 3.00
198 31-Aug-11 3000108 25 4 45000.00
199 31-Aug-11 3000108 26 3 4.00
200 31-Aug-11 3000108 26 4 17212.24
201 31-Aug-11 3000108 28 3 4.00
202 31-Aug-11 3000108 28 4 30567.03
203 31-Aug-11 3000108 33 3 3.00
204 31-Aug-11 3000108 33 4 30130.34
205 31-Aug-11 4000100 3 3 0.00
206 31-Aug-11 4000100 3 4 18.00
207 31-Aug-11 4000100 3 5 18.00
208 31-Aug-11 4000100 4 3 0.00
209 31-Aug-11 4000100 4 4 7.00
210 31-Aug-11 4000100 4 5 7.00
211 31-Aug-11 4000100 5 3 0.00
212 31-Aug-11 4000100 5 4 10.00
213 31-Aug-11 4000100 5 5 10.00
214 31-Aug-11 4000100 6 5 8.00
215 31-Aug-11 4000100 7 5 27.00
216 31-Aug-11 4000100 8 5 41.00
217 31-Aug-11 4000100 9 3 0.00
218 31-Aug-11 4000100 9 4 4.00
219 31-Aug-11 4000100 9 5 4.00
220 31-Aug-11 4000100 10 3 0.00
221 31-Aug-11 4000100 10 4 2.00
222 31-Aug-11 4000100 10 5 2.00
223 31-Aug-11 4000100 11 3 0.00
224 31-Aug-11 4000100 11 4 0.00
225 31-Aug-11 4000100 11 5 0.00
226 31-Aug-11 4000100 12 3 0.00
227 31-Aug-11 4000100 12 4 4.00
228 31-Aug-11 4000100 12 5 4.00
229 31-Aug-11 4000100 13 3 0.00
230 31-Aug-11 4000100 13 4 2.00
231 31-Aug-11 4000100 13 5 2.00
232 31-Aug-11 4000100 14 3 0.00
233 31-Aug-11 4000100 14 4 0.00
234 31-Aug-11 4000100 14 5 0.00
235 31-Aug-11 4000100 15 3 0.00
236 31-Aug-11 4000100 15 4 6.00
237 31-Aug-11 4000100 15 5 6.00
238 31-Aug-11 4000100 16 5 0.00
239 31-Aug-11 4000100 17 5 0.00
240 31-Aug-11 4000100 18 5 0.00
241 31-Aug-11 4000100 19 5 212.81
242 31-Aug-11 4000100 20 5 0.00
243 31-Aug-11 4000100 21 5 39.20
244 31-Aug-11 4000100 22 5 0.00
245 31-Aug-11 4000100 23 5 0.00
246 31-Aug-11 4000100 26 5 0.00
247 31-Aug-11 4000100 27 5 92.96
248 31-Aug-11 4000100 28 5 21.07
249 31-Aug-11 4000100 29 5 0.00
250 31-Aug-11 4000100 30 5 44.24
251 31-Aug-11 4000100 31 5 10.09
252 31-Aug-11 5000100 3 3 97700.00
253 31-Aug-11 5000100 4 3 100600.00
254 31-Aug-11 5000100 5 3 82700.00
255 31-Aug-11 5000100 6 3 33900.00
256 31-Aug-11 5000100 7 3 59800.00
257 31-Aug-11 5000100 8 3 196400.00
258 31-Aug-11 5000100 9 3 287600.00
259 31-Aug-11 5000100 10 3 77100.00
260 31-Aug-11 5000100 11 3 154200.00
261 31-Aug-11 5000100 12 3 79100.00
262 30-Nov-07 4000100 6 4 8.00
263 30-Nov-07 4000100 7 4 27.00
264 30-Nov-07 4000100 8 4 41.00
265 30-Nov-07 4000100 16 4 0.00
266 30-Nov-07 4000100 18 4 0.00
267 30-Nov-07 4000100 19 4 0.03
268 30-Nov-07 4000100 20 4 0.00
269 30-Nov-07 4000100 21 4 0.01
270 30-Nov-07 4000100 26 4 0.00
271 30-Nov-07 4000100 27 4 0.00
272 30-Nov-07 4000100 28 4 0.00
273 30-Nov-07 4000100 29 4 0.00
274 30-Nov-07 4000100 30 4 0.00
275 30-Nov-07 4000100 31 4 0.00
276 31-Aug-11 1000101 6 2 1000.00
277 31-Aug-11 1000101 6 1 5.00
278 31-Aug-11 1000101 6 3 50800.00
279 31-Aug-11 1000101 7 2 4000.00
280 31-Aug-11 1000101 7 1 11.00
281 31-Aug-11 1000101 7 3 129828.26
282 31-Aug-11 1000101 12 2 14000.00
283 31-Aug-11 1000101 12 1 27.00
284 31-Aug-11 1000101 12 3 244433.51
285 31-Aug-11 1000101 30 2 0.00
