Find Employee Worked 7 Consecutive days

Hello All,
I have a view with following columns
(EMP #, Dept #, Total hours worked, Date of the total hours, Current Pay period st date, Current Pay period end date, Previous pay period start date, Previous pay period start date, Next pay period st date, next pay period end date)
I need a query to find employees who worked consecutively for 7 Days
within a date range.
Please let me know...
Thanks,
Kottee
kotteeswaran

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '11/1/2010'
SET @EndDate ='11/10/2010'
SELECT       VP_ALLTOTALS.PERSONNUM,
       MIN(VP_ALLTOTALS.APPLYDATE) AS StartDate,
       MAX(VP_ALLTOTALS.APPLYDATE) AS Enddate
FROM       (
           SELECT   V.PERSONNUM,
               V.APPLYDATE,
               DATEDIFF(DAY, '17530101', VP_ALLTOTALS.APPLYDATE) - ROW_NUMBER() OVER (PARTITION BY VP_ALLTOTALS.PERSONNUM ORDER BY VP_ALLTOTALS.APPLYDATE) AS GroupID
           FROM   VP_ALLTOTALS V
           WHERE   VP_ALLTOTALS.APPLYDATE BETWEEN @StartDate AND @EndDate
       ) AS t
GROUP BY   VP_ALLTOTALS.PERSONNUM,
       GroupID
HAVING       COUNT(*) >= 7
I'm getting following errors
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
And Many Thanks for PESO and RAMIREDDY...
Thanks,
kotteesh
kotteeswaran

Similar Messages

Query help - Fetch employees working on two consecutive weekends(SAT/SUN)

Hello Gurus,
I have the following requirement and i need your help on this.
We have a table with all employees effort logged in for the days they have worked. a sample data is given below
TD_date     Emp_id     Effort     Archive_month
2-Mar-13     123     8     Mar-13
9-Mar-13     123     8     Mar-13
2-Mar-13     213     4     Mar-13
3-Mar-13     213     4     Mar-13
24-Mar-13     213     8     Mar-13
9-Mar-13     312     4     Mar-13
10-Mar-13     312     4     Mar-13
16-Mar-13     312     8     Mar-13
In the above sample data, we have employee 123 who worked on consecutive SATURDAY and 312 who worked on consecutive weekends (9th, 10th and 16th March) but the employee 213 worked on 1st weekend and 4th weekend of the month(Archive_month). So the output should return the employees who worked on two consecutive weekends as below.
Emp_id
123
312
I have written a query to fetch all employees who worked only on a SAT or SUN which is given below, but i am not able to return the employees who worked on consecutive weekends and i need your help.
select emp_id, count(*)
from timesheet_archive
where archive_month = '03/2013'
and trim(to_char(td_date,'DAY')) in ('SATURDAY','SUNDAY')
group by emp_id having count(*) > 1
order by td_date desc
Please help me with an approach in SQL or PL/SQL to generate a report of employees who worked on two consecutive weekends.
Thanks,
Edited by: 999145 on Apr 9, 2013 11:08 PM
Edited by: 999145 on Apr 9, 2013 11:10 PM

hi Manik,
thanks for your response!!
Please find the below create and insert scripts for your testing.
I am also validating the output with my requirement. Thanks for your help!
create table timesheet_archive as
(TD_date date,
Emp_id number(19,0),
Effort Float,
Archive_month varchar2);
insert into timesheet_archive values (to_date('2-MAR-2013','dd-MON-yyyy'), 123,8,'03/2013');
insert into timesheet_archive values (to_date('9-MAR-2013','dd-MON-yyyy'), 123,8,'03/2013');
insert into timesheet_archive values (to_date('2-MAR-2013','dd-MON-yyyy'), 213,4,'03/2013');
insert into timesheet_archive values (to_date('3-MAR-2013','dd-MON-yyyy'), 213,4,'03/2013');
insert into timesheet_archive values (to_date('24-MAR-2013','dd-MON-yyyy'), 213,8,'03/2013');
insert into timesheet_archive values (to_date('9-MAR-2013','dd-MON-yyyy'), 321,4,'03/2013');
insert into timesheet_archive values (to_date('10-MAR-2013','dd-MON-yyyy'), 321,4,'03/2013');
insert into timesheet_archive values (to_date('16-MAR-2013','dd-MON-yyyy'), 321,8,'03/2013');
insert into timesheet_archive values (to_date('2-MAR-2013','dd-MON-yyyy'), 124,8,'03/2013');
insert into timesheet_archive values (to_date('9-MAR-2013','dd-MON-yyyy'), 124,8,'03/2013');
insert into timesheet_archive values (to_date('16-MAR-2013','dd-MON-yyyy'), 124,4,'03/2013');
insert into timesheet_archive values (to_date('23-MAR-2013','dd-MON-yyyy'), 124,4,'03/2013');
insert into timesheet_archive values (to_date('16-MAR-2013','dd-MON-yyyy'), 241,8,'03/2013');
insert into timesheet_archive values (to_date('23-MAR-2013','dd-MON-yyyy'), 241,4,'03/2013');
insert into timesheet_archive values (to_date('24-MAR-2013','dd-MON-yyyy'), 241,4,'03/2013');
insert into timesheet_archive values (to_date('2-MAR-2013','dd-MON-yyyy'), 412,8,'03/2013');
insert into timesheet_archive values (to_date('3-MAR-2013','dd-MON-yyyy'), 412,8,'03/2013');
insert into timesheet_archive values (to_date('30-MAR-2013','dd-MON-yyyy'), 412,8,'03/2013');
insert into timesheet_archive values (to_date('31-MAR-2013','dd-MON-yyyy'), 412,8,'03/2013');

How to find consecutive days?

