Find highest order and last node in a tree..

Question

the problem is:-
suposse A is parent node and order 1
A's child is B and order 2
B's child is C and order 3
B's child is D and order 4
D child is E order 5
E child is F order 6
A's child is G and order 7
how can i find the highest order is 7 and last node is F order 6 of above thee?
order is from which tree is sorted assecnding.
Edited by: user1157479 on Aug 24, 2009 10:57 PM

Answer 1

with t as (
select '' par,'A' chi from dual union all
select 'A' par,'B' chi from dual union all
select 'B' par,'C' chi from dual union all
select 'C' par,'D' chi from dual union all
select 'D' par,'E' chi from dual union all
select 'E' par,'F' chi from dual union all
select 'A' par,'G' chi from dual )
select maxlvl,chi,maxorder from (select p.*,max(lvl) over () maxlvl,max(rnum) over () maxorder from (select t.*,level lvl,rownum rnum from t connect by prior chi=par start with chi='A') p)  where rnum=maxlvlRavi Kumar
Edited by: ravikumar.sv on Aug 25, 2009 11:45 AM