286 31-Aug-11 1000101 30 1 6.00
287 31-Aug-11 1000101 30 3 1415254.00
288 31-Aug-11 1000101 39 2 0.00
289 31-Aug-11 1000101 39 1 8.00
290 31-Aug-11 1000101 39 3 5300.00
291 31-Aug-11 3000103 6 6 46.00
292 31-Aug-11 3000103 6 7 585509.54
293 31-Aug-11 3000104 3 13 7.00
294 31-Aug-11 3000104 3 14 47721.81
295 31-Aug-11 3000104 4 13 6.00
296 31-Aug-11 3000104 4 14 80805.83
297 31-Aug-11 3000104 5 13 6.00
298 31-Aug-11 3000104 5 14 46569.72
299 31-Aug-11 3000104 6 13 7.00
300 31-Aug-11 3000104 6 14 112907.50
301 31-Aug-11 3000104 7 13 6.00
302 31-Aug-11 3000104 7 14 75500.00
303 31-Aug-11 3000104 8 13 13.00
304 31-Aug-11 3000104 8 14 123471.04
305 31-Aug-11 3000104 9 13 6.00
306 31-Aug-11 3000104 9 14 101401.56
307 31-Aug-11 3000104 20 13 6.00
308 31-Aug-11 3000104 20 14 60489.10
309 31-Aug-11 3000104 22 13 6.00
310 31-Aug-11 3000104 22 14 75567.03
311 31-Aug-11 3000104 23 13 6.00
312 31-Aug-11 3000104 23 14 61339.10
313 31-Aug-11 3000104 24 13 20.00
314 31-Aug-11 3000104 24 14 94688.52
315 31-Aug-11 3000104 25 13 45.00
316 31-Aug-11 3000104 25 14 5772805.47
317 31-Aug-11 3000104 26 13 6.00
318 31-Aug-11 3000104 26 14 76462.24
319 31-Aug-11 3000104 27 13 16.00
320 31-Aug-11 3000104 27 14 63742.32
321 31-Aug-11 3000104 31 13 6.00
322 31-Aug-11 3000104 31 14 60141.20
323 31-Aug-11 3000105 7 3 14.00
324 31-Aug-11 3000105 7 4 162632.63
325 31-Aug-11 3000105 7 5 11.00
326 31-Aug-11 3000105 7 6 92950.93
327 31-Aug-11 3000105 8 3 15.00
328 31-Aug-11 3000105 8 4 128938.59
329 31-Aug-11 3000105 8 5 14.00
330 31-Aug-11 3000105 8 6 1491571.98
331 31-Aug-11 3000105 9 3 14.00
332 31-Aug-11 3000105 9 4 1666338.36
333 31-Aug-11 3000105 9 5 13.00
334 31-Aug-11 3000105 9 6 1377521.70
335 31-Aug-11 5000100 13 3 91100.00
336 31-Aug-11 5000100 15 3 75100.00
337 31-Aug-11 5000100 16 3 60100.00
338 31-Aug-11 5000100 17 3 448700.00
339 31-Aug-11 5000100 18 3 1117400.00
340 31-Aug-11 5000100 19 3 81100.00
341 31-Aug-11 5000100 20 3 82100.00
342 31-Aug-11 5000100 24 3 157500.00
343 31-Aug-11 5000100 25 3 48800.00
344 31-Aug-11 7000001 19 1
345 31-Aug-11 7000001 32 1
346 31-Aug-11 7000001 40 1
347 31-Aug-11 7000001 42 1
348 31-Aug-11 7000001 43 1
349 31-Aug-11 7000001 45 1
350 31-Aug-11 7000001 48 1 0.15
351 31-Aug-11 7000001 50 1 0.15
352 31-Aug-11 7000001 51 1
353 31-Aug-11 7000001 54 1
354 31-Aug-11 7000001 55 1
355 31-Aug-11 7000001 66 1 4417.45
356 31-Aug-11 7000001 66 2
357 31-Aug-11 7000002 12 2
358 31-Aug-11 7000002 12 3
359 31-Aug-11 7000002 13 2
360 31-Aug-11 7000002 13 3
361 31-Aug-11 7000002 16 2
362 31-Aug-11 7000002 16 3
363 31-Aug-11 7000002 17 2
364 31-Aug-11 7000002 17 3
365 31-Aug-11 7000002 18 2
366 31-Aug-11 7000002 18 3
367 31-Aug-11 7000002 19 2
368 31-Aug-11 7000002 19 3
369 31-Aug-11 7000002 20 2
370 31-Aug-11 7000002 20 3
371 31-Aug-11 7000002 22 2
372 31-Aug-11 7000002 23 2
373 31-Aug-11 7000002 23 3 14900.00
374 31-Aug-11 7000002 27 2
375 31-Aug-11 7000002 27 3