Hi I have a requirement, where I need to find all employees who have taken 5 consecutive days off in one week.
I am trying to build a query in BI, which can identify these records, but of no avail. I am wondering if I can do this in visual Composer. My data output currently looks like this in a table.
Employee number     calendar day    time-off hours
100                           6/8/2009         8
100                           6/9/2009         8
100                           6/10/2009       8
100                           6/11/2009       8
100                           6/12/2009       8
101                           6/1/2009         8
101                           6/5/2009         8
I like to loop through this table, somehow, and identify that employee 100, has 5 consecutive days off, but not 101.
I like to filter those employees who do not have 5 consecutive days off, and just show those who have 5 days off, like employee number 100. My output should look like, this
Employee number     calendar day    time-off hours
100                           6/8/2009         8
100                           6/9/2009         8
100                           6/10/2009       8
100                           6/11/2009       8
100                           6/12/2009       8
Any ideas will be greatly appreciated. I am trying out dynamic expression, but cannot find a way to access the first row of data, while processing the second row.

Hi
Why dont you try with time characteristics '0CALWEEK'. Add '0CALWEEK' to your infocube & map it with the date which you already have in the table. Now consider the your example for employee '100' -
100 6/8/2009 8
100 6/9/2009 8
100 6/10/2009 8
100 6/11/2009 8
100 6/12/2009 8
by adding Calweek you will get - 100   24.2009 (that is 24 th week) 40 hrs.
Now in your query divide this 40 hrs (that is total working hours in week) with daily min working hrs. (In your case assume it 8 Hrs per day). So in query you will get number of working days in a week for each employee. From this you can easily find out how many leaves each employee has taken.
I think this is what you are looking for.
Regards
Sandeep

To find the number of years an employee working in an organization

hi,
we need to find how many years an employee working in a particular organization. i.e using the hire date and sysdate we need to find how many years an employee works there. how to execute this.

Hi,
The MONTHS_BETWEEN function returns the number of months between two dates. There's no YEARS_BETWEEN function, but it's very easy to take the value returned by MONTHS_BETWEEN and divide it by the number of months in a year, like this:
SELECT     ename
,     hiredate
,     MONTHS_BETWEEN ( SYSDATE
                 , hiredate
                 ) / 12     AS years_worked
FROM    scott.emp
;Output (when I ran it on June 2, 2013):
ENAME      HIREDATE    YEARS_WORKED
SMITH      17-12-1980         32.46
ALLEN      20-02-1981         32.29
WARD       22-02-1981         32.28
JONES      02-04-1981         32.17
MARTIN     28-09-1981         31.68
BLAKE      01-05-1981         32.09
CLARK      09-06-1981         31.98
SCOTT      19-04-1987         26.12
KING       17-11-1981         31.54
TURNER     08-09-1981         31.74
ADAMS      23-05-1987         26.03
JAMES      03-12-1981         31.50
FORD       03-12-1981         31.50
MILLER     23-01-1982         31.36
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all the tables involved, and the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say what version of Oracle you're using (e.g. 11.2.0.2.0).
See the forum FAQ {message:id=9360002}

Count Employee Working Days

Hello all
i have a attandance table
create table attn(
EMPNO NUMBER,
ADATE DATE,
ATIME DATE,
ETYPE VARCHAR2(2)); ( IN/OUT )
i want to count a employee working days....i have save all employee in/out attndance table......any body help me

hello all
thanks for replay
but my problem is this........
emp # date time type
4 01-JAN-04 12:15 OUT
4 01-JAN-04 09:50 IN
112 01-JAN-04 10:15 IN
4 01-JAN-04 17:15 OUT
4 01-JAN-04 01:50 IN
112 01-JAN-04 18:57 OUT
10 01-JAN-04 10:50 IN
10 01-JAN-04 19:15 OUT
my problem is one employee in/out more then 1 time a day..same situation end of month.when i have calculate working day end of month....if employee in/out more time a day query only calculate 1........

Have timesheet data. Trying to get staff at risk of burn out (worked 8hrs a day during last 3 weeks)

