How to remove last char in a string by space

I have to implement backspace application(remove a last char in a string , when we pressed a button).
for ex: I enter the no
1234
instead of 1236
So when i press a button on the JWindow... it should display
123
so that i can enter 6 now.
I tried to display the string "123 " instead over "1234" but it is not working when the no background is specified. but works fine when a background color is specified.
The string is displayed as
Graphics2D g = (Graphics2D)window.getGraphics();
AttributedString as = new AttributedString(string, map);
g.drawString(as.getIterator(),x,y);
In the map, the background is set to NO_BACKGROUND.
Thanks and regards

Deja vu. I saw this kind of post before, and I'm sure
it was today.http://forum.java.sun.com/thread.jspa?threadID=588110&tstart=0
Here it is.

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How to remove empty char from a string

Hi,
In my code I should get numeric int numbers and convert them to 1 and 0 , concatenate thm to make an string ( 8 chars) . the problem I have is the empty chars as result of conversion from number to string
so lets say pxiAnaIn=1 dutVdd=2 and dutOut=5 so then the output should be 10110001 but now the output is 10110 1 . could you please let me know how can I fix this problem
thanks

tintin_99 wrote:
Hi,
In my code I should get numeric int numbers and convert them to 1 and 0 , concatenate thm to make an string ( 8 chars) . the problem I have is the empty chars as result of conversion from number to string
so lets say pxiAnaIn=1 dutVdd=2 and dutOut=5 so then the output should be 10110001 but now the output is 10110 1 . could you please let me know how can I fix this problem
thanks
You could make your life a little easier and only use 1 format string. Use "%03b%02b%03b" for the format string. You can then expand the format string to allow multiple inputs. You will do the job of 4 functions with just 1.
"%3b" just says to give 3 spaces for the binary number. But any preceding 0s will be turned into spaces. Adding the 0 in there tells the format string to prepend 0s instead of using spaces.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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Remove last char of string

Hi Guys
How can I remove the last char of a String ?

With [the substring method|http://java.sun.com/javase/6/docs/api/java/lang/String.html#substring(int,%20int)] .

How to delete the last char in a String?

i want to delete the last char in a String, but i don't want to convert the String to a StringBuffer or an array, who knows how to do?

Try it in this way
String MyString = "ABCDEF";
MyString = MyString.substring(0,MyString.length()-1);

Remove last char

Ok i am trying to make just a simple calculator program for a class. I am trying to get the backspace button to work. How would i delete the last char in the string.

use a substring, the last char. will be:
myString.length
that will give you the length and from that you know what the last char. is

Deleting the last char of a string

How can I Delete the last char of a string???
example:
asd@fdg@vvdfgfd@gdgdfgfd@gdfgdf@
I want delete the last @!
Tks in advance!

hi,
try this:
lv_count = strlen(string).
lv_count_last = lv-count - 1.
replace string+lv_count_last(lv_count) in string by ' '.
This should work.
thnx,
ags.
Edited by: Agasti Kale on Jun 4, 2008 9:03 PM

Deleting last char in a string...

I have a string that is created as follows: strBuffer += k.getKeyChar();(k is KeyPressed ...KeyEvent) How can I delete the last Char in the string strBuffer?

Hi
// simply substring
if (strBuffer.length() > 1)
    strBuffer = strBuffer.substring(0, strBuffer.length()-1);
// you may also use
if (strBuffer.length() > 1)
    StringBuffer buffer = new StringBuffer(strBuffer).
                               deleteCharAt(strBuffer.length()-1);
    strBuffer = buffer.toString();
}I've not tested the above code myself & I've written the above code on the go after reading your query. The above code definitely work & help you.
Regards,
JPassion

How to remove the Char.from one Operating Concern

Hi Guys,
How to remove the Char. from one Operating Concern.
I have created one Char. (WWDOC) and moved to Operating Concern (OOCC). Operating Concern is in red status.
Now, i want to remove that new assigned Char. (WWDOC)from the operating concern (OOCC). I did't find any option in the menu also.
Appreciate your help.....
T&R
VVR

Hi Sasi,
Iam not able to push back that char. from my operating concern. In help it is given you have to delete the data contents in the table before pushing back. Please let me know if any other option available.
Thanks for your reply.
VVR

Finding last char in the string

Hi
i need to find out whether the last char of a string is '/' (forward slash). please let me know if there's a FM to do that. Other post me the logic for this ASAP.
thanks

len = strlen(char).
len = len - 1.
if char+len(1) = '/'.
*write ur code
endif.
chk this code
REPORT ychatest.
DATA : str(5) VALUE '123/',
len TYPE i.
len = STRLEN( str ).
len = len - 1.
IF str+len(1) = '/'.
WRITE : '/ found'.
ENDIF.
<b>Reward points if helpful and close thrad if solved</b>
Message was edited by: Chandrasekhar Jagarlamudi

How to get a char from a String Class?

How to get a char from a String Class?