376 31-Aug-11 7000002 28 2
377 31-Aug-11 7000002 29 2
378 31-Aug-11 7000002 30 2
379 31-Aug-11 7000002 30 3 59100.00
380 31-Aug-11 7000002 32 2
381 31-Aug-11 7000002 32 3 56100.00
382 31-Aug-11 7000002 34 2
383 31-Aug-11 7000002 34 3 373880.00
384 31-Aug-11 7000002 35 2
385 31-Aug-11 7000002 35 3 119363875.00
386 31-Aug-11 7000002 36 2
387 31-Aug-11 7000002 36 3 9629230.00
388 31-Aug-11 7000002 38 2
389 31-Aug-11 7000002 38 3 2287214.00
390 31-Aug-11 7000002 40 2
391 31-Aug-11 7000002 40 3 1935671.00
392 31-Aug-11 7000002 41 2
393 31-Aug-11 7000002 41 3 2515010.00
394 31-Aug-11 7000002 42 2
395 31-Aug-11 7000002 42 3 36348309.00
396 31-Aug-11 7000002 43 2
397 31-Aug-11 7000002 43 3 3212922.00 -
Dear All
I have received common error when creating relation:
The relationship cannot be created because each column contains duplicate values. Select at least one column that contains only unique values.
The issue is strange because I am sure that there are no duplicate values in my table! I checked it.
What I've done was to create a single column "Append column" by append few columns with articles from different databases using Power Query. After that I removed duplicates.
The final column with unique values was added to powerpivot model as a new table. There are no duplicates and spaces.
Then I tried to create the relation between the column with append values and other databases which I had used to create this column.
So it is look like this:
Details of error:
Error Message:
============================
The relationship cannot be created because each column contains duplicate values. Select at least one column that contains only unique values.
============================
Call Stack:
============================
at Microsoft.AnalysisServices.Common.RelationshipController.CreateRelationship(DataModelingColumn sourceColumn, DataModelingColumn relatedColumn)
at Microsoft.AnalysisServices.Common.RelationshipController.CreateRelationship(String fkTableName, String fkColumnName, String pkTableName, String pkColumnName)
at Microsoft.AnalysisServices.Common.SandboxEditor.erDiagram_CreateRelationshipCallBack(Object sender, ERDiagramCreateRelationshipEventArgs e)
at Microsoft.AnalysisServices.Common.ERDiagram.ERDiagramActionCreateRelationship.Do(IDiagramActionInstance actionInstance)
============================
What could be a reason of this issue?Thanks recio but your solutions not works
I have found the issue but not a solution.
The problem is that there is a space at the end of some articles names.
In my Database 1 I have an "a" article but
in my Database 2 I have an "a_"
where "_" is invisible space character
So PowerQuery and excel "Remove duplicate" function did not find duplicates but Powerpivot see ones
My data model looks like as on example below
So now my question is how to automaticly get rid of space character to be able to create relation?
