Finding char in a string

Hi,
In C there is a function strchr() to find a char in a string. Is there an equivalent funtion in Java?
The function indexOf() returns an int, but I want this char search would return a boolean value.
So help please, thanks a lot
chanh

public boolean strchr(char myChar, String myString){
 for(int j = 0; j < myString.length(); j++){
 if(myChar == myString.charAt(j) return true;
 return false;
}Is this what you are looking for?

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Finding last char in the string

Hi
i need to find out whether the last char of a string is '/' (forward slash). please let me know if there's a FM to do that. Other post me the logic for this ASAP.
thanks

len = strlen(char).
len = len - 1.
if char+len(1) = '/'.
*write ur code
endif.
chk this code
REPORT ychatest.
DATA : str(5) VALUE '123/',
len TYPE i.
len = STRLEN( str ).
len = len - 1.
IF str+len(1) = '/'.
WRITE : '/ found'.
ENDIF.
Reward points if helpful and close thrad if solved
Message was edited by: Chandrasekhar Jagarlamudi

Finding first numeric in string

Hi,
I am trying to find a way I can find the first numeric in a string.
This works but I have to do it 10 times:
String vtemp = vdoc.indexOf('1');Example of data:
AB123
CDE456
ABCD789I am trying to find a way to do something like: indexOf(any number); So I can get the result in one line of code.
Thanks for any help

Hi GaryJSF,
You have to convert your string into an array of characters and for each character, check if it's a digit until you find the first one :
String str = "ABC123";
char[] crs = str.toCharArray();
for (int i = 0; i < crs.length; i++) {
if (Character(crs).isDigit()) {
System.out.println("first index = " + i);
break;

Query engine : Can not find DSN in Connection String

DearSir/Madam,
Opearating System Windows 7 Professional(32-bit).
I am using Application, which is developed : Visual basic 6.0(32-bit), Report Writer : Crystal Report 9.2.693(32-bit) and database: Oracle 9.2.0.10(32-bit).
ODBC Data source : System DSN created and Connection established (Based on Driver : CR ORACLE ODBC Driver 4.10 (cror818.dll))
In windows 7 environment Data Base connectivity and data fetching also wroking fine.
My problem is while running reports it display error as "Query engine : Can not find DSN in Connection String"
I want run time reports.
For your kind information, at the same time in Windows XP Professional there is no problem found and working fine.
Kindly help me.
Thanks and regards,
Swarup

Crystal Reports 9.x is not supported on Win 7. See the following wiki:
http://wiki.sdn.sap.com/wiki/x/b4JiAw
- Ludek

[Forum FAQ] How to find and replace text strings in the shapes in Excel using Windows PowerShell

Windows PowerShell is a powerful command tool and we can use it for management and operations. In this article we introduce the detailed steps to use Windows PowerShell to find and replace test string in the
shapes in Excel Object.
Since the Excel.Application
is available for representing the entire Microsoft Excel application, we can invoke the relevant Properties and Methods to help us to
interact with Excel document.
The figure below is an excel file:
Figure 1.
You can use the PowerShell script below to list the text in the shapes and replace the text string to “text”:
$text = “text1”,”text2”,”text3”,”text3”
$Excel
= New-Object -ComObject Excel.Application
$Excel.visible = $true
$Workbook
= $Excel.workbooks.open("d:\shape.xlsx")
#Open the excel file
$Worksheet
= $Workbook.Worksheets.Item("shapes")
#Open the worksheet named "shapes"
$shape = $Worksheet.Shapes
# Get all the shapes
$i=0
# This number is used to replace the text in sequence as the variable “$text”
Foreach ($sh in $shape){
$sh.TextFrame.Characters().text
# Get the textbox in the shape
$sh.TextFrame.Characters().text =
$text[$i++]
#Change the value of the textbox in the shape one by one
$WorkBook.Save()
#Save workbook in excel
$WorkBook.Close()
#Close workbook in excel
[void]$excel.quit()
#Quit Excel
Before invoking the methods and properties, we can use the cmdlet “Get-Member” to list the available methods.
Besides, we can also find the documents about these methods and properties in MSDN:
Workbook.Worksheets Property (Excel):
http://msdn.microsoft.com/en-us/library/office/ff835542(v=office.15).aspx
Worksheet.Shapes Property:
http://msdn.microsoft.com/en-us/library/office/ff821817(v=office.15).aspx
Shape.TextFrame Property:
http://msdn.microsoft.com/en-us/library/office/ff839162(v=office.15).aspx
TextFrame.Characters Method (Excel):
http://msdn.microsoft.com/en-us/library/office/ff195027(v=office.15).aspx
Characters.Text Property (Excel):
http://msdn.microsoft.com/en-us/library/office/ff838596(v=office.15).aspx
After running the script above, we can see the changes in the figure below:
Figure 2.
Please click to vote if the post helps you. This can be beneficial to other community members reading the thread.