Use charAt(int index), like this for example:
String s = "Java";
char c = s.charAt(2);
System.out.println(c);

Read last char of a String

I have the following code that functions like a basic RPN calculator:
public class Main {
     * @param args the command line arguments
     static public ArrayList<Double> stack = new ArrayList<Double>();
     static double numberInput;
     static double answer;
     static String operation;
//Prints Welcome screen, initialized checkforInput
     public static void main(String[] args) {
         System.out.println();
         System.out.println("Welcome to RPNCalc by theCoffeeShop()");
         checkForInput();
//Checks for input, redirects to appropriate method
     public static void checkForInput() {
         Scanner reader = new Scanner(System.in);
      String input = reader.nextLine();
         if(isDouble(input) == true) {
            double number = Double.parseDouble( input );
            stack.add(0, number);
            repeat();
         } else {
            operation = input;
            operation();
//Processes numeric operations
     public static void operation () {
         if(operation.equals("+")) {
             answer = stack.get(1)+stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else if (operation.equals("-")) {
             answer = stack.get(1)-stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else if (operation.equals("*")) {
             answer = stack.get(1)*stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else if (operation.equals("/")) {
             answer = stack.get(1)/stack.get(0);
             stack.add(0, answer);
             System.out.println(answer);
             repeat();
         } else {
             System.out.println("Incompatible operation");
             repeat();
//Called when ready to recheck for input
     public static void repeat() {
         checkForInput();
//Checks if string is double
     public static boolean isDouble( String input )
        try
            Double.parseDouble( input );
            return true;
        catch(Exception e)
           return false;
}To perform a basic operation (5+2), you would do the following
5
enter
2
enter
(plus)
enter
Computer prints 7.
I would like it to function like this:
5
enter
2(plus)
enter
Computer prints 7.
To do this, I have to be a be to split a string into 2 parts, the operation and the number. I think I could do this with a StringBuffer, but How to read the LAST char of a StringBuffer, instead of just a specific char? If there is a way to do it w/out a StringBuffer, I'm open to suggestions.

Hint:
The last character of a String (or StringBuilder or StringBuffer, etc.) is at the index (length_of_string - 1).
Are you sure you're supposed to solve the problem this way? Usually homework assignments of this sort involve writing a whole parser.

How to remove HTML tags from a String ?

Hello,
How can I remove all HTML Tags from a String ?
Would you please to give me a simple example ?
Best regards,
Eric

Here's some code I cooked up. I have created an object that processes code so that it can be incorporated directly into a project. There is some redundancy so that the it can be used in more than one way. Depending on your situation you might have to make the condition statement a little more sophisticated to catch stray ">" tags.
I have also included a Tester application.
//This removes Html tags from a String either by submitting the String during construction and then
// calling getProcessedString() or
// by simply calling " stringwithoutTags=removeHtmlTags(stringWithTagsSubmission); "
//Note: This code assumes that all"<" tags are accompanied by a ">" tag in the proper order.
public class HtmlTagRemover
     private String stringSubmission,processedString,stringBeingProcessed;
     private int indexOfTagStart,indexOfTagEnd;
     public HtmlTagRemover()
     public HtmlTagRemover(String s)
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     public String removeHtmlTags(String s)
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     private void removeNextTag()
          checkForNextTag();
          while((!(indexOfTagStart==-1||indexOfTagEnd==-1))&<indexOfTagEnd)
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          indexOfTagEnd=stringBeingProcessed.indexOf(">");
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     public String getProcessedString()
          return processedString;
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public class HtmlRemovalTester
     static void main(String[] args)
          String output;
          HtmlTagRemover h=new HtmlTagRemover();
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How to remove extra char in the uploaded file...?

Dear All,
There is file upload page in our portal.When user uploads the file (CSV) i can see there is extra char (^M) in the unix env.How can I remove that extra char before inserting into the database.For inserting into database I am using below code:
BlobDomain blobdomain = (BlobDomain)pageContext.getParameterObject(upldFileNameHD);
header.setFileData(blobdomain);
Did anyone can help me on this...
Thanks

Raffy is right in giving the explanation on why this happens.
Now way to
1. Remove it:
A. open file in vi
B. use this command, the way it works is, search(%s) for the ^M char and replace it with space (//) , and do this globally (g)
:%s/^M//g
C. To type ^M char press Ctrl Key and press either M or J, it should print that char.
D. Save the file (:wq)
2. Avoid it:
when doing FTP, use binary mode, just type bin before you do a put.
Thanks,
Tapash

How to delete last character in a string

Guys i have a question...
how can i delete the last character in a string..
for example
String myString = "helloWorld, ";
how do i delete the last character in this string which is a "," ?

String newString = myString.substring(0, myString.length()-1);

How to remove last blank page from preview of Smartform

Hi Experts ,
I am creating a smartform having vbeln range option. Now if i give range from 2 to 10 then After Doc NO. 10
i got a blank page . So can u please tell me how to remove that.
Rgds,
Premraj

hey,
Create a program lines node.....
in that describe the internal table in which you are having the document number.If you are having 10 document number then you will be having 10 pages.... so create program lines befor the command line in the command line just give a flag ok.
when the 10th page is created then the control comes to program line where the pagenumber will be equal to the number of document number there create a flag ( f = 'X') then give this codition in command line.Trigger the command line when ever f NE 'X'.So in the last time new page will not be triggered.
Regards,
Midhun Abraham

How to remove last char in a string by space

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