As I see power Query does not have such an option. Maybe a look up formula in PowerPivot? But how it should look like
This is how my "Append column" Should look like: -
Referencing multiple cells and removing duplicate values.
Hello.
I have a very complicated question, to be honest I am not totally sure if numbers is capable of handling all of this but it's worth a shot.
I am working on a spreadsheet for organising a film. I've had the templates for years but I'm now using numbers to automate it as much as possible. Everything was going well until I hit the schedule/callsheet.
On other sheets I can tell it to "look up scene two" it will then look up the correct row and find everything I need. On the callsheet however I might say "we're filming scenes two, five and nine" and numbers gets confused with the multiple values, Is there anyway around this?
Also, if there is, I have a more complex question to ask. Is it possible for numbers to find and remove duplicate data? For example lets say scene two and five require Alice, but scene nine requires bob. If numbers just adds that info together it will display the result "Alice Alice Bob", is there a way to get it to parse the text, recognise the duplicate value and remove the unnecessary Alice?
I realise that numbers has limitations so it may not be able to do everything I want, however every bit I can automate saves me hours so even if I can only get half way there, totally worth it.
Thanks in advance for any help you can offer, all the best.Ah excellent thank you.
I've modified it to there are now multiple (well only four for now until I get this in better shape) indexes for finding a scene. And assigning each block to a new row.
I only have one slight reservation about this. If I create 10 rows, it totally works, most of the time we'll only shoot three scenes a day so it's just blank space... However Murphy's law will inevitable raise its ugly head and put me in a situation where we are shooting 11 scenes in a day.
For countif, I think I get what you mean... Kinda. Basicially I would create a cell which combines the character strings from each scene into one long scene. Then I would have 100 extra cells (Lets say 100 so I'll never run out) each linked to the cast list, using the character name as a variable. These cells will each parse through the string to find their character name. If it appears then a true value comes up. This will remove duplicates as each cell will only respond once. So if Alice appears in every scene shooting that day, the cell will still only light up once. Is that it.
One other question. Whenever I combine filled cells with blank cells. I usually gets the data from the filled cells, with a 0 for each blank cell. Usually this isn't a problem, but if I want to keep this flexible then I'll have quite a few blanks. The actor example above could result in 98 zeroes. Is there anyway to have blanks just not show up at all.
I'll email the spreadsheet in a moment, a lot of it is still rough and under construction, but you should be able to see where it's all going hopefully.
Thanks again, you have been extraordinarily helpful. -
Comparing values in a vector!!
I solved my previous problem, but now i've come across another, it seems my unfamiliarity with vectors aint helping, oh well practice makes perfect. Anyway I've written a method which will iterate through a list of numbers using a vector and delete any duplicate items from the vector. Here's the code
public int deleteMultiple() {
int i = 0;
while(i<current_size) {
int j;
int k = 0;
int l = k + 1;
m = 0;
for(j = 0; j<current_size; j++) {
if(data.elementAt(k) == data.elementAt(l)) {
data.removeElementAt(l);
m++;
else {
l++;
k++;
i++;
return m;
}Sorry about the alignment, it's hard to get right in this thing. I think the problem lies in the if statement I don't think it ever gets into that particular block. Say I had a list comprising of the following numbers
1 2 3 1
Then what the list should look like after deletion is
1 2 3
Any input would be greatly appreciated!!!!Ok I'm going to post all of the code cos I know I'm really close to solving this problem now.