Hi all,
I've been trying to get a semi-complex measure out for over a day now but seem to be going round in circles. Most frustrating is I don't quite understand why one version throws an error, another throws out the wrong number and then whatever you guys come
up with will give me the correct answer!
I have a workbook uploaded here which I used for a different question, but majority of the data model is the same :
https://onedrive.live.com/?cid=1C0322C61F94C9E9&id=1C0322C61F94C9E9%21125
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TaskID (fk to task table)
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EffortInHrs
my date dim is standard fare, only thing i've added is an EndOfWeekDate (eg EOWDate. sunday is the last day therefore for each date for this week the endofweekdate column = 18-jan. For last week it was 11-Jan etc) and I also have a 'last freshed date' that
shows the last time the model was refreshed
A staff member can only record time against a specific task once per day, but they can have multiple tasks across multiple clients for one day
The business rule im working with is
if they've worked more than 8hrs at least once in the last 3 weeks (dates that fall between EOWdate for 'now' minus 3 weeks and EOWdate for 'now' ), then return the sum of EffortInHrs for all clients for every day in the last 3 weeks
I've given up in getting it in one go so i'm trying to cobble together a number of calc columns and measures to get me closer.. but it all seems to stall
eg the following calc column (DailySumOfHrs)
=
CALCULATE (
SUM ( [EffortInHours] ),
FILTER (
ALLEXCEPT ( TIME, 'Time'[TimesheetDate], TIME[StaffID] ),
DATESBETWEEN (
'Date'[Date],
'time'[TimesheetDate],
'Time'[TimesheetDate]
gives me the sum of effort in hrs for the day for each staff member. I couldn't get a measure version of this working. It would either aggregate across all days/staff or give context errors.
So when I tried to take it to the next step to find the max using the same formula
=
CALCULATE (
SUM ( [EffortInHours] ),
FILTER (
ALLEXCEPT ( TIME, 'Time'[TimesheetDate], TIME[StaffID] ),
DATESBETWEEN (
'Date'[Date],
'time'[TimesheetDate],
'Time'[TimesheetDate]
I get errors, i'm guessing because i'm mixing my fact and date tables now and it doesn't know it can use the TimeSheetDate 'context' to filter.
To get the 'last 3 weeks' filter working I added the following to the date dim
=if([EndOfWeek]<[RefreshDateLocal] +7 && [EndOfWeek] > [RefreshDateLocal] -14,1,0)
i then used it in an intermediate measure to get the max at the weekly grain
WeeklyMax :=
IF (
MAX ( 'Date'[Last3WeeksFilter] ) = 1,
CALCULATE (
MAX ( TIME[DailySumOfHrs] ),
FILTER (
ALL ( 'Date'[date] ),
MAX ( 'Date'[EndOfWeek] ) = MAX ( 'Date'[EndOfWeek] )
'Date'[Last3WeeksFilter] = 1
BLANK ()
and finally the measure itself
BurntOutHrs:=if([WeeklyMax]>8,SUM([EffortInHours]),blank())
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answer.
As is, it only works for a simple Staff, date, burntouthrs report. If users attempt to create their own pivot table/chart and try to break it down by client or task it doesn't look right at all. I'd also like to be able to count how much stuff are working
long hrs but this approach wouldn't support that at all.
I could probably post dozens of my attempted dax that to me logically look like it should work but either aggregate wrong or throw context errors. Unfortunately my current approach to dax still is to try various, almost random variations until one works
for whatever reason
I always aim to have a measure that 'just works' in all contexts where it makes logical sense. For me to get that happening here i'd probably need to spend another few hrs trying all kinds of allexcept() conditions for each filter where i want it to work
and hope none contradict each other
Thinking about it now, this isn't really a separate measure at all.. i think a better approach would be to add a calc column to the staff table that checks if that staff member has >8hrs assigned for any day (i dont think the default time->staff relationship
would allow this though). But i'm still interested on how to accomplish it using the separate 'measure' approach
I'll go spend the rest of today trying to get the flag working in the staff dim!
Thanks!
Jakub @ Adelaide, Australia Blog

Jakubk, is this still an issue?
Thanks!
Ed Price, Azure & Power BI Customer Program Manager (Blog,
Small Basic,
Wiki Ninjas,
Wiki)
Answer an interesting question?
Create a wiki article about it!

Find the same day in a range then find the difference between the days

Need assistnace with the following .
I have a table of ids for courses and each course class is on a day. I have to take the first day the course class is on and find the next same day then work out the difference in days.
eg. a course class is on a saturday then have to go thru the course class associated to a course and find the next saturday then work out the difference.
Anyone able to help - it would be much appreciated

course class id date day
abcdefa 18/12/2002 wednesday
abcdefb 19/12/2002 thursday
abcdefc 20/12/2002 friday
zxvyza 17/12/2002 monday
zxvyzb 20/12/2002 thursday
zxvyzc 21/12/2002 friday
zxvyzd 24/12/2002 monday
zxvyze 26/12/2002 wednesday
lmnopa 11/11/2002 tuesday
lmnopb 12/11/2002 wednesday
lmnopc 14/11/2002 friday
lmnopd 19/11/2002 wednesday
lmnope 21/11/2002 friday
where abcdefa, abcdefbc, abcdefc are for course id abcdef
and the other set of course class ids are for course id zxvyz.
and 3rd set relates to course id lmnop.
expectation:
the difference between days for the first set of data to be 0
the difference between days for 2nd set to be 7 days (ie. take the first day for the course class and see if can find another that is the same and then work out the difference i.e monday) then return the difference then go to next course class id.
the diff between 3rd set is calc the diff between Wednesdays, ignore the last friday and find the next course class id. the answer here will be 7 days.
I have worked out the days from the dates (although the above is only an example)but wasnt sure how to pick the same days then work out the difference and then move to the next course class id. Some course classes wont have another same day.

Finder not working well-show folders empty

Hi,
for some times now I have problems with finder.
First I thought it was a problem accessing the network but I also have the problem with the local folders!!
After logging to my account, it works well for some times and then suddenly (may be after accessing machine on my network - Synology NAS) finder begin to show all folders as they are empty!!!
The funny thing is that if for instance I do a "file/open" within an app or do an attachment and so access a "windows like finder" it works!!
But if I use the finder ... folders are empty (shown as ...).
The only thing to get everything back is to restart the computer (and many times I have to hard stop the machine as the finder is not working anymore and my mac mini don't want to restart. I keep the desktop background and nothing happened!!
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The mac mini was a clean install!
So many problem with Yosemite!!!
Ragards