Thank you for the information, but does this thread really need to be stuck to the top of the forum?
If there must be a sticky, I'd rather see a link to a page on the wiki that has links to all of these ForumFAQ posts.
EDIT: I see this is no longer stuck to the top of the forum, thank you.
Don't retire TechNet! -
(Don't give up yet - 13,085+ strong and growing)

Find and Replace text string in HTML

Opps... I hope this forum is not just for Outlook. My Html files reside on my hard-drive. I am looking for VBA code to open specified file names ####File.html and then find and replace text strings within the html for example "####Name" replaced
with "YYYYY"
I drive the "####File.html" names and the find and replace text strings from an Excel sheet. I am an artist and this Sub would give me time to paint instead of find and replace text. Thank you!
[email protected]

Hello Phil,
The current forum is for developers and Outlook related programming questions. That's why I'd suggest hiring anybody for developing the code for you. You may find freelancers, for example. Try googling for any freelance-related web sites and asking such
questions there.
If you decide to develop an Outlook macro on your own, the
Getting Started with VBA in Outlook 2010 article is a good place to start from.

How to delete the last char in a String?

i want to delete the last char in a String, but i don't want to convert the String to a StringBuffer or an array, who knows how to do?

Try it in this way
String MyString = "ABCDEF";
MyString = MyString.substring(0,MyString.length()-1);

How to find out if a string is all alphabets

Hi,
How can I find out if a string contains all alphabets? Please help. Thanks.

Hi,
How can I find out if a string contains all
all alphabets? Please help. Thanks. I am not sure if there's easier way. But this code should do what you want:
boolean bAlpha = true;
for (int i=0; i<str.length; i++)
if (!Character.isLetter(str.charAt(i))){
bAlpha = false;
break;
//bAlpha is true if str contains only alphabets.

Newbie question: cannot find symbol symbol: class STRING

I've just decided to teach myself some java, and on my first try something's going wrong and I don't know what it is.
I'm currently doing this tutorial: http://java.sun.com/docs/books/tutorial/uiswing/learn/example1.html
and everything is good until I try to compile it and I get this error in the cmd
HelloWorldSwing.java:30: cannot find symbol
cannot find symbol
symbol: class STRING
everything has been written verbatim from the tutorial, including "import javax.swing.*;"
What's wrong with it and how do I fix it?

Hi,
I saw the coding that You had given a link in your post. Change the following
public static void main(String[] args) {bye for now
sat

Deleting the last char of a string

How can I Delete the last char of a string???
example:
asd@fdg@vvdfgfd@gdgdfgfd@gdfgdf@
I want delete the last @!
Tks in advance!

hi,
try this:
lv_count = strlen(string).
lv_count_last = lv-count - 1.
replace string+lv_count_last(lv_count) in string by ' '.
This should work.
thnx,
ags.
Edited by: Agasti Kale on Jun 4, 2008 9:03 PM

How to remove last char in a string by space

I have to implement backspace application(remove a last char in a string , when we pressed a button).
for ex: I enter the no
1234
instead of 1236
So when i press a button on the JWindow... it should display
123
so that i can enter 6 now.
I tried to display the string "123 " instead over "1234" but it is not working when the no background is specified. but works fine when a background color is specified.
The string is displayed as
Graphics2D g = (Graphics2D)window.getGraphics();
AttributedString as = new AttributedString(string, map);
g.drawString(as.getIterator(),x,y);
In the map, the background is set to NO_BACKGROUND.
Thanks and regards

Deja vu. I saw this kind of post before, and I'm sure
it was today.http://forum.java.sun.com/thread.jspa?threadID=588110&tstart=0
Here it is.

Deleting last char in a string...

I have a string that is created as follows: strBuffer += k.getKeyChar();(k is KeyPressed ...KeyEvent) How can I delete the last Char in the string strBuffer?