This code is ListDemo2.java, and this is basically the main progrm thats sets up all the applet stuff and displays the lists. What it can do is insert an item onto the end of the list, make an ordered list from zero up to an input in the text field(integer), make a random list, clear the list, delete duplicates ( this is what i'm having trouble with ) and exit the applet.
import java.awt.*;
import java.awt.event.*; /* new in 1.1 for EventListener */
import java.applet.Applet;
import java.util.*;
public class ListDemo2 extends Applet implements ActionListener,
AdjustmentListener
private ListByVector list = new ListByVector(0);
// setup a limit for displaying the list
final int numRow = 5;
final int numCol = 10;
final int maxDisplay = numRow * numCol;
private int scrollbarPos = 0;
private TextField userInput;
private Label messageLabel;
private Label scrollbarLabel;
private Label[] itemLabels;
private Scrollbar listScroll;
private Button insertButton;
private Button mk_olistButton;
private Button mk_rlistButton;
private Button clearButton;
private Button deleteButton;
private Button exitButton;
// ... adding more buttons here
public void init() {
// 1. define stuff on the first panel - control panel
Panel controlPanel1 = new Panel();
userInput = new TextField("", 5);
insertButton = new Button("insert");
mk_olistButton = new Button("mk_olist");
mk_rlistButton = new Button("mk_rlist");
clearButton = new Button("clear");
deleteButton = new Button("delete");
exitButton = new Button("quit");
controlPanel1.setLayout(new FlowLayout(FlowLayout.LEFT));
controlPanel1.add(userInput);
controlPanel1.add(insertButton);
controlPanel1.add(mk_olistButton);
controlPanel1.add(mk_rlistButton);
controlPanel1.add(clearButton);
controlPanel1.add(deleteButton);
controlPanel1.add(exitButton);
// ... adding new buttons
// for event handling we need these lines
insertButton.addActionListener(this);
mk_olistButton.addActionListener(this);
mk_rlistButton.addActionListener(this);
clearButton.addActionListener(this);
deleteButton.addActionListener(this);
exitButton.addActionListener(this);
// ... any newly added buttons need the above line
// 2. define stuff on the second panel - message panel
Panel controlPanel2 = new Panel();
messageLabel = new Label("Initially, the list is empty");
scrollbarLabel = new Label(" ");
controlPanel2.setLayout(new GridLayout(2,1));
controlPanel2.add(messageLabel);
controlPanel2.add(scrollbarLabel);
// 3. define stuff on the third panel - list display panel
Panel listPanel = new Panel();
Panel listDisplay = new Panel();
itemLabels = new Label[maxDisplay];
listDisplay.setLayout(new GridLayout(numRow,numCol));
int tmp=0;
for(tmp=0; tmp < maxDisplay; tmp++) {
itemLabels[tmp] = new Label(" ");
listDisplay.add(itemLabels[tmp]);
listScroll =
new Scrollbar(Scrollbar.VERTICAL,0,0,0,
list.sizeLimit()/numCol + 1);
listScroll.addAdjustmentListener(this); /* new in 1.1 */
listPanel.setLayout(new BorderLayout());
listPanel.add( "West", listDisplay);
listPanel.add( "East", listScroll);
// finally, add the above 3 to the applet
setLayout(new BorderLayout());
add("North", controlPanel1);
add("Center", controlPanel2);
add("South", listPanel);
} // end of ListDemo's constructor
public void actionPerformed(ActionEvent event) {
String input_buffer;
int k;
// read a string from the text field
input_buffer = new String(userInput.getText());
if(event.getSource() == clearButton) {
list.clearUp();
showList(list);
showMessage("list cleared");
else if(event.getSource() == insertButton) {
k = list.insertAtEnd(input_buffer);
if(k>=0) { // inserted OK
showList(list);
showMessage(
"inserted " + input_buffer + " at " + k);
else { // reached the limit, nothing inserted
showMessage("sorry, you cannot insert any more");
else if(event.getSource() == mk_olistButton) {
k = list.createOrderedList(input_buffer);
if(k>0) {
showList(list);
showMessage("an ordered list is created, the list size is "+k);
else showMessage("please input the size of your list");
else if(event.getSource() == mk_rlistButton) {
k = list.createRandomList(input_buffer);
if(k>0) {
showList(list);
showMessage("a random list is created, the list size is "+k);
else showMessage("please input the size of your list");
/*Quick note about the code below, if I keep it as is
with the showList(list) commented out it will not visibly
delete the duplicates but the message that comes up
saying how many duplicates were deleted gives the
correct answer for the first time only, if I were to create