1. This procedure is a diagnostic test. It changes nothing, for better or worse, and therefore will not, in itself, solve the problem. But with the aid of the test results, the solution may take a few minutes, instead of hours or days.
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com.microsoft.office.licensing.helper com.oracle.java.Helper-Tool com.oracle.java.JavaUpdateHelper com.oracle.java.JavaUpdateHelper org.macosforge.xquartz.privileged_startx org.macosforge.xquartz.privileged_startx org.macosforge.xquartz.startx ' ' 879294308 4071182229 461455494 3627668074 1083382502 1274181950 1855907737 2758863019 1848501757 464843899 3694147963 1233118628 2456546649 2806998573 2778718105 2636415542 842973933 2051385900 3301885676 891055588 998894468 695903914 1443423563 4136085286 523110921 2883943871 3873345487 ' 51 5120 files );N5=${#p[@]};p[N5]=` networksetup -listnetworkserviceorder|awk ' NR>1 { sub(/^$[0-9]+$ /,"");n=$0;getline;} $NF=="'${p[26]}')" { sub(/.$/,"",$NF);print n;exit;} ' `;f=('\n%s: %s\n' '\n%s\n\n%s\n' '\nRAM details\n%s\n' %s\ %s '%s\n-\t%s\n' );S0() { echo ' { q=$NF+0;$NF="";u=$(NF-1);$(NF-1)="";gsub(/^ +| +$/,"");if(q>='${p[$1]}') printf("%s (UID %s) is using %s '${p[$2]}'",$0,u,q);} ';};s=(' s/[0-9A-Za-z._]+@[0-9A-Za-z.]+\.[0-9A-Za-z]{2,4}/EMAIL/g;/faceb/s/(at\.)[^.]+/\1NAME/g;/\/Shared/!s/(\/Users\/)[^ /]+/\1USER/g;s/[-0-9A-Fa-f]{22,}/UUID/g;' ' s/^ +//;/de: S|[nst]:/p;' ' {sub(/^ +/,"")};/er:/;/y:/&&$2<'${p[10]} ' 1s/://;3,6d;/[my].+:/d;s/^ {4}//;H;${ g;s/\n$//;/s: (E[^m]|[^EO])|x([^08]|02[^F]|8[^0])/p;} ' ' 5h;6{ H;g;/P/!p;} ' ' ($1~/^Cy/&&$3>'${p[11]}')||($1~/^Cond/&&$2!~/^N/) ' ' /:$/{ N;/:.+:/d;s/ *://;b0'$'\n'' };/^ *(V.+ [0N]|Man).+ /{ s/ 0x.... //;s/[()]//g;s/(.+: )(.+)/ (\2)/;H;};$b0'$'\n'' d;:0'$'\n'' x;s/\n\n//;/Apple[ ,]|Genesy|Intel|SMSC/d;s/\n.*//;/\)$/p;' ' s/^.*C/C/;H;${ g;/No th|pms/!p;} ' '/= [^GO]/p' '{$1=""};1' ' /Of/!{ s/^.+is |\.//g;p;} ' ' $0&&!/ / { n++;print;} END { if(n<10) print "com.apple.";} ' ' { sub(/ :/,"");print|"tail -n'${p[12]}'";} ' ' NR==2&&$4<='${p[13]}' { print $4;} ' ' END { $2/=256;if($2>='${p[15]}') print int($2) } ' ' NR!=13{next};{sub(/[+-]$/,"",$NF)};'"`S0 21 22`" 'NR!=2{next}'"`S0 37 17`" ' NR!=5||$8!~/[RW]/{next};{ $(NF-1)=$1;$NF=int($NF/10000000);for(i=1;i<=3;i++){$i="";$(NF-1-i)="";};};'"`S0 19 20`" 's:^:/:p' '/\.kext\/(Contents\/)?Info\.plist$/p' 's/^.{52}(.+) <.+/\1/p' ' /Launch[AD].+\.plist$/ { n++;print;} END { if(n<200) print "/System/";} ' '/\.xpc\/(Contents\/)?Info\.plist$/p' ' NR>1&&!/0x|\.[0-9]+$|com\.apple\.launchctl\.(Aqua|Background|System)$/ { print $3;} ' ' /\.(framew|lproj)|\):/d;/plist:|:.+(Mach|scrip)/s/:[^:]+//p ' '/^root$/p' ' !/\/Contents\/.+\/Contents|Applic|Autom|Frameworks/&&/Lib.+\/Info.plist$/ { n++;print;} END { if(n<1100) print "/System/";} ' '/^\/usr\/lib\/.+dylib$/p' ' /Temp|emac/{next};/(etc|Preferences|Launch[AD].+)\// { sub(".(/private)?","");n++;print;} END { split("'"${p[41]}"'",b);split("'"${p[42]}"'",c);for(i in b) print b[i]".plist\t"c[i];if(n<500) print "Launch";} ' ' /\/(Contents\/.+\/Contents|Frameworks)\/|\.wdgt\/.+\.([bw]|plu)/d;p;' 's/\/(Contents\/)?Info.plist$//;p' ' { gsub("^| |\n","\\|\\|kMDItem'${p[35]}'=");sub("^...."," ") };1 ' p '{print $3"\t"$1}' 's/\'$'\t''.+//p' 's/1/On/p' '/Prox.+: [^0]/p' '$2>'${p[43]}'{$2=$2-1;print}' ' BEGIN { i="'${p[26]}'";M1='${p[16]}';M2='${p[18]}';M3='${p[31]}';M4='${p[32]}';} !/^A/{next};/%/ { getline;if($5<M1) a="user "$2"%, system "$4"%";} /disk0/&&$4>M2 { b=$3" ops/s, "$4" blocks/s";} $2==i { if(c) { d=$3+$4+$5+$6;next;};if($4>M3||$6>M4) c=int($4/1024)" in, "int($6/1024)" out";} END { if(a) print "CPU: "a;if(b) print "I/O: "b;if(c) print "Net: "c" (KiB/s)";if(d) print "Net errors: "d" packets/s";} ' ' /r\[0\] /&&$NF!~/^1(0|72\.(1[6-9]|2[0-9]|3[0-1])|92\.168)\./ { print $NF;exit;} ' ' !/^T/ { printf "(static)";exit;} ' '/apsd|BKAg|OpenD/!s/:.+//p' ' (/k:/&&$3!~/(255\.){3}0/ )||(/v6:/&&$2!