Hi
// simply substring
if (strBuffer.length() > 1)
    strBuffer = strBuffer.substring(0, strBuffer.length()-1);
// you may also use
if (strBuffer.length() > 1)
    StringBuffer buffer = new StringBuffer(strBuffer).
                               deleteCharAt(strBuffer.length()-1);
    strBuffer = buffer.toString();
}I've not tested the above code myself & I've written the above code on the go after reading your query. The above code definitely work & help you.
Regards,
JPassion

How to find and replace any string between " "

Hi everyone,
Here my sample
String szTest;
szTest = "Yellow banana";
szTest = "Blue monkey";
szTest = "Red mango";
szTest is only needed when it's in testing progress. Now I want to put all of that in the /*comment*/ so the released program won't run those code any more (but still keep szTest so I can use it for future develop testing).
So Here what I want after using the Find and Replace Box:
//String szTest; //Manual
/*szTest = "Yellow banana";*/ //use find and replace
/*szTest = "Blue monkey";*/ //use find and replace
/*szTest = "Red mango";*/ //use find and replace
I think I can do this with Regular expressions or Wildcards. But I don't know how to find and replace any string between " and ".
Find: szTest = " ??Any string?? ";
Replace with: /*szTest = " ??Any string?? ";*/
Thanks for reading.

Hi Nathan.j.Smith,
Based on your issue, I suggest you can try the Joel's suggestion check your issue again. In addition, I find a MSDN document about how to use the Regex.Replace Method to match a regular expression pattern with a specified replacement string,
maybe you will get some useful message.
https://msdn.microsoft.com/en-us/library/xwewhkd1(v=vs.110).aspx
If the above suggestion still could not provide you, could you please tell me what language you use to create the program for finding and replace any string using regular expression so that we will find the correct programming develop forum to support this
issue?
Best Regards,
We are trying to better understand customer views on social support experience, so your participation in this interview project would be greatly appreciated if you have time. Thanks for helping make community forums a great place.
Click
HERE to participate the survey.

Compare individual char of 2 string

Hi
I need to compare the each individual char of 2 string.
String a = "Ae12";
String b = "aE12";
// I tried the followings:
// a
String c = a.substring(0,0);
String d = a.substring(1,1);
String e = a.substring(2,2);
String f = a.substring(3,3);
// b
String c1 = b.substring(0,0);
String d1 = b.substring(1,1);
String e1 = b.substring(2,2);
String f1 = b.substring(3,3);
if(c.equalsIgnoreCase(c1)&&d.equalsIgnoreCase(d1)&&e.equalsIgnoreCase(e1)&&f.equalsIgnoreCase(f1)) // Cannot be compared
// and I tried the followings:
// a
char c = a.charAt(0);
char d = a.charAt(1);
char e = a.charAt(2);
char f = a.charAt(3);
// b
char c1 = b.charAt(0);
char d1 = b.charAt(1);
char e1 = b.charAt(2);
char f1 = b.charAt(3);
if(c==c1&&d==d1&&e==e1&&f==f1) // cannot be compared.
Both cases cannot be compared. How can I fix it?
Because I want to compare those 2 strings without case sensitive and numbers.
Thanks

techissue2008 wrote:
String a = "Ae12";
String b = "aE12";
Then, are "Ae12" and "aE12" the same when ignore case?
If so, the Strings are actually the same.No, the Strings are not the same, if by same, you mean the "same" Object, or the "same" value when case is not ignored, but they are the "same" value when case is ignored.
This prints true (try it yourself), as it should
public class Test {
public static void main (String[] args) {
System.out.println("aE12".equalsIgnoreCase("Ae12"));
}They are still two distinct instances with two distinct values however, so where, exactly, is your problem?

Finding number in a string

I am trying to find a number in a string from my database to replace it. Here is my funciton:
function findUserID($friendsString, $userToFind){
 echo $friendsString . " " . $userToFind;
 $pos = strpos($friendsString,$userToFind);
 if($pos){
 return true;
 return false;
it returns "25,29 25". How can it not find 25 in that string?

I understand that it starts at 0. it should still work. i had it working before. i must've changed something.
here is my code for passing to the function:
$query = mysql_query("SELECT friends, pendingFriendRequest
FROM members
WHERE username = '$userID'");
if (mysql_affected_rows() > 0) {
 $row = mysql_fetch_array($query) or die(mysql_error());
 $friends = $row['friends'];
 $pendingFriends = $row['pendingFriendRequest'];
// If the user exists in the waiting list, then
//continue (we must confirm that they are first by checking the DB
$test = findUserID($pendingFriends, "25");
if($test){
 // If they are, then continue to add them
 $test = confirmFriend($pendingFriends, "25");
 if($test) {
 echo " You have confirmed " . findUserName(24) . "as a friend.";
 } else {
 echo " Error: Please try again, or contact us.";
} else {
 echo " Error: You either have this person as a friend already, or there was an internal error.";

Finding char in a string

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