another random list with a different set of duplicates then
the message will be incorrect. Also if the showList(list)
were to be uncommented then the program suffers from
overflow problems??????*/
else if(event.getSource() == deleteButton) {
k = list.deleteMultiple();
// showList(list);
showMessage("deleted " +k + " duplicate items");
else if(event.getSource() == exitButton) {
System.exit(0);
public void adjustmentValueChanged(AdjustmentEvent event) {
if(event.getSource() == listScroll) {
scrollbarPos = listScroll.getValue();
showScrollbarMessage(
"the scrollbar position is " + scrollbarPos);
showList(list);
void showList(ListByVector list)
int i = scrollbarPos;
int n = list.size();
int c = 0;
i = i * numCol;
while((i < n) && (c < maxDisplay)) {
itemLabels[c].setVisible(true);
itemLabels[c].setText(list.item(i));
i++; c++;
while(c < maxDisplay) {
itemLabels[c].setVisible(true);
itemLabels[c].setText("");
c++;
// clear input text field
userInput.setText("");
void showMessage(String Message) {
messageLabel.setVisible(true); /* this line was not needed
in java1.0 */
messageLabel.setText(Message);
void showScrollbarMessage(String Message) {
scrollbarLabel.setVisible(true); /* this line was not needed
in java1.0 */
scrollbarLabel.setText(Message);
public static void main(String args[])
Frame f = new Frame("List Demo");
ListDemo2 appletListDemo = new ListDemo2();
f.setFont(new Font("Helvetica", Font.BOLD, 12));
f.setSize(700, 300);
f.setBackground(Color.green);
f.add(appletListDemo);
appletListDemo.init();
f.setVisible(true);
}This code is called ListByVector.java and is used to generate the lists and then return the info back to ListDemo2.
import java.util.*;
public class ListByVector {
private final int default_max_size = 4096;
private int current_size;
private int m;
private Vector data;
ListByVector(int initial_size) {
data = new Vector();
current_size = initial_size;
public int sizeLimit(){ return default_max_size; }
public int size(){ return current_size; }
public String item(int which){ return (String)data.elementAt(which); }
public void clearUp() {
current_size = 0;
public int insertAtEnd(String input_item) {
if(current_size < default_max_size) {
data.insertElementAt(input_item, current_size);
current_size++;
return(current_size - 1);
else {
return -1;
public int createRandomList(String string_size) {
int i;
int j;
if(!isIntString(string_size)) {
return 0;
else {
Integer size = Integer.valueOf(string_size);
current_size = size.intValue();
Random R = new Random();
for(i = 0; i<current_size; i++) {
j = (int)(R.nextFloat()*current_size);
data.insertElementAt(Integer.toString(j), i);
return current_size;
public int createOrderedList(String size_string) {
int i;
if(!isIntString(size_string)) {
return 0;
else {
Integer size = Integer.valueOf(size_string);
current_size = size.intValue();
for(i = 0; i<current_size; i++) {
data.insertElementAt(Integer.toString(i), i);
return current_size;
/* As you can see for the delete method I have tried
several variations all giving the same problem, the one
which isn't commented out is the one which kind of
works i.e. when the delete button is pressed the correct
value appears for the number of duplicates that should
have been deleted but nothing visibly happens*/
public int deleteMultiple() {
/* int i = 0;
while(i<data.size()) {
int j;
int k = 0;
int l = k + 1;
m = 0;
for(j = 0; j<data.size()-1; j++) {
if(data.elementAt(k) == data.elementAt(l)) {
data.removeElementAt(l);
}//end if
else {
m++;
l++;
}//end else
}//end for
k++;
i++;
}//end while */
m = 0;
for(int i=0; i<data.size(); i++) {
for(int j=data.size()-1; j>i; j--) {
if(data.elementAt(i).equals(data.elementAt(j))) {
data.removeElementAt(j);
m++;
/* int currIndex = 0;
while(currIndex<data.size()) {
int currIndex2;
for(currIndex2 = currIndex + 1; currIndex2<data.size(); currIndex2++) {
if(data.elementAt(currIndex2).equals(data.elementAt(currIndex))) {
data.removeElementAt(currIndex2);
currIndex2++;
currIndex++;
return m;
private boolean lessThan(String s1, String s2) {
if(isIntString(s1) && isIntString(s2))
return(Integer.parseInt(s1) < Integer.parseInt(s2));
else
return(s1.compareTo(s2) < 0);
private boolean isIntString(String s) {
int n = s.length();
int i;
if(n==0) return false;
if(s.charAt(0) == '-') i = 1;
else i = 0;
if(i == n) return false;
for(; i<n; i++) {
if(s.charAt(i) < '0') return false;
if(s.charAt(i) > '9') return false;
return true;
} -
Error 5398 Duplicate value addition in attribute ...