~/A/ ) ' ' $1~"lR"&&$2<='${p[25]}';$1~"li"&&$3!~"wpa2";' ' BEGIN { FS=":";p="uniq -c|sed -E '"'s/ +\$[0-9]+\$\$.+\$/\\\2 x\\\1/;s/x1$//'"'";} { n=split($3,a,".");sub(/_2[01].+/,"",$3);print $2" "$3" "a[n]$1|p;b=b$1;} END { close(p);if(b) print("\n\t* Code injection");} ' ' NR!=4{next} {$NF/=10240} '"`S0 27 14`" ' END { if($3~/[0-9]/)print$3;} ' ' BEGIN { L='${p[36]}';} !/^[[:space:]]*(#.*)?$/ { l++;if(l<=L) f=f"\n "$0;} END { F=FILENAME;if(!F) exit;if(!f) f="\n [N/A]";"cksum "F|getline C;split(C, A);C="checksum "A[1];"file -b "F|getline T;if(T!~/^(AS.+ (En.+ )?text(, with v.+)?$|(Bo|PO).+ sh.+ text ex|XM)/) F=F" ("T", "C")";else F=F" ("C")";printf("\nContents of %s\n%s\n",F,f);if(l>L) printf("\n ...and %s more line(s)\n",l-L);} ' ' s/^ ?n...://p;s/^ ?p...:/-'$'\t''/p;' 's/0/Off/p' ' END{print NR} ' ' /id: N|te: Y/{i++} END{print i} ' ' / / { print "'"${p[28]}"'";exit;};1;' '/ en/!s/\.//p' ' NR!=13{next};{sub(/[+-M]$/,"",$NF)};'"`S0 39 40`" ' $10~/$L/&&$9!~"localhost" { sub(/.+:/,"",$9);print $1": "$9|"sort|uniq";} ' '/^ +r/s/.+"(.+)".+/\1/p' 's/(.+\.wdgt)\/(Contents\/)?Info\.plist$/\1/p' 's/^.+\/(.+)\.wdgt$/\1/p' ' /l: /{ /DVD/d;s/.+: //;b0'$'\n'' };/s: /{ /V/d;s/^ */- /;H;};$b0'$'\n'' d;:0'$'\n'' x;/APPLE [^:]+$/d;p;' ' /^find: /d;p;' "`S0 44 45`" ' BEGIN{FS="= "} /Path/{print $2} ' ' /^ *$/d;s/^ */ /;' ' s/^.+ |\(.+$$//g;p ' '/\.(appex|pluginkit)\/Contents\/Info\.plist$/p' ' /2/{print "WARN"};/4/{print "CRITICAL"};' ' /EVHF|MACR|^s/d;s/^.+: //p;' );c1=(system_profiler pmset\ -g nvram fdesetup find syslog df vm_stat sar ps crontab iotop top pkgutil 'PlistBuddy 2>&1 -c "Print' whoami cksum kextstat launchctl smcDiagnose sysctl\ -n defaults\ read stat lsbom mdfind ' for i in ${p[24]};do ${c1[18]} ${c2[27]} $i;done;' pluginkit scutil dtrace profiles sed\ -En awk /S*/*/P*/*/*/C*/*/airport networksetup mdutil lsof test osascript\ -e );c2=(com.apple.loginwindow\ LoginHook '" /L*/P*/loginw*' "'tell app \"System Events\" to get properties of login items'|tr , \\\n" 'L*/Ca*/com.ap*.Saf*/E*/* -d 1 -name In*t -exec '"${c1[14]}"' :CFBundleDisplayName" {} \;|sort|uniq' '~ $TMPDIR.. $ -flags +sappnd,schg,uappnd,uchg -o ! -user $UID -o ! -perm -600 $' '.??* -path .Trash -prune -o -type d -name *.app -print -prune' :${p[35]}\" :Label\" '{/,}L*/{Con,Pref}* -type f ! -size 0 -name *.plist -exec plutil -s {} \;' "-f'%N: %l' Desktop L*/Keyc*" therm sysload boot-args status " -F '\$Time \$(RefProc): \$Message' -k Sender Req 'fsev|kern|launchd' -k RefProc Rne 'Aq|WebK' -k Message Rne 'Goog|ksadm|probe|Roame|SMC:|smcD|sserti|suhel| VALI|ver-r|xpma' -k Message Req 'abn|bad |Beac|caug|corru|dead[^bl]|FAIL|fail|GPU |hfs: Ru|inval|jnl:|last value [1-9]|NVDA$|pagin|proc: t|Roamed|rror|SL|TCON|Throttli|tim(ed? ?|ing )o|WARN' " '-du -n DEV -n EDEV 1 10' 'acrx -o comm,ruid,%cpu' '-t1 10 1' '-f -pfc /var/db/r*/com.apple.*.{BS,Bas,Es,J,OSXU,Rem,up}*.bom' '{/,}L*/Lo*/Diag* -type f -regex .\*[cght] ! -name .?\* ! -name \*ag \( -exec grep -lq "^Thread c" {} \; -exec printf \* \; -o -true $ -execdir stat -f:%Sc:%N -t%F {} \;|sort -t: -k2 |tail -n'${p[38]} '/S*/*/Ca*/*xpc* >&- ||echo No' '-L /{S*/,}L*/StartupItems -type f -exec file {} +' '-L /S*/L*/{C*/Sec*A,Ex}* {/,}L*/{A*d,Ca*/*/Ex,Co{mpon,reM},Ex,In{p,ter},iTu*/*P,Keyb,Mail/B,Pr*P,Qu*T,Scripti,Sec,Servi,Spo,Widg}* -path \\*s/Resources -prune -o -type f -name Info.plist' '/usr/lib -type f -name *.dylib' `awk "${s[31]}"<<<${p[23]}` "/e*/{auto,{cron,fs}tab,hosts,{[lp],sy}*.conf,mach_i*/*,pam.d/*,ssh{,d}_config,*.local} {,/usr/local}/etc/periodic/*/* /L*/P*{,/*}/com.a*.{Bo,sec*.ap}*t {/S*/,/,}L*/Lau*/*t .launchd.conf" list getenv /Library/Preferences/com.apple.alf\ globalstate --proxy '-n get default' -I --dns -getdnsservers\ "${p[N5]}" -getinfo\ "${p[N5]}" -P -m\ / '' -n1 '-R -l1 -n1 -o prt -stats command,uid,prt' '--regexp --only-files --files com.apple.pkg.