Finding an anomaly in a set of numbers

Question

Hi,
I am trying to find an anomaly in a set of numbers. However, I'm struggling to implement it. Let's say I have the following numbers:
1
2
3
2
1
5
1
The number five would be the anomaly in this case.
How would I be able to find this with a piece of java code?
Thanks

Answer 1

It is not homework. I am creating a peer assisted study portal. This is where students can submit work and other people can mark it. I was first thinking of counting the occurrences of each rating and then putting them in order and flag the lowest occurrences. When I put that into practise it didn't really work. The other option I tried was the following:
for(int i = 0;i < originalResponses.size(); i++)
            int iValue = Integer.parseInt(originalResponses.get(i).toString());
            iValue = iValue + 2;
            if(iValue > 5)
                iValue = 5;
            for(int a = 0; a < originalResponses.size(); a++)
                int aValue = Integer.parseInt(originalResponses.get(a).toString());
                System.err.println("aValue: " + aValue + " iValue: " + iValue);
                if(aValue < iValue)
                    System.err.println(aValue + " is an anomaly");
        }The problem this threw was that lets say I have the following ratings in the database:
5
1
1
1
1
It would recognise that 5 is an anomaly but it would also recognise that 1 is an anomaly as it is comparing all numbers in all possible combinations.