I'm seeing the following error messages in my error log and am not sure what to do about it since the reference guide does not list it. Solaris 8, DS 5.2.
ERROR<5398> - Entry - conn=-1 op=-1 msgId=-1 - Duplicate value addition in attribute "objectClass" of entry "ou=Configs, o=Contivity, o=vpn"
ERROR<5398> - Entry - conn=-1 op=-1 msgId=-1 - Duplicate value addition in attribute "objectClass" of entry "cn=14649, ou=Configs, o=Contivity, o=vpn"
Here are some historical events that may help shed light on things:
The errors are occuring on Searay. I have another LDAP server called Mantaray. Here is some historical data that ay help shed light on the matter:
I wanted the DNS domain the LDAP was using changed on Searay so I configured searay:o=vpn for Master replication and created o=vpn on Mantaray and configured it as a consumer.
After the suffix was replicated I broke the replication and unconfigured Searay and then configured it. I then did the reverse and made Mantaray:o=vpn the master and Searay:o=vpn the consumer. I then broke the replication again and tried to get Multi-Master replication to work between the two servers. It took a few tries before things seemed to start working right.This thread (http://swforum.sun.com/jive/thread.jspa?forumID=13&threadID=21473) seems similar but I cannot find where the nsslapd-rererral that kunal mehta mentions is located.
I did look at the des.ldif for each server and both looked okay. -
I need to find duplicates (ID) but the sum of column VALUES has tu be zero. can anyone help me please ?
I HAVE TABLE
ID VALUE
100 -100
100 100
100 100
200 50
--------------- THE DESIRED RESULT IS
ID VALUE
100 -100
100 100
------------Sorry,
I only read you leading question:
I need to find duplicates (ID) but the sum of column VALUES has tu be zero(The obvious answer would be there isn't any)
Only now do I see your expected output.
You need to explain which row to eliminate and why, in order to go from
ID VALUE
100 -100
100 100
100 100To just:
ID VALUE
100 -100
100 100Also, what should happen if you have, say
ID VALUE
200 -50
200 -50
200 100Regards
Peter -
Help with Finding Duplicate records Query
HI,
I am trying to write a query that will find duplicate records/cases.
This query will be used in a report.
So, here are the requirements:
I need to find duplicate cases/records based on the following fields:
DOB, DOCKET, SENT_DATEI was able to do that with the following query. The query below is able to give me all duplicate records based on the Criteria above
SELECT DEF.BIRTH_DATE DOB,
S.DOCKET DOCKET,
S.SENT_VIO_DATE SENT_DATE, COUNT(*)
FROM SENTENCES S,
DEFENDANTS DEF
WHERE S.DEF_ID = DEF.DEF_ID
AND S.CASE_TYPE_CODE = 10
GROUP BY DEF.BIRTH_DATE, S.DOCKET, S.SENT_VIO_DATE
HAVING COUNT(*) > 1;
//I AM GOING TO CALL THIS QUERY 'X'Now, the information to be displayed on the report: defendants Name, DOB, District, Docket, Def Num, Sent Date, and PACTS Num if possible.
The problem that I need help on is how to combine those queries together (what I mean is a sub query). the 'X' query returns multiple values. please have a look at the comments on the query below to see what I'm trying to achieve.
here is the main query:
SELECT INITCAP(DEF.LAST_NAME) || ' ' || INITCAP(DEF.FIRST_NAME) || ' ' || INITCAP(DEF.MIDDLE_NAME) DEFENDANT_NAME,
DEF.BIRTH_DATE DOB,
TRIM(DIST.DISTRICT_NAME) DISTRICT_NAME,
S.DOCKET DOCKET,
S.DEF_NUM DEF_NUM,
S.SENT_VIO_DATE SENT_DATE,
DEF.PACTS_ID PACTS_NUM
FROM USSC_CASES.DEFENDANTS DEF,
USSC_CASES.SENTENCES S,
LOOKUP.DISTRICTS DIST
WHERE DEF.DEF_ID = S.DEF_ID
AND S.DIST_ID = DIST.USSC_DISTRICT_ID
AND S.CASE_TYPE_CODE = 10
AND S.USSC_ID IS NOT NULL
AND // what i'm trying to do is: DOB, DOCKET, SENT_DATE IN ('X' QUERY), is this possible ??