*|sort|uniq' -kl -l -s\ / '-R -l1 -n1 -o mem -stats command,uid,mem' '+c0 -i4TCP:0-1023' com.apple.dashboard\ layer-gadgets '-d /L*/Mana*/$USER&&echo On' '-app Safari WebKitDNSPrefetchingEnabled' "+c0 -l|awk '{print(\$1,\$3)}'|sort|uniq -c|sort -n|tail -1|awk '{print(\$2,\$3,\$1)}'" -m 'L*/{Con*/*/Data/L*/,}Pref* -type f -size 0c -name *.plist.???????|wc -l' kern.memorystatus_vm_pressure_level '3>&1 >&- 2>&3' " -F '\$Time \$Message' -k Sender kernel -k Message CSeq 'n Cause: -' " );N1=${#c2[@]};for j in {0..9};do c2[N1+j]=SP${p[j]}DataType;done;N2=${#c2[@]};for j in 0 1;do c2[N2+j]="-n ' syscall::'${p[33+j]}':return { @out[execname,uid]=sum(arg0) } tick-10sec { trunc(@out,1);exit(0);} '";done;l=(Restricted\ files Hidden\ apps 'Elapsed time (s)' POST Battery Safari\ extensions Bad\ plists 'High file counts' User Heat System\ load boot\ args FileVault Diagnostic\ reports Log 'Free space (MiB)' 'Swap (MiB)' Activity 'CPU per process' Login\ hook 'I/O per process' Mach\ ports kexts Daemons Agents XPC\ cache Startup\ items Admin\ access Root\ access Bundles dylibs Apps Font\ issues Inserted\ dylibs Firewall Proxies DNS TCP/IP Wi-Fi Profiles Root\ crontab User\ crontab 'Global login items' 'User login items' Spotlight Memory Listeners Widgets Parental\ Controls Prefetching SATA Descriptors App\ extensions Lockfiles Memory\ pressure SMC Shutdowns );N3=${#l[@]};for i in 0 1 2;do l[N3+i]=${p[5+i]};done;N4=${#l[@]};for j in 0 1;do l[N4+j]="Current ${p[29+j]}stream data";done;A0() { id -G|grep -qw 80;v[1]=$?;((v[1]==0))&&sudo true;v[2]=$?;v[3]=`date +%s`;clear >&-;date '+Start time: %T %D%n';};for i in 0 1;do eval ' A'$((1+i))'() { v=` eval "${c1[$1]} ${c2[$2]}"|'${c1[30+i]}' "${s[$3]}" `;[[ "$v" ]];};A'$((3+i))'() { v=` while read i;do [[ "$i" ]]&&eval "${c1[$1]} ${c2[$2]}" \"$i\"|'${c1[30+i]}' "${s[$3]}";done<<<"${v[$4]}" `;[[ "$v" ]];};A'$((5+i))'() { v=` while read i;do '${c1[30+i]}' "${s[$1]}" "$i";done<<<"${v[$2]}" `;[[ "$v" ]];};A'$((7+i))'() { v=` eval sudo "${c1[$1]} ${c2[$2]}"|'${c1[30+i]}' "${s[$3]}" `;[[ "$v" ]];};';done;A9(){ v=$((`date +%s`-v[3]));};B2(){ v[$1]="$v";};for i in 0 1;do eval ' B'$i'() { v=;((v['$((i+1))']==0))||{ v=No;false;};};B'$((3+i))'() { v[$2]=`'${c1[30+i]}' "${s[$3]}"<<<"${v[$1]}"`;} ';done;B5(){ v[$1]="${v[$1]}"$'\n'"${v[$2]}";};B6() { v=` paste -d: <(printf "${v[$1]}") <(printf "${v[$2]}")|awk -F: ' {printf("'"${f[$3]}"'",$1,$2)} ' `;};B7(){ v=`grep -Fv "${v[$1]}"<<<"$v"`;};C0() { [[ "$v" ]]&&sed -E "$s"<<<"$v";};C1() { [[ "$v" ]]&&printf "${f[$1]}" "${l[$2]}" "$v"|sed -E "$s";};C2() { v=`echo $v`;[[ "$v" != 0 ]]&&C1 0 $1;};C3() { v=`sed -E "${s[63]}"<<<"$v"`&&C1 1 $1;};for i in 1 2 7 8;do for j in 0 2 3;do eval D$i$j'(){ A'$i' $1 $2 $3; C'$j' $4;};';done;done;{ A0;D20 0 $((N1+1)) 2;D10 0 $N1 1;B0;C2 27;B0&&! B1&&C2 28;D12 15 37 25 8;A1 0 $((N1+2)) 3;C0;D13 0 $((N1+3)) 4 3;D23 0 $((N1+4)) 5 4;D13 0 $((N1+9)) 59 50;for i in 0 1 2;do D13 0 $((N1+5+i)) 6 $((N3+i));done;D13 1 10 7 9;D13 1 11 8 10;B1&&D73 19 53 67 55;D22 2 12 9 11;D12 3 13 10 12;D23 4 19 44 13;D23 5 54 12 56;D23 5 14 12 14;D22 6 36 13 15;D22 20 52 66 54;D22 7 37 14 16;D23 8 15 38 17;D22 9 16 16 18;B1&&{ D82 35 49 61 51;D82 11 17 17 20;for i in 0 1;do D82 28 $((N2+i)) 45 $((N4+i));done;};D22 12 44 54 45;D22 12 39 15 21;A1 13 40 18;B2 4;B3 4 0 19;A3 14 6 32 0;B4 0 5 11;A1 17 41 20;B7 5;C3 22;B4 4 6 21;A3 14 7 32 6;B4 0 7 11;B3 4 0 22;A3 14 6 32 0;B4 0 8 11;B5 7 8;B1&&{ A8 18 26 23;B7 7;C3 23;};A2 18 26 23;B7 7;C3 24;D13 4 21 24 26;B4 4 12 26;B3 4 13 27;A1 4 22 29;B7 12;B2 14;A4 14 6 52 14;B2 15;B6 14 15 4;B3 0 0 30;C3 29;A1 4 23 27;B7 13;C3 30;B3 4 0 65;A3 14 6 32 0;B4 0 16 11;A1 26 50 64;B7 16;C3 52;D13 24 24 32 31;D13 25 37 32 33;A2 23 18 28;B2 16;A2 16 25 33;B7 16;B3 0 0 34;B2 21;A6 47 21&&C0;B1&&{ D73 21 0 32 19;D73 10 42 32 40;D82 29 35 46 39;};D23 14 1 62 42;D12 34 43 53 44;D12 22 20 32 25;D22 0 $((N1+8)) 51 32;D13 4 8 41 6;D12 21 28 35 34;D13 27 29 36 35;A2 27 32 39&&{ B2 19;A2 33 33 40;B2 20;B6 19 20 3;};C2 36;D23 33 34 42 37;B1&&D83 35 45 55 46;D23 32 31 43 38;D12 36 47 32 48;D13 10 42 32 41;D13 37 2 48 43;D13 4 5 32 1;D13 4 3 60 5;D12 21 48 49 49;B3 4 22 57;A1 21 46 56;B7 22;B3 0 0 58;C3 47;D22 4 4 50 0;D12 4 51 32 53;D23 22 9 37 7;A9;C2 2;} 2>/dev/null|pbcopy;exit 2>&-
Copy the selected text to the Clipboard by pressing the key combination command-C.
8. Launch the built-in Terminal application in any of the following ways:
☞ Enter the first few letters of its name into a Spotlight search. Select it in the results (it should be at the top.)
☞ In the Finder, select Go ▹ Utilities from the menu bar, or press the key combination shift-command-U. The application is in the folder that opens.
☞ Open LaunchPad. Click Utilities, then Terminal in the icon grid.
Click anywhere in the Terminal window and paste by pressing command-V. The text you pasted should vanish immediately. If it doesn't, press the return key.
9. If you see an error message in the Terminal window such as "Syntax error" or "Event not found," enter
exec bash
and press return. Then paste the script again.
10. If you're logged in as an administrator, you'll be prompted for your login password. Nothing will be displayed when you type it. You will not see the usual dots in place of typed characters. Make sure caps lock is off. Type carefully and then press return. You may get a one-time warning to be careful. If you make three failed attempts to enter the password, the test will run anyway, but it will produce less information. In most cases, the difference is not important. If you don't know the password, or if you prefer not to enter it, press the key combination control-C or just press return three times at the password prompt. Again, the script will still run.
If you're not logged in as an administrator, you won't be prompted for a password. The test will still run. It just won't do anything that requires administrator privileges.
11. The test may take a few minutes to run, depending on how many files you have and the speed of the computer. A computer that's abnormally slow may take longer to run the test. While it's running, there will be nothing in the Terminal window and no indication of progress. Wait for the line
[Process completed]
to appear. If you don't see it within half an hour or so, the test probably won't complete in a reasonable time. In that case, close the Terminal window and report what happened. No harm will be done.
12. When the test is complete, quit Terminal. The results will have been copied to the Clipboard automatically. They are not shown in the Terminal window. Please don't copy anything from there. All you have to do is start a reply to this comment and then paste by pressing command-V again.
At the top of the results, there will be a line that begins with the words "Start time." If you don't see that, but instead see a mass of gibberish, you didn't wait for the "Process completed" message to appear in the Terminal window. Please wait for it and try again.
If any private information, such as your name or email address, appears in the results, anonymize it before posting. Usually that won't be necessary.
13. When you post the results, you might see an error message on the web page: "You have included content in your post that is not permitted," or "You are not authorized to post." That's a bug in the forum software. Please post the test results on Pastebin, then post a link here to the page you created.
14. This is a public forum, and others may give you advice based on the results of the test. They speak only for themselves, and I don't necessarily agree with them.
Copyright © 2014 by Linc Davis. As the sole author of this work, I reserve all rights to it except as provided in the Use Agreement for the Apple Support Communities website ("ASC"). Readers of ASC may copy it for their own personal use. Neither the whole nor any part may be redistributed.