ORDER BY DEFENDANT_NAME; thanks in advance.
I am using Oracle 11g, and sql developer.
if my approach doesn't work, is there a better approach ?
Edited by: Rooney on Jul 11, 2012 3:50 PMIf I got it right, you want to join table USSC_CASES.DEFENDANTS to duplicate rows in USSC_CASES. If so:
SELECT INITCAP(DEF.LAST_NAME) || ' ' || INITCAP(DEF.FIRST_NAME) || ' ' || INITCAP(DEF.MIDDLE_NAME) DEFENDANT_NAME,
DEF.BIRTH_DATE DOB,
TRIM(DIST.DISTRICT_NAME) DISTRICT_NAME,
S.DOCKET DOCKET,
S.DEF_NUM DEF_NUM,
S.SENT_VIO_DATE SENT_DATE,
DEF.PACTS_ID PACTS_NUM
FROM USSC_CASES.DEFENDANTS DEF,
SELECT *
FROM (
SELECT S.*,
COUNT(*) OVER(PARTITION BY DEF.BIRTH_DATE, S.DOCKET, S.SENT_VIO_DATE) CNT
FROM USSC_CASES.SENTENCES S
WHERE CNT > 1
) S,
LOOKUP.DISTRICTS DIST
WHERE DEF.DEF_ID = S.DEF_ID
AND S.DIST_ID = DIST.USSC_DISTRICT_ID
AND S.CASE_TYPE_CODE = 10
AND S.USSC_ID IS NOT NULL
ORDER BY DEFENDANT_NAME;If you want to exclude duplicates from the query and do not care which row out of duplicate rows to choose:
SELECT INITCAP(DEF.LAST_NAME) || ' ' || INITCAP(DEF.FIRST_NAME) || ' ' || INITCAP(DEF.MIDDLE_NAME) DEFENDANT_NAME,
DEF.BIRTH_DATE DOB,
TRIM(DIST.DISTRICT_NAME) DISTRICT_NAME,
S.DOCKET DOCKET,
S.DEF_NUM DEF_NUM,
S.SENT_VIO_DATE SENT_DATE,
DEF.PACTS_ID PACTS_NUM
FROM USSC_CASES.DEFENDANTS DEF,
SELECT *
FROM (
SELECT S.*,
ROW_NUMBER() OVER(PARTITION BY DEF.BIRTH_DATE, S.DOCKET, S.SENT_VIO_DATE ORDER BY 1) RN
FROM USSC_CASES.SENTENCES S
WHERE RN = 1
) S,
LOOKUP.DISTRICTS DIST
WHERE DEF.DEF_ID = S.DEF_ID
AND S.DIST_ID = DIST.USSC_DISTRICT_ID
AND S.CASE_TYPE_CODE = 10
AND S.USSC_ID IS NOT NULL
ORDER BY DEFENDANT_NAME;SY. -
Hi,
I have to find duplicate rows from a view where 2 columns of the view should be duplicate but the 3 col value should not be same.
Pls help it's urgent.
Thanks
Regards
PrashantTry this
with t
as
select 1 rno, 'AAA' c1, 1 c2, 'NAME1' c3 from dual union all
select 2, 'AAA', 1, 'NAME1' from dual union all
select 3, 'AAA', 1, 'NAME3' from dual union all
select 4, 'BBB', 2, 'NAME4' from dual union all
select 5, 'BBB', 2, 'NAME4' from dual union all
select 6, 'BBB', 2, 'NAME5' from dual
select rno, c1, c2, c3
from (
select t.*, row_number() over(partition by c1, c2, c3 order by rno) rno1
from t
where rno1 = 1
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