Employee works for 4 org units and want to distribute the cost to 4 cost ce

Hi Experts,
I am in the implementation phase, requirement gathering.
I have scenerio where, Employee works for 4 org units and want to distribute the cost to 4 different cost centers.
so that I can be able to find the exact cost occured for each Org unit.
Please let me know how to map this in SAP?
P oints will be rewarded fully
Kindly dont post if you are not sure of your solution friends.
Thanks
Jay

Hello,
Infotype 0027 is the standard solution for multiple reporting / multi tasking in SAP.
but also check which org unit he will be primarily assigned.
Regards

After moving all photographs from my first catalogue, which was a mess, to a new catalogue, it all worked fine. Until that is I tried to open the new catalogue, which had worked OK all day. I now get a window that says "Unexpected error, select another ca

After moving all photographs from my first catalogue, which was a mess, to a new catalogue, it all worked fine. Until that is I tried to open the new catalogue, which had worked OK all day. I now get a window that says "Unexpected error, select another catalogue."

OK, restart in Safe Mode, this will clear some caches. It's possible one or more is corrupt. To restart in Safe Mode when you hear the start up tone hold down the Shift Key until you see a progress bar. Let it fully boot then restart normally and test.
Also I am assuming you have checked Finder - Preferences - General and see what boxes are checked in "Show these items on desktop." You can also mount an item in Disk Utility, simply highlight it and then look in the File menu for Mount.....

How can we configure in MSS to view Employee work schedule?

Hi,
How can we configure in MSS to view Employee work schedule?
Regards,
Poornima

Hi,
Can you please tell me what is your exact requirement?....
I think in the standard MSS package there is an iview for viewing the workschedule related information like Hours/day, Hrs/week, hrs/month and hrs/year for a position.
However, if you want to view the workschedule for employee, it can easily be configured through the OADP.
You can create a custom Function module for fetching the workschedule for each employee and after creating a custom column, add it to any data view.
Thanks,
Pinki

Help with time employee work

hallow,
i have problem that i have to find how much time employee work during the month but i have to consider month with holidays and so on what is the best way to do that?
example
if the standard hour for month is 180 hours and employee work just half month i wont to find the relative part of employee working in this month with consider the calendar of this moth (4 or 5 Sunday or more holidays).
Regards

dude dont mess up code like this. Think before you go for writing some code.

Count consecutive days in array

Hi,
I'm looking for an algorithm to count consecutive days in array, but i don't find one.
for example, if i have this array.
2009/07/01
2009/07/02
2009/07/03
2009/07/06
2009/07/08
2009/07/09
2009/07/10
2009/07/11
The result be
3
1
4
Anyone have one?
Thanks for all.

jverd wrote:
kajbj wrote:
It's a fairly specialist algorithm so you are unlikely to find someone to post a solution. By just keeping a reference to the previous date, it is easy to iterate though the list counting consecutive dates.I think the trick to making this algorithm sucessful is to make sure that when you change months your algorithm doesn't set consec_days to 0 Why not?Presumably he's talking about this case:
7/31
8/1
and not this case
7/1
8/1
So he really should have said, "...when you increment month by one, or from 12 to 1, and the day went from the last day of the old month to 1, don't set consec_days to 0"Ok. I would use the Calendar class and SimpleDateFormat. The tricky part would otherwise be to keep track of days per month, and leap year.

I hve pop up from adobe that tell me they have problem with my paiement and billing information and to go in my account or my lisence will stop working in 25 days

I have pop up from adobe that tell me they have problem with my paiement and billing information and to go in my account or my lisence will stop working in 25 days again... I can't find anything wrong in my account infos. What do I need to check and change? Adobe takes the money directly on my credit card since almost 2 years and I haven't change anything sicne then. The expiration date is good. Also, I'm not able to contact the Adobe support, it's not available.

ImprimerieModerne, my response of about being unable to find the CC was for Kathy P. The issue that you are facing is being worked upon.
I am sorry for the confusion.
Regards
Rajshree

Ok my phone was working fine two days ago and it stared to say connent to itunes how do i get it off

ok my iphone 3gs or 3g was working fine two days ago and it stared to say conniet to itunes can u help me

Hi agforlife2010,
If your iPhone isn't responding and is displaying a screen indicating you need to connect to iTunes, you may find the following article helpful:
Apple Support: If you can't update or restore your iOS device
http://support.apple.com/kb/ht1808
Regards,
- Brenden

Find Employee Worked 7 Consecutive days

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